how can I count the
mysql_fetch_array($res)
because when i am puting it like this it will playing an infinite loop:
$count= mysql_fetch_array($res);
While($count)
{
}
Please tell me a method to solve this query via variable.
If you want to get the number of rows in the results, you can simply use
$count = mysql_num_rows($res);
If you want to count them in a loop, you need to call mysql_fetch_array() each time through the loop, and increment a counter inside the loop.
$count = 0;
while ($row = mysql_fetch_array($res)) {
$count++;
// do something with $row
}
Related
The code below works for a string value but not when I try to access the variable directly.
The data being accessed is a table at http://webrates.truefx.com/rates/connect.html?f=html
My code strips it of tags and put it in an array $row0
And puts it in a function. But I can't get it out. The function is simplified for this question. I intend to concatenate some of the variables inside the function once I find out what I'm doing wrong.
$row0 = array();
include "scrape/simple_html_dom.php";
$url = "http://webrates.truefx.com/rates/connect.html?f=html";
$html = new simple_html_dom();
$html->load_file($url);
foreach ($html->find('tr') as $i => $row) {
foreach ($row->find('td') as $j => $col) {
$row0[$i][$j]= strip_tags($col);
}
}
myArray($row0); //table stripped of tags
function myArray($arr) {
$a = 'hello'; //$arr[0][0]; HELLO will come out but not the variable
$b = $arr[1][0];
$r[0] = $a;
$r[1] = $b;
//echo $r[1]; If the //'s are removed one can see the proper value here but not outside the function.
return $r;
}
$arrayToEcho = myArray($arr);
echo $arrayToEcho[0]; // will echo "first"
I have tried all the suggestions from here:
http://stackoverflow.com/questions/3451906/multiple-returns-from-function
http://stackoverflow.com/questions/5692568/php-function-return-array
Suggestion appreciated please and more info available if required. Thank you very much for viewing.
You need to get the innertext of $col in your loop. Like this:
$row0[$i][$j]= $col->innertext;
The next thing is:
myArray($row0);
This call will correctly return the parsed array; try echoing it and you'll see. But when you do this:
$arrayToEcho = myArray($arr);
...you're referencing to $arr which is a local variable (a parameter, actually) inside your function myArr. So what you probably meant was this:
$arrayToEcho = myArray($row0);
Hope this helps!
UPDATE
Look, I show you what happens when you call a function:
I am using Zend fetch method to fetch huge number of records from database for creating reports.Since fetchAll is costly as compared to fetch i am using it.And if its the last row i need to add some additinoal logic.So my question is that is there a way to check if next record exists or not inside the while loop. I am using it like the following
//$select is the select query
$objDb = Zend_Registry::get('db');
$objAchQry = $objDb->query($select);
while($arrResult = $objAchQry->fetch()) {
//Do something
//I need to do something here if its the last record like
/*
if($last_rec)
do something
*/
}
Is there a way to check if the current one is last record or if any other record exists. I know to do it by taking count of records and incrementing a counter inside the loop.But i dont need it.Any solutions.?
"is there a way to check if next record exists" The condition on your while loop does exactly just that. The loop won't execute any more if no more rows exist to fetch.
Think of it this way:
while($arrResult = $objAchQry->fetch()) {
//Do something
}
// Now I'm just after the last record
/*
do something
*/
If you really need to do something before the last row is processed, you could modify your code to
$total_records = // get total no of rows
$counter = 0;
while($arrResult = $objAchQry->current()) {
//Do something
$counter ++;
//I need to do something here if its the last record like
if( ! $bojAchQry->next()) {
// The row currently being processed is the last one.
} else {
break;
}
}
One way - You can track with counter,
$total_records = // get total no of rows
$counter = 0;
while($arrResult = $objAchQry->fetch()) {
//Do something
$counter ++;
//I need to do something here if its the last record like
if($counter == $total_records ) // this iteration will be the last one.
//do something
}
I have following mysql query
SELECT count(order_id), date FROM tbl_order WHERE campaign_status = 'In Progress' or campaign_status = 'Pending' GROUP BY DATE_FORMAT(date,'%d %b %y')
and then following loop
<?php do { ?>
['<?php echo $row_chartData['date']; ?>', <?php echo $row_chartData['count(order_id)']; ?>],
<?php } while ($row_chartData = mysql_fetch_assoc($chartData)) ?>
this loop is used to create data for my chart. Now the problem is that there are certain days that users dont make orders in my store so those dates are not stored inside database, so when I loop trough those dates are not showed in above results and inside the chart.
The question I have, is there any way to show those missing dates in loop above even if they dont exist inside mysql database.
Thanks for help.
Well, in this case, create a temporary array based on the date range, e.g. if you want to show the graph from May 1, to May 31.
Loop from 1 to 30,
set $data[i] = 0;
Now loop through the db records and set
$data['date'] = $row['count']
Yes.
Firstly make $row_chartData as array instead of a mysql_result.
