I am trying to do an LEFT Join in Yii v.1 Mysql .
There are alreday 4 tables joined and I want to join this table also.
$cmd = Yii::app()->db->createCommand();
$selectString .= "table2.dir_pic, table2.pic1, table2.pic2 , table2.pic3 ";
$cmd->select($selectString);
$cmd->from('table1');
$cmd->leftjoin('table2', 'table1.id=table2.user_entry_id');
$entries = $cmd->queryAll();
$this->render('index', compact('entries', 'model'));
It is giving an CDbException
CDbCommand failed to execute the SQL statement: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '.`dir_pic`, `table2`.`pic1`, `table2`.`pic2`, ' at line 1.
I tried this query in mysql(phpmyadmin)
SELECT table1.id,table2.dir_pic,table2.pic1,table2.pic2, table2.pic3 FROM
table1 LEFT JOIN table2 ON table1.id = table2.user_entry_id
and It shows proper output.BUt not when I try in Yii .
I found the solution. Actually I missed an comma (,) after the end of previous $selectString query.
Related
I got an error while updating the table with the join query. The error message is:
Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from employee details join employeedept on employee details.emp_dept=employeedept.' at line 3
Can anyone help me to resolve this error?
update employeeDetails
set employeeDetails.emp_age = employeeDetails.emp_age+20, employeeDetails.emp_salary = employeeDetails.emp_salary-500
from employeeDetails
join employeedept on employeeDetails.emp_dept = employeedept.dept_name
where employeedept.dept_name = 'CSE';
select * from employeeDetails;
List item
Have you tried using MySQL's UPDATE JOIN syntax yet? e.g.:
update employeeDetails
join employeeDept on employeeDetails.emp_dept = employeeDept.dept_name
set
employeeDetails.emp_age = employeeDetails.emp_age+20,
employeeDetails.emp_salary = employeeDetails.emp_salary-500
where employeeDept.dept_name = 'CSE';
select * from employeeDetails;
I have a problem with my request, the request doesn't recognized WITH(). I work on Ubuntu & MySQL, can I get help please!
DB::select(DB::raw("WITH liststudentsoff as (
SELECT tbl_etudiants.*, tbl_cours.idCours FROM dependance_groupes
inner join tbl_etudiants on tbl_etudiants.idStudent = dependance_groupes.studentID
inner join tbl_cours on tbl_cours.groupID = dependance_groupes.groupID
inner join tbl_formations on tbl_formations.idFormation = tbl_cours.formationID
)
SELECT * FROM liststudentsoff
LEFT JOIN tbl_absences ON liststudentsoff.idStudent = tbl_absences.studentID AND liststudentsoff.idCours = tbl_absences.coursID
WHERE liststudentsoff.idCours = ".$request->idCours." and liststudentsoff.formationID = ".$cours->formationID.""));
Error display:
[previous exception] [object] (PDOException(code: 42000): SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'liststudentsoff as (
SELECT tbl_etudiants.*, tbl_cours.idCours FROM ' at line 1 at /var/www/html/emarge-backoffice/vendor/laravel/framework/src/Illuminate/Database/Connection.php:338)
when select images from a database below error is shown & after i delete record in the database its remain the same number inside (id)
this is the error
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL
server version for the right syntax to use near '16,19,1,2,1,2,1 )' at line 1
select * from images where id in(,16,19,1,2,1,2,1 )
Filename: controllers/Admin.php
Line Number: 1046
and this is select statment :
if (!empty($data->images)) {
$qry = $this->db->query("select * from images where id in($data-
>images )");
$res['results'] = $qry->result();
}
and now my database is empty and this error still remaining ?
just remove the leading comma. like this.
select * from images where id in( 16,19,1,2,1,2,1 )
there is a leading comma in $data->images
I am not that good at SQL but i do as much as i can for the little knowledge i have..
I have made a single a flat SQL string with the help from a friend that gathers data from a table using a relative table from an initial data from the first table, the SQL was made like this:
SELECT id, username, auth_assignment.created_at
FROM `user` JOIN `auth_assignment`
ON (user.id = auth_assignment.user_id)
JOIN `auth_item`
ON (auth_item.name = auth_assignment.item_name)
WHERE auth_item.name = 'Admin'
the initial data to look is Admin so everything works in that side, but i tried to simulate this SQL using Yii2 functions.. so far i have made this code
$query = new Query;
$command = $query->select('id, username')
->innerJoin('auth_assignment', ['user.id'=>'auth_assignment.user_id'])
->innerJoin('auth_item', ['auth_item.name'=>'auth_assignment.item_name'])
->where('auth_item.name = :name', [':name'=>$name])->createCommand();
var_dump($command->query());
this returns an SQLSTATE error:
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN `auth_assignment` ON `user`.`id`='auth_assignment.user_id' INNER JOIN' at line 1
The SQL being executed was: SELECT `id`, `username` INNER JOIN `auth_assignment` ON `user`.`id`='auth_assignment.user_id' INNER JOIN `auth_item` ON `auth_item`.`name`='auth_assignment.item_name' WHERE auth_item.name = 'Admin'
i checked the method $command->sql; to know how the SQL was being generated.. but i really don't know how to fix it due to my lack of my knowledge to SQL and lack of understanding to yii2 api documentation
SQL is generated like this:
SELECT `id`, `username` INNER JOIN `auth_assignment` ON `user`.`id`=:qp1 INNER JOIN `auth_item` ON `auth_item`.`name`=:qp2 WHERE auth_item.name = :name
i appreciate any help
Try This Query
$query = (new yii\db\Query())
->select('id, username, auth_assignment.created_at')
->from('user')
->innerJoin('auth_assignment','user.id=auth_assignment.user_id')
->innerJoin('auth_item','auth_item.name = auth_assignment.item_name')
->where([
'auth_item.name' => 'Admin'
])->all();
I'm trying to delete some data from 3 tables. Here is my SQL:
DELETE
FROM productdetail
JOIN (productdescription,productmineralcategories,productspeciescategories)
ON
(
productdetail.id = productspeciescategories.id_product
AND productdetail.id = productmineralcategories.id_product
AND productdetail.id = productdescription.id_product
)
WHERE productdetail.id='".$data['id'].
And here is the output error:
Error Number: 1064
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'JOIN (productdescription, productmineralcategories,
productspeciescategories) ' at line 3
What does it mean and how can I fix it?
Your DELETE statement should be:
$query="DELETE
FROM productdetail
WHERE productdetail.id='".$data[$id] . "'";
OR
$query="DELETE
FROM productdetail
WHERE productdetail.id='$data[$id]'";
OR do not add single quote if field type is numeric.
$query="DELETE
FROM productdetail
WHERE productdetail.id=$data[$id]";
Have a look at DELETE JOIN syntax.