I have an SQL code.
SELECT DISTINCT SQL_CALC_FOUND_ROWS
sales.code as code,
SUM(CASE WHEN sales.type = 51 THEN sales.amount ELSE 0 END) AS amount,
sales.type as type
FROM sales
Now the thing is that I need to subtract the sales.amount from the total SUM IF the sales.type != 51 AND sales.amount > 0. How could I do it? I guess I need another CASE statement inside the first one after ELSE statement, but I don't know how this works.
As example if the type is not 51 and it has sales.amount bigger than 0, then I should subtract it from the amount.
Thanks.
Where is this select distinct coming from? Use GROUP BY:
SELECT s.code as code,
SUM(CASE WHEN s.type = 51 THEN s.amount ELSE 0 END) AS amount
FROM sales s
GROUP BY s.code;
Then the answer to your question is to change the ELSE clause:
SELECT s.code as code,
SUM(CASE WHEN s.type = 51 THEN s.amount ELSE - s.amount
END) AS amount
FROM sales s
GROUP BY s.code;
Related
new to MySQL..so pls help me out with this basic code..
i have a query something like this...
select weekofyear(id_time),
(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
and it gives correct results as--here
however i want to use sum after case when statement so that I can get total values where BO=1 and group by week of year , so i made following changes-
select weekofyear(id_time),
count(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
sum(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
group by weekofyear(id_time)
but it always returns 0 as output.
Output --here 2
Please help , I don't know what am I doing wrong here.
Thanx !
As others have already said, session variables can be unpredictable (especially when aggregation gets mixed in). That said, it doesn't look like you're using the session variables to carry over values from one row to the next (as is often done), but to just make aliases of sorts for calculations you don't want to repeat.
A better way to handle that is just through subqueries.
SELECT woy, id, Tat1, Tat2, check1, check2
, CASE
WHEN check2=0 THEN (
CASE
WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+10))) THEN 1
ELSE 0
END
)
ELSE (
CASE WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+20))) THEN 1
ELSE 0
END
)
END AS BO
FROM (
SELECT WEEKOFYEAR(id_time) AS woy
, id
, exp1 AS Tat1
, exp2 AS Tat2
, exp3 AS check1
, exp4 AS check2
FROM datb
WHERE cid=18
AND id_time BETWEEN '2019-11-01 06:00:00' AND '2019-11-25 06:00:00'
) AS subQ
;
You can then tweak the above query for aggregation, or use it as a subquery for an aggregating outer query.
I have the following data in mysql table called wallet_txns.
wlt_name wlt_txn_type wlt_txn_amount
A Income 200
A Expense 100
B Income 100
B Income 500
B Expense 200
I trying to get the output of the data like below ( the sum of income and expense in a single row)
Wlt_name Expense Income
A 100 200
B 200 600
I have used the following query, But i am not getting the output as expected, (the income and expense in getting in seperate rows) Please help...
select
wlt_name,
if(wlt_txn_type = 'Expense', wlt_txn_amount, 0) as Expense,
if(wlt_txn_type = 'Income', wlt_txn_amount, 0) as Income
from wallet_txns
;
Maybe you can help this part of the code: SUM(IF(wlt_txn_type = "Income", wlt_txn_amount, 0)) AS IncomeTotal.
You already almost wrote correct query, but you forget about sum and group. Here query:
select
wlt_name,
sum(if(wlt_txn_type = 'Expense', wlt_txn_amount, 0)) as Expense,
sum(if(wlt_txn_type = 'Income', wlt_txn_amount, 0)) as Income
from wallet_txns
group by wlt_name
;
You can use conditional sum and then group by
select
wlt_name,
sum(
case when wlt_rxn_type ='Income' then wlt_txn_amount else 0 end
) as `Income`,
sum(
case when wlt_rxn_type ='Expense' then wlt_txn_amount else 0 end
) as `Expense`
from wallet_txns group by wlt_name;
You could do something like this:
SELECT
Wlt_name,
SUM(CASE WHEN wlt_txn_type='Expense' THEN wlt_txn_amount ELSE 0 END) AS Expense,
SUM(CASE WHEN wlt_txn_type='Income' THEN wlt_txn_amount ELSE 0 END) AS Income
FROM
wallet_txns
GROUP BY
Wlt_name
I'm not a mysql user, but TSQL has little secrets to me. Check for PIVOT - UNPIVOT alternatives on the WWW.
I have made an attendance system for a project, However I'm stuck right now by trying to create a query.
