i have this sql which selects data from the database and returns two columns
for this sql,
SELECT count(*) cnt, date(created) dt FROM mlm_users GROUP by dt
i get something line
count, date
1, 2013-05-10
2, 2013-06-10
11, 2013-09-10
for the following,
SELECT count(*) cnt, week(DATE_SUB(created, INTERVAL 1 DAY)) dt
FROM mlm_users GROUP by dt
i get
count, week no
1, 12
2, 22
11, 34
is there anyway i can return the week date range like
count, week no
1, 2013-01-12 - 2013-07-12
2, 2013-08-12 - 2013-14-12
11, 2013-15-12 - 2013-29-12
and for the mnonth return thw month
SELECT month( created ) dt, date(created) dt FROM mlm_users GROUP by dt
i could have calculated this value manually, but because of minor issues in date calculation, i wanted to know if the database can give this value.
pls see http://sqlfiddle.com/#!2/cd3db/2
thanks
Maybe something like this,if I understand you
http://sqlfiddle.com/#!2/cd3db/18
Related
ID
TIMESTAMP
1
2020-01-01 12:00:00
2
2020-02-01 12:00:00
3
2020-05-01 12:00:00
4
2020-06-01 12:00:00
5
2020-07-01 12:00:00
I am looking for a way to get records in a MySQL database that are within a certain range of each other. In the above example, notice that there is a month between the first two records, then a three month gap, before we see another three records with a month between.
What is a way to group these into two result sets, so I will get Ids 1, 2 and 3, 4, 5 A solution using days would be probably work the best as thats easier to modify.
You can use lag() and then logic to see where a gap is big enough to start a new set of records. A cumulative sum gives you the groups you want:
select t.*,
sum(case when prev_timestamp >= timestamp - interval 1 month then 0 else 1 end) over (order by timestamp) as grouping
from (select t.*,
lag(timestamp) over (order by timestamp) as prev_timestamp
from t
) t;
If you want to summarize this with a start and end date:
select min(timestamp), max(timestamp)
from (select t.*,
sum(case when prev_timestamp >= timestamp - interval 1 month then 0 else 1 end) over (order by timestamp) as grouping
from (select t.*,
lag(timestamp) over (order by timestamp) as prev_timestamp
from t
) t
) t
group by grouping;
For example, the following query:
select group_concat(ID)
from (
select w1.ID,w1.TS,w2.ID flag
from work1 w1 left outer join work1 w2
on timestampdiff(month,w2.TS,w1.TS)=1
order by w1.ID
) w
group by
case when flag is null then #str:=ID else #str end
See db fiddle
I have a table called months - this contains all 12 months of the calendar, the IDs correspond to the month number.
I will be running a query to retrieve 2 or 3 sequential months from this table, e.g
April & May
June, July, August
December & January
However I want to ensure that whenever December are January and retrieved, that it retrieves them in that order, and not January - December. Here is what I have tried:
SELECT * FROM `months`
WHERE start_date BETWEEN <date1> AND <date2>
ORDER BY
FIELD(id, 12, 1)
This works for December & January, but now when I try to retrieve January & February it does those in the wrong order, i.e "February - January" - I'm guessing because we specified 1 in the ORDER BY as the last value.
Anybody know the correct way to achieve this? As I mentioned this should also work for 3 months, so for example "November, December, January" and "December, January, February" should all be retrieved in that order.
If you want December first, but the other months in order, then:
order by (id = 12) desc, id
MySQL treats booleans as numbers, with "1" for true and "0" for false. The desc puts the 12s first.
EDIT:
To handle the more general case, you can use window functions. Assuming the numbers are consecutive, then the issue is trickier. This will work for 2 and 3-month spans:
order by (case min(id) over () > 1 then id end),
(case when id > 6 1 else 2 end),
id
I'm reluctant to think about a more general solution based only on months. After all, you can just use:
order by start_date
Or, if you have an aggregation query:
order by min(start_date)
to solve the real problem.
