I have some trouble to count more than 2 counts in mysql statement.
My count(b.entry_id) as totalbooking wont work. What have i done wrong? Is the statement setup also correctly made?
This is how i tried:
"SELECT
t.restaurant_id as restaurant_id, ct.title as title,
count(DISTINCT t.cardid) as totalmembers,
count(t.restaurant_id) as totaltransactions,
count(b.entry_id) as totalbooking
from transactions as t
inner join exp_menucard_booking as b on (t.restaurant_id = b.entry_id)
inner join exp_channel_titles as ct on (t.restaurant_id = ct.entry_id)
inner JOIN exp_channel_data as cd on (ct.entry_id = cd.entry_id)
where t.cardid != 88888888 and ct.status = 'open'
group by t.restaurant_id
order by ct.title asc";
Use this pattern to count subsets of the total rowset:
sum( case when ColumnToBeTested = trueCondition then 1 else 0 end) as SubCount
Related
query taking 1 minute to fetch results
SELECT
`jp`.`id`,
`jp`.`title` AS game_title,
`jp`.`game_type`,
`jp`.`state_abb` AS game_state,
`jp`.`location` AS game_city,
`jp`.`zipcode` AS game_zipcode,
`jp`.`modified_on`,
`jp`.`posted_on`,
`jp`.`game_referal_amount`,
`jp`.`games_referal_amount_type`,
`jp`.`status`,
`jp`.`is_flaged`,
`u`.`id` AS employer_id,
`u`.`email` AS employer_email,
`u`.`name` AS employer_name,
`jf`.`name` AS game_function,
`jp`.`game_freeze_status`,
`jp`.`game_statistics`,
`jp`.`ats_value`,
`jp`.`integration_id`,
`u`.`account_manager_id`,
`jp`.`model_game`,
`jp`.`group_id`,
(CASE
WHEN jp.group_id != '0' THEN gm.group_name
ELSE 'NA'
END) AS group_name,
`jp`.`priority_game`,
(CASE
WHEN jp.country != 'US' THEN jp.country_name
ELSE ''
END) AS game_country,
IFNULL((CASE
WHEN
`jp`.`account_manager_id` IS NULL
OR `jp`.`account_manager_id` = 0
THEN
(SELECT
(CASE
WHEN
account_manager_id IS NULL
OR account_manager_id = 0
THEN
`u`.`account_manager_id`
ELSE account_manager_id
END) AS account_manager_id
FROM
user_user
WHERE
id = (SELECT
user_id
FROM
game_user_assigned
WHERE
game_id = `jp`.`id`
LIMIT 1))
ELSE `jp`.`account_manager_id`
END),
`u`.`account_manager_id`) AS acc,
(SELECT
COUNT(recach_limit_id)
FROM
recach_limit
WHERE
recach_limit = '1'
AND recach_limit_game_id = rpr.recach_limit_game_id) AS somewhatgame,
(SELECT
COUNT(recach_limit_id)
FROM
recach_limit
WHERE
recach_limit = '2'
AND recach_limit_game_id = rpr.recach_limit_game_id) AS verygamecommitted,
(SELECT
COUNT(recach_limit_id)
FROM
recach_limit
WHERE
recach_limit = '3'
AND recach_limit_game_id = rpr.recach_limit_game_id) AS notgame,
(SELECT
COUNT(joa.id) AS applicationcount
FROM
game_refer_to_member jrmm
INNER JOIN
game_refer jrr ON jrr.id = jrmm.rid
INNER JOIN
game_applied joa ON jrmm.id = joa.referred_by
WHERE
jrmm.STATUS = '1'
AND jrr.referby_user_id IN (SELECT
ab_testing_user_id
FROM
ab_testing)
AND joa.game_post_id = rpr.recach_limit_game_id
AND (rpr.recach_limit = 1
OR rpr.recach_limit = 2)) AS gamecount
FROM
(`game_post` AS jp)
JOIN
`user_info` AS u ON `jp`.`user_user_id` = `u`.`id`
JOIN
`game_functional` jf ON `jp`.`game_functional_id` = `jf`.`id`
LEFT JOIN
`group_musesm` gm ON `gm`.`group_id` = `jp`.`group_id`
LEFT JOIN
`recach_limit` rpr ON `jp`.`id` = `rpr`.`recach_limit_game_id`
WHERE
`jp`.`status` != '3'
GROUP BY `jp`.`id`
ORDER BY `posted_on` DESC
LIMIT 10
I would first suggest not nesting select statements because this will cause an n^x performance hit on every xth level and I see at least 3 levels of selects inside this query.
Add index
INDEX(status, posted_on)
Move LIMIT inside
Then, instead of saying
FROM (`game_post` AS jp)
say
FROM ( SELECT id FROM game_post
WHERE status != 3
ORDER BY posted_on DESC
LIMIT 10 ) AS ids
JOIN game_post AS jp USING(id)
(I am assuming that the PK of jp is (id)?)
