$index as a parameter : multiple if statement issue - function

Please take a look at this function :
function my_func($index_bis) {
if (!is_int($index_bis) || $index_bis > 5 || $index_bis < 0) return;
elseif ($index_bis = 5) : echo 'This';
elseif ($index_bis = 1) : echo 'That';
endif;
}
What's wrong with this? I actually can't understand where is the mistake...
Thank you for your help.

What is this? PHP?
And what are you attempting to do?
How about this:
function my_func($index_bis) {
if (!is_int($index_bis) || $index_bis > 5 || $index_bis < 0){
$str = $index_bis;
}
elseif ($index_bis == 5) {
$str='This';
}
elseif ($index_bis == 1) {
$str='That';
}
return $str;
}
It's pretty atypical to put anything after "return"; and I think "return" stops the function, effectively.
Edit: FOREACH method.
If you are building html from two related variables, FOREACH is a great method for handling them, as you can set a data "key" and "value" for each item in the array.
By default, the "key" in PHP is assigned a number, starting from 0 and progressing through increasing integers. You have the option of naming these keys, instead of using the PHP-assigned default.
So consider setting up your array as such:
$newArray = (
'tab name' => 'label name',
'apples' => 'red',
'oranges' => 'orange',
);
Wherein the item to the left of the "=>" is always the key, and the item to the right is always the value.
Then, you can add more elements to this array in your code by using this line:
$newArray['bananas'] = 'yellow';
Note the key (tab) name, with square brackets (because it is the key name) and single quotes (because it is a string).
Now that you have an array, you can "walk" it using a FOREACH loop and echoing the html. Here is the code:
foreach($newArray as $key => $value) {
echo "<tab>$key</tab> : ";
echo "<label>$value</label>
echo "<br /";
}
This will output the html below:
<tab>tab name</tab> : <label>label name</label><br />
<tab>apples</tab> : <label>red</label><br />
<tab>oranges</tab> : <label>orange</label><br />
<tab>bananas</tab> : <label>yellow</label><br />
Very useful. Have fun!
Note: There are likely better ways to do this, but I'm sharing this one as a simple solution. And also, because you shouldn't go further without understanding both FOREACH and simple arrays.
Note: If you want to incorporate more than two variables, you will need a more complex data structure. In PHP, these are called "multidimensional arrays". Give it a read. Beyond that, there are still more methods for handling data (ie. "objects").

Related

MYSQL How can I make dropdown list?

I created a new table in workbench where I want to put a season of a soccer championship.
I don't want to write down every time the team's names, can you help me pls, how can I make like a dropdown list (or set of values, what are the only options for that column), when I begin to type "Bay..." its automatically offer "Bayern München" as the only option.
I don't know how much will this help, but I have made a dropdown list for something else and I hope my way might give you an idea:
foreach ($dbo->query($sql) as $row) //Array or records stored in $row
{
if($row[id]==10)
{
echo "<option value=$row[id] selected>$row[name]</option>";
}
else
{
echo "<option value=$row[id]>$row[name]</option>";
}
}
echo "</select>"; // Closing of list box
As the same answer above, but using short-hand ternary operator instead of if-else statement, and don't forget to use ' or " when reference to object string index.
foreach ($dbo->query($sql) as $row) //Array or records stored in $row
{
printf("<option value='%s' %s>%s</option>", $row['id'], $row['id'] == 10 ? 'selected' : '', $row['name']);
}
}
echo "</select>"; // Closing of list box

What is the best way to add some codes before a function in cakephp3?

I want to convert $token to lower case before I call the __($token) function.
How can I do this in a clean manner?
Possible solutions:
1. Manipulation the original function.
public function __($token, $args = null) {
if (!$token) {
return null;
}
$lowerCase = strtolower($token);
$arguments = func_num_args() === 2 ? (array)$args : array_slice(func_get_args(), 1);
$translation = I18n::translator()->translate($lowerCase , $arguments);
return $translation == $lowerCase ? $token : $translation;
}
I think it's not a good idea.
2. Using somethings like beforeFilter. It's better way.
3. Redeclaring function where I need. It's really bad idea :)
Any solution or best solution is appreciated.

Compare a current user against a list of employees logged into computers Perl, CGI

