I have this table
| BookID | BookTitle | NumberOfPages | NoOfCopies |
+--------+--------------------------------+---------------+------------+
| 1 | The Help | 444 | 4 |
| 2 | The Catcher in the Rye | 277 | 10 |
| 3 | Crime and Punishment | 545 | 2 |
| 4 | The Brothers Karamazov | 795 | 1 |
| 5 | A Crown of Wishes | 369 | 12 |
| 6 | The Fireman | 752 | 3 |
| 7 | Fahrenheit 451 | 174 | 9 |
| 8 | The Hobbit | 366 | 1 |
| 9 | Lord of Emperors | 560 | 4 |
| 10 | Holy Bible: King James Version | 1590 | 11 |
----------------------------------------------------------------------------
When I insert a book title and expect it to return the book id, it always returns an empty set
so far, I have tried these queries.->book_info is the name of the table:
select BookID from book_info where ucase(BookTitle) = ' THE HELP% ';
select BookID from book_info where BookTitle = ' The Help ';
select BookID from book_info where lcase(trim(BookTitle) = 'the help';
but none of them worked.
Note I don't rely on sql in my job.
you need to use like if you want to use "%"
when you use "=" you need to sure it is same. even space also count
select BookID from book_info where BookTitle LIKE 'THE HELP%';
The issue here is with the operator you are using and the value you are function you are expecting from it, = operator checks for the exact match that's why your queries are returning no records:
select BookID from book_info where ucase(BookTitle) = ' THE HELP% ';
select BookID from book_info where BookTitle = ' The Help ';
select BookID from book_info where lcase(trim(BookTitle) = 'the help';
And one more thing that is:
MySQL queries are not case-sensitive by default.
So you don't need to add the string methods here to change the values case.
We usually use the % with LIKE only like this:
select BookID from book_info where ucase(BookTitle) LIKE '%THE HELP%';
In this query LIKE %THE HELP% will match all the string having THE HELP in them;
Related
I have sample Data
+----+-----------+
| Id | Name |
+----+-----------+
| 1 | $John |
| 2 | $Carol |
| 3 | $Mike |
| 4 | $Sam |
| 5 | $David$Mohan$ |
6 | $David$
7 | $David$Mohan$
| 8 | Robert$Ram$ |
| 9 | Maxwell$ |
+----+-----------+
I need to remove the only $ first character
Need output :
+----+-----------+
| Id | Name |
+----+-----------+
| 1 | John |
| 2 | Carol |
| 3 | Mike |
| 4 | Sam |
| 5 | David$Mohan |
6 | David
7 | David$Mohan
| 8 | Robert$Ram |
| 9 | Maxwell |
+----+-----------+
Select REPLACE(col,'$','') from Tbl
select regexp_replace(name, '^$', '') name from mytable
I have tried with Replace and Substring but still missing the point .
Can anyone suggest me .
If you are only looking for starting $, you can use this below logic-
DEMO HERE
SELECT
CASE
WHEN LEFT(D,1) = '$' THEN RIGHT(D, LENGTH(D)-1)
ELSE D
END STR,
IF(LEFT(D,1) = '$', RIGHT(D, LENGTH(D)-1), D) STR2
-- you can use any of the above option
FROM
(
select '$David$Mohan$' D UNION ALL
select 'Da$Mo$'
)A
Try this:
select
id,
case when SUBSTR(Name, 1,1)='$' and SUBSTR(Name,-1,1)='$' then substr(Name,2,(length(Name)-2))
when SUBSTR(Name, 1,1)='$' then substr(Name,2)
else Name
end
from Tbl
Based on your example you should try;
Replace(trim(replace({col},'$',' ')), ' ','$')
This is turning the '$' into spaces, removing spaces at the start or end or the string, then switching back to '$'.
Try this, it's working for me for all your test cases
SELECT REGEXP_SUBSTR(name,'[^$].+[^$]') from users;
If case you want to replace $ with space, David$Ang => David Ang
SELECT REGEXP_REPLACE(REGEXP_SUBSTR(name,'[^$].+[^$]'), "[$]", " ") from users;
I have the following 3-column table:
+----+---------+------------+
| ID | First | Last |
+----+---------+------------+
| 1 | Maurice | Richard |
| 2 | Yvan | Cournoyer |
| 3 | Carey | Price |
| 4 | Guy | Lafleur |
| 5 | Steve | Shutt |
+----+---------+------------+
If I want to look for everyone in (Maurice,Guy) I can do select * from table where first in (Maurice,Guy).
If I want to find just Maurice Richard, I can do select * from table where first = "Maurice" and last = "Richard".
How do I do a map, an array of multiples?
[
[Maurice, Richard]
[Guy,Lafleur]
[Yvan,Cournoyer]
]
If I have an arbitrary number of entries, I cannot construct a long complex where (first = "Maurice" and last = "Richard") or (first = "Guy" and last = "Lafleur") or .....
How do I do the moral equivalent of where (first, last) in ((Guy,Lafleur),(Maurice,Richard)) ?
You can do it just like you describe it:
SELECT *
FROM mytable
WHERE (first, last) IN (('Guy','Lafleur'),('Maurice','Richard'))
Demo here
I have two tables.
rp_format
+-----+--+--------------+
| fid | | recordformat |
+-----+--+--------------+
| 1 | | CD |
| 2 | | Vinyl |
| 3 | | DVD |
+-----+--+--------------+
rp_records
+----+--+--------+
| id | | format |
+----+--+--------+
| 1 | | 1 |
| 2 | | 2 |
| 3 | | 3 |
+----+--+--------+
What I would like to achieve is to display everything from "rp_format". But I would also like make a check to see if there is a "fid"-value found in "format".
