another annoying student here!
Today I spend hours trying to combine (select) 2 already joined SQL outputs + the ID of the original table in a single table output. which ultimately resulted in this query:
SELECT * FROM(
SELECT fd1.User_idUser,avg(fd1.caloryIntake)
AS 'workdays'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1 ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'N'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) A,
(SELECT avg(fd1.caloryIntake) AS 'weekend'
FROM fact_dailysnapshot fd1
INNER
JOIN dim_day dd1 ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'Y'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) B;
Which translates into…
Now this is a false result, the second column gives an almost constant value for all user entries. I think this must be solved with some kind of EXTRA join but I literally ran out of ideas. Thanks in advance..!
Your JOIN is missing an ON clause to relate dUser_idUser.
But, the simplest way to write the query uses conditional aggregation:
SELECT fd1.User_idUser,
avg(case when dd1.weekend_ind = 'N' then fd1.caloryIntake end) as weekday_avg,
avg(case when dd1.weekend_ind = 'Y' then fd1.caloryIntake end) as weekend_avg
FROM fact_dailysnapshot fd1 INNER JOIN
dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser;
This is one query instead of two.
If I understand correctly, this is what you are looking for:
SELECT A.User_idUser, A.workdays, B.weekend
FROM (
SELECT fd1.User_idUser, avg(fd1.caloryIntake) AS 'workdays'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'N'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) A
JOIN
(SELECT fd1.User_idUser, avg(fd1.caloryIntake) AS 'weekend'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'Y'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) B
ON A.User_idUser = B.User_idUser
Each query gives you all users by ID and their workdays or weekends. You need to JOIN the results of the two query on the user ID.
Related
i have a query and i'm having trouble to change the name of the last row of columb name to 'TOTAL'. The result gives me the same name of the row above the last row.
Here's my query:
SELECT COALESCE(ticket_types.name,'TOTAL') AS name,
COUNT(1) AS quantity
FROM tr_logs
LEFT JOIN tickets ON tr_logs.value = tickets.id
LEFT JOIN ticket_types ON tickets.ticket_type_id = ticket_types.id
LEFT JOIN transactions ON tr_logs.transaction_id = transactions.id
LEFT JOIN tr_fields_data AS tfd_shipping ON tfd_shipping.transaction_id = transactions.id
WHERE type = 'ADDITEM'
AND transactions.event_id = '46'
AND DATE(tr_logs.created_date)
BETWEEN '2017-03-26' AND '2017-05-24'
AND tfd_shipping.data IN ('0','570','571','771')
AND name IS NOT NULL
GROUP BY ticket_types.id WITH ROLLUP
The result looks like this:
name quantity
premium 56
outlaw 6
outlaw 62
Last row name from rollup is not null.... I need it to be TOTAL and not outlaw
Thanks
You haven't changed the name to TOTAL at all: you've changed the name of the column to name, and you've told it to replace any null values with TOTAL.
If you want to change the name of ticket_types.name to total, you just want
SELECT ticket_types.name AS total ...
(But it would be weird to rename something called name to total, so perhaps you need to clarify your requirements a little.)
This may or not be related to your observed problem, but the WHERE and GROUP BY clauses turn all the outer joins into inner joins. You should simplify the query to:
SELECT COALESCE(tt.name, 'TOTAL') AS name, COUNT(1) AS quantity
FROM tr_logs l JOIN
tickets
ON l.value = t.id JOIN
ticket_types tt
ON t.ticket_type_id = tt.id JOIN
transactions tr
ON l.transaction_id = tr.id JOIN
tr_fields_data fd
ON fd.transaction_id = tr.id
WHERE type = 'ADDITEM' AND
tr.event_id = '46' AND
DATE(l.created_date) BETWEEN '2017-03-26' AND '2017-05-24' AND
fd.data IN ('0', '570', '571', '771') AND
tt.name IS NOT NULL
GROUP BY tt.id WITH ROLLUP
Thanks to Gordon Linoff I have figure out my problem.
The name of the last row was never null beacause i GROUP BY with a different attribute.
Here's the solution.
SELECT COALESCE(tckn,'TOTAL') AS name, quantity FROM
(SELECT tt.name AS tckn, COUNT(1) AS quantity
FROM tr_logs AS l
LEFT JOIN tickets AS t ON l.value = t.id
LEFT JOIN ticket_types AS tt ON t.ticket_type_id = tt.id
LEFT JOIN transactions AS tr ON l.transaction_id = tr.id
LEFT JOIN tr_fields_data AS tfd ON tfd.transaction_id = tr.id
WHERE type = 'ADDITEM'
AND tr.event_id = '46'
AND DATE(l.created_date)
BETWEEN '2017-03-26' AND '2017-05-24'
AND tfd.data IN ('0','570','571','771')
GROUP BY tckn WITH ROLLUP) as sum;
I want to do conditional join on two tables and wanted to join with highest status in the second table. The status values are Assigned, Booked, Delivery and Closed.
