I'm using MySQL to store my data. I'm recorded dates with different offset according to each timezone. What is important on those dates are only "effective" time. Here is an example:
date1 = "Thu, 27 Oct 2016 07:00:00 CEST +02:00"
# I want to get 700
date2 = "Thu, 27 Oct 2016 22:00:00 CEST +02:00"
# I want to get 2200
I would like to get these values to compare them with my current time. Then if it's currently "2016-11-17 10:12:00 +0100", I would like to compare on a where clause:
"1012" > "2200"
# or
"1012" > "700"
Here is a fake record value:
# my_table
# | id | my_hour
# | XX | "Thu, 27 Oct 2016 07:00:00 CEST +02:00"
# | XY | "Thu, 27 Oct 2016 22:00:00 CEST +11:00"
Here is my code:
hour = Time.zone.now
# "2016-11-18 21:10:00 +0100"
where("CAST(DATE_FORMAT(my_hour,'%H%i') AS UNSIGNED) < ?", hour.strftime("%H%M").to_i)
# => Get XX record?
Use strftime to format date in Rails.
hour = Time.zone.now
MyTable.where("cast(strftime('%H%M', my_hour) as int) < ?", hour.strftime("%H%M").to_i)
here MyTable is your Model, my_hour is your date column and hour is current time.
Related
I have a script called "main.ksh" which returns "output.txt" file and I am sending that file via mail (list contains 50+ records, I just give 3 records for example).
mail output I am getting is: (10 cols)
DATE FEED FILE_NAME JOB_NAME SCHEDULED TIME SIZE COUNT STATUS
Dec 17 INVEST iai guxmow080 TUE-SAT 02:03 0.4248 4031 On_Time
Dec 17 SECURITIES amltxn gdcpl3392 TUE-SAT 02:03 0.0015 9 Delayed
Dec 17 CONNECTED amlbene gdcpl3392 TUE-SAT 02:03 0.0001 1 No_Records
output with perfect coloring: (6 cols only)
DATE FEED FILE_NAME JOB_NAME SCHEDULED TIME SIZE COUNT STATUS
Dec 17 INVEST iai guxmow080 On_Time(green color)
Dec 17 SECURITIES amltxn gdcpl3392 Delayed(red color)
Dec 17 CONNECTED amlbene gdcpl3392 No_Records(yellow color)
I am implementing coloring for Delayed, On_Time and No_Records field and I wrote below script which gives me bottom output.
awk 'BEGIN {
print "<html>" \
"<body bgcolor=\"#333\" text=\"#f3f3f3\">" \
"<pre>"
}
NR == 1 { print $0 }
NR > 1 {
if ($NF == "Delayed") color="red"
else if ($NF == "On_time") color="green"
else if ($NF == "No_records") color="yellow"
else color="#003abc"
Dummy=$0
sub("[^ ]+$","",Dummy)
print Dummy "<span style=\"color:" color (bold ? ";font-weight:bold" : "")(size ? ";font-size:size" : "") (italic ? ";font-style:italic" : "") "\">" $NF "</span>"
}
END {
print "</pre>" \
"</body>" \
"</html>"
}
' output.txt > output.html
There are 4 columns are skipped automatically.
