I have a table with columns id, item, qty and expiration date. I have to select item with a given total qty based on expiration date. The item that expires first need to be the priority to select. The query works fine if the item has different expiration date but, my problem is if the item has the same expiration date it does not return any row. Please check out the query below.
SELECT t.ID,
t.itemcode,
t.qty,
t.expdate,
t.total,
t.prev_total,
CASE WHEN t.total > 500 THEN 500 - t.prev_total ELSE t.qty END AS total
FROM
(
SELECT t1.ID,
t1.itemcode,
t1.qty,
t1.expdate,
(SELECT SUM(t2.qty) FROM put_in t2
WHERE t2.expdate <= t1.expdate AND t2.itemcode = 'ITEM01') AS total,
COALESCE((SELECT SUM(t2.qty) FROM put_in t2
WHERE t2.expdate < t1.expdate AND t2.itemcode = 'ITEM01'), 0) AS prev_total
FROM put_in t1
WHERE t1.itemcode = 'ITEM01'
) t
WHERE t.total - t.qty < 500 AND
t.itemcode = 'ITEM01'
ORDER BY t.expdate;
Related
Below I cannot do Group by Date the following figures.
I have tried to put Group By in different lines, but not working.
SELECT SUM(a.NetAmount) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a
I wanted to see:
Days Total Amount
March 1 xxxx
March 2 xxxx
March 3 xxx
MySQL does not use TOP. Use LIMIT:
SELECT ChargeCreatedDate, SUM(netamount)
FROM (SELECT ch.ChargeCreatedDate,
(CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE bt.BalanceTransactionNet * (SELECT e.ExrateValue
FROM Exrate e
WHERE e.ExrateDate < bt.BalanceTransactionCreated AND
e.CurrencyID = bt.BalanceTransactionCurrencyID
ORDER BY ExrateDate Desc
LIMIT 1
)
END) AS NetAmount
FROM Charge ch JOIN
BalanceTransaction bt
ON ch.BalanceTransactionID = bt.BalanceTransactionID
WHERE ch.ChargeCreatedDate BETWEEN '2019-03-01' AND '2019-03-31'
) chtbt
GROUP BY ChargeCreatedDate;
If you happen to be using SQL Server, you can replace the LIMIT 1 with FETCH FIRST 1 ROW ONLY.
The following code will hopefully display what you are looking for
SELECT a.Days AS Days, SUM(cast(a.NetAmount as decimal(16,9))) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount,
ch.ChargeCreatedDate as Days
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a GROUP BY a.Days
This should be sufficient. You need to SELECT the desired value in the query in order to get it to show up. Also when using the SUM() function you need to specify what the group value will be.
I am trying to do a consecutive days count in mysql from a timestamp column. I thought I had this problem solved once long ago - but for some strange reason, it is returning the wrong value.
It should return a single column containing a username, the lowest date with the highest time value in the consecutive date list, and the largest number of consecutive days.
It all works except the largest number of consecutive days is not always correct.
SELECT username, day1, count(distinct date) days from (
SELECT t1.username, t1.date, max(tmp.date) day1 from sites_surfed t1
LEFT JOIN (
SELECT tmp1.date from sites_surfed tmp1
LEFT JOIN sites_surfed tmp2
ON DATE_FORMAT(tmp1.date,'%d/%m/%Y') = DATE_FORMAT(tmp2.date,'%d/%m/%Y')+1
AND tmp1.username = tmp2.username where (tmp1.username = 'viraladmin')
AND (tmp2.date is null))tmp on (t1.date >= tmp.date) where t1.username = 'viraladmin'
GROUP BY t1.date
) fin
WEHERE username = 'viraladmin'
GROUP BY day1 having count(distinct date) > 1 order by days
The below jsfiddle shows an example of it returning 3 for the total amount of consecutive days when it should only be return 2 as only two unique dates are in the table list
http://sqlfiddle.com/#!9/85f6d6/4
What is going on here and how do I fix this?
I've changed
GROUP BY t1.date
to
GROUP BY DATE_FORMAT(t1.date,'%d/%m/%Y')
This seems to be working.
