i need to display rank with my sql on 2 joined table, there's my mysql query to display
SELECT a.UserID, b.Nama,a.Matematika,a.IPA,a.IPS,a.BIND,a.BING,a.Rata,
FIND_IN_SET( a.Rata, (SELECT GROUP_CONCAT( a.Rata ORDER BY a.Rata DESC ) FROM datanilaiujian )) AS rank
from datanilaiujian as a JOIN
datauser as b
ON a.UserID=b.UserID
ORDER BY a.Rata DESC
but when i execute this command, mysql return Error Code: 1242. Subquery returns more than 1 row
list field on table datanilaiujian
UserID Matematika IPA IPS BIND BING Rata
1000 90 76 78.9 78 65 77.58
1001 78.9 87 67 56 78 73.38
1002 80 78.9 67 55 65.9 69.36
1003 78.9 56 77 88 90 77.97999999999999
list field on table datauser
UserID Pass Nama Alamat NoTelepon AsalSekolah Tanggal Masuk NilaiUN
1000 1000 Habib Jl.sesama 232323232323 23dsdsdsfsdfsdfsdfsdff 2017-01-13 19:35:22 Sudah
1001 1001 wisnu jl sesama 085600336706 SMA 2 Purwokerto 2017-01-28 17:35:32 Sudah
1002 1002 Arif Jl Sungkio 085600336706 SMA BINTEK 2017-01-28 19:30:56 Sudah
1003 1003 Akbar Jl sesama 085600133558 SMPN 1 Purwokerto 2017-02-02 18:59:47 Sudah
my expected result :
Nama Matematika IPA IPS BIND BING Rata Rank
I see the problem. Your subquery is saying a.Rata. This refers to the outer table. I suspect that the GROUP_CONCAT() is then confusing MySQL, so the subquery is not interpreted as an aggregation query.
However, you should move the subquery to the FROM clause:
SELECT a.*,
FIND_IN_SET( a.Rata, l.list) AS rank
from datanilaiujian a JOIN
datauser b
ON a.UserID = b.UserID CROSS JOIN
(SELECT GROUP_CONCAT( a2.Rata ORDER BY a2.Rata DESC ) as list
FROM datanilaiujian a2
) l
ORDER BY a.Rata DESC;
This generally helps the optimizer choose the best execution plan.
Related
i need help find who fail in exam & resit and pass the exam only,
heres the code:
select STUDENT_ID,EXAM_ID,SCORE,PASS_THRESHOLD,s.NAME , c.NAME as Course_name, EXAM_DT,
case
when SCORE>=PASS_THRESHOLD then 'PASS'
else 'Fail'
end as Flag
from exam_submission es
left join student s on es.STUDENT_ID = s.ID
left join exam e on es.EXAM_ID = e.ID
left join course c on e.COURSE_ID = c.ID
heres the result:
STUDENT_ID EXAM_ID SCORE PASS_THRESHOLD NAME Course_name EXAM_DT Flag
1 3 88 65 Anthony Data Mining 2019-12-17 PASS
1 5 71 70 Anthony Statistic 2019-12-19 PASS
2 1 53 55 Sisca Machine Learning2019-12-17 Fail
2 3 77 65 Sisca Data Mining 2019-12-17 PASS
2 4 85 63 Sisca Data Science 2019-12-18 PASS
2 1 60 55 Sisca Machine Learning2020-01-08 PASS
I need find like this:
2 1 53 55 Sisca Machine Learning2019-12-17 Fail
2 1 60 55 Sisca Machine Learning2020-01-08 PASS
Possibly using a query like below.
this is using your query as input.
Also we have assumed that it is not possible to have a student have (PASS, FAIL) for a student on same exam on two years chronologically.