That should efficiently use the new index to get the 10 ids needed. Then it will reach back into game_post to get the other columns.
LEFT
Also, don't say LEFT unless you need it. It costs something to generate NULLs that you may not be needing.
Is GROUP BY necessary?
If you remove the GROUP BY, does it show dup ids? The above changes may have eliminated the need.
IN(SELECT) may optimize poorly
Change
AND jrr.referby_user_id IN ( SELECT ab_testing_user_id
FROM ab_testing )
to
AND EXISTS ( SELECT * FROM ab_testing
WHERE ab_testing_user_id = jrr.referby_user_id )
(This change may or may not help, depending on the version you are running.)
More
Please provide EXPLAIN SELECT if you need further assistance.
another annoying student here!
Today I spend hours trying to combine (select) 2 already joined SQL outputs + the ID of the original table in a single table output. which ultimately resulted in this query:
SELECT * FROM(
SELECT fd1.User_idUser,avg(fd1.caloryIntake)
AS 'workdays'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1 ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'N'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) A,
(SELECT avg(fd1.caloryIntake) AS 'weekend'
FROM fact_dailysnapshot fd1
INNER
JOIN dim_day dd1 ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'Y'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) B;
Which translates into…
Now this is a false result, the second column gives an almost constant value for all user entries. I think this must be solved with some kind of EXTRA join but I literally ran out of ideas. Thanks in advance..!
Your JOIN is missing an ON clause to relate dUser_idUser.
But, the simplest way to write the query uses conditional aggregation:
SELECT fd1.User_idUser,
avg(case when dd1.weekend_ind = 'N' then fd1.caloryIntake end) as weekday_avg,
avg(case when dd1.weekend_ind = 'Y' then fd1.caloryIntake end) as weekend_avg
FROM fact_dailysnapshot fd1 INNER JOIN
dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser;
This is one query instead of two.
If I understand correctly, this is what you are looking for:
SELECT A.User_idUser, A.workdays, B.weekend
FROM (
SELECT fd1.User_idUser, avg(fd1.caloryIntake) AS 'workdays'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'N'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) A
JOIN
(SELECT fd1.User_idUser, avg(fd1.caloryIntake) AS 'weekend'
FROM fact_dailysnapshot fd1
INNER JOIN dim_day dd1
ON dd1.DATE_SK = fd1.DATE_SK
WHERE dd1.weekend_ind = 'Y'
GROUP BY fd1.User_idUser
ORDER BY fd1.User_idUser) B
ON A.User_idUser = B.User_idUser
Each query gives you all users by ID and their workdays or weekends. You need to JOIN the results of the two query on the user ID.
I'm starting out with this query, which gives me back 8 records with a "claimed" status. I'm looking to see if any of the addresses in the invites-from-address column are different from that in the moves-from-address column :
SELECT i.id, i.company_id, i.status,
ia_f.base_street as "invites-from-address", a_f.base_street as "moves-from-address",
ia_t.base_street as "invites-to-address", a_t.base_street as "moves-to-address", i.`mover_first_name`,
i.mover_last_name, i.`to_address_id`
FROM invites i
JOIN moves m ON i.id = m.`claimed_invite_id`
JOIN `invite_addresses` ia_f ON ia_f.id = i.`from_address_id`
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN `invite_addresses` ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.`company_id` = 1040345
GROUP BY id
What I'm trying to do in this query below is to create an average_discrepancy column on the fly that shows the proportion of addresses that differ between invites-from-address and moves-from-address. I was able to successfully check for address discrepancies by using a WHERE clause that checks that ia_f.base_street is not equal to a_f.base_street (which are aliased to the columns invites-from-address and moves-from-address respectively) but when I put this WHERE clause inside the count function in my SELECT cause it doesn't work. Is it because I can't place a WHERE clause inside a SELECT or a count function or both? And is there also a problem with trying to divide the results of two calls to the count function in my SELECT clause ?
