Group by date every 10 days - mysql

I have this scheme:
+----+--+--------+--------------------+
| ID | Amount | paydate |
+----+-----------+--------------------+
| 1 | 200 |2016-11-05 |
+----+-----------+--------------------+
| 2 | 3000 |2016-11-10 |
+----+-----------+--------------------+
| 3 | 2500 |2016-11-11 |
+----+-----------+--------------------+
| ID | 100 |2016-11-21 |
+----+-----------+--------------------+
| 1 | 200 |2016-11-22 |
+----+-----------+--------------------+
| 2 | 3000 |2016-11-23 |
+----+-----------+--------------------+
| 3 | 2500 |2016-11-29 |
+----+-----------+--------------------+
How can I get the total Amount grouped by every 10 days like from the first of every month to the 10th then from 11th to 20th and from 21st to the end of the month?
to be shown like this :
+-----------+------------------------+
| Amount | paydate |
+-----------+------------------------+
| 3200 |2016-11-1 to 2016-11-10 |
+-----------+------------------------+
| 2500 |2016-11-11 to 2016-11-20|
+-----------+------------------------+
| 5800 |2016-11-21 to 2016-11-31|
+-----------+------------------------+
I tried
SELECT
SUM(Amount) AS Amount,
year(Facture.paydate) AS Annee,
month(Facture.paydate) AS Mois
FROM Facture
GROUP BY year(Facture.paydate), month(serFacture.paydate)
but this does not give me the result I need.

select sum(Amount) as sum_amount
,case
when day(paydate) <= 10 then concat(DATE_FORMAT(paydate,'%Y-%m-01'),' to ',DATE_FORMAT(paydate,'%Y-%m-10'))
when day(paydate) <= 20 then concat(DATE_FORMAT(paydate,'%Y-%m-11'),' to ',DATE_FORMAT(paydate,'%Y-%m-20'))
else concat(DATE_FORMAT(paydate,'%Y-%m-21'),' to ',DATE_FORMAT(paydate,'%Y-%m-31'))
end as paydate_period
from t
group by paydate_period
;
sum_amount paydate_period
3200 2016-11-01 to 2016-11-10
2500 2016-11-11 to 2016-11-20
5800 2016-11-21 to 2016-11-31

Here is an example query:
select
case
when day(date_field) between 1 and 10 then "01 to 10"
when day(date_field) between 11 and 20 then "11 to 20"
when day(date_field) between 21 and 31 then "21 to 31"
end as the_range,
date_format(date_field, "%m%Y") as the_month,
count(*)
from
the_table
group by
the_range, the_month
order by
the_month, the_range;
You can adapt the query so you display your result the way you need.

Related

Cumulative count for each ID

Data:
Create table completion(user integer, count integer, completed date);
Insert into completion values (100,1,'2021-01-01'),(100,4,'2021-01-02'),(100,2,'2021-01-03'),
(101,4,'2021-01-05'),(101,5,'2021-01-08'),(102,1,'2021-01-04');
I want to produce 2 tables.
The 1st target is to get a cumulative count with respect to date for each individual ID:
user| cumulative | date
100| 1 | 2021-01-01
100| 5 | 2021-01-02
100| 7 | 2021-01-03
101| 4 | 2021-01-05
101| 9 | 2021-01-08
102| 1 | 2021-01-04
The 2nd target is to transform the date into number of days, counted from the minimum date for that ID:
user| cumulative | days passed
100| 1 | 0
100| 5 | 1
100| 7 | 2
101| 4 | 0
101| 9 | 3
102| 1 | 0
Thanks.
You can use window functions:
select c.*,
sum(count) over (partition by user order by completed) as cumulative,
datediff(completed, min(completed) over (partition by user)) as days_passed
from completion c;
Here is a db<>fiddle.

How to write an SQL query to calculate the average for three consecutive values?

