Milion Record Sql Order By and count rows - mysql

Question

I have a database with millions of records.
The table is structured as:
Table name : record
Filed1: Name (varchar)(Primary key)
Field2: Record(int/bigint)
example:
Name | Record
Darrin | 256
Aaron | 3
Daryl | 12
...
I need to know what position does the user with the name 'namex' in sorted records.
Currently i implement this solution:
...
$name=namex;
$query= mysqli_query($mysqli,"SELECT Name FROM record ORDER BY Record DESC");
$x=0;
$rank=0;
if ($query->num_rows > 0) {
// output data of each row
while($row = $query->fetch_assoc()) {
if($row["Name"]==$name){
$rank=$x+1;
echo "Rank : $rank<br>";
break;
}
$x++;
}
}
...
With it and 1 million records in the database, the answer comes in about 4 second.
I tried to put a table index on the field Record but have remained the same performance.
how can I reduce the execution times?

Answer 1

Since I don't know what DBMS you are using for (in tags you are using both mysql and sql-server...), you can you create a view (for SQL server have to be a indexed view) or for mysql implement/emulate a kind of materialized view (has a better performance). The view is good to get a better perfomance through some DBMS. For MySQL may have no difference.
In the view show up the rank position as the query below (mysql example):
CREATE VIEW ranked_record AS
SELECT
record.Name,
#curRank := #curRank + 1 AS rank
FROM
record,
(SELECT #curRank := 0) r
ORDER BY Record DESC;
or SQL server:
CREATE VIEW ranked_record AS
SELECT
record.Name,
row_number() over(ORDER BY record)
FROM
record;
And just run your query:
SELECT name , rank FROM ranked_record WHERE name LIKE 'some name'
Update:
After John comments, I've realized about the error from views using variables. It isn't possible due the "feature/bug" of/from MySQL
Due this, you can choose about use this as subquery in FROM clause:
SELECT
name,
rank
FROM (
SELECT
record.Name,
#curRank := #curRank + 1 AS rank
FROM
record,
(SELECT #curRank := 0) r
) AS ranked_record
WHERE
name LIKE 'some name';
OR create a function to count the rank inside the view (like this example):
CREATE FUNCTION `func_inc_var_session`() RETURNS int(11)
begin
SET #var := IFNULL(#var,0) + 1;
return #var;
end;
Then, create your view as before, just using the function instead of the variable:
CREATE VIEW ranked_record AS
SELECT
record.Name,
func_inc_var_session() as rank
FROM
record
ORDER BY Record DESC;

Answer 2

We can write this in sql query instead of fetching the records and looping it in PHP.
select row = row_number() over( order by Record ) , * from record where name like 'namex'

Answer 3

I dont really understand why are you looping every record knowing that the column "Name" its your PK (unique values).
$name="Darrin";
$query= mysqli_query($db_connection, "SELECT COUNT(1) as rank FROM record WHERE Name = '".mysqli_real_escape_string($name)."' ORDER BY Record DESC");
$row = mysqli_fetch_row($query);
if ($query->num_rows > 0) {
echo "Rank : $row["rank"]<br>";
}