How can I get all entities without a specific related entity? - mysql

I have these tables:
users
id
name
events
id
name
entries
id
user_id
event_id
How can I get all users that do not have an entry with event_id 4?
With this code:
$users = User::query();
$users->leftJoin('entries', 'users.id', '=', 'entries.user_id')
->where('event_id','!=', $event_id)->get();
I still get users that already have an entry for that specific event.
This is what I want:
Get all entries which have event_id 4
Get the user_id from those entries
Remove other entries which have that user_id.
$entries = Entry::where(event_id, '=', 4)->get();
foreach ($entries as &$entry) {
//remove all entries from $entries array which "user_id = $entry->user_id"
}
How can I do the above with just a query?

Going by your question following is the answer but i guess this is not what you finally want. so elaborate more and specify the sample input and output datasets
select * from your_table where event_id <> 4;

The SQL you want is:
select user_id
from t
group by user_id
having sum(event_id = 4) = 0;

select u.*
from User u
left join entries e
on e.user_id = u.id and e.event_id = 4
where e.id is null

You're looking for <>, not !=. Also you're not letting it know which table event_id is on.
Try
$users = User::query();
$users->leftJoin('entries', 'users.id', '=', 'entries.user_id')
->where('entries.event_id','<>', $event_id)->get();
More information can be found at https://laravel.com/docs/5.4/queries#where-clauses

You can use the whereDoesntHave builder method.
$users = User::query()->whereDoesntHave("entry", function($q) use ($event_id) {
$q->where('id', $event_id);
})->get();
The method takes a closure in which you can define criteria for the related entities that must not exist.
If you need the users and the entries, I think you can still join the entries using with.
$users = User::query()
->with('entries')
->whereDoesntHave("entry", function($q) use ($event_id) {
$q->where('id', $event_id); })
->get();

Related

Laravel GroupBy and Count using eloquent model

I have a table
'new_comments'
with fields
id,user_id,
title,
comment_description
I have another table named
'comments_upvote'
having
field user_id,
post_id,
likes
id of new_comments and post_id of comments_upvote table are same. we have to take those comments which have the most likes. how we fetch that data.
$ud = Comments_upvote::select('post_id')->groupby('post_id')-
>orderby(DB::raw('count(likes)'), 'desc')->get();
$postid = array();
foreach ($ud as $key => $value) {
$postid[] = $value->post_id;
}
$data = DB::table('new_comments')->whereIn('id',$postid)->get();
but the problem is that i have to count all likes whose value = 1 how can we do that.
If you showed us some code you'd get a more concrete answer, but here's a quick outline of what you need: define your relationships (make sure you use your custom foreign key), use whereHas, group by post_id count, and sort by count descending.
So I'm guessing you have at least two models NewComment and CommentUpvote (you should). In the NewComment define a 1:n relationship:
public function upvotes(){
$this->hasMany('App\CommentUpvote', 'post_id');
}
Then in your controller (again, guessing, since you didn't show any code):
$bestComments = NewComment::whereHas('upvotes', function($query){
$query->select('post_id', DB::raw('count(*) as total'))->groupBy('post_id')->orderBy('total', 'desc');
})->get();
Disclaimer: this is untested and off the top of my head, but should nugde you in the right direction.

Filter duplicates by field max value

I have a problem with getting data. I'm trying to get all users with there max value (points). My question is just like OData filter by max value and field.
Code for my question is:
$query = User::select('users.id','users.username','games.points',
'games.created_at')
->join('games', 'users.id', '=', 'games.user_id')
->whereBetween('games.created_at', [$start, $end]);
But the problem is when I want to remove duplicates and get max points for each user.
In the version where I don't need whereBetween I'm doing in this way:
return User::select('users.id', 'users.username', 'games.points',
'games.created_at')
->join('games', 'users.id', '=', 'games.user_id')
->whereRaw('(users.id, games.points) IN (SELECT user_id, MAX(points)
FROM games GROUP BY user_id)')
->orderByDesc('points')
->get();
Thanks
Why don't you simply GROUP BY your query on users.id and users.username?
-- I let you translate the query into your framework
SELECT users.id, users.username, max(games.points) as points
FROM users, games
WHERE users.id = games.user_id
AND games.created_at BETWEEN $start AND $end
GROUP BY users.id, users.username
ORDER BY max(games.points) DESC
That way, you'll get the max of points per user (id and username).
Hope this helps.
I have resolved my problem with using unique method form eloquent.
Game::with('user')
->whereBetween('created_at', [$start, $end])
->orderByDesc('points')
->orderBy('created_at')
->limit($limit)
->get()
->unique('user_id')
->values();
Thanks a lot to Lucas for his time and his help.

