For the schema below, I need to get this report
This is what I have
select c.name, sr.name, count(o.order_id)
from contact c
INNER JOIN accounts a
ON c.account_id=a.account_id
INNER JOIN sales_reps sr
ON a.sales_rep_id =sr.sales_rep_id
INNER JOIN orders o
ON a.account_id =o.account_id
where o.order_id in (
select SUM(oi.quantity*p.price) from
order_items oi INNER JOIN parts p
on oi.part_id =p.part_id
)
group by a.account_id, c.name
But this does not give any results.
Please help.
Your where condition is not right, how should be a order_id equal a sum?
Try the below:
select
c.name, sr.name, COUNT(o.order_id), SUM(op.order_total)
FROM
contact c
INNER JOIN
accounts a ON c.account_id = a.account_id
INNER JOIN
sales_reps sr ON a.sales_rep_id = sr.sales_rep_id
INNER JOIN
orders o ON a.account_id = o.account_id
INNER JOIN
(SELECT
oi.order_id, SUM(oi.quantity * p.price) AS order_total
FROM
order_items oi
INNER JOIN
parts p ON oi.part_id = p.part_id
GROUP BY
oi.order_id
) op ON o.order_id = op.order_id
WHERE o.delivery_data >= CURDATE()
GROUP by c.contact_id
It won't give results as your WHERE ... IN SELECT is based on a query returning a sum() value which will not equal a key (most likely), or incorrect at best... and since you are dealing with a quantity and price which will have decimal precision (typically), you won't even get that to match even LESS likely...
I would swap the query around to pre-qualify the orders within a given date in question and sum that... THEN join to rest...
select
c.name,
sr.name,
PreQualified.NumberOrders,
PreQualified.OrderTotal
from
( select
o.Account_ID,
count( distinct o.order_id ) as NumberOrders,
sum( oi.quantity * p.price ) as OrderTotal
from
orders o
join order_items oi
on o.order_id = oi.order_id
join parts p
on oi.part_id = p.part_id
where
o.Delivery_Date >= CURDATE()
group by
o.Account_ID ) as PreQualified
JOIN Accounts a
on PreQualified.Account_ID = a.Account_ID
Join Contact C
on a.Account_ID = c.Account_ID
JOIN Sales_Reps sr
ON a.sales_rep_id = sr.sales_rep_id
If you want to count records use
count(*)
Instead of
count(o.order_id)
Related
I have tables named company, product, purchase_order, skid, process_record and I want MySQL query result as below.
I tried
SELECT s.id as skidId, s.skidBarcode, po.poNumber, s.companyId, c.companyName, p.productId , p.productName, totalProcessed
FROM skid s
INNER JOIN company c ON s.companyId = c.id
INNER JOIN purchase_order po on s.purchaseOrderId = po.id
INNER JOIN product prdct on p.productId = prdct.id
LEFT JOIN (SELECT skidID, productId , COUNT(*) as processedQuantity FROM process_record GROUP BY productId ) p ON p.skidID= s.id
WHERE s.status = 'closed' ORDER By s.companyId,s.id
However, this query result gives processedQuantity count NULL and random wrong count on some rows.
How can I get the desired MySQL query output as shown in screenshot?
I added GROUP BY skidID, productId instead of GROUP BY productId and it resolved the issue.
SELECT s.id as skidId, s.skidBarcode, po.poNumber, s.companyId, c.companyName, p.productId , p.productName, totalProcessed
FROM skid s
LEFT JOIN (SELECT skidID, productId , COUNT(*) as processedQuantity FROM process_record GROUP BY skidID, productId ) p ON p.skidID= s.id
INNER JOIN company c ON s.companyId = c.id
INNER JOIN purchase_order po on s.purchaseOrderId = po.id
INNER JOIN product prdct on p.productId = prdct.id
WHERE s.status = 'closed' ORDER By s.companyId,s.id
I have created two queries that both return the required results independent of each other. I am trying to join them to have the returned values be customerName, Amount Ordered, and Amount Paid.
Currently, this query works but only returns the customerName. How can it get the query to return the other two columns?
SELECT c1.customerName
FROM
(SELECT cc.customerName, ROUND(SUM(od.priceEach * od.quantityOrdered), 2) as '$ Amount Ordered'
FROM customers cc
INNER JOIN orders o ON o.customerNumber = cc.customerNumber
INNER JOIN orderdetails od ON od.orderNumber = o.orderNumber
GROUP BY cc.customerName
) c1
INNER JOIN
(SELECT c.customerName, ROUND(SUM(p.amount), 2) as 'Total $ Amount Paid'
FROM customers c
INNER JOIN payments p ON p.customerNumber = c.customerNumber
GROUP BY c.customerName
) c2
WHERE c1.customerName = c2.customerName
GROUP BY c1.customerName
ORDER BY c1.customerName;
this should select the others column
SELECT c1.customerName, c1.Amount_Ordered as '$ Amount Ordered', c2.Total_Amount_Paid as 'Total $ Amount Paid'
FROM
(SELECT cc.customerName, ROUND(SUM(od.priceEach * od.quantityOrdered), 2) as Amount_Ordered
FROM customers cc
INNER JOIN orders o ON o.customerNumber = cc.customerNumber
INNER JOIN orderdetails od ON od.orderNumber = o.orderNumber
GROUP BY cc.customerName
) c1
INNER JOIN
(SELECT c.customerName, ROUND(SUM(p.amount), 2) as Total_Amount_Paid
FROM customers c
INNER JOIN payments p ON p.customerNumber = c.customerNumber
GROUP BY c.customerName
) c2
WHERE c1.customerName = c2.customerName
GROUP BY c1.customerName
ORDER BY c1.customerName;
simply add them to the select section:
SELECT c1.customerName, C1.amountOrdered, C2.amountPaid FROM ...