SELECT i.id, i.company_id, i.status,
count(WHERE ia_f.base_street != a_f.base_street)/count(i.status="claimed") as "average_discrepancy",
ia_f.base_street as "invites-from-address", a_f.base_street as "moves-from-address",
ia_t.base_street as "invites-to-address", a_t.base_street as "moves-to-address",
i.`mover_first_name`,
i.mover_last_name, i.`to_address_id`
FROM invites i
JOIN moves m ON i.id = m.`claimed_invite_id`
JOIN `invite_addresses` ia_f ON ia_f.id = i.`from_address_id`
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN `invite_addresses` ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.`company_id` = 1040345
AND i.status = "claimed"
You need to put this into a SUM instead of a COUNT. Something like this would do the trick:
SELECT i.id, i.company_id, i.status,
SUM(CASE WHEN ia_f.base_street != a_f.base_street THEN 1 ELSE 0 END)/ SUM(CASE WHEN i.status='claimed' THEN 1 ELSE 0 END) as 'average_discrepancy',
ia_f.base_street as 'invites-from-address',
a_f.base_street as 'moves-from-address',
ia_t.base_street as 'invites-to-address',
a_t.base_street as 'moves-to-address',
i.mover_first_name,
i.mover_last_name,
i.to_address_id
FROM invites i
JOIN moves m ON i.id = m.claimed_invite_id
JOIN invite_addresses ia_f ON ia_f.id = i.from_address_id
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN invite_addresses ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.company_id = 1040345
AND i.status = 'claimed'
SELECT p . * , (
SELECT (
SELECT COUNT( * )
FROM sales s
WHERE s.affiliate != ''
AND s.pid = p.pid
AND s.saletype = 'sale' )
) AS popular
FROM products p
INNER JOIN members m ON m.uname = p.vendor
WHERE (m.mpid = p.pid OR p.marketavail = 'yes')
AND p.showinmarket = 'yes'
AND p.pname != ''
AND p.pdesc != ''
AND p.active = 'yes'
ORDER BY popular DESC
Here, If i use ORDER BY popular , it takes 17 seconds to load. without this ordering , query is executed in 4 seconds.
Please tell me why it is taking too much time while ordering by virtual columns?
All tables has index on required columns, so indexing is not the issue i guess. And if i run select count(*) for single product, it is executing in milliseconds.
And one more error i saw, If i remove SELECT word (second select word in my sql), it takes 105 sec to execute.
Please tell me if i need to give any more information.
Due to such delay in sorting, i am using php instead of mysql for sorting. Please help me to make it better.
Thank you in advance.
please try this query
SELECT p.column1,
p.column2,
p.column3,
COUNT(s.pid) as popular
FROM products p
INNER JOIN members m ON m.uname = p.vendor
LEFT JOIN sales s ON s.pid = p.pid AND s.affiliate != '' AND s.saletype = 'sale'
WHERE (m.mpid = p.pid OR p.marketavail = 'yes')
AND p.showinmarket = 'yes'
AND p.pname != ''
AND p.pdesc != ''
AND p.active = 'yes'
GROUP BY p.column1,p.column2,p.column3
ORDER BY popular DESC
column1,column2,column3 are just examples of columns you want, because you're select * I don't know what column names are from product. so change them to your actual column names.
edit: try this query see if it's any faster
SELECT p.pname, p.vendor, p.pid,
COUNT( s.pid ) AS popular
FROM products p INNER JOIN members m ON m.uname = p.vendor
LEFT JOIN
(SELECT pid FROM sales
WHERE affiliate != ''
AND saletype = 'sale'
)s
ON (s.pid = p.pid)
WHERE ( m.mpid = p.pid OR p.marketavail = 'yes' )
AND p.showinmarket = 'yes' AND p.pname != ''
AND p.pdesc != ''
AND p.active = 'yes'
GROUP BY p.pid, p.pname
ORDER BY popular DESC
if it runs faster you can pre-filter products too like this query and see if it runs even faster
SELECT p.pname, p.vendor, p.pid,
COUNT( s.pid ) AS popular
FROM (SELECT pname,vendor,pid,marketavail
FROM products
WHERE showinmarket = 'yes'
AND pname != ''
AND pdesc != ''
AND active = "yes"
)p
INNER JOIN members m ON m.uname = p.vendor
LEFT JOIN
(SELECT pid FROM sales
WHERE affiliate != ''
AND saletype = 'sale'
)s
ON (s.pid = p.pid)
WHERE ( m.mpid = p.pid OR p.marketavail = 'yes' )
GROUP BY p.pid, p.pname
ORDER BY popular DESC
How do I put these two queries into a single query?
select count(id) as cnt from {$site_id}.proofingv2_packages where active='1'
select count(id) as cnt from {$site_id}.proofingv2_package_options where active='1' and parent={$row["id"]} order by sort
$row['id'] is the id field from the first query. I am trying to determine if there are any valid packages. A valid package must be active and have at least 1 active option. Running 2 queries for this doesn't seem right.
Can anyone help?
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN
{$site_id}.proofingv2_package_options
pt ON pp.active = pt.Active AND
pp.Active = 1
if the id is the PK or FK on the same on both tables use this query
select count(id) as cnt from
{$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options pt ON pp.id= pt.id
AND pp.Active = 1
SELECT IF(count(*) > 0, 1, 0) AS isValid
FROM {$site_id}.proofingv2_packages pp
INNER JOIN {$site_id}.proofingv2_package_options ppo ON ppo.parent = pp.id
WHERE pp.active = '1'
AND ppo.active = '1'
This should return 1 if there are valid packages or 0 if not