Maybe the title is a bit strange, but I can't seem to find anything about on google.
Question: I have a folder that only contains .ts files and .json files.. Typescript compiles the .ts files and puts it into a separate directory (not as a bundle, just the directory structure 'as-is').
Src /
Workers /
[ModuleA.ts, ModuleA.json],
[ModuleB.ts, ModuleB.json],
[MobuleC.ts, ModuleC.json]
Most of the time I can just require('*.json') and the JSON file will be also placed in to build directory.
But now I have a situation, where importing the JSON will make no sense, because the JSON file gets updated every few seconds and I read the file with fs.readFile('*.json'), so I also don't want it floating around in the v8 cache (through require)
So how do I 'include' a JSON/None-Typescript file into the build, that is not explicitly being importing by either require or import?
For now I just used gulp to copy every .json file in the src folder over to the the respective dist/** folder.
But still find it strange typescript doesn't have something included for it..
Maybe you should checkout --resolveJsonModule, it's a newer feature of typescript.
Related
I'm generating .js.map files so that I can debug my TypeScript code in Chrome. js.map files point to the correct location of the typescript in the "sources" property. sourceRoot is "", and sources is the path to the typescript code from the location of the js file on disk (using outDir in jsconfig.json so that they're placed under the WebContent tree), but the typescript is outside of the web content tree. In the debugger in Chrome, it shows that map files were detected, I see a directory tree in the Sources list in the debugger, it points to the right location on disk, and it contains all of my ts files in the right locations (visually), but opening any one of them shows empty contents. Double-clicking in the .js file in the debugger to set a bp takes me to the empty .ts file. I don't know what details to provide in order to have a chance of getting help on this. All questions welcome.
I had the same problem as you. The solution is simple.
In your build.xml you have excluded somehow these *.ts files or their parent's folder, so the server doesn't load these files. You can find the excluded files and folders inside a tag fileset excludes="" in your build.xml.
Or inside the same fileset includes="" tag you don't include these files.
See my fileset:
I have a TypeScript project I manage with PhpStorm. All the *.ts files are properly recognized as TypeScript files and in my file types setting I have the *.ts file map TypeScript.
All the files? No, one file stubbornly won't be treated as a TypeScript file but is shown as plain text. I have no idea how to mark this one as a TypeScript file.
All the *.ts file have the proper ts icon next to them. This one hasn't.
When I open the rogue .ts file, PhpStorm tells me that there are plugins for that file type, yet if I try to follow that route, all it leads me to is for PhpStorm to try to install the TypoScript plugin for which I have no need at all.
I tried:
renaming file from *.ts to *.txt and back to *.ts;
deleting it within PhpStorm and checking it out via git again;
right clicking the file in the Project pane hoping a setting is there in order to mark it as a TypeScript file, yet no such things seems to exist;
invalidating the cache and restart.
It remains a simple text file without syntax highlighting and other TypeScript code importing this file have the error that the references cannot be found within PhpStorm.
It's a valid TypeScript project though, tsc on command line runs fine.
How can I tell PhpStorm to treat this rogue .ts file as a TypeScript file as well?
Go to Preferences > File Types > Text Files and see if the name of the file is listed there. If it is, delete it from that list.
All my projects contains alot of files with the same name 'file1.php file1.less file1.css file1.min.js file1.js file1.json'
Is there a plugin or a way to group all those files with same basename under eg. file1.php, just like the filewatchers does it.
The grouping relations can only be established when running watchers, so using watchers is the right way to go. It can indeed be a batch script that does nothing - this is the 'Output paths to refresh' option that matters: it should provide a pattern for files that has to be nested. For example, let you have same-named files with .php, .css and .js extensions in some folder, and like to nest the latter 2 in .php file (doesn't make much sense, but it's just an example).
create a .bat/sh file that does nothing (echos some string, etc.)
create a new custom file watcher, set 'php' as file type, your .bat - as a program
specify $FileName$ and $FileDir$ as 'Arguments' and 'Working directory' respectively
set $FileNameWithoutExtension$.css:$FileNameWithoutExtension$.js as 'Output paths to refresh'
Now when you modify your phpfile watcher will be run and nest .js and .css in .php
Currently it is not possible to perform such nesting/grouping manually (excluding File Watchers).. and I personally know no plugin that can do this.
