Show names from two values - mysql

Question

I am trying to get a SQL code but can't really figure out how to do it so I will explain what I want.
I have 4 tables called Person, Customer, Adres and Store. Now I have to show each customer NAMES which lives in the same city as where there is a Store. So First I figured out which persons are customers by:
SELECT person_name
FROM person
WHERE person_id IN
(SELECT Person_Person_Id
FROM customer);
Which stores are in which city:
SELECT Store_name, adres_city
FROM store s, adres a
WHERE s.Adres_Adres_Id = a.adres_id;
Note that person_person_id is the same as person_id just as a fk.
I am stuck at this code and don''t know how to go further from here. My column name of table adres = adres_city.

Answer 1

Okay, if I realised what do you want, try to do this:
select --distinct
b.Adres_City,
a.person_id
from
dbo.Person a
join dbo.Adres b on a.adres_adres_id = b.Adres_Id
join dbo.Customer c on a.person_id = c.Person_Person_Id
join dbo.Store d on b.Adres_Id = d.Adres_Adres_Id
If you are not sure, that all your keys in tables are uniq, uncomment --distinct in the first string.
Or, if you are want to know statistics among your cities, do this:
select
b.Adres_City,
count(distinct a.person_id) as cnt
from
dbo.Person a
join dbo.Adres b on a.adres_adres_id = b.Adres_Id
join dbo.Customer c on a.person_id = c.Person_Person_Id
join dbo.Store d on b.Adres_Id = d.Adres_Adres_Id
group by b.Adres_City
Please let me know, if it will help you.
Update1:
select --distinct
b.Adres_City,
a.person_id
from
dbo.Person a
join dbo.Adres b on a.adres_adres_id = b.Adres_Id
join dbo.Customer c on a.person_id = c.Person_Person_Id
where
b.Adres_City in (
select y.Adres_City
from dbo.Store x join dbo.Adres y on y.Adres_Id = x.Adres_Adres_Id
)