SELECT username, day1, count(distinct date) days from (
SELECT t1.username, t1.date, max(tmp.date) day1 from sites_surfed t1
LEFT JOIN (
SELECT tmp1.date from sites_surfed tmp1
LEFT JOIN sites_surfed tmp2
ON DATE_FORMAT(tmp1.date,'%d/%m/%Y') = DATE_FORMAT(tmp2.date,'%d/%m/%Y')+1
AND tmp1.username = tmp2.username where (tmp1.username = 'viraladmin')
AND (tmp2.date is null))tmp on (t1.date >= tmp.date) where t1.username = 'viraladmin'
GROUP BY DATE_FORMAT(t1.date,'%d/%m/%Y')
) fin
WHERE username = 'viraladmin'
GROUP BY day1 having count(distinct date) > 1 order by days
The formula in cell G2 "ReplenQty" is:
=SUMIFS(D:D,A:A,A2,B:B,B2,C:C,">=" & E2,C:C,"<=" &F2)
The formula in cell H2 "RpInVar" is:
=IF($A2<>$A1,ROUND(VAR(IF($A:$A=$A2,$G:$G)),2),0)
I attempted this in MySQL:
SELECT DISTINCT
Part,
Customer,
OrdDt,
OrdQty,
StartDate,
ReplenDate,
SUM(CASE WHEN Part = Part AND Customer = Customer AND OrdDt >= StartDate AND OrdDt <= ReplenDate THEN OrdQty ELSE 0 END) AS ReplenQty,
VARIANCE(CASE WHEN Part = Part AND Customer = Customer AND OrdDt >= StartDate AND OrdDt <= ReplenDate THEN OrdQty ELSE 0 END) AS RpInVar,
FROM
BeforeReplenQty
GROUP BY
Part,
Customer,
OrdDt,
OrdQty,
StartDate,
ReplenDate;
Problem is OrdQty and ReplenQty are the same and RpInVar are all 0.
This query is quite long and complicated but working on this demo: http://sqlfiddle.com/#!9/3b3334/70
One task is to do a sum where order date is between start date and replenish date.
Then get the row where part is new compared to previous row.
The first part of the query is to get the variance, the second subquery is to get the sum of Ordered qty and the sub-query at the bottom is to get the row where part column has changed.
select tab.Part,tab.Customer,tab.OrdDt,tab.OrdQty,tab.StartDate,tab.ReplenDate,tab.ReplenQty,
case when sumtab.Rnk=1 then
(select variance(ReplenQty)
from (select sum(t1.OrdQty) as ReplenQty
from BeforeReplenQty t2
inner join BeforeReplenQty t1
where t2.part=t1.part and t2.customer=t1.customer
and t2.OrdDt between t1.StartDate and t1.ReplenDate
group by t1.Part,t1.Customer,t1.OrdDt,t1.OrdQty,t1.StartDate,t1.ReplenDate) t3) else 0 end as ReplenVar
from (
select t1.*,sum(t1.OrdQty) as ReplenQty
from BeforeReplenQty t2
inner join BeforeReplenQty t1
where t2.part=t1.part and t2.customer=t1.customer
and t2.OrdDt between t1.StartDate and t1.ReplenDate
group by t1.Part,t1.Customer,t1.OrdDt,t1.OrdQty,t1.StartDate,t1.ReplenDate) tab
left join (select part,customer,orddt,rnk
from (
select t.part,t.customer,t.OrdDt,
#s:=CASE WHEN #c <> t.part THEN 1 ELSE #s+1 END AS rnk,
#c:=t.part AS partSet
from (SELECT #s:= 0) s
inner join (SELECT #c:= 'A') c
inner join (SELECT * from BeforeReplenQty