How to get "unique" users by combining email and date

I am using Laravel 5.5.
I have a database which contains users. The problem is that some users exist more than one time because of a bug. I want to query my database and select all "unique" users.
By using the word "unique" I mean the below :
If a user with email "test#test.com" exists 50 times I want the row that created_at is closest to now.
My query, which returns all users is written below :
DB::table('users')
->select('name', 'surname', 'email', 'phone', 'answers', 'newsletter', 'created_at')
->get();
I got confused and I'm not sure if i should use limit combining it with order by created_at column.
Any ideas?
Ok, this is what you need to do: First off, you get a table with the users in their last created_at 'version'. Now you have a list of emails and dates. Then you perform a left join of all the users with that temporary table.
TL;DR:
$users = DB::select('select t1.* from users t1 right join (SELECT email, MAX(created_at) as created_at from users group by email) as t2 on t1.email=t2.email and t1.created_at=t2.created_at');
I hate raw SQL, and I hate subqueries, but this is the only way I know using generic SQL (I mean, you could do a better MySQL or MSSQL native queries, but this should do for you.)
You can use
DB::table('users')->select('name', 'surname', 'email','phone','answers','newsletter','created_at')->orderBy('created_at', 'desc')->groupBy('email')->get();
For more help refer Order By before Group By using Eloquent (Laravel)
What you need is groupby and orderby
try this code
DB::table('users')->select('name', 'surname', 'email','phone','answers','newsletter','created_at')
->orderBy('created_at', 'desc')
->groupBy('email')
->get();
hope it will help you if you need further info try above link!
To get latest user record among duplicates you can use a self join
DB::table('users as u')
->select('u.*')
->leftJoin('users as u1', function ($join) {
$join->on('u.email', '=', 'u1.email')
->whereRaw(DB::raw('u.created_at < u1.created_at'));
})
->whereNull('u1.id')
->get();
In plain SQL it would be something like
select u.*
from users u
left join users u1 on u.email = u1.email
and u.created_at < u1.created_at
where u1.id is null

Laravel. Using WHERENOTIN

Basically I want to build tihs query in Laravel, but it does not work.
SELECT films.id, films.name AS film
FROM films
WHERE films.id NOT IN
(
SELECT films.id
FROM actors, actor_film, films
WHERE actors.id = actor_film.actor_id
AND actor_film.film_id = films.id
GROUP BY films.id
)
ORDER BY films.id DESC
LIMIT 600
;
Using a "whereNotIn" I have written these two queries:
The first one get all films in the Data Base that has at least an actor associated like this:
$films_with_actors = DB::table('films')
->join('actor_film', 'actor_film.film_id', '=', 'films.id')
->join('actors', 'actors.id', '=', 'actor_film.actor_id')
->select( 'films.id')
->groupBy('films.id')
->get();
Now I want to get the films that do not have associated an actor. For that I am trying to get the ID that are not included in the previous method, like this:
$films_with_no_actors = DB::table('films')
->whereNotIn('films.id', $films_with_actors)
->orderBy('films.id', 'desc')
->take(500)
->get();
-
Any help?
I am giving you a basic solution based on the code you shared.
In laravel you have a method called pluck for retrieving an array with all the values for a given key.
Therefore, you can get only the ids for the $films_with_actors. Something like (based on your first query):
$films_with_actors = DB::table('films')
->join('actor_film', 'actor_film.film_id', '=', 'films.id')
->join('actors', 'actors.id', '=', 'actor_film.actor_id')
->select( 'films.id')
->groupBy('films.id')
->pluck('id')->toArray();
Now you have an array with the ids and you can include that array in the whereNotIn clause of your second query:
$films_with_no_actors = DB::table('films')
->whereNotIn('films.id', $films_with_actors)
->orderBy('films.id', 'desc')
->take(500)
->get();

Brain boiling from MySQL - How to do a complicated select from multiple tables?

I have two tables: Users and Groups
In my table "Users", there is a column called "ID" for all the user ids.
In my table "Groups" there is a column called "Participants", fields in this column are filled with all the user ids like this "PID_134,PID_489,PID_4784," - And there is a column "ID" that identifies a specific group.
Now what i want to do, i want to create a menu that shows all the users that are not yet in this particular group.
So i need to get all the user ids, that are not yet in the Participants column of a group with a particular ID.
It would be cool if there was a single mysql query for that - But any PHP + MySQL solutions are okay, too.
How does that work? Any guesses?
UPDATE:
i know, that's not code, but is there a way I could do something like this that would return me a list of all the users?
SELECT *
FROM users, groups
WHERE groups.participants NOT LIKE '%PID_'users.id'%' AND groups.id = 1;
Something like this. You just get rid of "PID_" part of ID.
SELECT * FROM [users] WHERE [id] NOT IN
(SELECT replace(id,'PID_','') FROM groups WHERE group_name='group1')
Group1 would be your variable - group id/name of menu that you've opened.
You can select from multiple tables as shown below:
SELECT * from users, groups WHERE users.id != groups.participants AND groups.id = 1;
This will list all users who are not in group id 1; A more elegant solution can be found by using joins, but this is simple and will do the trick.
I believe something like that should help:
SELECT * FROM users WHERE users.id NOT IN (SELECT groups.participants FROM groups)
But this works only if your DB is normalized. So for your case I see only PHP + MySQL solution. Not very elegant, but it does the job.
<?php
$participants_array = mysql_query("SELECT participants FROM groups");
$ids = array();
while ($participant = mysql_fetch_assoc($participants_array))
{
$id = explode(',', $participant['participant']);
foreach ($id as $instance)
{
if (!in_array($instance, $ids)) $ids[] = $instance;
}
}
$participants = implode(',', $ids);
$result = mysql_query("SELECT * FROM users WHERE id NOT IN ( $participants )");
But I highly recommend normalizing the database.