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Is the following function is correct?
local function yes()
return 1
end
local function no()
return 0
end
Can I use it to set the values of the variables in this way?
local May_I = yes()
if May_I ~= 0 then
-- Yes I can do that
end
I like numbers, but sometimes they are not very precise.
You can deal with the imprecision you mentioned like so:
> epsilon = 1e-2
> function yes()
>> return 1
>> end
> if math.abs( yes() - 1 ) <= epsilon then
>> print("Yes I can")
>> end
Yes I can
Or alternately, be precise and use true and false.
Related
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So I got his problem as homework in my course, when I solved it the result I came up with was 1, but everywhere I check the solution stops at line 4 is if it is the final solution, but I can't spot the error in my logic for some reason!
Line1: (a+b+c')(a'b'+c)
Line2: =aa'b'+ba'b'+c'a'b'+ac+bc+c'c
Line3: =0+0+c'a'b'+ac+bc+0
Line4: =c'a'b'+ac+bc
Line5: =c'a'b'+c(a+b)
Line6: =c'+c(a'b'+(a+b))
Line7: =1*(a'b'+(a+b))
Line8: =1
You can do a very little bit better if XOR (^) is a primitive operation in your system:
Line1: (a+b+c')(a'b'+c)
Line2: = aa'b'+ba'b'+c'a'b'+ac+bc+c'c
Line3: = 0+0+c'a'b'+ac+bc+0
Line4: = c'a'b'+ac+bc
Line5: = c'a'b'+c(a+b)
Line6: = c'a'b'+c(a'b')'
Line7: = c^(a'b')
Your error is the following:
Line5: = c'a'b'+c(a+b)
Line6: = c'+c(a'b'+(a+b))
Clearly, lines 5 and 6 do not show equivalent expressions because c=0 satisfies the second regardless of a and b whereas c=0, a=1 does not satisfy the first.
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Im trying run this sql statement but its not working..
the select statement is ok but its just the bottom part that's giving me trouble.
SELECT VRVDIL.INVOICE_DATE,
VRVDIL.INVOICE_NO,
VRVDIL.DEAL_NO,
VRVDIL.COST,
VVD.DEAL_DATE,
VVD.SALESMAN_NAME,
VVD.SIGNED_DATE,
VVD.STOCK_NO,
VVD.VEHICLE_ID,
VVD.VEHICLE_SALES_GROUP_DESCRIPTION,
VVD.INVOICE_TO_NAME,
VRVS.DATE_SOLD,
VRVS.DAYS_IN_STOCK_BEFORE_SOLD,
VRVS.LOCATION_NAME,
VRVS.STOCKED_DATE,
VRVS.VEHICLE_CLASS_DESCRIPTION,
VRVRD.BUYER_NAME,
VRVRD.PURCHASING_PRICE,
VRVRD.SELLING_PRICE,
VRV.VIN,
VRV.VEHICLE_TYPE,
VRV.REGO_NO,
VRV.REGISTRATION_EXPIRY_DATE,
VRV.MODEL_ID,
VRV.MAKE_ID,
VRVDOL.QTY
FROM VW_RG_VEHICLE_DEAL_INVOICE_LINE VRVDIL,
VW_VEHICLE_DEAL VVD,
VW_RG_VEHICLE_DEAL_ORDER_LINE VRVDOL,
VW_RG_VEHICLE VRV,
VW_RG_VEHICLE_STOCKCARD VRVS,
VW_RG_VEHICLE_REGISTER_DETAIL VRVRD
WHERE (VRVDIL.VEHICLE_DEAL_KEY = VVD.VEHICLE_DEAL_KEY
AND VRVDOL.VEHICLE_DEAL_KEY = VVD.VEHICLE_DEAL_KEY
AND VVD.VEHICLE_KEY = VRV.VEHICLE_KEY
AND VRVS.VEHICLE_STOCKCARD_KEY = VVD.VEHICLE_STOCKCARD_KEY
AND VRVS.VEHICLE_KEY = VRV.VEHICLE_KEY
AND VRVS.VEHICLE_STOCKCARD_KEY = VRVRD.VEHICLE_STOCKCARD_KEY
what is the error?
Do you miss a closing parenthesis?
WHERE (VRVDIL.VEHICLE_DEAL_KEY = VVD.VEHICLE_DEAL_KEY
AND VRVDOL.VEHICLE_DEAL_KEY = VVD.VEHICLE_DEAL_KEY
AND VVD.VEHICLE_KEY = VRV.VEHICLE_KEY
AND VRVS.VEHICLE_STOCKCARD_KEY = VVD.VEHICLE_STOCKCARD_KEY
AND VRVS.VEHICLE_KEY = VRV.VEHICLE_KEY
AND VRVS.VEHICLE_STOCKCARD_KEY = VRVRD.VEHICLE_STOCKCARD_KEY)
At the end of the last AND condition, you should put a closing parenthesis.
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My task is to read every html file from a directory. Conditions are to find whether each file contains tags
(1) <strong>OO</strong>
(2) <strong>QQ</strong>
Then
Your write function is nested in the for loop, that's why you write multiple lines to your index.txt, just move the write out of the loop and put all your parti text to a variable parti_names like this:
participants = soup.find(find_participant)
parti_names = ""
for parti in participants.find_next_siblings("p"):
if parti.find("strong", text=re.compile(r"(Operator)")):
break
parti_names += parti.get_text(strip=True)+","
print parti.get_text(strip=True)
indexFile = open('index.txt', 'a+')
indexFile.write(filename + ', ' + title.get_text(strip=True) + ticker.get_text(strip=True) + ', ' + d_date.get_text(strip=True) + ', ' + parti_names + '\n' )
indexFile.close()
Update:
You can work with basename to get the file name:
from os.path import basename
# you can call it directly with basename
print(basename("C:/Users/.../output/100107-.html"))
Output:
100107-.html
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Whats is the most elegant solution in angular2 for displaying an html table of z numbers in x rows and y columns?
X, Y and Z are numbers not necessarily collections. Also the table should contain numbers 1 to z.
I would do it like this : Plunker
Component
rows : any[];
cols : any[];
constructor() {
this.rows = Array(50).fill('');
this.cols = Array(10).fill('');
}
Template :
<table>
<tr *ngFor="let row of rows; let rowId = index">
<td *ngFor="let col of cols; let colId = index">{{rowId + colId*10+1}}</td>
</tr>
</table>
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I have a very basic question related to boolean logic.
I have two boolean flags- flagA and flagB. I need to calculate flagC based on the values of flagA and flagB.
The code/rules are:
if($flagA && $flagB) {
$flagC = true;
} else if (!$flagA || !$flagB) {
$flagC = false;
} else if(!$flagA && !$flagB) {
$flagC = true;
}
These rules match with the XNOR truth table - http://en.wikipedia.org/wiki/XNOR_gate
I want to find out different ways to re-write the above code(if possible) with:
fewer lines of code
better performance (even if it is a minute difference)
using bit shifting?
The languages I am hoping to write this in - php, ruby/ruby on rails.
Any help/pointers will be great!
Thanks!
Don't use these languages much but this might work:
$flagC = ($flagA == $flagB);
From the link posted: http://en.wikipedia.org/wiki/XNOR_gate
two-input version implements logical equality, behaving according to the truth table to the right. A HIGH output (1) results if both of the inputs to the gate are the same. If one but not both inputs are HIGH (1), a LOW output (0) results.
So flagC is true when flagA equals flagB.
if($flagA && $flagB) {
$flagC = true;
} else {
$flagC = false;
}
(Your second rule covers all other cases.)