mysql map comma seperated coumn values with new values by table lookup - mysql

Question

I am using MySQL database.
I have a CUST_INV_DET table where I have data in below format
---------------------------
CUSTOMER_ID CUSTOMER_NO
---------------------------
1 1983,1988,1989
2 2014,2011,2010
3 3012,3059,3045
---------------------------
And there is another table. NEW_CUSTOMER_NO_FORMAT
--------------------------------------
OLD_CUSTOMER_NO NEW_CUSTOMER_NO
--------------------------------------
1983 C1983-01
1988 C1988-03
1989 C1989-06
2014 C2014-01
2011 C2011-02
2010 C2010-02
3012 C3012-03
3059 C3059-23
3045 C3045-09
Can anybody suggest me on how to map CUST_INV_DET.CUSTOMER_NO in a new format by doing lookup from NEW_CUSTOMER_NO_FORMAT Table.
I know I need to use cursor but inside cursor below section I am clueless how to map since it's a comma separated value.
Do I need one more cursor inside NO_MORE_DATA =0 ?
IF (NO_MORE_DATA = 0) THEN
//MAP OLD TO NEW FORMAT HERE
END IF;
Below are the insert script
CREATE TABLE CUST_INV_DET(
CUSTOMER_ID INT(11) AUTO_INCREMENT PRIMARY KEY,
CUSTOMER_NO VARCHAR(500)
);
INSERT INTO CUST_INV_DET(CUSTOMER_NO) VALUES
('1983,1988,1989'),
('2014,2011,2010'),
('3012,3059,3045');
CREATE TABLE NEW_CUSTOMER_NO_FORMAT (
OLD_CUSTOMER_NO VARCHAR(500),
NEW_CUSTOMER_NO VARCHAR(500)
);
INSERT INTO NEW_CUSTOMER_NO_FORMAT VALUES
('1983','C1983-01'),
('1988','C1988-03'),
('1989','C1989-06'),
('2014','C2014-01'),
('2011','C2011-02'),
('2010','C2010-02'),
('3012','C3012-03'),
('3059','C3059-23'),
('3045','C3045-09');
Below is the final output I am looking for
CUSTOMER_ID CUSTOMER_NO
1 'C1983-01,C1988-03,C1989-06'
2 'C2014-01,C2011-02,C2010-02'
3 'C3012-03,C3059-23,C3045-09'

Answer 1

select
CUSTOMER_ID,
substring(Customer_no,0,charindex(',',Customer_no,1)) col1,
substring(Customer_no,charindex(',',Customer_no,1) + 1,charindex(',',Customer_no,1)-1) col2,
substring(Customer_no,charindex(',',Customer_no,1) + len(substring(Customer_no,charindex(',',Customer_no,1) + 1,charindex(',',Customer_no,1)-1) )+2,charindex(',',Customer_no,1)-1) col3
into #Temp2
from CUST_INV_DET

Answer 2

SELECT T. CUSTOMER_ID,
NCD1.NEW_CUSTOMER_NO + ',' + NCD2.NEW_CUSTOMER_NO + ',' + NCD3.NEW_CUSTOMER_NO
FROM #Temp2 T
INNER JOIN NEW_CUSTOMER_NO_FORMAT NCD1 ON NCD1.OLD_CUSTOMER_NO = T.col1
INNER JOIN NEW_CUSTOMER_NO_FORMAT NCD2 ON NCD2.OLD_CUSTOMER_NO = T.col2
INNER JOIN NEW_CUSTOMER_NO_FORMAT NCD3 ON NCD3.OLD_CUSTOMER_NO = T.col3