Not sure I am doing this correctly as it doesn't appear to be working.
Is this the correct way to declare my users, and is the If statement correctly formated?
At the top I have declared:
my $las = 'jpietrza hpietrza oszones';
These are employees we are checking against current users.
Further down in the code, I want to change the text color that is printed if the user is in the list vs. someone else.
while ( $sth->fetch() ) {
next unless defined $currentuser;
$lastlogin =~ s/ .*$//;
$host_name =~ s/1408//;
foreach ( #las ) {
if ( $currentuser eq "$_" ) {
$lacolor = "black";
last;
}
else {
$lacolor = "red";
}
}
print "<tr>";
print "<td>$host_name</td>";
print "<td><font color=\"$lacolor\">System In-Use (User Undisclosed)</font></td><td> </td>";
}
maybe there was nothing wrong with the if statement, but the whole 9 lines of code can be condensed to 1 very readable line:
$lacolor = any { /^$currentuser$/ } #las ? "black" : "red";
please
use List::Util qw/any/;
while($sth->fetch()) {
# $currentuser is assigned between the 'while' and this 'next' statement ?
# if not, then outside the loop and do not loop at all unless defined
next unless defined $currentuser;
$lastlogin=~s/ .*$//;
$host_name=~s/1408//;
$lacolor = any { /^$currentuser$/ } #las ? "black" : "red";
print "<tr>";
print "<td>$host_name</td>";
print "<td><font color=\"$lacolor\">System In-Use (User Undisclosed)</font></td><td> </td>";
}
please, also use strict; and use warnings;
I figured out how to put the array together correctly:
my #las = qw(
jpietrza
hpietrza
oszones
);
instead of:
my $las='
jpietrza
hpietrza
oszones
';
Firstly, as I think you have worked out now, the scalar variable $las and the array #las are completely different. As you've seen, you should declare and initialise your array like this:
my #las = qw(
jpietrza
hpietrza
oszones
);
Actually, I suspect this all gets easier if you store this in a hash, not an array;
my %las = map { $_ => 1 } qw(jpietrza hpietrza oszones);
Then your check just becomes:
my $lacolour = $las{$currentuser} ? 'black' : 'red';
A few more points:
Please add use strict and use warnings. And understand and fix the problems they reveal.
The quotes are unnecessary in if ($currentuser eq "$_").
Using a templating system to create the output will make your life a lot easier.
Update: Oh, and one I forgot earlier. It's 2017. No-one has used the font element in HTML for fifteen years. Take a look at CSS.

echo a variable from a multidimentional array outside a function

The code below works for a string value but not when I try to access the variable directly.
The data being accessed is a table at http://webrates.truefx.com/rates/connect.html?f=html
My code strips it of tags and put it in an array $row0
And puts it in a function. But I can't get it out. The function is simplified for this question. I intend to concatenate some of the variables inside the function once I find out what I'm doing wrong.
$row0 = array();
include "scrape/simple_html_dom.php";
$url = "http://webrates.truefx.com/rates/connect.html?f=html";
$html = new simple_html_dom();
$html->load_file($url);
foreach ($html->find('tr') as $i => $row) {
foreach ($row->find('td') as $j => $col) {
$row0[$i][$j]= strip_tags($col);
}
}
myArray($row0); //table stripped of tags
function myArray($arr) {
$a = 'hello'; //$arr[0][0]; HELLO will come out but not the variable
$b = $arr[1][0];
$r[0] = $a;
$r[1] = $b;
//echo $r[1]; If the //'s are removed one can see the proper value here but not outside the function.
return $r;
}
$arrayToEcho = myArray($arr);
echo $arrayToEcho[0]; // will echo "first"
I have tried all the suggestions from here:
http://stackoverflow.com/questions/3451906/multiple-returns-from-function
http://stackoverflow.com/questions/5692568/php-function-return-array
Suggestion appreciated please and more info available if required. Thank you very much for viewing.
You need to get the innertext of $col in your loop. Like this:
$row0[$i][$j]= $col->innertext;
The next thing is:
myArray($row0);
This call will correctly return the parsed array; try echoing it and you'll see. But when you do this:
$arrayToEcho = myArray($arr);
...you're referencing to $arr which is a local variable (a parameter, actually) inside your function myArr. So what you probably meant was this:
$arrayToEcho = myArray($row0);
Hope this helps!
UPDATE
Look, I show you what happens when you call a function:

Multidimensional Array insert into Mysql rows

I have an Array (twodimensional) and i insert it into my database.
My Code:
$yourArr = $_POST;
$action = $yourArr['action'];
$mysql = $yourArr['mysql'];
$total = $yourArr['total'];
unset( $yourArr['action'] , $yourArr['mysql'] , $yourArr['total'] );
foreach ($yourArr as $k => $v) {
list($type,$num) = explode('_item_',$k);
$items[$num][$type] = $v;
$pnr= $items[$num][pnr];
$pkt= $items[$num][pkt];
$desc= $items[$num][desc];
$qty= $items[$num][qty];
$price= $items[$num][price];
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
I get 5 inserts in the Database but only the 5th have the informations i want. The firsts are incomplete.
Can someone help me?
Sorry for my english.
check if You have sent vars from browser in array (like
input name="some_name[]" ...
also You can check, what You get at any time by putting var_dump($your_var) in any place in script.
good luck:)
You probably want to have your query and the 5 assignments above that outside of the foreach. Instead in a new loop which only executes once for every item instead of 5 times. Your indentation even suggests the same however your brackets do not.
Currently it is only assigning one value each time and executing a new query. After 5 times all the variables are assigned and the last inserted row finally has everything proper.
error_reporting(E_ALL);
$items = array();
foreach($yourArr as $k => $v) {
// check here if the variable is one you need
list($type, $num) = explode('_item_', $k);
$items[$num][$type] = $v;
}
foreach($items as $item) {
$pnr = mysql_real_escape_string($item['pnr']);
$pkt = mysql_real_escape_string($item['pkt']);
$desc = mysql_real_escape_string($item['desc']);
$qty = mysql_real_escape_string($item['qty']);
$price = mysql_real_escape_string($item['price']);
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
Switching on your error level to E_ALL would have hinted in such a direction, among else:
unquoted array-keys: if a constant of
the same name exists your script will
be unpredictable.
unescaped variables: malformed values
or even just containing a quote which
needs to be there will fail your
query or worse.
naïve exploding: not each $_POST-key
variable will contain the string
item and your list will fail, including subsequent use of $num