I followed the first answer on this question but i have some problems with my sql query. I don´t get any result.
What error i made ?
How can i set CURDATE always on the first day of the month ?
SELECT DATE_FORMAT(`date`, '%Y-%m-%d') , `price`
FROM `sales`
WHERE `id` = :id
AND (`date` BETWEEN CURDATE() - INTERVAL 30 DAY AND CURDATE())
Edit Whole code:
$verkaufmonat3 = 0;
$verkaufmonatanzahl2 = 0;
$verkaufmonat4 = array();
$sqluser5 = $X['dbh']->prepare("SELECT DATE_FORMAT(`date`, '%Y-%m-%d') , `preis` FROM `verkauf` WHERE `vertreterid` = :id AND (`date` BETWEEN CURDATE(), '%Y-%m-01' - INTERVAL 60 DAY AND CURDATE(), '%Y-%m-01')");
$sqluser5->execute(array(
':id'=>$_SESSION['id']
));
$verkaufmonatanzahl2 = $sqluser5->rowCount();
$verkaufmonat4 = $sqluser5->fetchAll();
for ($a = 0; $a <= $verkaufmonatanzahl2; $a++) {
$verkaufmonat3 += $verkaufmonat2[$a]['preis'];
}
In my database i have a sale on the 28.10.2016 wich has for ex. a value of 50 eur. So my $verkaufmonat3 should be 50 but it isn´t, it´s 0.
Your question isnt clear but to get the first day of current month then you use
SELECT DATE_FORMAT(CURDATE() , '%Y-%m-1')
So if you want the previous month data try
SELECT
DATE_FORMAT(CURDATE() , '%Y-%m-1') - INTERVAL 1 MONTH as first_day,
DATE_FORMAT(CURDATE() , '%Y-%m-1') - INTERVAL 1 DAY as last_day
MEANING
WHERE `date` BETWEEN DATE_FORMAT(CURDATE() , '%Y-%m-1') - INTERVAL 1 MONTH
AND DATE_FORMAT(CURDATE() , '%Y-%m-1') - INTERVAL 1 DAY
Related
i have this date 2021-08-19,
i want to select by month all my data from my table where dateC = ( extract month).
EXEMPLE QUERY
SELECT * FROM MYTABLE WHERE dateC= extract month "08" from(2021-08-19)
You can use:
where year(dateC) = year('2021-08-19') and
month(dateC) = month('2021-08-19')
If you just want the month regardless of year, then:
where month(dateC) = month('2021-08-19')
Or
where date_format(dateC, '%Y%m') = date_format('2021-08-19', '%Y%m')
Neither of these are index friendly. That requires a little more work. Let met call your date #date:
where dateC >= #date + interval (1 - day(#date)) day and
dateC < (#date + interval (1 - day(#date)) day) + interval 1 month
Note: all of the above work if there is a time component. If dateC is really a date with no time component, then:
where dateC > last_day(#date - interval 1 month) and
dateC <= last_day(#date)
I'm trying to make a query where one of the fields shows the units of the orders table that are planned tomorrow, but if tomorrow is Sunday it should be Monday.
I have the table orders and the table format.
Orders table:
id_order, order_date, units
Format table:
id_format, format_type
My query initially is this:
SELECT format_type, units, DATE (NOW () + INTERVAL 1 DAY) as Tomorrow
FROM orders Join format on orders.id_format = format.id_format
WHERE DATE (date_delivery) = DATE (NOW () + INTERVAL 1 DAY)
But it would have to be something similar like this:
SELECT format_type, units, DATE (NOW () + INTERVAL 1 DAY) as Tomorrow
FROM orders Join format on orders.id_format = format.id_format
WHERE (
CASE
WHEN DAYNAME (date) = "Sunday" THEN DATE (order_date) = DATE (NOW () + INTERVAL 2 DAY)
ELSE DATE (order_date) = DATE (NOW () + INTERVAL 1 DAY)
END;
_____EDIT_____
This is the result I wanted
SELECT format.format_type, units, DATE(NOW()) as TODAY
FROM orders Join format on orders.id_format = format.id_formatopeso
WHERE
CASE
WHEN WEEKDAY(now()) = 6 then DATE(order_date) = DATE(NOW() + INTERVAL 2 DAY)
ELSE DATE(order_date) = DATE(NOW() + INTERVAL 1 DAY)
END;
Yuu can simply select what you have in where
SELECT format_type, units,
CASE
WHEN WEEKDAY(date) = 6
then DATE_ADD(curdate(), INTERVAL +2 DAY)
else DATE_ADD(curdate(), INTERVAL +1 DAY)
END as tomorrow_with_sunday_check,
DATE_ADD(curdate(), INTERVAL +1 DAY) as Tomorrow
FROM orders Join format on orders.id_format = format.id_format
I am trying to retrieve all data from table in a specific month, my date format in the database table is 2016-06-19 I am need to find with the respect of a selected date, like if I select 2016-05-22
it will retrieve 2016-05-07 to 2016-06-06 interval values from the table.
