All my projects contains alot of files with the same name 'file1.php file1.less file1.css file1.min.js file1.js file1.json'
Is there a plugin or a way to group all those files with same basename under eg. file1.php, just like the filewatchers does it.
The grouping relations can only be established when running watchers, so using watchers is the right way to go. It can indeed be a batch script that does nothing - this is the 'Output paths to refresh' option that matters: it should provide a pattern for files that has to be nested. For example, let you have same-named files with .php, .css and .js extensions in some folder, and like to nest the latter 2 in .php file (doesn't make much sense, but it's just an example).
create a .bat/sh file that does nothing (echos some string, etc.)
create a new custom file watcher, set 'php' as file type, your .bat - as a program
specify $FileName$ and $FileDir$ as 'Arguments' and 'Working directory' respectively
set $FileNameWithoutExtension$.css:$FileNameWithoutExtension$.js as 'Output paths to refresh'
Now when you modify your phpfile watcher will be run and nest .js and .css in .php
Currently it is not possible to perform such nesting/grouping manually (excluding File Watchers).. and I personally know no plugin that can do this.
Watch these tickets (star/vote/comment) to get notified on progress:
https://youtrack.jetbrains.com/issue/IDEA-113347
https://youtrack.jetbrains.com/issue/WEB-7635
Related
I want to find files that includes some keyword and copy it to other folder.
So I need two features.
Find files by keyword and list it at "file" type value.
copy the file to different directory.
But Google drive supports same folder name so I don't know how to targeting folder by name. And I want copy the file only if there is not file has same name. Because I'll run this script every 5 minutes and if I don't set about that, there are many same name files to target directory.
How can I do this?
AFAIK, the only supported methods that you can use to get files in Class DriveApp are:
getFileById(id)
getFiles()
getFilesByName(name)
getFilesByType(mimeType)
Then, to make a copy to other folder, you can use the following methods that are given in Class File
makeCopy(destination)
makeCopy(name, destination)
Lastly, the suggested solutions given in this SO post might also help.
Maybe the title is a bit strange, but I can't seem to find anything about on google.
Question: I have a folder that only contains .ts files and .json files.. Typescript compiles the .ts files and puts it into a separate directory (not as a bundle, just the directory structure 'as-is').
Src /
Workers /
[ModuleA.ts, ModuleA.json],
[ModuleB.ts, ModuleB.json],
[MobuleC.ts, ModuleC.json]
Most of the time I can just require('*.json') and the JSON file will be also placed in to build directory.
But now I have a situation, where importing the JSON will make no sense, because the JSON file gets updated every few seconds and I read the file with fs.readFile('*.json'), so I also don't want it floating around in the v8 cache (through require)
So how do I 'include' a JSON/None-Typescript file into the build, that is not explicitly being importing by either require or import?
For now I just used gulp to copy every .json file in the src folder over to the the respective dist/** folder.
But still find it strange typescript doesn't have something included for it..
Maybe you should checkout --resolveJsonModule, it's a newer feature of typescript.
I need to visit a folder and all of its children with SSIS (SQL Server Integration Services). At the moment by setting the folder path into a variable after reading it, I able to loop through all the .txt files of the current folder and fill a pre-generated (with head info) xml file.
What I would need now is to be able to create one per each accessed folder, a new xml file (the beginning content will be always the same). Once I would be able to create it, as first action once a new folder is accessed, I can then simply apply the logic I developed so far.
However I am blocked at the moment, since within the loop where i read the files (with their full path) I cannot find a way to express "create the xml file if the accessed folder is new".
Assuming I understand the problem, you need to walk the entirety of a directory structure and for each folder you find, you need to create a base XML file. Then for each text file you find in that folder, you will perform some operation on the XML file. The trick being how do you only create the XML file once.
I would envision a process like this.
A script task that makes use of the System.IO.GetDirectories to populate a variable (directoryXML> that contains the folder structure, something like
<Dir>
<D>C:\ssisdata</D>
<D>C:\ssisdata\a</D>
<D>C:\ssidata\a\b</D>
</Dir>
Use a Foreach Nodelist Enumerator to shred that XML out into a variable (currentDirecotry).
You'd perform your one-time task of creating the XML file in currentDirectory.
Further using the currentDirectory variable as an expression on the Foreach File Enumerator (assign to Directory with a FileSpec of *.txt) you can then perform your task on all the files meeting that specification. Do not check the traverse subfolder option as that will not give the desired results.