I have a table like this
userID time NoOfVisits
1 2014 50
2 2015 60
3 2016 70
4 2017 80
5 2018 90
6 2019 100
I need to write a sql query which will print time and average of past 3 years NoOfVisits for a particular site.
output should be as
userID time NoOfVisits
1 2014 50.0000
2 2015 55.0000
3 2016 60.0000
4 2017 70.0000
5 2018 80.0000
6 2019 90.0000
Explanation :
For user Id 6 (80+90+100)/3=90.0000
Please help me to solve this problem.
You can use a cumulative average, available in MySQL 8+:
select t.*,
avg(visits) over (order by time rows between 2 preceding and current row) as avg_visits_3
from t;
Assuming there are no gaps between the years (like your sample data), you can self join the table and group by userid, time to get the average:
select
t.userid, t.time, avg(tt.noofvisits) NoOfVisits
from tablename t inner join tablename tt
on tt.time between t.time - 2 and t.time
group by t.userid, t.time
See the demo.
Results:
| userid | time | NoOfVisits |
| ------ | ---- | ---------- |
| 1 | 2014 | 50 |
| 2 | 2015 | 55 |
| 3 | 2016 | 60 |
| 4 | 2017 | 70 |
| 5 | 2018 | 80 |
| 6 | 2019 | 90 |

mysql getting average of client per day in a month

SELECT COUNT(client_ID) / DAY(LAST_DAY(dateRequested))
FROM `tbl_client`
WHERE dateRequested BETWEEN DATE_FORMAT(dateRequested,'%Y-%m-01') AND LAST_DAY(dateRequested)
I want to show the average of client per day in the month
client_ID | dateRequested
1 | 2018-07-04
2 | 2018-07-05
3 | 2018-07-06
4 | 2018-07-07
5 | 2018-08-04
6 | 2018-08-06
7 | 2018-08-09
i want to show
Average | Month
4 | July 2018
3 | August 2018
Try below query:
SELECT COUNT(client_ID),concat(month(dateRequested),year(dateRequested))
FROM `tbl_client`
WHERE dateRequested BETWEEN DATE_FORMAT(dateRequested,'%Y-%m-01') AND LAST_DAY(dateRequested)
group by concat(month(dateRequested),year(dateRequested))

Mysql - Rows within hourly ranges on specific days using DAYOFWEEK

I am trying to get a query that will return a result set with reading total within certain hour ranges (defined in the working_hours table) depending on the DAYOFTHEWEEK for the date with a result that looks like:
working | nonworking | weekend | date | group_id
-----------------------------------------------------------------
50.3 | 30.8 | 0 | 2015-04-01 00:00 | 7
40.3 | 60.8 | 0 | 2015-04-01 00:00 | 8
50.3 | 30.8 | 0 | 2015-04-02 00:00 | 7
40.3 | 60.8 | 0 | 2015-04-02 00:00 | 8
Working and Weekend ranges are stored in the database in working_hours, Nonworking time ranges are implied (NOT BETWEEN the other ranges on that day basically)
The tables are as following:
Readings table has the hourly readings, named readings
group_id | reading | datestamp
------------------------------------------------------
7 | 30.8 | 2015-04-01 00:00
7 | 20.2 | 2015-04-01 01:00
7 | 11.2 | 2015-04-02 00:00
7 | 20.2 | 2015-04-02 01:00
8 | 26.2 | 2015-04-01 00:00
8 | 30.2 | 2015-04-01 01:00
8 | 26.2 | 2015-04-02 00:00
8 | 30.2 | 2015-04-02 01:00
Hour Ranges are stored in the working_hours table, the day column is DAYOFTHEWEEK format (1 = Sunday, 2 = Monday, etc):
group_id | day | range_start | range_end | range_type_id | day_type_id
------------------------------------------------------------------------------
7 | 5 | 08:00:00 | 15:59:00 | 1 | 1
7 | 6 | 00:00:00 | 05:59:00 | 1 | 2
7 | 6 | 06:00:00 | 23:59:00 | 2 | 2
7 | 1 | 00:00:00 | 22:59:00 | 2 | 4
7 | 1 | 23:00:00 | 23:59:00 | 1 | 4
Day Types are in the working_hours_day_type table and where things get complicated for me, Weekday and Weekend only have one range but Start/End Weekend have two ranges ('Start Weekend' first range is working hours, second range weekend hours and 'End Weekend' first range is weekend hours, second range working hours).
id | type
------------------
1 | Weekday
2 | Start Weekend
3 | Weekend
4 | End Weekend
Range Types are in the working_hours_range_type table:
id | type
------------------
1 | Working
2 | Weekend
My Mysql knowledge is limited to simple SELECT, INSERT etc and the basics of JOINs - I have found out about HOUR(datestamp) BETWEEN 8 AND 14 but dont know how to get subqueries to iterate within a parent query using WHERE datestamp BETWEEN '2015-04-01 00:00:00' AND '2015-04-02 23:59:00' if in fact thats how its done...
I am not totally clear on what constitutes working hours or non-working hours, but does this work?
SELECT
sum(CASE WHEN rtype.range_type_id = 1 THEN reading ELSE 0 END) AS working
sum(CASE WHEN rtype.range_type_id = 2 THEN reading ELSE 0 END) AS nonworking
CASE WHEN r1.daynum in (7,1) THEN 1 ELSE 0 END as weekend
date(datestamp) as date
r1.group_id
FROM
(SELECT
group_id,
reading,
time(datestamp) as rTime,
case when weekday(datestamp) = 0 THEN 2 #weekday() monday to working hours monday
when weekday(datestamp) = 1 THEN 3
when weekday(datestamp) = 2 THEN 4
when weekday(datestamp) = 3 THEN 5
when weekday(datestamp) = 4 THEN 6
when weekday(datestamp) = 5 THEN 7
when weekday(datestamp) = 6 THEN 1
else NULL
END CASE AS daynum
FROM readings) AS r1
LEFT JOIN working_hours w1
ON (r1.daynum = w1.day)
AND (r1.group_id = w1.group_id)
AND (r1.rTime BETWEEN w1.range_start AND w1.range_end)
LEFT JOIN working_hours_day_type dtype
ON w1.day_type_id = dtype.id
LEFT JOIN working_hours_range_type rtype
ON w1.range_type_id = rtype.id
GROUP BY
CASE WHEN daynum in (7,1) THEN 1 ELSE 0 END,
date(datestamp) as date,
r1.group_id