; with inputdata as
(
select STUDENT_ID,EXAM_ID,SCORE,PASS_THRESHOLD,s.NAME , c.NAME as Course_name, EXAM_DT,
case
when SCORE>=PASS_THRESHOLD then 'PASS'
else 'Fail'
end as Flag
from exam_submission es
left join student s on es.STUDENT_ID = s.ID
left join exam e on es.EXAM_ID = e.ID
left join course c on e.COURSE_ID = c.ID
)
select * from Inputdata I
join
( select student_id, exam_id from
inputdata
group by student_id, exam_id
having count(distinct flag)=2
)T on I.student_id=T.student_id and I.exam_id=T.exam_id
order by exam_dt asc
below is database and table details.
database name - mis_v1
table 1 name - trips
table 2 name - client
i tried below queries
Query 1
select cl.client_name CLIENT
, count(t.trip_type) TRIPS
, count(distinct t.vehicle_reg_no) VEHICLES
from mis_v1.trips t
JOIN mis_v1.client cl
ON cl.id = t.client_id
group
by cl.client_name;
Query 1 result
CLIENT TRIPS VEHICLES
anz-ABlr 118 16
citrix-CBlr 159 15
dxc-DBlr 26 5
Eps-Blr 116 24
goc-GocHyd 191 10
Unisys-BLR 192 55
Wipro-Ncr 86 33
Wipro-Pnq 10 5
Query 2
select cl.client_name CLIENT
, count(t.trip_delay_reason) LATE_TRIPS
FROM mis_v1.trips t
JOIN mis_v1.client cl
ON cl.id = t.client_id
where t.trip_delay_reason = "DRIVER"
group
by cl.client_name;
Query 2 result
CLIENT LATE_TRIPS
anz-ABlr 53
citrix-CBlr 25
dxc-DBlr 1
Wipro-Ncr 1
goc-GocHyd 17
I need result as below
CLIENT TRIPS VEHICLES LATE_TRIPS
anz-ABlr 118 16 53
citrix-CBlr 159 15 25
dxc-DBlr 26 5 1
Eps-Blr 116 24 -
goc-GocHyd 191 10 17
Unisys-BLR 192 55 -
Wipro-Ncr 86 33 1
Wipro-Pnq 10 5 -
Kindly give me solution.Thanks in advance
If I understood you correctly, you need something like this:
select cl.client_name CLIENT
, count(t.trip_type) TRIPS
, count(distinct t.vehicle_reg_no) VEHICLES
, coalesce(cast(count(case when t.trip_delay_reason = "DRIVER" then 1 else null end) as char), '-') LATE_TRIPS
from mis_v1.trips t
JOIN mis_v1.client cl
ON cl.id = t.client_id
group
by cl.client_name;
So, please read more about COUNT aggreagate function and probably CASE operator
this is my query:
SELECT br.employee_id AS rat_id,
br.rating_comment,
br.created_at,
br.id
FROM employee_followers
LEFT JOIN employee_ratings AS br ON employee_followers. employee_id = br.employee_id
WHERE employee_followers.employee_id IN
(SELECT `employee_id`
FROM employee_followers
WHERE user_id =32)
GROUP BY br.id
ORDER BY created_at DESC
what I am getting:
rat_id rating_comment created_at id
18 superb developer 2016-02-19 18:26:54 82
9 james to manoj-joshi 2016-02-19 16:42:17 84
50 james to prem 2016-02-19 13:05:30 83
50 pinal to prem 2016-02-19 12:20:00 73
50 prem to premal-joshi 2016-02-19 11:40:52 78
18 prem to mukund 2016-02-19 11:21:52 77
18 pinal to mukund 2016-02-18 11:37:00 76
9 mukund rate to mitesh 2016-02-15 22:34:14 51
9 Not a bad. 2016-02-10 00:16:31 45
9 sda 2016-02-08 01:36:33 39
what I want:
rat_id rating_comment created_at id
18 superb developer 2016-02-19 18:26:54 82
9 james to manoj-joshi 2016-02-19 16:42:17 84
50 james to prem 2016-02-19 13:05:30 83
Try This
SELECT rat_id,rating_comment, MAX(created_at) AS created, id FROM (
SELECT br.employee_id AS rat_id,
br.rating_comment,
br.created_at,
br.id
FROM employee_followers
LEFT JOIN employee_ratings AS br ON employee_followers. employee_id = br.employee_id
WHERE employee_followers.employee_id IN
(SELECT `employee_id`
FROM employee_followers
WHERE user_id =32)
GROUP BY br.id
ORDER BY created_at DESC) AS temp GROUP BY temp.rat_id
It seems that you want only the latest record per employee_id. You can use a derived table to get the maximum date, then join again to get all fields from employee_ratings table for this date:
SELECT er.employee_id AS rat_id,
er.rating_comment,
er.created_at,
er.id
FROM employee_followers AS ef
LEFT JOIN (
SELECT employee_id, MAX(created_at) AS max_date
FROM employee_ratings
GROUP BY employee_id
) AS emp_max ON ef.employee_id = emp_max.employee_id
LEFT JOIN employee_ratings AS er
ON emp_max.employee_id = er.employee_id AND
emp_max.max_date = er.max_date
WHERE user_id = 32
ORDER BY created_at DESC
I have also removed GROUP BY br.id that seems to be redundant in the context of the query. Also IN operator can be replaced by user_id = 32 since you are selecting from the same table.