This is not "mysql solution" properly :
with cte (id, month) AS (
select id, month from months
union all
select id, month from months
)
, cte1 (id, month, r) as (select id, month, row_number() over() as r from cte )
select * from cte1
where id in (12, 1)
and r >= 12 order by r limit 2 ;
DECLARE
#monthfrom int = 12,
#monthto int = 1;
with months as (select 1 m
union all
select m+1 from months where m<12)
select m
from months
where m in (#monthfrom,#monthto)
order by
case when #monthfrom>#monthto
then
m%12
else
m
end
result:
12
1
Basically in MySQL this can be done the same way:
set #from =12;
set #to =1;
with recursive months(m) as (
select 1 m
union all
select m+1 from months where m<12)
select *
from months
where m in (#from,#to)
order by case when #from>#to then m%12 else m end;
I'm trying to write a query that aggregates data from a table.
Essentially I have a long list of devices that have been inventoried and eventually installed over the last couple of years.
I want to find the average amount of time between when the device was received and when it was installed, and then have that data sorted by the month the device was installed. BUT in each month's row, I also want to include the data from the previous months.
So essentially what I want to see is: (sorry for terrible formatting)
MonthInstalled | TimeToInstall | Total#Devices
-----------------+---------------+----------------------------
Jan | 10 Days | 5
Feb(=Jan+Feb) | 15 Days | 18 (5 in Jan + 13 in Feb)
Mar(=Jan+Feb+Mar)| 13 Days | 25 (5 + 13 + 7)
...
The query I currently have written looks like this:
INSERT INTO DevicesInstall
SELECT ROUND(AVG(DATEDIFF(dvc.dt_install , dvc.dt_receive)), 1) AS 'Install',
COUNT(dvc.dvc_model) AS 'Total Devices',
MAX(dvc.dt_install) AS 'Date',
loc.loc_campus AS 'Campus'
FROM dvc_info dvc, location loc
WHERE dvc.dvc_loc_bin = loc.loc_bin
AND dvc.dt_install < '20160201'
;
Although this is functional, I have to iterate this for each month manually, so it is not scale-able. Is there a way to condense this at all?
We can return the dates using an inline view (derived table), and then join to the dvc_info table, so we can get the "cumulative" results.
To get the results for:
Jan
Jan+Feb
Jan+Feb+Mar
We need to return three copies of the rows for Jan, and two copies of the rows for Feb, and then collapse the those rows into an appropriate group.
The loc_campus is being included in the SELECT list... not clear why that is needed. If we want results "by campus", then we need to include that expression in the GROUP BY clause. Otherwise, the value returned for that non-aggregate is indeterminate... we will get a value for some row "in the group", but it could be any row.
Something like this:
SELECT d.dt AS `before_date`
, loc.loc_campus AS `Campus`
, ROUND(AVG(DATEDIFF(dvc.dt_install,dvc.dt_receive)),1) AS `Install`
, COUNT(dvc.dvc_model) AS `Total Devices`
, MAX(dvc.dt_install) AS `latest_dt_install`
FROM ( SELECT '2016-01-01' + INTERVAL 1 MONTH AS dt
UNION ALL SELECT '2016-01-01' + INTERVAL 2 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 3 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 4 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 5 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 6 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 7 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 8 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 9 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 10 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 11 MONTH
UNION ALL SELECT '2016-01-01' + INTERVAL 12 MONTH
) d
CROSS
JOIN location loc
LEFT
JOIN dvc_info dvc
ON dvc.dvc_loc_bin = loc.loc_bin
AND dvc.dt_install < d.dt
GROUP
BY d.dt
, loc.loc_campus
ORDER
BY d.dt
, loc.loc_campus
Note that the value returned for d.dt will be the "up until" date. We're going to get '2016-02-01' returned for the January results. If we want to return a value of January date, we can use an expression in the SELECT list...
SELECT DATE_FORMAT(d.dt + INTERVAL -1 MONTH,'%Y-%m') AS `month`
Lots of options on query alternatives.
But it looks like the "big hump" is that to get cumulative results, we need to return multiple copies of the dvc_info rows, so the rows can be collapsed into each "grouping".
I recommend working on just the SELECT first. And get that tested working, before monkeying around to turn it into an INSERT ... SELECT.
FOLLOWUP
We can use any query as an inline view (derived table d) that returns a set of dates we want.
e.g.
