How to Display 4week per month with condition in sql - mysql

Question

I have this logic but I cant figure out what to do to come up with the results. I want to achieve the results below, the idea is (Ex. month of October 2014), normally it has 5 weeks. If there is a 5th week and days is greater than 3 then consider whole week in the next month else add it to 4th week.
Input:
date range
from: 10-01-2014
to: 11-30-2014
Sample Output:
Date Customer week# Dates covered
10-01-2014 Cust01 1 Oct 01 - Oct 11, 2014
10-08-2014 Cust02 1 Oct 01 - Oct 11, 2014
10-17-2014 Cust02 2 Oct 12 - Oct 18, 2014
10-25-2014 Cust03 3 Oct 19 - Oct 25, 2014
10-31-2014 Cust01 4 Oct 26 - Oct 31, 2014
11-01-2014 Cust01 1 Nov 01 - Nov 08, 2014
11-28-2014 Cust02 4 Nov 23 - Nov 30, 2014
11-30-2014 Cust05 4 Nov 23 - Nov 30, 2014
Thanks

Answer 1

Use datepart(ww,[date]) to get week number in a year, then compare the week number by the begin date of a month.
Below is the detail approach to calculate for one date:
declare #dt date, #month_begin date, #month_end date, #week_of_month int
set #dt='20141031'
set #month_begin = convert(date,(convert(char(6),#dt,112)+'01'))
set #month_end = dateadd(day, -1, dateadd(month,1,#month_begin))
set #week_of_month = datepart(ww,#dt) - datepart(ww,convert(date,(convert(char(6),#dt,112)+'01'))) + 1
select
case when #week_of_month > 4 and datepart(dw,#month_end)>3
then 1
else #week_of_month
end as week,
case when #week_of_month > 4 and datepart(dw,#month_end)>3
then datepart(month,dateadd(month,1,#dt))
else datepart(month,#dt)
end as month