I have the 2 following select in Mysql:
1st select:
(SELECT DISTINCT `Online_playerdatabase_v2`.`Player`,
Online_playerdatabase_v2.First_Deposit_Date As FirstDep,
TRUNCATE(Online_playerdatabase_v2.Balance,2) as Balance
FROM Online_playerdatabase_v2
WHERE `Online_playerdatabase_v2`.`Player`<>'Player'
ORDER BY `Online_playerdatabase_v2`.`Balance` DESC;
2d select:
SELECT DISTINCT(Online_customer_activity_v2.Customers) as Player,
max(Online_customer_activity_v2.Date) as LastAction
FROM Online_customer_activity_v2
WHERE `Online_customer_activity_v2`.`Total_Bets`>0
Group by Online_customer_activity_v2.Customers
Output Select 1
Player FirstDep Balance
Ray 2014-10-19 9100.00
Ramzi 2014-11-02 9.61
tareq 2014-11-06 805.00
STAN 2014-10-17 7.50
Bill 2014-03-25 68.40
karam 2014-11-16 676.50
Abdul 2014-11-13 650.00
Renaud 2014-03-12 507.00
John 2014-11-22 500.00
Output select 2
Player LastAction
John 2015-11-13
Bill 2014-12-14
Renaud 2015-03-14
Abdul 2015-11-16
Ray 2015-11-22
STAN 2015-10-29
Ramzi 2015-11-10
Tarek 2015-05-10
karam 2014-12-10
Abdul 2015-02-10
Desired Output, a join on both Select that adds following calculations:
active days (FirstDep-LastAction) and Days_last_Visit (CurrentDate - Last Action)
Summarized in following table:
Player FirstDep Balance LastAction Active_days Days_last_Visit
Ray 2014-10-19 9100.00 2015-11-22 399 1
Ramzi 2014-11-02 9.61 2015-11-10 373 13
tareq 2014-11-06 805.00 2015-05-10 185 197
STAN 2014-10-17 7.50 2015-10-29 377 25
Bill 2014-03-25 68.40 2014-12-14 264 344
karam 2014-11-16 676.50 2014-12-10 24 348
Abdul 2014-11-13 650.00 2015-02-10 89 286
Renaud 2014-03-12 507.00 2015-03-14 367 254
John 2014-11-22 500.00 2015-11-13 356 10
Your help is greatly appreciated!
Thanks
The following query should give the result you want. I will add that I joined the two tables from your intermediate queries above using the Player field. This is not a very robust way to join, because the name may not be unique among all players in the table. A better way to join would be to use a unique identifier of some sort.
SELECT t1.Player, t1.FirstDep, t1.Balance, t2.LastAction,
DATEDIFF(t2.LastAction, t1.FirstDep) AS Active_days,
DATEDIFF(NOW(), t2.LastAction) AS Days_last_Visit
FROM
(
SELECT DISTINCT `Online_playerdatabase_v2`.`Player`,
Online_playerdatabase_v2.First_Deposit_Date AS FirstDep,
TRUNCATE(Online_playerdatabase_v2.Balance,2) AS Balance
FROM Online_playerdatabase_v2
WHERE `Online_playerdatabase_v2`.`Player` <> 'Player'
) t1
INNER JOIN
(
SELECT DISTINCT(Online_customer_activity_v2.Customers) AS Player,
MAX(Online_customer_activity_v2.Date) AS LastAction
FROM Online_customer_activity_v2
WHERE `Online_customer_activity_v2`.`Total_Bets` > 0
GROUP BY Online_customer_activity_v2.Customers
) t2
ON t1.`Player` = t2.`Player`
You need to join the 2 selects as subqueries in a 3rd select using the player field. The Active_days and Days_last_Visit fields can be calculated using the DateDiff() function.