FROM ( SELECT DATE_FORMAT(m.install_dt,'%Y-%m-01') + INTERVAL 1 MONTH AS dt
FROM dvc_install m
WHERE m.install_dt >= '2016-01-01'
GROUP BY DATE_FORMAT(m.install_dt,'%Y-%m-01') + INTERVAL 1 MONTH
) d
Note that with this approach, if there are no install_dt in February, we won't get back a row for February. Using the static UNION ALL SELECT approach allows us to get back "zero" counts, i.e. to return rows for months where there isn't an install_dt in that month. (But that's the answer to a different question... how do I get back a "zero" count for February when there aren't any rows for Februrary?)
Alternatively, if we have a calendar table e.g. cal that contains a list of the dates we want, we could just reference the table in place of the inline view, or the inline view query could get rows from that.
FROM ( SELECT cal.dt
FROM cal cal
WHERE cal.dt >= '2016-01-01'
AND cal.dt <= NOW()
AND DATE_FORMAT(cal.dt,'%d') = '01'
) d
I want the count of records in every month and total count of records from start upto that month.
For ex.,
I have a table that looks like this:
#id,created#
1,'2016-01-01'
2,'2011-02-02'
3,'2011-02-09'
4,'2011-02-05'
5,'2011-03-07'
6,'2011-03-08'
How do I select and group these so the output is:
#Month, new, total#
Jan 2016, 1, 1
Feb 2016, 3, 4
Mar 2016, 2, 6
Thanks very much.
Here you go:
SELECT DATE_FORMAT(`created`,'%M %Y') AS month, COUNT(*) AS count,
(SELECT count(*) FROM test WHERE MONTH(created) <= MONTH(t.created)) AS total
FROM test t
GROUP BY MONTH(created);
Here's the SQL Fiddle.
Using single table read:
SELECT
CONCAT(LEFT(MONTHNAME(dt), 3), ' ', YEAR(dt)) month,
new,
#total:=#total + new total
FROM
(SELECT
created - INTERVAL DAY(created) - 1 DAY dt, COUNT(*) new
FROM
t
GROUP BY created - INTERVAL DAY(created) - 1 DAY
ORDER BY dt) t
CROSS JOIN
(SELECT #total:=0) t2
Demo
I have a table with some dates. I need a query which will return the max (last) date from this table and last date of quarter this max date belongs to.
So for data i table
ID| EDATE
--+----------
1|2014-03-06
2|2014-10-12
this query should return 2014-10-12 and 2014-12-31.
As I understand you want the last day of the quarter, so 31 March, 30 June, 30 Sept, 31 Dec? So you can use the answer from Gordon Linoff and adjust it to do that.
You only need a case statement on month(date) and concat that with the year.
http://dev.mysql.com/doc/refman/5.1/de/control-flow-functions.html
str_to_date(
concat(
year(edate),
(case
when month(edate) in (1, 2, 3) then '-03-31'
when month(edate) in (4, 5, 6) then '-06-30'
when month(edate) in (7, 8, 9) then '-09-30'
else '-12-31'
end)
),
'%Y-%m-%d'
)
Getting the day of the last quarter for the date is a bit yucky, but possible. Here is a sort of brute force solution:
select edate,
str_to_date(concat(year(edate), '-', 1 + floor((month(edate) - 1)/ 3)) * 3, '-',
(case when month(edate) in (1, 2, 3, 10, 11, 12) then 31 else 30 end)),
'%Y-%m-%d'
)
from table t
order by edate desc
limit 1;
Here is a SQL Fiddle that demonstrates it.
You can use LAST_DAY to select the last day of a specific month depending on where your quarters end you may have to change the 3,6,9,12 to different months.
select t1.max_date,
(
case
when month(max_date) <= 3
then last_day(concat(year(max_date),'-3-1'))
when month(max_date) <= 6
then last_day(concat(year(max_date),'-6-1'))
when month(max_date) <= 9
then last_day(concat(year(max_date),'-9-1'))
else last_day(concat(year(max_date),'-12-1'))
end
) last_quarter_day
from (
select max(EDATE) max_date from myTable
) t1
I found the simplest answer:
SELECT MAKEDATE(YEAR(edate),1)
+ INTERVAL QUARTER(edate) QUARTER
- INTERVAL 1 DAY
This query takes the first day of year, adds quarters to it and subtracts 1 day to get the last day in wanted quarter. So the required query should look like:
SELECT MAX(edate),
MAKEDATE(YEAR(MAX(edate)),1)
+ INTERVAL QUARTER(MAX(edate)) QUARTER
- INTERVAL 1 DAY
FROM table