And also to all the values in this month which is 05 month, I am using mysqli with PHP. I have tried using this query
SELECT * FROM t_tenancy_details WHERE
agreement_date >= DATE_FORMAT( CURRENT_DATE - INTERVAL 1 MONTH, '%Y/%m/01' )AND
agreement_date < DATE_FORMAT( CURRENT_DATE, '%Y/%m/01' )
This works fine for the running month, But problem is that if I select a previous month it does not work.
It's not very clear from the question as to what is needed. Based on the 2 requirements that I could understand:
Get everything surrounding the given date (i.e. +-15 days from the given date):
SELECT *
FROM t_tenancy_details
WHERE agreement_date >= DATE_SUB(#d, INTERVAL 15 DAY)
AND agreement_date <= DATE_ADD(#d, INTERVAL 15 DAY);
Get all the records where the month is same as the month in the given date:
SELECT *
FROM t_tenancy_details
WHERE MONTH(agreement_date) = MONTH(#d)
AND YEAR(agreement_date) = YEAR(#d);
where #d is the input date, in your case - CURRENT_DATE
Should be this
SELECT * FROM t_tenancy_details
WHERE (YEAR(t_tenancy_details) => YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(agreement_date) => MONTH(CURRENT_DATE - INTERVAL 1 MONTH))
AND (YEAR(t_tenancy_details) <= YEAR(CURRENT_DATE)
AND MONTH(agreement_date) <= MONTH(CURRENT_DATE))
I need to select data from MySQL database between the 1st day of the current month and current day.
select*from table_name
where date between "1st day of current month" and "current day"
Can someone provide working example of this query?
select * from table_name
where (date between DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )
Or better :
select * from table_name
where (date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
I was looking for a similar query where I needed to use the first day of a month in my query.
The last_day function didn't work for me but DAYOFMONTH came in handy.
So if anyone is looking for the same issue, the following code returns the date for first day of the current month.
SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);
Comparing a date column with the first day of the month :
select * from table_name where date between
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE
select * from table_name
where `date` between curdate() - dayofmonth(curdate()) + 1
and curdate()
SQLFiddle example
I have used the following query. It has worked great for me in the past.
select date(now()) - interval day(now()) day + interval 1 day
try this :
SET #StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET #EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= #StartDate and date < #EndDate);
Complete solution for mysql current month and current year, which makes use of indexing properly as well :)
-- Current month
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
-- Current year
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
select * from table
where date between
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;
select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
and curdate();
I found myself here after needing this same query for some Business Intelligence Queries I'm running on an e-commerce store. I wanted to add my solution as it may be helpful to others.
set #firstOfLastLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)))-1 DAY);
set #lastOfLastLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH));
set #firstOfLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)))-1 DAY);
set #lastOfLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH));
set #firstOfMonth = DATE_ADD(#lastOfLastMonth, INTERVAL 1 DAY);
set #today = CURRENT_DATE;
Today is 2019-10-08 so the output looks like
#firstOfLastLastMonth = '2019-08-01'
#lastOfLastLastMonth = '2019-08-31'
#firstOfLastMonth = '2019-09-01'
#lastOfLastMonth = '2019-09-30'
#firstOfMonth = '2019-10-01'
#today = '2019-10-08'
A less orthodox approach might be
SELECT * FROM table_name
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
AND table_name.date <= CURDATE();
as a date being between the first of a month and now is equivalent to a date being in this month, and before now. I do feel that this is a bit easier on the eyes than some other approaches, though.
SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;
I had some what similar requirement - to find first day of the month but based on year end month selected by user in their profile page.
Problem statement - find all the txns done by the user in his/her financial year. Financial year is determined using year end month value where month can be any valid month - 1 for Jan, 2 for Feb, 3 for Mar,....12 for Dec.
For some clients financial year ends on March and some observe it on December.
Scenarios - (Today is `08 Aug, 2018`)
1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
2. If `financial year` ends on `December` then query should return `01 January 2018`.
3. If `financial year` ends on `March` then query should return `01 April 2018`.
4. If `financial year` ends on `September` then query should return `01 October 2017`.
And, finally below is the query. -
select #date := (case when ? >= month(now())
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)
where ? is year end month (values from 1 to 12).
The key here is to get the first day of the month. For that, there are several options. In terms of performance, our tests show that there isn't a significant difference between them - we wrote a whole blog article on the topic. Our findings show that what really matters is whether you need the result to be VARCHAR, DATETIME, or DATE.