SELECT *
,DateDiff(t2.LastAction,t1.FirstDep) AS Active_days
,DateDiff(CURDATE(), t2.LastAction) AS Days_last_Visit
FROM
(SELECT DISTINCT `Online_playerdatabase_v2`.`Player`,
Online_playerdatabase_v2.First_Deposit_Date As FirstDep,
TRUNCATE(Online_playerdatabase_v2.Balance,2) as Balance
FROM Online_playerdatabase_v2
WHERE `Online_playerdatabase_v2`.`Player`<>'Player'
ORDER BY `Online_playerdatabase_v2`.`Balance` DESC) t1
LEFT JOIN
(SELECT DISTINCT(Online_customer_activity_v2.Customers) as Player,
max(Online_customer_activity_v2.Date) as LastAction
FROM Online_customer_activity_v2
WHERE `Online_customer_activity_v2`.`Total_Bets`>0
Group by Online_customer_activity_v2.Customers) t2
ON t1.Player=t2.Player
You have to consider, however, how you join the 2 datasets. I used left join, since the players table will probably hold all players, but you may want to go for inner join or simulate a full outer join depending your requirements and your data.
EDIT:
I'm trying to do a MySQL query which will give me the latest entry for duplicates together with those without any duplicates.
This is what my table look like:
mentor table:
mentor_id applicant_id mentor_count mento_email mentor_name mentor_pass
193 92 1 test#yahoo.com test 1234
194 92 2 table#yahoo.com table 4567
195 92 3 lamp#yahoo.com lamp 7890
196 92 1 test#yahoo.com test 1234
197 92 2 table#yahoo.com table 4567
198 92 3 lamp#yahoo.com lamp 7890
mf table:
mf_id mentor_id dept contact orgname yrs length sak social char goal resp emomat res others impact evaluation
43 193 math dept 9111111 etc 1 1 e e e e e e e e e good
114 196 math dept 9111111 etc 1 1 e e e e e e e e e good
193 197 sci dept 9222222 org 2 2 n n n n n n n n n medium
194 194 sci dept 9222222 org 2 2 n n n n n n n n n medium
220 195 eng dept 9333333 hello 3 3 q q q q q q q q q bad
I tried using this query:
SELECT *
FROM mentor m1
LEFT JOIN (
SELECT mentor_name, max( mentor_id ) AS maxid
FROM mentor m
GROUP BY m.mentor_id
)m2 ON m1.mentor_name = m2.mentor_name
AND m1.mentor_id < m2.maxid
LEFT JOIN mf ON m1.mentor_id = mf.mentor_id
WHERE m1.applicant_id =833
AND m2.maxid IS NULL
ORDER BY m1.mentor_id ASC
LIMIT 0 , 30
but this is what happens:
mentor_id applicant_id mentor_count mentor_email mentor_name mentor_pass mentor_name maxid mf_id mentor_id dept contact orgname yrs length sak social char goal resp emomat res others spirit concept comm impact evaluation
/*there is data here but the column for mentor_name onwards is null*/
How can I make it so that the columns for mentor_name onwards is not null, but still displays the latest duplicates as well as those without any duplicates?
try
select * from mentor
where mentor_id in
(
SELECT max(mentor_id) from mf
where applicant_id = 92
group by mentor_id
)
I guess you want to add mentor.application_id = mf.application_id to the JOIN condition
select *
from mentor
inner join
(
SELECT *, max(mentor_id) as maxid
from mf
group by mentor_id
) mf on mentor.mentor_id = mf.maxid AND mentor.application_id = mf.application_id
where applicant_id = 92
Typically you will need an extra condition to get the duplicates. WHERE applicant_id = 92 won't be a duplicate unless there were others with the same applicant_id in the same table.