I want the count of records in every month and total count of records from start upto that month.
For ex.,
I have a table that looks like this:
#id,created#
1,'2016-01-01'
2,'2011-02-02'
3,'2011-02-09'
4,'2011-02-05'
5,'2011-03-07'
6,'2011-03-08'
How do I select and group these so the output is:
#Month, new, total#
Jan 2016, 1, 1
Feb 2016, 3, 4
Mar 2016, 2, 6
Thanks very much.
Here you go:
SELECT DATE_FORMAT(`created`,'%M %Y') AS month, COUNT(*) AS count,
(SELECT count(*) FROM test WHERE MONTH(created) <= MONTH(t.created)) AS total
FROM test t
GROUP BY MONTH(created);
Here's the SQL Fiddle.
Using single table read:
SELECT
CONCAT(LEFT(MONTHNAME(dt), 3), ' ', YEAR(dt)) month,
new,
#total:=#total + new total
FROM
(SELECT
created - INTERVAL DAY(created) - 1 DAY dt, COUNT(*) new
FROM
t
GROUP BY created - INTERVAL DAY(created) - 1 DAY
ORDER BY dt) t
CROSS JOIN
(SELECT #total:=0) t2
Demo
Related
I have a table with columns day, month, year, total_payments. And I have to calculate total_payments according to days, months, years.
How can I calculate values?
I am thinking code like :
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
day;
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
month;
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
year;
but it will not return the correct answers. And I want to calculate total_payments daywise, monthwise, yearwise. Please help me to find values.
Sample input :
Day Month Year Total_payments
10 01 2008 10
10 01 2008 20
11 02 2008 10
10 03 2010 10
Output:
Daywise :
day month year total_payments
-----------------------------
10 01 2008 30
11 02 2008 10
10 03 2010 10
Same for month and yearwise
You can get a summary with Totals by Year, Month and Day using GROUP BY WITH ROLLUP:
SELECT
`Year`,
`Month`,
`Day`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`,`Month`,`Day` WITH ROLLUP;
If you want individual queries for Year, Month and Day:
By Year:
SELECT
`Year`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`
ORDER BY `Year;
By Month:
SELECT
`Year`,
`Month`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
WHERE `Year` = 2017
GROUP BY `Year`,`Month`
ORDER BY `Year`,`Month`;
By Day:
SELECT
`Year`,
`Month`,
`Day`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`,`Month`,`Day`
ORDER BY `Year`,`Month`,`Day`;
A way could be the use on an union for show the different result based on different group by level
select day, month,year,sum(total_payments)
from webassignment.subscription_stats group by day, month,year
union
select null, month,year,sum(total_payments)
from webassignment.subscription_stats group by month,year
union
select null, null ,year,sum(total_payments)
from webassignment.subscription_stats group by year
order by year, month, day
for the sample you provided should be enough
select day, month,year,sum(total_payments)
from webassignment.subscription_stats group by day, month,year
order by day, month,year
SR_ AREA INS_PRODUCT DATEADD TOTAL
Clinical Question PS 2016-01-06 280
I'm trying to show the month by name say January and I want all the totals for the month of January not just for one day in the month.
I got it to show just Month and total how do I get it to show all the months this is the code I have so far.
SELECT DATENAME(MM,GETDATE()) AS MONTH, COUNT(*) AS TOTAL
FROM S_SRV_REQ WITH (NOLOCK)
WHERE (dbo.fn_dstoffset(CREATED) >= '11-15-2015')
AND (dbo.fn_dstoffset(CREATED) <= DATEADD(D, 1, '3-31-2016'))
AND (INS_PRODUCT IN ('PS'))
AND [SR_AREA] IS NOT NULL
AND (SR_AREA IN ('Clinical Question'))
select date_format(dateadd, '%M'), sum(total)
from your_table
group by date_format(dateadd, '%M')
You can use MONTH
select month(dateadd), sum(total)
from your_table
group by month(dateadd)
I would like to group a series of counts but by week. I know that using the week() function returns a number for the week, but i'd like something like this:
Week count(*)
Jan 1 - Jan 7 30
Jan 8 - 14 50
and so on...
Is there a way to do this? Thank you very much.
select
concat(cast(DATE_ADD(yourdate, INTERVAL(1-DAYOFWEEK(yourdate)) DAY) as char), ' - ',
cast(DATE_ADD(yourdate, INTERVAL(7-DAYOFWEEK(yourdate)) DAY) as char))
as period, count(*)
from tablename
group by week(yourdate)
i have this sql which selects data from the database and returns two columns
for this sql,
SELECT count(*) cnt, date(created) dt FROM mlm_users GROUP by dt
i get something line
count, date
1, 2013-05-10
2, 2013-06-10
11, 2013-09-10
for the following,
SELECT count(*) cnt, week(DATE_SUB(created, INTERVAL 1 DAY)) dt
FROM mlm_users GROUP by dt
i get
count, week no
1, 12
2, 22
11, 34
is there anyway i can return the week date range like
count, week no
1, 2013-01-12 - 2013-07-12
2, 2013-08-12 - 2013-14-12
11, 2013-15-12 - 2013-29-12
and for the mnonth return thw month
SELECT month( created ) dt, date(created) dt FROM mlm_users GROUP by dt
i could have calculated this value manually, but because of minor issues in date calculation, i wanted to know if the database can give this value.
pls see http://sqlfiddle.com/#!2/cd3db/2
thanks
Maybe something like this,if I understand you
http://sqlfiddle.com/#!2/cd3db/18
Here's the table structure and some sample data:
pID.....month.....year
27 .....3 .....2008
27 .....12 .....2012
31 .....6 .....2008
99 .....1 .....2006
42 .....1 .....2009
pID is the practiceID and month and year represent the date period they've entered data for. I need to grab the number of practices that have entered data for the first time in Oct 2012, Nov 2012, Dec 2012 and so on.
I tried the following query for Oct 2012:
SELECT *
FROM
IPIPKDIS
where
practiceID NOT IN (
SELECT practiceID
from
IPIPKDIS
where
year < 2012 and month < 10
)
and year = 2012
and month = 10
and measureCatRecID = 2
ORDER BY year, month;
but it's grabbing months and year less than 10/2012.
If I run the queries isolated (not as subquery) they both work fine.
Any ideas?
This summary query will yield the first (smallest) date in the table for each value of practiceID.
SELECT practiceID,
MIN(STR_TO_DATE( CONCAT(year, ' ', month), '%Y %m')) first_date
FROM IPIPKDIS
GROUP BY practiceID
If you want to retrieve then the whole row for the first reported month, you'd do a nested query like this:
SELECT *
FROM IPIPKDIS I
JOIN (
SELECT practiceID,
MIN(STR_TO_DATE( CONCAT(year, ' ', month), '%Y %m')) first_date
FROM IPIPKDIS
GROUP BY practiceID
) first ON ( first.practiceID = I.practiceID
AND STR_TO_DATE( CONCAT(I.year, ' ', I.month), '%Y %m') = first.first_date)
The trick to the second query is to use the JOIN to extract just the first-month rows from your table. We use date arithmetic to do the date comparisons.