Question Rewritten:
HOMEDIR="ftpuser"
REMOTEIP="1.1.1.1"
MYSQLPASS="password"
Q1="DROP USER "$HOMEDIR"_shop;"
Q2="DROP DATABASE "$HOMEDIR"_shop;"
Q3="CREATE DATABASE IF NOT EXISTS "$HOMEDIR"_shop;"
Q4="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'#'localhost' IDENTIFIED BY '$MYSQLPASS';"
Q5="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'#'anotherip' IDENTIFIED BY '$MYSQLPASS';"
# Need to grant permissions from another server as well
Q6="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}${Q4}${Q5}${Q6}"
echo $SQL
echo " "
ssh -p 8899 root#$REMOTEIP "mysql -u root -p "$SQL""
I then run:
/root/testing/migratesite.sh
And get:
bash: DROP: command not found
bash: CREATE: command not found
bash: GRANT: command not found
bash: GRANT: command not found
bash: FLUSH: command not found
What am I missing?
You are missing quotes and a proper mysql client command line:
ssh -p 8899 root#$REMOTEIP "mysql -u root -p -e \"$SQL\""
You need to escape the quotes around the $SQL variable so they get passed to the remote shell, else they get interpreted by the local shell (that's why you get DROP: command not found, the semi colon is interpreted by the shell.) Also, to have the mysql client to execute a command you have to pass the -e command line option.
Did you try this:
ssh -p 8899 root#$REMOTEIP "echo \"$SQL\" | mysql -u root --password=$SQL_PASS"
Related
I want to run MySQL query from bash script to create new user:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser#localhost IDENTIFIED BY 'somepass'"
Where $BUILD variable is set to a number, for example 15, so final query should look like this:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_15.* TO appuser#localhost IDENTIFIED BY 'somepass'"
But... in directory where script is and is run there is a tar archive with same name as database, so query becomes like this:
mysql -u root -p$dbpass -e "GRANT ALL PRIVILEGES ON appdb_15.tar.gz TO appuser#localhost IDENTIFIED BY 'somepass'"
I guess this happens because there is a match, but changing file name is not an option. Moving script to other directory is not allowed too.
I tried to escape dot with backslashes (appdb_${BUILD}\.*) - nothing changed.
How I can fix this?
There is nothing wrong with your approach and it is working in my case. See below. Can you tell us what is the error that you are getting so that we can help you?
[root#cloud mysql]# ls
appdb_15.tar.gz test.sh
[root#cloud mysql]# cat test.sh
#!/bin/bash
BUILD=15
# First Method
mysql -u root -ptest -e "GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser#localhost IDENTIFIED BY 'somepass';"
# Second Method
mysql -u root -ptest <<EOF
GRANT ALL PRIVILEGES ON appdb_${BUILD}.* TO appuser1#localhost IDENTIFIED BY 'somepass';
select user, host from mysql.user where user like 'appuser%';
EOF
[root#cloud mysql]# ./test.sh
user host
appuser localhost
appuser1 localhost
EDIT 1:
I forgot to mention that this is definitely not a bash issue.
EDIT 2: Changed the build variable to 15 from 5.
I have a shell script which calls the mysql command with one parameter from external file, it looks like this (also I saw this example in other resources):
mysql --user=root --password=`cat /root/.mysql`
Bit it not working:
Failed to connect to MySQL server: Access denied for user 'root'#'localhost' (using password: YES).
I tried different quotes without success. How to pass it?
UPDATE 1:
Found that I can pass password without space symbol. The problem in this, my root pass contains spaces.
Store your password in a protected mysql cnf file:
install -m 700 -d /srv/secrets/
install -m 600 /dev/null /srv/secrets/root#localhost.cnf
editor /srv/secrets/root#localhost.cnf
Store the password in the client.password ini property
[client]
password="password"
Include this file as the first argument in your mysql command:
mysql \
--defaults-extra-file=/srv/secrets/root#localhost.cnf \
--user=root \
--host=localhost \
--no-auto-rehash
Use mysql_config_editor which is installed with the mysql client
mysql_config_editor set --login-path=dev --user=dbuser --host=localhost -p
Enter the password and then you can log in like this
mysql --login-path=dev
You should use the mysql_config_editor for this.