not matching when inside mysql case statement is not showing in result

I have an mysql statement as below
SELECT CASE
WHEN HOUR(created_at) BETWEEN 0 AND 11 THEN 'Morning'
WHEN HOUR(created_at) BETWEEN 12 AND 15 THEN 'Afternoon'
WHEN HOUR(created_at) BETWEEN 16 AND 18 THEN 'Evening'
WHEN HOUR(created_at) BETWEEN 19 AND 24 THEN 'Night'
END AS session,
SUM(total) AS `total` FROM `orders` WHERE (purchase_date between '2014-05-01' and '2014-05-30')
GROUP BY CASE
WHEN HOUR(created_at) BETWEEN 0 AND 11 THEN 1
WHEN HOUR(created_at) BETWEEN 12 AND 16 THEN 2
WHEN HOUR(created_at) BETWEEN 17 AND 18 THEN 3
WHEN HOUR(created_at) BETWEEN 19 AND 24 THEN 4
END;
I am getting an output like this
+------------+------------+
| session | total |
+------------+------------+
| Morning | 47083.21 |
| Afternoon | 1124804.51 |
| Evening | 165643.34 |
| Night | 1690492.01 |
+------------+------------+
But when there are no entries for morning then the output is missing the Morning row in results but I want an row with morning but total as 0.
please help me how to achieve the same
Expected output
+------------+------------+
| session | total |
+------------+------------+
| Morning | 0 |
| Afternoon | 14804.51 |
| Evening | 16643.34 |
| Night | 19492.01 |
+------------+------------+
actual output is without morning row
Actual output
+------------+------------+
| session | total |
+------------+------------+
| Afternoon | 1124804.51 |
| Evening | 165643.34 |
| Night | 1690492.01 |
+------------+------------+
I would greatly appreciate if Any kind of help or hint is given to solve this problem
Add create table cal (hours int not null). Fill it with 0 to 23 (there is no 24 hour?). Then do
SELECT CASE
WHEN cal.hours BETWEEN 0 AND 11 THEN 'Morning'
WHEN cal.hours BETWEEN 12 AND 15 THEN 'Afternoon'
WHEN cal.hours BETWEEN 16 AND 18 THEN 'Evening'
WHEN cal.hours BETWEEN 19 AND 24 THEN 'Night'
END AS session
,sum(coalesce(total, 0)) from
(select created_at, total from orders
where purchase_date between '2014-05-01' and '2014-05-30') T1
right outer join cal on (cal.hours = hour(T1.created_at))
group by CASE
WHEN cal.hours BETWEEN 0 AND 11 THEN 'Morning'
WHEN cal.hours BETWEEN 12 AND 15 THEN 'Afternoon'
WHEN cal.hours BETWEEN 16 AND 18 THEN 'Evening'
WHEN cal.hours BETWEEN 19 AND 24 THEN 'Night' END;