MySQL json_search on numeric values - mysql

Question

I've got a json list of objects like that
[{
"something": "bla",
"id": 2
}, {
"something": "yes",
"id": 1
}]
My id field is always a numeric value. But when I try to find id = 2, MySQL returns NULL
select
json_search(
json_extract(
'[{"something": "bla" ,"id": 2}, {"something": "yes","id": 1}]',
"$[*].id"
),
'one',
2
) as json_search;
json_search |
------------|
|
When I use a string as value in my json id object instead of a numeric value, I got a result with Index 0.
select
json_search(
json_extract(
'[{"something": "bla" ,"id": "2"}, {"something": "yes","id": 1}]',
"$[*].id"
),
'one',
"2"
) as json_search;
json_search |
------------|
"$[0]" |
I'm using MySQL 5.7.17
##version |
-----------|
5.7.17-log |
Is numeric search in json arrays not provided in MySQL?

Answer 1

You can try something complicated, not intuitive and possibly with performance problems, but it's an option:
mysql> SELECT JSON_SEARCH(
-> REPLACE(
-> REPLACE(
-> REPLACE(
-> JSON_EXTRACT('[
'> {"something": "bla" ,"id": 2},
'> {"something": "yes","id": 1}
'> ]', "$[*].id"),
-> ', ', '","'),
-> '[', '["'),
-> ']', '"]'),
-> 'one', '2') `json_search`;
+-------------+
| json_search |
+-------------+
| "$[0]" |
+-------------+
1 row in set (0.00 sec)

Answer 2

Although the JSON_EXTRACT function was returning [2, 1] and it was a valid JSON, if you search the documentation the JSON_SEARCH function is:
JSON_SEARCH(json_doc, one_or_all, search_str[, escape_char[, path] ...])
So, as I understood you can only work with STRING values, and not with numeric values. But one solution to your problem could be to use the JSON_CONTAINS function as it returns 1 or 0 if the numeric value exists or not.
select
json_contains(
json_extract(
'[{"something": "bla" ,"id": 2}, {"something": "yes","id": 1}]',
"$[*].id"
),
"2"
) as json_contains;
The only problem is that you could not get the path to the given value within the JSON document. Hope it helped.