| date | feed_names | file_names | job_names | scheduled_time| timestamp| size| count| status |
Dec 19 ISS_BENEFICIAL_OWNERS_FEED amlcpbo_iss_20161219.txt gdcpl3392_uxmow080_ori_isz_dat WEEK_DAYS 00:03 9.3734 34758 On_Time
Dec 19 ISS_INVESTORS_FEED amlinvest_iss_20161219.txt gdcpl3392_uxmow080_ori_isz_dat WEEK_DAYS 00:01 0.0283 82 On_Time
Dec 19 ISS_TRANSACTIONS_FEED amltran_iss_1_20161219.txt gdcpl3392_uxmow080_ori_isz_dat WEEK_DAYS 00:12 14.022 36532 DELAYED
Dec 19 ISS_TRANSACTIONS_FEED amltran_iss_5_20161219.txt gdcpl3392_uxmow080_ori_isz_dat WEEK_DAYS 00:23 0.0010 3 DELAYED
Dec 19 IBS_CUSTOMER_FEED ibscust_aml_***_20161219.txt gdcpl3392_uxmow080_ori_sfp_ibc WEEK_DAYS (11 _out_of_11) -NA- ARRIVED
Dec 19 IBS_DDA_NOSTRO_ACCOUNT_FEED ibsacct_aml_***_20161219.txt gdcpl3392_uxmow080_ori_sfp_ibc WEEK_DAYS (44 _out_of_44) -NA- ARRIVED
Dec 19 GP__TRANSACTIONS_FEED amltrans__20161219.txt gdcpl3392_uxmow080_ori_sfp_glo WEEK_DAYS (3 _out_of_30) -NA- ARRIVED
But when I am trying to print in a sequential order by using below command
awk '{printf("%-5s%s\t%-33s%-35s%-39s%s\t%s%-3s\t%s\t%s\n", $1,$2,$3,$4,$5,$6,$7,$8,$9,$10)}' output.txt, I am getting the output in a sequential format
but 4 cols are skipped. Kindly suggest!!!
| date | feed_names | file_names | job_names | scheduled_time| timestamp| size| count| status |
Dec 19 ISS_BENEFICIAL_OWNERS_FEED amlcpbo_iss_20161219.txt gdcpl3392_uxmow080_ori_isz_dat On_Time
Dec 19 ISS_INVESTORS_FEED amlinvest_iss_20161219.txt gdcpl3392_uxmow080_ori_isz_dat On_Time
Dec 19 ISS_TRANSACTIONS_FEED amltran_iss_1_20161219.txt gdcpl3392_uxmow080_ori_isz_dat DELAYED
Dec 19 ISS_TRANSACTIONS_FEED amltran_iss_5_20161219.txt gdcpl3392_uxmow080_ori_isz_dat DELAYED
Dec 19 IBS_CUSTOMER_FEED ibscust_aml_***_20161219.txt gdcpl3392_uxmow080_ori_sfp_ibc ARRIVED
Dec 19 IBS_DDA_NOSTRO_ACCOUNT_FEED ibsacct_aml_***_20161219.txt gdcpl3392_uxmow080_ori_sfp_ibc ARRIVED
Dec 19 GP__TRANSACTIONS_FEED amltrans__20161219.txt gdcpl3392_uxmow080_ori_sfp_glo YET_TO_RECEIVE
I have used this query to retrieve the dates for one particular user's approved leaves -
LeaveRequest.where(user_id: 6).where(status: 1).pluck(:from_date, :to_date)
and I'm getting this array as result -
[[Mon, 12 Sep 2016, Fri, 16 Sep 2016], [Tue, 06 Sep 2016, Tue, 06 Sep 2016], [Thu, 01 Sep 2016, Fri, 02 Sep 2016], [Tue, 30 Aug 2016, Wed, 31 Aug 2016]]
what I want is to fetch all the dates as well as the dates between 12 Sep 2016 and 16 Sep, 2016 (13th 14th and 15th).
I am assuming you mean something like this
require 'date'
#This is to simulate your current Array
current_array = 5.times.map {|n [Date.new(2016,n+1,1).<<(1),Date.new(2016,n+1,1)]}
#map the 2 dates to a Range
new_array = current_array.map{|start_date,end_date| (start_date..end_date)}
new_array.first.class
#=> Range
Calling to_a on the Range will blow it out into all the dates between start_date and end_date
With a rails you could do something like
class LeaveRequest
def self.user_requested_ranges(user_id, status_id)
scoped.
where(user_id: user_id, status: status_id).
pluck(:from_date, :to_date).
map do |from_date, to_date|
#optionally to output the full Array in each Range you could use
#(from_date..to_date).to_a
(from_date..to_date)
end
end
end
Then call as
LeaveRequest.user_requested_ranges(6,1)
I am using Rails 4. I've read 2 records(b1 and b2) from database. Both them have a column called build_start_time, which is defined as datetime type in Mysql. The build_start_time between b1 record and b2 record are like this:
2.0.0-p643 :021 > b1.build_start_time
=> Tue, 12 Aug 2014 18:23:31 UTC +00:00
2.0.0-p643 :012 > b2.build_start_time
=> Fri, 15 Aug 2014 10:07:18 UTC +00:00
How do I calculate the duration between them in Rails ? Does anybody have an idea?
