I have created two queries that both return the required results independent of each other. I am trying to join them to have the returned values be customerName, Amount Ordered, and Amount Paid.
Currently, this query works but only returns the customerName. How can it get the query to return the other two columns?
SELECT c1.customerName
FROM
(SELECT cc.customerName, ROUND(SUM(od.priceEach * od.quantityOrdered), 2) as '$ Amount Ordered'
FROM customers cc
INNER JOIN orders o ON o.customerNumber = cc.customerNumber
INNER JOIN orderdetails od ON od.orderNumber = o.orderNumber
GROUP BY cc.customerName
) c1
INNER JOIN
(SELECT c.customerName, ROUND(SUM(p.amount), 2) as 'Total $ Amount Paid'
FROM customers c
INNER JOIN payments p ON p.customerNumber = c.customerNumber
GROUP BY c.customerName
) c2
WHERE c1.customerName = c2.customerName
GROUP BY c1.customerName
ORDER BY c1.customerName;
this should select the others column
SELECT c1.customerName, c1.Amount_Ordered as '$ Amount Ordered', c2.Total_Amount_Paid as 'Total $ Amount Paid'
FROM
(SELECT cc.customerName, ROUND(SUM(od.priceEach * od.quantityOrdered), 2) as Amount_Ordered
FROM customers cc
INNER JOIN orders o ON o.customerNumber = cc.customerNumber
INNER JOIN orderdetails od ON od.orderNumber = o.orderNumber
GROUP BY cc.customerName
) c1
INNER JOIN
(SELECT c.customerName, ROUND(SUM(p.amount), 2) as Total_Amount_Paid
FROM customers c
INNER JOIN payments p ON p.customerNumber = c.customerNumber
GROUP BY c.customerName
) c2
WHERE c1.customerName = c2.customerName
GROUP BY c1.customerName
ORDER BY c1.customerName;
simply add them to the select section:
SELECT c1.customerName, C1.amountOrdered, C2.amountPaid FROM ...
And one more word of advice - DONT use whitespace or special signs like $ in your column names, it is bad practice. I think it's a mistake that mySql even allows it
Related
I need to select the customer and product code and the date on which the order was made, but I'm having some trouble with the join orders.
My SQL select:
select c.customerNumber, p.productCode, o.orderDate as data_compra
from customers as c inner join orders as o
inner join products as p
where p.productCode =
any (
select p2.productCode from products as p2
inner join orders as o
inner join orderdetails as odt
where o.orderNumber = odt.orderNumber and
p2.productCode = odt.productCode
)
and o.orderNumber =
any (
select o2.orderNumber from orders as o2
inner join orderdetails as odt
where o.orderNumber = odt.orderNumber and
p.productCode = odt.productCode
)
Two simple joins should do what you want:
select
c.customerNumber,
d.productCode,
o.orderDate
from customer c
join orders o on o.customerNumber = c.customerNumber
join orderdetails d on d.orderNumber = o.orderNumber
In the code you're asking to inner join two tables but not specifying the relationship. You need to do so SQL can relate and match the rows in each table.
You do this with the ON keyword.
I suggest you watch this video and read this article before continuing
I'm trying to get the sum of each customer's orders separately, but I'm actually getting the sum of all the orders. What am I doing wrong here?
SELECT c.customerNumber, sum( r.quantityOrdered * r.priceEach ) AS sum
FROM customers c, orders o, orderdetails r
WHERE c.customerNumber = o.customerNumber
AND o.orderNumber = r.orderNUmber
GROUP BY c.customerNumber
HAVING COUNT( o.orderNumber ) <=3
First, you should use JOIN as it is the standardised way of writing the syntax. Makes it easier to read.
SELECT c.customerNumber, sum( r.quantityOrdered * r.priceEach ) AS sum
FROM customers c
LEFT JOIN orders o ON c.customerNumber = o.customerNumber
LEFT JOIN orderdetails r ON o.orderNumber = r.orderNUmber
GROUP BY c.customerNumber
HAVING COUNT( o.orderNumber ) <=3
When you use LEFT JOIN, this will give the results of the table customers, even if they dont have any recods in the orders and orderdetails.
Give it a try!
Your query looks ok to me other than the HAVING clause. I don't know what you are really trying to achieve with HAVING COUNT( o.orderNumber ) <=3. Do you really want customers with order of 3 or less? Have you tried using :
SELECT c.customerNumber, sum(r.quantityOrdered * r.priceEach) AS sum
FROM customers c
INNER JOIN orders o ON c.customerNumber = o.customerNumber
INNER JOIN orderdetails r ON o.orderNumber = r.orderNUmber
GROUP BY c.customerNumber
For the schema below, I need to get this report
This is what I have
select c.name, sr.name, count(o.order_id)
from contact c
INNER JOIN accounts a
ON c.account_id=a.account_id
INNER JOIN sales_reps sr
ON a.sales_rep_id =sr.sales_rep_id
INNER JOIN orders o
ON a.account_id =o.account_id
where o.order_id in (
select SUM(oi.quantity*p.price) from
order_items oi INNER JOIN parts p
on oi.part_id =p.part_id
)
group by a.account_id, c.name
But this does not give any results.
Please help.
Your where condition is not right, how should be a order_id equal a sum?
Try the below:
select
c.name, sr.name, COUNT(o.order_id), SUM(op.order_total)
FROM
contact c
INNER JOIN
accounts a ON c.account_id = a.account_id
INNER JOIN
sales_reps sr ON a.sales_rep_id = sr.sales_rep_id
INNER JOIN
orders o ON a.account_id = o.account_id
INNER JOIN
(SELECT
oi.order_id, SUM(oi.quantity * p.price) AS order_total
FROM
order_items oi
INNER JOIN
parts p ON oi.part_id = p.part_id
GROUP BY
oi.order_id
) op ON o.order_id = op.order_id
WHERE o.delivery_data >= CURDATE()
GROUP by c.contact_id
It won't give results as your WHERE ... IN SELECT is based on a query returning a sum() value which will not equal a key (most likely), or incorrect at best... and since you are dealing with a quantity and price which will have decimal precision (typically), you won't even get that to match even LESS likely...