Watch these tickets (star/vote/comment) to get notified on progress:
https://youtrack.jetbrains.com/issue/IDEA-113347
https://youtrack.jetbrains.com/issue/WEB-7635
I'm trying to use Swagger to create API documentation for an API we're building and I've never used it before.
The documentation on Github says that the Resources Listing needs t be at /api-docs and the various resource files need to be at /api-docs/books etc.
This makes naming files and folders very tricky. I think they expect the files to have no file names, rather than having a folder called /api-docs it has to be an extension-less file, then you can't put the resources in an api-docs folder because you can't call the folder that, so they suggest using a folder called /listings.
This folder doesn't appear in the URL structure of your documentation though, it's kind of invisible because you set the baseURL in your resources to the proper path, but it looks like that has to be an absolute path, which is awkward if you want to have it on several servers (local and production).
Maybe I just don't get it but this all seems to be absolutely nuts.
So, I have 2 questions.....
1) Can I give my resource listing file and my resource files a .json extension? This would make sense as it's a JSON file.
2) Can I use a relative path to the resource listing file in the baseURL in my resource files?
Ideally, my file structure would be flatter, like this...
/api-docs
resources.json
books.json
films.json
Is Swagger flexible enough to do this?
It's an IIS server if that makes any difference (if the solution requires routing for example).
I was able to put model files into a folder under the web root and could reference them like this.
$ref: '/models/model.yml#/MyObject'
Relative paths also worked without a leading slash.
$ref: 'models/model.yml#/MyObject'
Inside the model.yml, I can reference other objects int eh same file like this
$ref: '#/MyObject2'.
However, I could only get the main swagger file to import model files. I could not get one model file to cross-reference another model file.
I was using a Tomcat web server but the principle will be the same.
I am creating a Zip file from a folder (and subfolders). it works fine and creates a new .zip file also but I am having an issue while using glob.glob. It is reading all files from the desired folder (source folder) and writing to the new zip file but the problem is that it is, however, adding subdirectories, but not adding files form the subdirectories.
I am giving user an option to select the filename and path as well as filetype also (Zip or Tar). I don;t get any problem while creating .tar.gz file, but when use creates .zip file, this problem comes across.
Here is my code:
for name in (Source_Dir):
for name in glob.glob("/path/to/source/dir/*" ):
myZip.write(name, os.path.basename(name), zipfile.ZIP_DEFLATED)
myZip.close()
Also, if I use code below:
for dirpath, dirnames, filenames in os.walk(Source_Dir):
myZip.write(os.path.join(dirpath, filename) os.path.basename(filename))
myZip.close()
Now the 2nd code taks all files even if it inside the folder/ subfolders, creates a new .zip file and write to it without any directory strucure. It even does not take dir structure for main folder and simply write all files from main dir or subdir to that .zip file.
Can anyone please help me or suggest me. I would prefer glob.glob rather than the 2nd option to use.
Thanks in advance.
Regards,
Akash
Glob by design does not expand into subdirectories. It follows UNIX style path rules and expansions see the documentation for fnmatch for more information. If you want to get at the subdirectories you need to add it to the path. This example will get everything at one level down.
for name in (Source_Dir):
for name in glob.glob("/path/to/source/dir/*/*" ):
myZip.write(name, os.path.basename(name), zipfile.ZIP_DEFLATED)
myZip.close()
Doug Hellman has an excellent discussion here. If you are not using the pattern features of glob (like *.txt for all text files or *[0-9].txt for all text files that have a number before the extension) then I think your os.walk solution is better