$ mysql_config_editor set \
--login-path=name_of_connection \
--host=server.example.com \
--user=login_as_user \
--password
this will prompt for a password, and save to a .mylogin.cnf file in your homedir.
mysql --login-path=name_of_connection dbname will connect to dbname on server.example.com as login_as_user
If --login-path is used with other options, ex. --silent, --login-path has to be the first argument/option
Finally this line working:
mysql --user=root --password="$(cat /root/.mysql)"
or:
mysql --user=root --password="$(< /root/.mysql)"
Root password must be without quotes: bla bla bla
If your password not contains spaces you can use:
mysql --user=root --password=`cat /root/.mysql`
I am not sure if that is possible, but you could definitely use configuration
file.
Try:
if [ $MYSQL_PASS ]
then
mysql -u "$MYSQL_ROOT" -p "$MYSQL_PASS" -e "SHOW DATABASES"
else
mysql -u "$MYSQL_ROOT" -e "SHOW DATABASES"
fi
In a simple script like this one:
set -x
# Check if db exists, if not we make it, make user, give privileges
if ! mysql -u root -p -e "use $db" 2>/dev/null; then
c1="CREATE DATABASE $db"
c2="GRANT ALL PRIVILEGES ON ${db}.* to '$username'#'localhost' IDENTIFIED BY '$password'"
c3="FLUSH PRIVILEGES"
mysql -u root -p -e "$c1; $c2; $c3"
else
echo 'DATABASE ExISTS, ABORTING'; exit $DB_EXISTS
fi
I am asked each time, bash sees mysql command, for my root credentials.
Is there a way to avoid that, so that once entered the root password, all
additional mysql commands execute seamlessly?
Try looking into adding password to ~/.my.cnf
[client]
user = root
password = XXXXXXXX
Check out :
How to execute a MySQL command from a shell script?
Specifying the --password argument
mysql -u root --password=my_mysql_pass db_name
Safer using a bash variable
mysql -u root --password=$MYSQL_PASS db_name
I am trying to run MySQL query on remote machine with this command:
ssh user#192.168.2.26 "mysql -uroot -proot -e \"use test";""
I am not able to use that database.
Please suggest a working command.
Try this:
mysql -h host -u root -proot -e "show databases;";
Try this:
ssh root#host "mysql database -e 'query to run on table_name; more queries to run;'"
Same can be done with user#host if that user has permission to execute SQL queries let alone launch mysql in general. Using -e is the same as --execute, which will run whatever you put within the trailing quotes (single or double) and quit. The standard output format would be the same as you would see using --batch.
MySql seems to have a special command line syntax which includes the database.
mysql -u user -p -e 'SQL Query' database
This documentation is rather old but I got it to work
http://www.cyberciti.biz/faq/run-sql-query-directly-on-the-command-line/
Final working command with ssh:
ssh user#host "mysql -u user -e 'show tables;' databasename"
This ended up working for me in a bash script:
query='USE [database]; SELECT ...'
mysql='mysql -u [username] -p[password] -e '"'""$query""'"
ssh [username]#[server] -t "$mysql"
If you want to make it more safe then add a prompt for the password instead of storing it somewhere potentially unsafe.
This worked for me after a few tests (basically same answer as #King-Wzrd):
ssh -t kom "mysql -uroot -p -e 'show databases;'"
ssh -t kom "mysql -uroot -p < /home/ling/websites/jin_test/.deploy/tmp.sql"
The "trick" was the quotes around the command.
The -t option allows for prompting password interactively via the remote shell.
The kom here is just a ssh config identifier defined in my ~/.ssh/config file (see more here: https://www.cyberciti.biz/faq/create-ssh-config-file-on-linux-unix/).
Running this from my Host environment against MySQL within my Homestead VM produced a nice result... although I did have to set the root password from within the VM first in order for it to work.
ssh vagrant#192.168.10.10 mysql -h localhost -u root -p -e "'SELECT * FROM user;' mysql";
Making a script to print out data from a MySQL db via bash, I met the following problem:
While I try to log in, it uses the password as the database to log in to.
Script is like this:
#!/bin/bash
echo $1
db=$1
pasx=$2
CMD="use $db; select * from job_log;"
mysql -u sqluser -p "${pasx}" -e "$CMD"
If I'm going to run the script with the command
User#server:/path/with/file$ sh sql.sh ok hobo
MySQL returns the following:
User#server:/path/with/file$ sh sql.sh ok hobo
ok
Enter password: ERROR 1049 (42000): Unknown database 'hobo'
I might have fully misunderstood something, but I can't put my finger on what it might be.
You need to remove the space after the -p parameter. See the mysql man page. You also need to specify the database in the command (remove it from the query)
mysql -u sqluser -p$pasx -e "$CMD" $db
Or maybe more clear:
mysql --user=sqluser --password=$pasx --execute="$CMD" $db
Try this:
mysql -u sqluser --password=${pasx} -e "$CMD" $db