order by Part, Customer, OrdDt) t
) tab
where rnk = 1
) sumtab
on tab.part=sumtab.part and tab.customer=sumtab.customer and tab.orddt=sumtab.orddt;
I have the following query:
SELECT
(Date + INTERVAL -(WEEKDAY(Date)) DAY) `Date`,
I would like to use a subquery here to get the oldest and newest inventory from the max and min Date:
(select sellable from clabDevelopment.fba_history_daily where Date =
max(Date))
max(Date), min(Date),
ASIN,
ItemSKU,
it.avgInv,
kt.Account, kt.Country, SUM(Sessions) `Sessions`, avg(Session_Pct)`Session_Pct`,
sum(Page_Views)`Page_Views`, avg(Page_Views_Pct)`Page_Views_Pct`, avg(Buy_Box_Pct)`Buy_Box_Pct`,
sum(Units_Ordered)`Units_Ordered`, sum(Units_Ordered_B2B) `Units_Ordered_B2B`,
avg(Unit_Session_Pct)`Unit_Session_Pct`, avg(Unit_Session_Pct_B2B)`Unit_Session_Pct_B2B`,
sum(Ordered_Product_Sales)`Ordered_Product_Sales`, sum(Total_Order_Items) `Total_Order_Items`, sum(Actual_Sales) `Actual_Sales`,
sum(Orders) `Orders`, sum(PPC_Revenue) `PPC_Revenue`, sum(PPC_Orders) `PPC_Orders`,
sum(Revenue)`Revenue`, sum(Sales_Tax_Collected) `Sales_Tax_Collected`, sum(Total_Ad_Spend) `Total_Ad_Spend`, sum(Impressions) `Impressions`,
sum(Profit_after_Fees_before_Costs) `Profit_after_Fees_before_Cost`
FROM clabDevelopment.KPI_kpireport as kt
left outer join
(SELECT Month(Date) as mnth, sku, account, country, avg(sellable)`avgInv` FROM clabDevelopment.`fba_history_daily`
where sellable >= 0
group by Month(Date), sku, account, country) as it
on kt.ItemSKU = it.SKU
and kt.Account = it.account
and kt.Country = it.country
and it.mnth = Month(kt.Date)
WHERE kt.Country = 'USA' or kt.Country = 'CAN'
GROUP BY Account, Country,(Date + INTERVAL -(WEEKDAY(Date)) DAY), ItemSKU
ORDER BY Date desc
The sub-query would be from the same table I am joining on the bottom except I group by month there. So I want to run this subquery and grab the value under sellable for the date of max(Date):
(select sellable from clabDevelopment.`fba_history_daily where Date = max(Date))
When I do it this way I get invalid use of group function.
Without known your schema and the engine/db it is difficult to understand the problem. But, here is a best guess with the following schema:
fba_history_daily
- mnth
- sku
- account
- country
- sellable
- SKU
KPI_kpireport
- Account
- Country
- ItemSKU
- Account
- Date
- Country
- ASIN
The following query would give you what you're looking for. This uses a GROUP_CONCAT in order to build the required results through aggregation. With the nested query join MySQL might be building a temporary table within memory to sort through those records which would not be optimal. You can check this using EXPLAIN and you would see Using temporary in the details.
