I have a table like this:
| ID1 | ID2 |
------------------
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
| 5 | 1 |
| 6 | 1 |
| 7 | 1 |
| 8 | 1 |
| 9 | 1 |
| 10 | 1 |
| 11 | 1 |
| 12 | 1 |
| 13 | 1 |
| 1 | 2 |
| 2 | 2 |
| 5 | 2 |
| 1 | 4 |
| 9 | 4 |
Some of the ID1s have both the 1 and 4 values like this:
And I would like to return the ID1s like this:
| ID1 |
----------
| 1 |
| 9 |
I have tried some basic queries but Im not even close.. I just cannot get this to work even remotely and I need some serious help with this one.
Try this:
select id1
from yourtable
where id2 in (1,4)
group by id1
having count(distinct id2) = 2
Demo Here
If ID1 is supposed to have only one unique value then the following query would work for you:
SELECT
ID1
FROM your_table
GROUP BY ID1
HAVING COUNT(DISTINCT ID2) > 1;
EDIT: May be you are looking for those entries having ID2 as 1 and 4 both.
SELECT
ID1
FROM your_table
WHERE ID2 IN (1,4)
GROUP BY ID1
HAVING COUNT(DISTINCT ID2) = 2;
Note: It would have been better if you clarify what combination of ID1 & ID2 is supported in your table.
Related
Here is my table:
// table
+----+------+------+
| id | col1 | col2 |
+----+------+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 2 | 1 |
| 5 | 2 | 2 |
| 6 | 3 | 1 |
| 7 | 3 | 2 |
| 8 | 3 | 3 |
| 9 | 3 | 4 |
| 10 | 3 | 5 |
+----+------+------+
Now I want to search in both col1 and col2. Something like this:
select * from table where col1,col2 IN (1,2);
And I want this output:
+----+------+------+
| id | col1 | col2 |
+----+------+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 2 | 1 |
| 5 | 2 | 2 |
| 6 | 3 | 1 |
| 7 | 3 | 2 |
+----+------+------+
Well, My problem is on this part: ... where col1,col2 IN (1,2). How can I solve it?
Note: I can do that like this: ... where col1 IN (1,2) or ,col2 IN (1,2). But this this way, I have to create two separate index on each column. While I want a query which need to a group-index like this: KEY NameIndex (col1, col2)
You want this, correct?
WHERE col1 IN (1,2)
OR col2 IN (1,2)
If so, turn the OR into a UNION. (This is a common optimization trick.)
( SELECT ... WHERE col1 IN (1,2) )
UNION DISTINCT -- since there are likely to be dups
( SELECT ... WHERE col2 IN (1,2) );
And provide the optimal index for each SELECT:
INDEX(col1),
INDEX(col2)
A composite index of those two columns will not suffice.
(Appologies -- this is probably a summary of best of the many disjointed comments.)
I have two tables containing fields as below.
Table 1
| SetID | InQty | Day |
| 1 | 10 | 1 |
| 2 | 10 | 2 |
| 3 | 10 | 3 |
Table 2
| SetID | OtQty | Day |
| 1 | 1 | 5 |
| 1 | 2 | 6 |
| 1 | 3 | 7 |
SetID in table 2 is linked with SetId in table 1. Day is placed in place of date, just for convenience only. Expected Output,
| Day | InQty | OtQty |
| 1 | 10 | |
| 5 | | 1 |
| 6 | | 2 |
| 7 | | 3 |
Blank Space can be filled with NULL or Zero.
It appears you are querying ONLY for set ID = 1 otherwise, I would expect to see in/out values for Set 2 and 3. You should be able to get with a simple UNION
select t1.Day, t1.InQty, 0 OutQty
from Table1 t1
where SetID = 1
order by t1.Day
union select t2.Day, 0, t2.OtQty
from Table2 t2
where SetID = 1
Now, if you want totals spanning different "setID"s and keeping them differentiated from each other, just add the setID as a column and also add to the group by clause as well.
