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Whats is the most elegant solution in angular2 for displaying an html table of z numbers in x rows and y columns?
X, Y and Z are numbers not necessarily collections. Also the table should contain numbers 1 to z.
I would do it like this : Plunker
Component
rows : any[];
cols : any[];
constructor() {
this.rows = Array(50).fill('');
this.cols = Array(10).fill('');
}
Template :
<table>
<tr *ngFor="let row of rows; let rowId = index">
<td *ngFor="let col of cols; let colId = index">{{rowId + colId*10+1}}</td>
</tr>
</table>
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I have a small question. How to put an object's property to href.
I marked with comment the line
success: function (listOfTags) {
let tagData = '';
$.each(listOfTags, function (i, tag) {
// ON THE NEXT LINE
tagData += '' + tag.name + '</li>';
});
$('#recentTags').html(tagData);
}
Try this:
tagData += `<li class="post-tag">${tag.name}</li>`;
For a valid markup, the anchor should be inside the list item, and the latter should be the child of a ul like this:
//before the loop
tagData += '<ul>';
tagData += `<li class="post-tag">${tag.name}</li>`;
//after the loop
tagData += '</ul>';
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So I got his problem as homework in my course, when I solved it the result I came up with was 1, but everywhere I check the solution stops at line 4 is if it is the final solution, but I can't spot the error in my logic for some reason!
Line1: (a+b+c')(a'b'+c)
Line2: =aa'b'+ba'b'+c'a'b'+ac+bc+c'c
Line3: =0+0+c'a'b'+ac+bc+0
Line4: =c'a'b'+ac+bc
Line5: =c'a'b'+c(a+b)
Line6: =c'+c(a'b'+(a+b))
Line7: =1*(a'b'+(a+b))
Line8: =1
You can do a very little bit better if XOR (^) is a primitive operation in your system:
Line1: (a+b+c')(a'b'+c)
Line2: = aa'b'+ba'b'+c'a'b'+ac+bc+c'c
Line3: = 0+0+c'a'b'+ac+bc+0
Line4: = c'a'b'+ac+bc
Line5: = c'a'b'+c(a+b)
Line6: = c'a'b'+c(a'b')'
Line7: = c^(a'b')
Your error is the following:
Line5: = c'a'b'+c(a+b)
Line6: = c'+c(a'b'+(a+b))
Clearly, lines 5 and 6 do not show equivalent expressions because c=0 satisfies the second regardless of a and b whereas c=0, a=1 does not satisfy the first.
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I am trying to make a Calendar of my own
https://stackblitz.com/edit/angular-1kfbod?file=src/app/app.component.css
This is a full example of my component.
How can I merge the week divs that have the same value {{day.weekNumber}} (one div instead of 4 for the example below)?
In your case, you should have separate array for your week numbers.
Typescript
public weekNumbers: number[] = [];
public rowWidth: any = 100 + '%';
ngOnInit() {
...
... // your existing code
...
let weeks = [];
for (let i = 1; i <= this.numberOfDaysCurrentMonth; i++) {
this.daysToDisplayInCurrentMonth[i - 1] = new Date(this.currentYear, this.currentMonth - 1, i).getDay();
const day = {
number: i,
weekDay: new Date(this.currentYear, this.currentMonth - 1, i).getDay(),
name: this.dayNames[this.daysToDisplayInCurrentMonth[i - 1]],
weekNumber: this.getWeekNumber(new Date(this.currentYear, this.currentMonth - 1, i))
};
weeks.push(day.weekNumber);
this.days.push(day);
}
this.weekNumbers = [];
weeks.forEach((ele) => {
if(this.weekNumbers.indexOf(ele) < 0) {
this.weekNumbers.push(ele);
}
});
this.rowWidth = (100/this.weekNumbers.length) + '%';
}
HTML
<div class="row-calendar">
<div class="week-number" [style.width]="rowWidth" *ngFor="let week of weekNumbers">
<label class="number-label"><span>{{week}} </span></label>
</div>
</div>
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I have a very basic question related to boolean logic.
I have two boolean flags- flagA and flagB. I need to calculate flagC based on the values of flagA and flagB.
The code/rules are:
if($flagA && $flagB) {
$flagC = true;
} else if (!$flagA || !$flagB) {
$flagC = false;
} else if(!$flagA && !$flagB) {
$flagC = true;
}
These rules match with the XNOR truth table - http://en.wikipedia.org/wiki/XNOR_gate
I want to find out different ways to re-write the above code(if possible) with:
fewer lines of code
better performance (even if it is a minute difference)
using bit shifting?
The languages I am hoping to write this in - php, ruby/ruby on rails.
Any help/pointers will be great!
Thanks!
Don't use these languages much but this might work:
$flagC = ($flagA == $flagB);
From the link posted: http://en.wikipedia.org/wiki/XNOR_gate
two-input version implements logical equality, behaving according to the truth table to the right. A HIGH output (1) results if both of the inputs to the gate are the same. If one but not both inputs are HIGH (1), a LOW output (0) results.
So flagC is true when flagA equals flagB.
if($flagA && $flagB) {
$flagC = true;
} else {
$flagC = false;
}
(Your second rule covers all other cases.)
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Is the following function is correct?
local function yes()
return 1
end
local function no()
return 0
end
Can I use it to set the values of the variables in this way?
local May_I = yes()
if May_I ~= 0 then
-- Yes I can do that
end
I like numbers, but sometimes they are not very precise.
You can deal with the imprecision you mentioned like so:
> epsilon = 1e-2
> function yes()
>> return 1
>> end
> if math.abs( yes() - 1 ) <= epsilon then
>> print("Yes I can")
>> end
Yes I can
Or alternately, be precise and use true and false.