I would swap the query around to pre-qualify the orders within a given date in question and sum that... THEN join to rest...
select
c.name,
sr.name,
PreQualified.NumberOrders,
PreQualified.OrderTotal
from
( select
o.Account_ID,
count( distinct o.order_id ) as NumberOrders,
sum( oi.quantity * p.price ) as OrderTotal
from
orders o
join order_items oi
on o.order_id = oi.order_id
join parts p
on oi.part_id = p.part_id
where
o.Delivery_Date >= CURDATE()
group by
o.Account_ID ) as PreQualified
JOIN Accounts a
on PreQualified.Account_ID = a.Account_ID
Join Contact C
on a.Account_ID = c.Account_ID
JOIN Sales_Reps sr
ON a.sales_rep_id = sr.sales_rep_id
If you want to count records use
count(*)
Instead of
count(o.order_id)
As the title says, i am trying to find the customer's who have made orders but have not made payments yet.
I have Three tables;
Customers, Payments, Orders
The sql i have so far gives me (nested query) all the customers without payments, the outer query then tries to join all the customers with orders and checks if those customers are not in my inner table?
SELECT customerWOpayments.customerNumber FROM
ClassicModels.Customers c
INNER JOIN ClassicModels.Orders o ON c.customerName = o.customerNumber
NOT IN
(SELECT distinct c.customerNumber
FROM ClassicModels.Customers c
LEFT OUTER JOIN ClassicModels.Payments p ON c.customerNumber = p.customerNumber
WHERE p.customerNumber IS NULL) customerWOpayments;
I am getting a mysql syntax error at line 8 but cannot figure out why?
This should return customers who have orders but no matching payment assuming all of the keys you joined on in your original example were correct (for example c.customerName = o.customerNumber seems suspicious).
SELECT c.customerNumber
FROM ClassicModels.Customers c
INNER JOIN ClassicModels.Orders o
ON c.customerNumber = o.customerNumber
LEFT OUTER JOIN ClassicModels.Payments p
ON c.customerNumber = p.customerNumber
WHERE p.customerNumber IS NULL;
Basically you missed the WHERE clause. And your question lacks information. Please provide the Schema of your tables. Thanks!
try this one:
Are you sure with this condition ON c.customerName = o.customerNumber?
SELECT customerWOpayments.customerNumber
FROM ClassicModels.Customers c INNER JOIN ClassicModels.Orders o
ON c.customerName = o.customerNumber -- Please check this out
WHERE o.customerNumber NOT IN
(SELECT distinct c.customerNumber
FROM ClassicModels.Customers c LEFT JOIN ClassicModels.Payments p
ON c.customerNumber = p.customerNumber
WHERE p.customerNumber IS NULL);
OR Without Subquery
SELECT a.*
FROM Customers a INNER JOIN Orders b ON
a.CustomerName = b.CustomerNumber -- Please check this line
LEFT JOIN Payments c ON
b.CustomerNumber = c.CustomerNumber
WHERE c.CustomerNumber IS NULL
I believe it's a typo error on a.CustomerName = b.CustomerNumber, instead a.CustomerNumber = b.CustomerNumber
I can't tell exactly if it is because you didn't provide the schema of your tables with some dummy records.
Hope this helps.
Unlike the other solutions, this solution will not produce duplicate customer numbers when customers have more than one order.
SELECT C.customerNumber
FROM ClassicModels.Customers C
WHERE
EXISTS(
-- customer has orders
SELECT *
FROM ClassicModels.Orders AS O
WHERE O.customerNumber = C.customerNumber
)
AND NOT EXISTS(
-- customer does not have payments
SELECT *
FROM ClassicModels.Payments P
WHERE P.customerNumber = C.customerNumber
)
In my query below, i am trying to join one result set to another using the customerNumber identifier. I want to find each customer's amount ordered and the amount paid. The sql does not execute with no help from Navicat Client
SELECT DISTINCT tabl1.customerNumber,
tabl1.amountOrdered, tabl2.amountPaid
FROM
(
SELECT Distinct c.customerNumber, o.orderNumber,
SUM(od.quantityOrdered * od.priceEach) amountOrdered
FROM ClassicModels.Customers c
INNER JOIN ClassicModels.Orders o
ON c.customerNumber = o.customerNumber
INNER JOIN ClassicModels.OrderDetails od
ON o.orderNumber = od.orderNumber
GROUP BY od.orderNumber
ORDER BY c.customerNumber
) tabl1
INNER JOIN
(
SELECT DISTINCT c.customerNumber, p.amount amountPaid
FROM ClassicModels.Customers c
INNER JOIN ClassicModels.Payments p
ON c.customerNumber = p.customerNumber
) tabl2 ON tabl1.customerNumber = tabl2.customerNumber
If you want to select each customer's amount ordered and amount paid, this much simpler query should work:
SELECT o.customerNumber as customerNumber,
SUM(od.quantityOrdered * od.priceEach) as amountOrdered,
SUM(p.amount) as amountPaid
FROM ClassicModels.Orders o
INNER JOIN ClassicModels.OrderDetails od
ON o.OrderNumber = od.OrderNumber
LEFT JOIN ClassicModels.Payments p
ON p.customerNumber = o.customerNumber
GROUP BY o.customerNumber