The result should be something like:
b2.build_start_time - b1.build_start_time = 2 days 15 hours 53 minutes 47 seconds
Is this possible?
Assuming you can tolerate your answer being off by less than a second you could try using the to_i and ago methods:
def datetime_diff(datetime1, datetime2)
res = datetime1 <=> datetime2
if res == 0
# order doesn't matter in this case
min = datetime1
max = datetime2
elif res < 0
min = datetime1
max = datetime2
else
min = datetime2
max = datetime1
end
max.ago(min.to_i) # min.to_i returns min in seconds since the epoch
end
You figure out which time came first then you return the later of the two times x seconds ago, where x is the earlier time in seconds since the epoch. See http://api.rubyonrails.org/classes/DateTime.html#method-i-3C-3D-3E
I have this logic but I cant figure out what to do to come up with the results. I want to achieve the results below, the idea is (Ex. month of October 2014), normally it has 5 weeks. If there is a 5th week and days is greater than 3 then consider whole week in the next month else add it to 4th week.
Input:
date range
from: 10-01-2014
to: 11-30-2014
Sample Output:
Date Customer week# Dates covered
10-01-2014 Cust01 1 Oct 01 - Oct 11, 2014
10-08-2014 Cust02 1 Oct 01 - Oct 11, 2014
10-17-2014 Cust02 2 Oct 12 - Oct 18, 2014
10-25-2014 Cust03 3 Oct 19 - Oct 25, 2014
10-31-2014 Cust01 4 Oct 26 - Oct 31, 2014
11-01-2014 Cust01 1 Nov 01 - Nov 08, 2014
11-28-2014 Cust02 4 Nov 23 - Nov 30, 2014
11-30-2014 Cust05 4 Nov 23 - Nov 30, 2014
Thanks
Use datepart(ww,[date]) to get week number in a year, then compare the week number by the begin date of a month.
Below is the detail approach to calculate for one date:
declare #dt date, #month_begin date, #month_end date, #week_of_month int
set #dt='20141031'
set #month_begin = convert(date,(convert(char(6),#dt,112)+'01'))
set #month_end = dateadd(day, -1, dateadd(month,1,#month_begin))
set #week_of_month = datepart(ww,#dt) - datepart(ww,convert(date,(convert(char(6),#dt,112)+'01'))) + 1
select
case when #week_of_month > 4 and datepart(dw,#month_end)>3
then 1
else #week_of_month
end as week,
case when #week_of_month > 4 and datepart(dw,#month_end)>3
then datepart(month,dateadd(month,1,#dt))
else datepart(month,#dt)
end as month
I want to create a function for a calender programm, that does the following:
proceed :: Day -> Int -> Day
> proceed Mon 9
Wed
The function proceed should tell me, what weekday it is in 9 days, if today is Monday.
Now I try this:
data Day = Mon | Tue | Wed | Thu | Fri | Sat | Sun deriving Show
next :: Day -> Day
next Mon = Tue
next Tue = Wed
next Wed = Thu
next Thu = Fri
next Fri = Sat
next Sat = Sun
next Sun = Mon
proceed :: Day -> Int -> Day
proceed d a = if a==0 then next d
else proceed (next d) (a-1)
I try :
proceed Mon 9
Thu
But that's wrong, the right answear is Wed!!!!!!!
I don't know where I've made the mistake.
Thanks to bheklilr
if a == 0 then d else proceed (next d) (a-1)
It was only an off by one error!