The fastest solution to the real problem of getting the first day of the month returns VARCHAR:
SELECT CONCAT(LEFT(CURRENT_DATE, 7), '-01') AS first_day_of_month;
The second fastest solution gives a DATETIME result - this runs about 3x slower than the previous:
SELECT TIMESTAMP(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AS first_day_of_month;
The slowest solutions return DATE objects. Don't believe me? Run this SQL Fiddle and see for yourself 😊
In your case, since you need to compare the value with other DATE values in your table, it doesn't really matter what methodology you use because MySQL will do the conversion implicitly even if your formula doesn't return a DATE object.
So really, take your pick. Which is most readable for you? I'd pick the first since it's the shortest and arguably the simplest:
SELECT * FROM table_name
WHERE date BETWEEN CONCAT(LEFT(CURRENT_DATE, 7), '-01') AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE) - 1) DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE)) DAY + INTERVAL 1 DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE_FORMAT(CURRENT_DATE,'%Y-%m-01') AND CURDATE;
I used this one
select DATE_ADD(DATE_SUB(LAST_DAY(now()), INTERVAL 1 MONTH),INTERVAL 1 day) first_day
,LAST_DAY(now()) last_day, date(now()) today_day
All the responses here have been way too complex. You know that the first of the current month is the current date but with 01 as the date. You can just use YEAR() and MONTH() to build the month date by inputting the NOW() method.
Here's the solution:
select * from table_name
where date between CONCAT_WS('-', YEAR( NOW() ), MONTH( NOW() ), '01') and DATE( NOW() )
CONCAT_WS() joins a series of strings with a separator (a dash in this case).
So if today is 2020-08-28, YEAR( NOW() ) = '2020' and MONTH( NOW() ) = '08' and then you just need to append '01' at the end.
Voila!
Get first date and last date from month and year.
select LAST_DAY(CONCAT(year,'.',month,'.','01')) as registerDate from user;
select date_add(date_add(LAST_DAY(end_date),interval 1 DAY),interval -1 MONTH) AS closingDate from user;
SET #date:='2012-07-11';
SELECT date_add(date_add(LAST_DAY(#date),interval 1 DAY),
interval -1 MONTH) AS first_day
I need to select all rows in my database that were created last month.
For example, if the current month is January, then I want to return all rows that were created in December, if the month is February, then I want to return all rows that were created in January. I have a date_created column in my database that lists the date created in this format: 2007-06-05 14:50:17.
SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)
Here's another alternative. Assuming you have an indexed DATE or DATETIME type field, this should use the index as the formatted dates will be type converted before the index is used. You should then see a range query rather than an index query when viewed with EXPLAIN.
SELECT
*
FROM
table
WHERE
date_created >= DATE_FORMAT( CURRENT_DATE - INTERVAL 1 MONTH, '%Y/%m/01' )
AND
date_created < DATE_FORMAT( CURRENT_DATE, '%Y/%m/01' )
If there are no future dates ...
SELECT *
FROM table_name
WHERE date_created > (NOW() - INTERVAL 1 MONTH);
Tested.
Alternatively to hobodave's answer
SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)
You could achieve the same with EXTRACT, using YEAR_MONTH as unit, thus you wouldn't need the AND, like so:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM date_created) = EXTRACT(YEAR_MONTH FROM CURDATE() - INTERVAL
1 MONTH)
SELECT *
FROM yourtable
where DATE_FORMAT(date_created, '%Y-%m') = date_format(DATE_SUB(curdate(), INTERVAL 1 month),'%Y-%m')
This should return all the records from the previous calendar month, as opposed to the records for the last 30 or 31 days.
Even though the answer for this question has been selected already, however, I believe the simplest query will be
SELECT *
FROM table
WHERE
date_created BETWEEN (CURRENT_DATE() - INTERVAL 1 MONTH) AND CURRENT_DATE();
WHERE created_date >= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 DAY)
AND created_date <= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1 MONTH)), INTERVAL 0 DAY)
This worked for me (Selects all records created from last month, regardless of the day you run the query this month)
Alternative with single condition
SELECT * FROM table
WHERE YEAR(date_created) * 12 + MONTH(date_created)
= YEAR(CURRENT_DATE) * 12 + MONTH(CURRENT_DATE) - 1
select fields FROM table
WHERE date_created LIKE concat(LEFT(DATE_SUB(NOW(), interval 1 month),7),'%');
this one will be able to take advantage of an index if your date_created is indexed, because it doesn't apply any transformation function to the field value.
Here is the query to get the records of the last month:
SELECT *
FROM `tablename`
WHERE `datefiled`
BETWEEN DATE_SUB( DATE( NOW( ) ) , INTERVAL 1
MONTH )
AND
LAST_DAY( DATE_SUB( DATE( NOW( ) ) , INTERVAL 1
MONTH ) )
Regards
- saqib
if you want to get orders from last month, you can try using
WHERE MONTH(order_date) = MONTH(CURRENT_DATE()) -1
One more way to do this in:
MYSQL
select * from <table_name> where date_created >= DATE_ADD(NOW(), INTERVAL -30 DAY);
SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)