Finding min element of array in MIPS - mips

Question

I have seen that this question was already asked, but I'm trying to find why this logic is not working. I have tried this code, translating it to C++ and it is working fine. But here it is printing the last element of the array. Help?
.data
Array: .word 500 100 250 150
Len: .word 4
Sum: .word 0
Average: .word 0
NewLine: .asciiz "\n"
Min: .word 9999
Max: .word -9999
.text
la $t0, Array # Base address
li $t1, 0 # i = 0
lw $t2, Len # $t2 = Len
li $t3, 0 # Sum = 0
li $t5, 0 # Average = 0
la $t6, NewLine
lw $t7, Min # $t7 = min
lw $t8, Max # $t8 = max
while:
lw $t4, ($t0) # Array[i]
add $t3, $t3, $t4 # sum += Array[i]
blt $t4, $t7, else # If first element is < 9999, go to else
else: move $t7, $t4 # Min = Array[i]
add $t1, $t1, 1 # Increment index by 1
add $t0, $t0, 4 # Go to next array element
blt $t1, $t2, while # Do this cycle till i < $t2 (length)
sw $t3, Sum
div $t5, $t3, $t2 # Calculate avg.
sw $t5, Average
# Print sum
li $v0, 1
move $a0, $t3
syscall
# Print new line
li $v0, 4
move $a0, $t6
syscall
# Print average
li $v0, 1
move $a0, $t5
syscall
# Print new line
li $v0, 4
move $a0, $t6
syscall
# Print min element
li $v0, 1
move $a0, $t7
syscall

Answer 1

Compiler reads the code from up to down, let's look at calculating the minimum part of your code:
blt $t4, $t7, else # If first element is < 9999, go to else
else: move $t7, $t4 # Min = Array[i]
In the first line, it branches to else if $t4 < $t7. Looks fine for this situaton but if $t4 < $t7 it skips branching, then pass to the next line which is your else. So, that blz is uselles here because it will go the else line anyway so this code will always print the last element of your array.
But if you change your code like:
blt $t7, $t4, else # If first element is < 9999, go to else
move $t7, $t4 # Min = Array[i]
else:
...
It will skip "move $t7, $t4 line" if $t7 > $t4, so it will give you what you want.