SELECT
CPC.CpcID, StatusFlow = CPC.Status, Orders.CarModel, EnquiryLog.EnquiryStatus
FROM
CPC
INNER JOIN
Orders ON CPC.CpcID = Orders.CpcID
INNER JOIN
EnquiryLog ON CPC.CpcID = EnquiryLog.CpcID
WHERE
CPC.CpcID = '24092015/12'
So in this case it should show only one row with EnquiryStatus 'Delivery' but based on my query the result is:
SQL query output:
If I got it the right way:
SELECT CPC.CpcID, StatusFlow = CPC.Status, Orders.CarModel, ca.EnquiryStatus
FROM CPC
INNER JOIN Orders ON CPC.CpcID = Orders.CpcID
CROSS APPLY(SELECT TOP 1 * FROM EnquiryLog WHERE CPC.CpcID = EnquiryLog.CpcID
ORDER BY CASE EnquiryStatus
WHEN 'CLOSED' THEN 1
WHEN 'DELIVERY' THEN 2
WHEN 'BOOKED' THEN 3
WHEN 'ASSIGNED' THEN 4 END) ca
WHERE CPC.CpcID='24092015/12'
I have some trouble to count more than 2 counts in mysql statement.
My count(b.entry_id) as totalbooking wont work. What have i done wrong? Is the statement setup also correctly made?
This is how i tried:
"SELECT
t.restaurant_id as restaurant_id, ct.title as title,
count(DISTINCT t.cardid) as totalmembers,
count(t.restaurant_id) as totaltransactions,
count(b.entry_id) as totalbooking
from transactions as t
inner join exp_menucard_booking as b on (t.restaurant_id = b.entry_id)
inner join exp_channel_titles as ct on (t.restaurant_id = ct.entry_id)
inner JOIN exp_channel_data as cd on (ct.entry_id = cd.entry_id)
where t.cardid != 88888888 and ct.status = 'open'
group by t.restaurant_id
order by ct.title asc";
Use this pattern to count subsets of the total rowset:
sum( case when ColumnToBeTested = trueCondition then 1 else 0 end) as SubCount
I'm trying to combine the results of two queries. I'm not very proficient in mysql so I'm here for some help.
The first query is as follows:
select count(roomtypeid) as bookedrooms, day
from event_guest_hotel
where hotelid = 1 and roomtypeid = 1
group by day;
This returns:
The second query:
SELECT ehr.reservationid, ehr.day, h.name AS hotelname,
ehr.totalrooms as requested_rooms, r.name AS roomname
FROM event_hotel_reservation ehr
INNER JOIN hotel_room_type r
ON ehr.roomtypeid = r.roomtypeid
INNER JOIN hotel h
ON ehr.hotelid = h.hotelid
WHERE totalRooms != 0
AND reservationID = '1'
This returns:
Can I combine the first query with the second one, so I get the results of the first one in another resultcolumn next to 'roomname'? That way I know how many rooms are already booked and how many were originally requested from one single query.
Try:
SELECT ehr.reservationid, ehr.day, h.name AS hotelname,
ehr.totalrooms as requested_rooms, r.name AS roomname,
egh.bookedrooms
FROM event_hotel_reservation ehr
INNER JOIN hotel_room_type r ON ehr.roomtypeid = r.roomtypeid
INNER JOIN hotel h ON ehr.hotelid = h.hotelid
left outer join (
select hotelid, count(roomtypeid) as bookedrooms, day
from event_guest_hotel
where roomtypeid = 1
group by hotelid, day
) egh on h.hotelid = egh.hotelid and ehr.day = egh.day
WHERE totalRooms != 0
AND reservationID = '1'
How do I put these two queries into a single query?
select count(id) as cnt from {$site_id}.proofingv2_packages where active='1'
select count(id) as cnt from {$site_id}.proofingv2_package_options where active='1' and parent={$row["id"]} order by sort
$row['id'] is the id field from the first query. I am trying to determine if there are any valid packages. A valid package must be active and have at least 1 active option. Running 2 queries for this doesn't seem right.
Can anyone help?
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN
{$site_id}.proofingv2_package_options
pt ON pp.active = pt.Active AND
pp.Active = 1
if the id is the PK or FK on the same on both tables use this query
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options pt ON pp.id= pt.id
AND pp.Active = 1
SELECT IF(count(*) > 0, 1, 0) AS isValid
FROM {$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options ppo ON ppo.parent = pp.id
WHERE pp.active = '1'
AND ppo.active = '1'
This should return 1 if there are valid packages or 0 if not