Example that should be displayed on page like this:
fid recordformat
1 CD Remove this format
2 Vinyl Remove this format
3 DVD Remove this format
But let's say an "fid" value is found in "format" then I would like it to be displayed like this on page:
fid recordformat
1 CD Remove this format
2 Vinyl Can't remove this format
3 DVD Remove this format
"Remove this format / Can't remove this format" is text that will be displayed by checking if "fid" = "format" using PHP.
Here is my SQL query so far:
global $wpdb;
$rpdb = $wpdb->prefix . 'rp_format';
$rpdb2 = $wpdb->prefix . 'rp_records';
$sql = "
SELECT *
FROM $rpdb
LEFT OUTER JOIN $rpdb2 ON $rpdb.fid = $rpdb2.format
UNION
SELECT *
FROM $rpdb
RIGHT OUTER JOIN $rpdb2 ON $rpdb.fid = $rpdb2.format
WHERE $rpdb.fid IS NOT NULL
";
The issue I have with this query is that when "fid" is found in "format" (let's say it's found 10 times) every of these 10 values will be outputed also.
How can this be fixed?
Kind regards
Johan
If I understand correctly you want to display some message depending on if the data exists on rp_records or not and avoid multiple display.
Consider the following
mysql> select * from rp_format;
+------+--------------+
| fid | recordformat |
+------+--------------+
| 1 | CD |
| 2 | Vinyl |
| 3 | DVD |
| 4 | Test |
+------+--------------+
4 rows in set (0.00 sec)
mysql> select * from rp_records;
+------+--------+
| id | format |
+------+--------+
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
| 4 | 2 |
| 5 | 1 |
+------+--------+
So the query is
select
f.*,
case
when r.format is not null then 'Can\'t remove' else 'Remove this' end
as message
from rp_format f
left join rp_records r on r.format = f.fid
group by f.fid ;
+------+--------------+--------------+
| fid | recordformat | message |
+------+--------------+--------------+
| 1 | CD | Can't remove |
| 2 | Vinyl | Can't remove |
| 3 | DVD | Can't remove |
| 4 | Test | Remove this |
+------+--------------+--------------+
Not sure that i correctly understand your logic with found and not found format, if i wrong - add to if condition r.format IS NOT NULL instead r.format IS NULL. And i think you no need to use union, you should use join:
SELECT
r.fid,
f.recordformat,
IF(r.format IS NULL, "Can't remove this format", "Remove this format")
FROM rp_format f
LEFT JOIN rp_records r ON f.fid = r.format
GROUP BY f.fid
;
I'm sure that something like this will help you!
I have the following situation:
Table Words:
| ID | WORD |
|----|--------|
| 1 | us |
| 2 | to |
| 3 | belong |
| 4 | are |
| 5 | base |
| 6 | your |
| 7 | all |
| 8 | is |
| 9 | yours |
Table Sentence:
| ID | SENTENCE |
|----|-------------------------------------------|
| 1 | <<7>> <<6>> <<5>> <<4>> <<3>> <<2>> <<1>> |
| 2 | <<7>> <<8>> <<9>> |
And i want to replace the <<(\d)>> with the equivalent word from the Word-Table.
So the result should be
| ID | SENTENCE |
|----|--------------------------------|
| 1 | all your base are belong to us |
| 2 | all is yours |
What i came up with is the following SQL-Code:
SELECT id, GROUP_CONCAT(word ORDER BY pos SEPARATOR ' ') AS sentence FROM (
SELECT sentence.id, words.word, LOCATE(words.id, sentence.sentence) AS pos
FROM sentence
LEFT JOIN words
ON (sentence.sentence REGEXP CONCAT('<<',words.id,'>>'))
) AS TEMP
GROUP BY id
I made a sqlfiddle for this:
http://sqlfiddle.com/#!2/634b8/4
The code basically is working, but i'd like to ask you pros if there is a way without a derived table or without filesort in the execution plan.
You should make a table with one entry per word, so your sentense (sic) can be made by joining on that table. It would look something like this
SentenceId, wordId, location
2, 7, 1
2, 8, 2
2, 9, 3
They way you have it set up, you are not taking advantage of your database, basically putting several points of data in 1 table-field.
The location field (it is tempting to call it "order", but as this is an SQL keyword, don't do it, you'll hate yourself) can be used to 'sort' the sentence.
(and you might want to rename sentense to sentence?)
I am new to databases. In mysql database I have one table course. My question is: how to search all related words in both columns course_name and course_description and i need to get all the matched words in both columns? Can any one tell me the sql query for it? I have tried to write a query, but I am getting some syntax errors.
+----------+-----------+-----------------+------------+------------+
| courseId | cname | cdesc | sdate | edate |
+----------+-----------+-----------------+------------+------------+
| 301 | physics | science | 2013-01-03 | 2013-01-06 |
| 303 | chemistry | science | 2013-01-09 | 2013-01-09 |
| 402 | afm | finanace | 2013-01-18 | 2013-01-25 |
| 403 | English | language | 2013-01-17 | 2013-01-24 |
| 404 | Telugu | spoken language | 2013-01-10 | 2013-01-22 |
+----------+-----------+-----------------+------------+------------+
SELECT * from course WHERE cname='%searchtermhere%' AND cdesc='%searchtermhere%'
Adding the percent % makes the search within each value and not just beginning with.
If you want to search exact word
SELECT * FROM course WHERE cname ='word' AND cdesc = 'word'
OR you can also find each value and not just start from begining.
SELECT * FROM course WHERE cname = '".%searchtermhere%."' AND cdesc = '".%searchtermhere%."'
Since you say single parameter i guess. You will get either 'science' as input or 'physics' as input. Then you could simply use 'OR'.
select * from course where cname = (Input) or cdesc = (Input)