SELECT
(Date + INTERVAL -(WEEKDAY(Date)) DAY) `Date`,
ASIN,
ItemSKU,
-- MIN
(SUBSTRING_INDEX(GROUP_CONCAT(it.sellable ORDER BY it.Date ASC),',', 1) AS minSellable),
-- MAX
(SUBSTRING_INDEX(GROUP_CONCAT(it.sellable ORDER BY it.Date DESC),',', 1) AS maxSellable),
-- AVG
AVG(it.sellable) avgInv,
kt.Account, kt.Country, SUM(Sessions) `Sessions`, avg(Session_Pct)`Session_Pct`,
sum(Page_Views)`Page_Views`, avg(Page_Views_Pct)`Page_Views_Pct`, avg(Buy_Box_Pct)`Buy_Box_Pct`,
sum(Units_Ordered)`Units_Ordered`, sum(Units_Ordered_B2B) `Units_Ordered_B2B`,
avg(Unit_Session_Pct)`Unit_Session_Pct`, avg(Unit_Session_Pct_B2B)`Unit_Session_Pct_B2B`,
sum(Ordered_Product_Sales)`Ordered_Product_Sales`, sum(Total_Order_Items) `Total_Order_Items`, sum(Actual_Sales) `Actual_Sales`,
sum(Orders) `Orders`, sum(PPC_Revenue) `PPC_Revenue`, sum(PPC_Orders) `PPC_Orders`,
sum(Revenue)`Revenue`, sum(Sales_Tax_Collected) `Sales_Tax_Collected`, sum(Total_Ad_Spend) `Total_Ad_Spend`, sum(Impressions) `Impressions`,
sum(Profit_after_Fees_before_Costs) `Profit_after_Fees_before_Cost`
FROM KPI_kpireport as kt
left outer join fba_history_daily it on
kt.ItemSKU = it.SKU
and kt.Account = it.account
and kt.Country = it.country
and Month(it.Date) = Month(kt.Date)
and it.sellable >= 0
WHERE kt.Country = 'USA' or kt.Country = 'CAN'
GROUP BY Account, Country,(Date + INTERVAL -(WEEKDAY(Date)) DAY), ItemSKU
ORDER BY Date desc
I need to select how many days since there is a break in my data. It's easier to show:
Table format:
id (autoincrement), user_id (int), start (datetime), end (datetime)
Example data (times left out as only need days):
1, 5, 2011-12-18, 2011-12-18
2, 5, 2011-12-17, 2011-12-17
3, 5, 2011-12-16, 2011-12-16
4, 5, 2011-12-13, 2011-12-13
As you can see there would be a break between 2011-12-13 and 2011-12-16. Now, I need to be able say:
Using the date 2011-12-18, how many days are there until a break:
2011-12-18: Lowest sequential date = 2011-12-16: Total consecutive days: 3
Probably: DATE_DIFF(2011-12-18, 2011-12-16)
So my problem is, how can I select that 2011-12-16 is the lowest sequential date? Remembering that data applies for particular user_id's.
It's kinda like the example here: http://www.artfulsoftware.com/infotree/queries.php#72 but in the reverse.
I'd like this done in SQL only, no php code
Thanks
SELECT qmin.start, qmax.end, DATE_DIFF( qmax.end, qmin.start ) FROM table AS qmin
LEFT JOIN (
SELECT end FROM table AS t1
LEFT JOIN table AS t2 ON
t2.start > t1.end AND
t2.start < DATE_ADD( t1.end, 1 DAY )
WHERE t1.end >= '2011-12-18' AND t2.start IS NULL
ORDER BY end ASC LIMIT 1
) AS qmax
LEFT JOIN table AS t2 ON
t2.end < qmin.start AND
t2.end > DATE_DIFF( qmin.start, 1 DAY )
WHERE qmin.start <= '2011-12-18' AND t2.start IS NULL
ORDER BY end DESC LIMIT 1
This should work - left joins selects one date which can be in sequence, so max can be fineded out if you take the nearest record without sequential record ( t2.anyfield is null ) , same thing we do with minimal date.
If you can calculate days between in script - do it using unions ( eg 1. row - minimal, 2. row maximal )
Check this,
SELECT DATEDIFF((SELECT MAX(`start`) FROM testtbl WHERE `user_id`=1),
(select a.`start` from testtbl as a
left outer join testtbl as b on a.user_id = b.user_id
AND a.`start` = b.`start` + INTERVAL 1 DAY
where a.user_id=1 AND b.`start` is null
ORDER BY a.`start` desc LIMIT 1))
DATEDIFF() show difference of the Two days, if you want to number of consecutive days add one for that result.
If it's not a beauty contents then you may try something like:
select t.start, t2.start, datediff(t2.start, t.start) + 1 as consecutive_days
from tab t
join tab t2 on t2.start = (select min(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t4 where t4.start <= t.start and t4.start >= (select max(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t3 where t3.start <= t.start and t3.gap = 1))
where t.start = '2011-12-18'
Result should be:
start start consecutive_days
2011-12-18 2011-12-16 3