This is a fairly high level approach to the problem as I'm assuming you have some familiarity with SSIS but the approach should be sound. Let me know if you have any particular sticking points.
I'm trying to publish webpage using org-mode. Two questions:
Is there a way to "sync" the org-mode files in the base-directory and the html files in the publishing-directory? Specifically, if I delete an org file in the base-directory, can I get org-publish-html to delete the corresponding file in the html directory also?
If I have pages within subdirectories, how can I specify a single .css file in the root directory to be used for the style sheet? For instance, my directory structure is as follows:
public_html/
css/
mystyle.css
index.html
subdir/
index.html
With the following specifications in org-publish-project-alist (this is just a subset) --
:publishing-directory "public_html"
:style "<link rel=\"stylesheet\" href=\"css/mystyle.css\" type=\"text/css\"/>"
mystyle.css is used by public_html/index.html but not by public_html/subdir/index.html. Is there a simple remedy to this (I want the style sheet to be used by both/all files in subdirectories)?
Thanks much ~
There is no straightforward way of doing this. Org-mode doesn't know (or care) about the location to which it is publishing - it just sends things there and makes sure the correct directory structure exists. There is a hook in the publishing process that gets called after the files have been pushed to their published location. This is controlled by setting the :completion-function property in your org-publish-project-alist. You could use this hook to write a function that compares the *.org files in your base-dir and subdirectories to the accompanying *.html published files, and remove those *.html files that don't have an accompanying *.org file.
I suspect this will be most easily accomplished by making your Lisp completion-function call a shell script that removes the necessary files. If you are doing something fancy with the :include, :exclude, or :base-extension properties, you'll likely want your completion-function to grab the pertinent information from the plist and then pass them to your shell script. This org-mode page has an example completion-function that shows how to get property values for the org-publish-project-alist. You would then need to pass them to your shell script.
There are several ways to do this. Perhaps the simplest is to just override the default style sheet in each file with a line such as:
#+STYLE: <link rel="stylesheet" type="text/css" href="../stylesheet.css" />
for your first level of subdirectory files, and keep adding ../ as you get deeper in the directory structure.
Another possibility is generate generic template files for each level within the directory tree. This org-mode page gives a nice example of how to set this up.
Lastly, another option is to use the :preparation-function property of org-publish-project-alist to define a function that will automatically change the style file for each file. Again, this is probably best done by having the Lisp preparation-function call a shell script to parse the files. I could imagine doing this with the Unix sed program to find a regular expression denoted something like href="#MYLOC#/stylesheet.css" /> and substitute the stuff between #'s with the appropriate level within the directory tree. This seems like overkill, given the other options.
I am creating a Zip file from a folder (and subfolders). it works fine and creates a new .zip file also but I am having an issue while using glob.glob. It is reading all files from the desired folder (source folder) and writing to the new zip file but the problem is that it is, however, adding subdirectories, but not adding files form the subdirectories.
I am giving user an option to select the filename and path as well as filetype also (Zip or Tar). I don;t get any problem while creating .tar.gz file, but when use creates .zip file, this problem comes across.
Here is my code:
for name in (Source_Dir):
for name in glob.glob("/path/to/source/dir/*" ):
myZip.write(name, os.path.basename(name), zipfile.ZIP_DEFLATED)
myZip.close()
Also, if I use code below:
for dirpath, dirnames, filenames in os.walk(Source_Dir):
myZip.write(os.path.join(dirpath, filename) os.path.basename(filename))
myZip.close()
Now the 2nd code taks all files even if it inside the folder/ subfolders, creates a new .zip file and write to it without any directory strucure. It even does not take dir structure for main folder and simply write all files from main dir or subdir to that .zip file.
Can anyone please help me or suggest me. I would prefer glob.glob rather than the 2nd option to use.
Thanks in advance.
Regards,
Akash
Glob by design does not expand into subdirectories. It follows UNIX style path rules and expansions see the documentation for fnmatch for more information. If you want to get at the subdirectories you need to add it to the path. This example will get everything at one level down.
for name in (Source_Dir):
for name in glob.glob("/path/to/source/dir/*/*" ):
myZip.write(name, os.path.basename(name), zipfile.ZIP_DEFLATED)
myZip.close()
Doug Hellman has an excellent discussion here. If you are not using the pattern features of glob (like *.txt for all text files or *[0-9].txt for all text files that have a number before the extension) then I think your os.walk solution is better