And one more word of advice - DONT use whitespace or special signs like $ in your column names, it is bad practice. I think it's a mistake that mySql even allows it
I'm trying to get the total rental amount for each client from Sakila example database
so I tried with the following query:
select customer.customer_id, customer.first_name,
(select sum(payment.amount) from customer
inner join rental on customer.customer_id=rental.customer_id
inner join payment on rental.rental_id=payment.rental_id group by payment.amount)
from customer
inner join rental on customer.customer_id=rental.customer_id
inner join payment on rental.rental_id=payment.rental_id
group by customer.customer_id;
and I get this "Subquery returns more than one row". Do you know what could be wrong? Thank you
This is your query, with some reformatting and the use of table aliases:
select c.customer_id, c.first_name,
(select sum(p2.amount)
from customer ce inner join
rental r2
on c2.customer_id = r2.customer_id inner join
payment p2
on r2.rental_id = p2.rental_id
group by p2.amount
-------^
)
from customer c inner join
rental r
on c.customer_id = r.customer_id inner join
payment p
on r.rental_id = p.rental_id
group by c.customer_id;
I've highlighted the specific cause of your problem. But the fix is to radically simplify the query:
select c.customer_id, c.first_name, sum(p.amount)
from customer c left join
rental r
on c.customer_id = r.customer_id left join
payment p
on r.rental_id = p.rental_id
group by c.customer_id;
Is that the result you're looking for?
SELECT C.customer_id
,C.first_name
,SUM(P.amount) AS [total_amount]
FROM customer C
INNER JOIN rental R ON R.customer_id = C.customer_id
INNER JOIN payment P ON P.rental_id = R.rental_id
GROUP BY C.customer_id, C.first_name
-- Condition to get only the largest amount
-- without using an ORDER BY clause
HAVING SUM(P.amount) = (SELECT MAX(SUM(P2.amount))
FROM rental R2
INNER JOIN payment P2 ON P2.rental_id = R2.rental_id
GROUP BY R2.customer_id)
Hope this will help you.
In my query below, i am trying to join one result set to another using the customerNumber identifier. I want to find each customer's amount ordered and the amount paid. The sql does not execute with no help from Navicat Client
SELECT DISTINCT tabl1.customerNumber,
tabl1.amountOrdered, tabl2.amountPaid
FROM
(
SELECT Distinct c.customerNumber, o.orderNumber,
SUM(od.quantityOrdered * od.priceEach) amountOrdered
FROM ClassicModels.Customers c
INNER JOIN ClassicModels.Orders o
ON c.customerNumber = o.customerNumber
INNER JOIN ClassicModels.OrderDetails od
ON o.orderNumber = od.orderNumber
GROUP BY od.orderNumber
ORDER BY c.customerNumber
) tabl1
INNER JOIN
(
SELECT DISTINCT c.customerNumber, p.amount amountPaid
FROM ClassicModels.Customers c
INNER JOIN ClassicModels.Payments p
ON c.customerNumber = p.customerNumber
) tabl2 ON tabl1.customerNumber = tabl2.customerNumber
If you want to select each customer's amount ordered and amount paid, this much simpler query should work:
SELECT o.customerNumber as customerNumber,
SUM(od.quantityOrdered * od.priceEach) as amountOrdered,
SUM(p.amount) as amountPaid
FROM ClassicModels.Orders o
INNER JOIN ClassicModels.OrderDetails od
ON o.OrderNumber = od.OrderNumber
LEFT JOIN ClassicModels.Payments p
ON p.customerNumber = o.customerNumber
GROUP BY o.customerNumber
I currently have this query.
SELECT DISTINCT (o.customer_id), count( o.id ) AS orders, c.*
FROM `order` AS o LEFT JOIN customer AS c ON o.customer_id = c.id
GROUP BY customer_id
What it does is it returns all customers that have made an order and counts the number of orders each customer has made.
What I need to do is modify this query so it also returns those customers who haven't made an order. Do you have any idea how this would be done?
I tried to reverse the query but this didn't do the trick..
SELECT DISTINCT (o.customer_id), count( o.id ) AS orders, c.*
FROM customer AS c LEFT JOIN order AS o ON o.customer_id = c.id
GROUP BY o.customer_id
Try this.
SELECT o.customer_id, sum( case when o.id is not null then 1 else 0 end ) AS orders, c.*
FROM customer c
LEFT JOIN order o ON o.customer_id = c.id GROUP BY customer_id
What about:
SELECT DISTINCT (o.customer_id), count( o.id ) AS orders, c.*
FROM `order` AS o
LEFT OUTER JOIN customer AS c ON o.customer_id = c.id GROUP BY customer_id
SELECT o.customer_id, c.*
FROM customer AS c LEFT JOIN order AS o ON o.customer_id = c.id
WHERE o.id IS NULL
GROUP BY o.customer_id
You can also skip the "GROUP BY" clause because when the orders side is NULL, there is always only one row for the customer:
SELECT o.customer_id, c.*
FROM customer AS c LEFT JOIN order AS o ON o.customer_id = c.id
WHERE o.id IS NULL