SELECT
COUNT(Students.idStudents) total,
SUM(case when Attendance.status LIKE 'present' then 1 else 0 end) present,
SUM(case when Attendance.status LIKE 'late' then 1 else 0 end) late,
SUM(case when Attendance.status is null then 1 else 0 end) absents
FROM Students, Schools, Tags LEFT JOIN Attendance
ON Attendance.tagCode = Tags.tagCode
WHERE Schools.idSchools = Students.idSchools
AND Tags.idStudents = Students.idStudents
This code works and generates an attendance. However this will show all the dates.
When I add in another line to specify date
AND Attendance.date = DATE(NOW());
It will not show anything..
There's 'Present', 'Late' status for the attendance however if the student's record in that table doesn't exist, it is considered as absent.
How do I do that?
Assuming you're using a case insensitive collation, your purported solution can be rewritten as follows:
SELECT COUNT(p.idStudents) total
, SUM(CASE WHEN a.status = 'present' THEN 1 ELSE 0 END) present -- [or just SUM(a.status = 'present')]
, SUM(CASE WHEN a.status = 'late' THEN 1 ELSE 0 END) late
, SUM(CASE WHEN a.status IS NULL THEN 1 ELSE 0 END) absents
FROM Students p
JOIN Schools s
ON s.idSchools = p.idSchools
JOIN Tags t
ON t.idStudents = p.idStudents
LEFT
JOIN Attendance a
ON a.tagCode = t.tagCode
AND a.date = CURDATE() ;
For next time: Your ERD shows 10 tables, but only 4 feature in this problem. If a table isn't likely to be part of the proposed solution, don't show it. Don't provide pictures. Instead, where possible, provide proper DDLs (and/or an sqlfiddle), TOGETHER WITH THE DESIRED RESULT SET based upon a minimal, but properly representative data set.
Welcome to SO.
Figured it out..
SELECT
COUNT(Students.idStudents) total,
SUM(case when Attendance.status LIKE 'present' then 1 else 0 end) present,
SUM(case when Attendance.status LIKE 'late' then 1 else 0 end) late,
SUM(case when Attendance.status is null then 1 else 0 end) absents
FROM Students, Schools, Tags LEFT JOIN (SELECT * FROM Attendance WHERE Attendance.date = NOW()) AS Attendance
ON Attendance.tagCode = Tags.tagCode
WHERE Schools.idSchools = Students.idSchools
AND Tags.idStudents = Students.idStudents
The problem with the original query was you were asking for students where their attendance was "NOW" where no student was ever now but they are current attending classes. They may have signed in at 8am and you run the query at 10am. You'd need to manipulate the datetime to choose your start time and end time based on the current day.
timestampadd(HOUR, 08, CURDATE()) - this will give you 8am, you'd then query for when attendance.date is greater than or equal to 8am and then potentially less than or equal to 4pm?
I have a sql query for my MYSQL DB and want to limit the results to only 10 sales people instead of 20. I have tried inserting their names inside the query but keep getting error. Also is it possible to rank according to total. The sql query I am using is:
select sales_id, totalbuy, totalsell, totalbuy + totalsell as total from
(select sales_id, SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy,
SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell
from sales_id where sales_id='sales1', GROUP BY sales_id)q
where it says sales1 I have attempted to add the remaining 9 sales_ids' using a comma and single quotes but can't get it to work.
If you want certain sales_id only, use the "IN " clause.
if you wanna only the top 10 total, remove that line and use LIMIT
select sales_id, totalbuy, totalsell, totalbuy + totalsell as total from
(select owner_id, SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy,
SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell
from sales_id
where sales_id in ('sales1', 'sales2', 'sales3', 'sales4')-- if you wanna certain sales_id only
GROUP BY sales_id)q
order by total desc
limit 0, 10;--top 10 by total (bigger first)
I am having a mysql problem I am trying to find both the most current payment value, and, for a particular month (in this query I'm using April). Link to the sqlfillde is here
(case when max(py.pay_date)and month(py.pay_date)= 4 then amount else 0 end) max_pay_april,
This is what I have but it doesn't seem to be working. The most current payment value is: (5, '2012-04-20', 90,) therefore it would be 90 I would really appreciate some help please.
How about this:
select p.name,
v.v_name,
sum(case when Month(py.pay_date) = 4 then amount end) april_amount,
max(case
when month(py.pay_date)= 4
and py.pay_date = (select max(pay_date)
from payment
where month(pay_date) =4 )
then amount else 0 end) max_pay_april,
sum(case
when Month(py.pay_date) = Month(curdate())
then amount end) current_month_amount,
sum(case
when Month(py.pay_date) = Month(curdate())-1
then amount end) previous_month_amount
from persons p
left join vehicle v
on p.id = v.person_veh
left join payment py
on p.id = py.person_id
group by p.name,
v.v_name
see SQL Fiddle with demo