I want to run MySQL query from bash script to create new user:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser#localhost IDENTIFIED BY 'somepass'"
Where $BUILD variable is set to a number, for example 15, so final query should look like this:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_15.* TO appuser#localhost IDENTIFIED BY 'somepass'"
But... in directory where script is and is run there is a tar archive with same name as database, so query becomes like this:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_15.tar.gz TO appuser#localhost IDENTIFIED BY 'somepass'"
I guess this happens because there is a match, but changing file name is not an option. Moving script to other directory is not allowed too.
I tried to escape dot with backslashes (appdb_${BUILD}\.*) - nothing changed.
How I can fix this?
There is nothing wrong with your approach and it is working in my case. See below. Can you tell us what is the error that you are getting so that we can help you?
[root#cloud mysql]# ls
appdb_15.tar.gz test.sh
[root#cloud mysql]# cat test.sh
#!/bin/bash
BUILD=15
# First Method
mysql -u root -ptest -e "GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser#localhost IDENTIFIED BY 'somepass';"
# Second Method
mysql -u root -ptest <<EOF
GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser1#localhost IDENTIFIED BY 'somepass';
select user, host from mysql.user where user like 'appuser%';
EOF
[root#cloud mysql]# ./test.sh
user host
appuser localhost
appuser1 localhost
EDIT 1:
I forgot to mention that this is definitely not a bash issue.
EDIT 2: Changed the build variable to 15 from 5.
Related
For some strange reason, I can't find a way to make the runuser command work. I know it is possible to achieve this with sudo -u mysql mysql -e "$DB_SETUP but since I want to do this inside a script that already runs with sudo I find this not very pretty.
Here is what I am trying to do:
DB_SETUP="CREATE USER IF NOT EXISTS $DB_USER#$BASEURL IDENTIFIED BY '$DB_PASSWORD';CREATE DATABASE IF NOT EXISTS $DB_NAME;GRANT ALL PRIVILEGES ON $DB_NAME.* TO $DB_USER#$BASEURL IDENTIFIED BY '$DB_PASSWORD';FLUSH PRIVILEGES;"
sudo runuser -u mysql "mysql -e \"$DB_SETUP\"" # does not work
It gives me this error:
runuser: failed to execute mysql -e "CREATE USER IF NOT EXISTS db_user#baseurl IDENTIFIED BY 'db_password';CREATE DATABASE IF NOT EXISTS db_name;GRANT ALL PRIVILEGES ON db_name.* TO db_user#baseurl IDENTIFIED BY 'password';": No such file or directory
As commented above, I got it working with:
sudo runuser -u mysql mysql <<< $DB_SETUP
No quotation marks at all!
This is part of a Bash script, and the inside looks like this:
createdbcmd="docker exec $1 mysql -v -uroot -e \"GRANT ALL PRIVILEGES ON $dbname.* TO $2#$4 IDENTIFIED BY '$3'\""
echo $createdbcmd
$createdbcmd
the echo looks like this:
docker exec mysql_test_no mysql -v -uroot -e "GRANT ALL PRIVILEGES ON wordpress.* TO user#172.17.0.63 IDENTIFIED BY 'changeme'"
Running this exact command works just fine. via the bash-script it acts as if i'm just running 'mysql'
and i get the default help information with no error.
Try this way:
createdbcmd="docker exec $1 mysql -v -uroot -e \"GRANT ALL PRIVILEGES ON $dbname.* TO $2#$4 IDENTIFIED BY '$3'\""
echo $createdbcmd
eval $createdbcmd
Without the eval, the quoted expression is not interpreted correctly.
In a simple script like this one:
set -x
# Check if db exists, if not we make it, make user, give privileges
if ! mysql -u root -p -e "use $db" 2>/dev/null; then
c1="CREATE DATABASE $db"
c2="GRANT ALL PRIVILEGES ON ${db}.* to '$username'#'localhost' IDENTIFIED BY '$password'"
c3="FLUSH PRIVILEGES"
mysql -u root -p -e "$c1; $c2; $c3"
else
echo 'DATABASE ExISTS, ABORTING'; exit $DB_EXISTS
fi
I am asked each time, bash sees mysql command, for my root credentials.
Is there a way to avoid that, so that once entered the root password, all
additional mysql commands execute seamlessly?
Try looking into adding password to ~/.my.cnf
[client]
user = root
password = XXXXXXXX
Check out :
How to execute a MySQL command from a shell script?
Specifying the --password argument
mysql -u root --password=my_mysql_pass db_name
Safer using a bash variable
mysql -u root --password=$MYSQL_PASS db_name
I need to grant privileges to a database from within a bash script. Some parameters are in the form of variables, say, the username and the password. The command in a mysql shell would look like this:
GRANT ALL ON *.* TO "$user"#localhost IDENTIFIED BY "$password";
...Except that $user and $password would be replaced by their values.
Is there a way to perform such a command from within a bash script?
Thank you!
There you go :)
#!/bin/bash
MYSQL=`which mysql`
EXPECTED_ARGS=3
Q1="USE $1;"
Q2="GRANT ALL ON *.* TO '$1'#'localhost' IDENTIFIED BY '$2';"
Q3="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}"
if [ $# -ne $EXPECTED_ARGS ]
then
echo "Usage: $0 dbname dbuser dbpass"
exit $E_BADARGS
fi
$MYSQL -uroot -p -e "$SQL"
If we don´t know the password we can get it with:
cat /etc/psa/.psa.shadow
So we can get into mysql without prompt password like:
mysql -uadmin -p`cat /etc/psa/.psa.shadow`
Question Rewritten:
HOMEDIR="ftpuser"
REMOTEIP="1.1.1.1"
MYSQLPASS="password"
Q1="DROP USER "$HOMEDIR"_shop;"
Q2="DROP DATABASE "$HOMEDIR"_shop;"
Q3="CREATE DATABASE IF NOT EXISTS "$HOMEDIR"_shop;"
Q4="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'#'localhost' IDENTIFIED BY '$MYSQLPASS';"
Q5="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'#'anotherip' IDENTIFIED BY '$MYSQLPASS';"
# Need to grant permissions from another server as well
Q6="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}${Q4}${Q5}${Q6}"
echo $SQL
echo " "
ssh -p 8899 root#$REMOTEIP "mysql -u root -p "$SQL""
I then run:
/root/testing/migratesite.sh
And get:
bash: DROP: command not found
bash: CREATE: command not found
bash: GRANT: command not found
bash: GRANT: command not found
bash: FLUSH: command not found
What am I missing?
You are missing quotes and a proper mysql client command line:
ssh -p 8899 root#$REMOTEIP "mysql -u root -p -e \"$SQL\""
You need to escape the quotes around the $SQL variable so they get passed to the remote shell, else they get interpreted by the local shell (that's why you get DROP: command not found, the semi colon is interpreted by the shell.) Also, to have the mysql client to execute a command you have to pass the -e command line option.
Did you try this:
ssh -p 8899 root#$REMOTEIP "echo \"$SQL\" | mysql -u root --password=$SQL_PASS"