Suppose I have such a table:
+-----+---------+-------+
| ID | TIME | DAY |
+-----+---------+-------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 1 | 1 | 2 |
| 2 | 2 | 2 |
| 3 | 3 | 2 |
| 1 | 1 | 3 |
| 2 | 2 | 3 |
| 3 | 3 | 3 |
| 1 | 1 | 4 |
| 2 | 2 | 4 |
| 3 | 3 | 4 |
| 1 | 1 | 5 |
| 2 | 2 | 5 |
| 3 | 3 | 5 |
+-----+---------+-------+
I want to fetch a table which represents 2 IDs which got the largest sum of TIME within the last 3 days (means from 3 to 5 in a DAY column)
So the correct result would be:
+-----+---------+
| ID | SUM |
+-----+---------+
| 3 | 9 |
| 2 | 6 |
+-----+---------+
The original table is much larger and more complex. So i need a generic approach.
Thanks in advance.
And so I just learned that MySQL used LIMIT instead of TOP...
fiddle
CREATE TABLE tbl (ID INT,tm INT,dy INT);
INSERT INTO tbl (id, tm, dy) VALUES
(1,1,1)
,(2,2,1)
,(3,3,1)
,(1,1,2)
,(1,1,1)
SELECT ID
,SUM(SumTimeForDay) SumTimeFromLastThreeDays
FROM (SELECT ID
,SUM(tm) SumTimeForDay
FROM tbl
GROUP BY ID, dy
HAVING dy > MAX(dy) -3) a
GROUP BY id
ORDER BY SUM(SumTimeForDay) DESC
LIMIT 2
select t1.`id`, sum(t1.`time`) as `sum`
from `table` t1
inner join ( select distinct `day` from `table` order by `day` desc limit 3 ) t2
on t2.`da`y = t1.`day`
group by t1.`id`
order by sum(t1.`time`) desc
limit 2
I'm working on a huge dataset, with a table that looks like this :
+----+---------+--------+--------+
| id | otherid | value1 | value2 |
+----+---------+--------+--------+
| 1 | 1 | 2 | 5 |
| 1 | 1 | 4 | 8 |
| 1 | 2 | 3 | 6 |
| 2 | 123 | 1 | 4 |
+----+---------+--------+--------+
I need to multiply value1 and value2 for each row, and sum values per id and otherid. A result table might be:
+----+---------+-----+
| id | otherid | sum |
+----+---------+-----+
| 1 | 1 | 42 | ((2*5)+(4*8))
| 1 | 2 | 18 | (3*6)
| 2 | 123 | 4 | (1*4)
+----+---------+-----+
My question is if it is possible to avoid subqueries to do this, I only found solutions that used them.
Thanks!
it's easy.
SELECT id,
otherid,
SUM(value1*value2) AS sum
FROM your_table
GROUP BY id, otherid;
Try Below Query
SELECT ID,otherid ,SUM(value1 * value2) sum
FROM TABLE1
GROUP BY ID,otherid
I have one table like this:
+----+---------+-------------+
| id | site_id | search_term |
+----+---------+-------------+
| 1 | 2 | apple |
| 2 | 2 | banana |
| 3 | 3 | cheese |
| 4 | 1 | aubergine |
+----+---------+-------------+
And another like this:
+----+---------+-------------+
| id | site_id | search_term |
+----+---------+-------------+
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 1 |
| 5 | 3 | 3 |
| 6 | 1 | 4 |
+----+---------+-------------+
I want to find out how many times each search_term shows up in the 2nd table, and how many times.
In other words, from this data, if I was asking about site_id 2, I'd want this to be returned:
+-------------+-------+
| search_term | count |
+-------------+-------+
| apple | 3 |
| banana | 1 |
+-------------+-------+
I'm familiar with basic joins and such, as well as COUNT, but I'm not sure how to count things from another table.
Thanks!
You could join the tables together, and count the number of rows in the second table:
select t1.search_term
, count(t2.id)
from table1 t1
left join table2 t2
on t1.id = t2.search_term
group by t1.search_term
Give this a try:
select t1.search_term, count(*) from t1
join t2 on t1.id = t2.search_term and t1.site_id = t2.site_id
where t1.site_id = 2
group by t1.search_term