1) find the min date in the range or whichever date you want to start with
function _getDate($row) {
return $row['date'];
}
$dates = array_map('_getDate', $row_chartData);
$minDate = min($dates);
2) find the max date in the range or whichever date you want to end with
$maxDate = min($dates);
$dateRangeArray = array();
$date = $minDate;
while($date < $maxDate) {
$dateRangeArray[] = $date;
$date = date('Y-m-d', strtotime($date . ' +1 day'));
}
3) make the key of each element in your $row_chartdata array be the value of the date index
foreach($row_chartData as $key => $row) {
$row_chartData[$row['date']] = $row;
unset($row_chartData[$key]);
}
4) iterate over each of the days in the range and match that date to the index in your $row_chartdata array
foreach($dateRangeArray as $date) {
if(isset($row_chartData[$date])) {
//do whatever
}
}
I want use mysql_data_seek with PDO from google search I found that it should looks like this:
$row0 = $result->fetch(PDO::FETCH_ASSOC, PDO::FETCH_ORI_ABS, 0);
however it's not work, what I do wrong?
this is my code:
$query = "SELECT name,age FROM users";
$q = $db->prepare($query);
$q->execute();
$q->setFetchMode(PDO::FETCH_ASSOC);
$arrayData = $q->fetchAll();
foreach ($arrayData as $row){
echo $row['name'] ." ";
echo $row['age'] ."<br>";
}
$result = $q->fetch(PDO::FETCH_OBJ,PDO::FETCH_ORI_ABS,4);
var_dump($result);
I just want get the 5th row in object form from the last run query. I don't want run this query again (as some guys told me) I just want the results from sql buffer.
the var_dump result is: bool(false)
any ideas?
EDIT:
thanks for your answers and sorry but maybe I don't explain myself as well. I like the trick with JSON but the point is that the 5th row is example. I just want use the result of the query from the buffer with PDO exactly as I did it with mysql_data_seek in regular mysql (change the cursor). is it possible? I like all the tricks but that not what I look for.
the PDO 'cursor' default is PDO::CURSOR_FWDONLY that means that cursor can't back to zero like it happens with mysql_data_seek to allow cursor back to zero it necessary define use 'scrollable cursor'
example:
$db->prepare($query, array(PDO::ATTR_CURSOR => PDO::CURSOR_SCROLL));
before use it like this:
$row0 = $result->fetch(PDO::FETCH_ASSOC, PDO::FETCH_ORI_ABS, 0);
$result = $arrayData[4];
is all you need.
If you want the 5th row result you can do like this:
$result = json_decode(json_encode($arrayData[4]), FALSE);
var_dump($result);
or something like this:
$object = new stdClass();
foreach ($array as $key => $value)
{
$object->$key = $value;
}
Just curious! why do you need the object form?
EDIT (this will give the object form of the 5th row):
$index = 0;
$fifthRow = new stdClass();
while($row = $q->fetch())
{
if($index++==4)
$fifthRow = json_decode(json_encode($row), FALSE);
}
You could do it like this:
$c = 1;
$saved=null;
while($row = $q->fetch()){
if($c==4){
$saved = clone $row;
};
$c++;
somethingelse;
}
$saved will then contain the 4th element as an object with almost no extra overhead calculations.
I have an Array (twodimensional) and i insert it into my database.
My Code:
$yourArr = $_POST;
$action = $yourArr['action'];
$mysql = $yourArr['mysql'];
$total = $yourArr['total'];
unset( $yourArr['action'] , $yourArr['mysql'] , $yourArr['total'] );
foreach ($yourArr as $k => $v) {
list($type,$num) = explode('_item_',$k);
$items[$num][$type] = $v;
$pnr= $items[$num][pnr];
$pkt= $items[$num][pkt];
$desc= $items[$num][desc];
$qty= $items[$num][qty];
$price= $items[$num][price];
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
I get 5 inserts in the Database but only the 5th have the informations i want. The firsts are incomplete.
Can someone help me?
Sorry for my english.
check if You have sent vars from browser in array (like
input name="some_name[]" ...
also You can check, what You get at any time by putting var_dump($your_var) in any place in script.
good luck:)
You probably want to have your query and the 5 assignments above that outside of the foreach. Instead in a new loop which only executes once for every item instead of 5 times. Your indentation even suggests the same however your brackets do not.
Currently it is only assigning one value each time and executing a new query. After 5 times all the variables are assigned and the last inserted row finally has everything proper.
error_reporting(E_ALL);
$items = array();
foreach($yourArr as $k => $v) {
// check here if the variable is one you need
list($type, $num) = explode('_item_', $k);
$items[$num][$type] = $v;
}
foreach($items as $item) {
$pnr = mysql_real_escape_string($item['pnr']);
$pkt = mysql_real_escape_string($item['pkt']);
$desc = mysql_real_escape_string($item['desc']);
$qty = mysql_real_escape_string($item['qty']);
$price = mysql_real_escape_string($item['price']);
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
Switching on your error level to E_ALL would have hinted in such a direction, among else:
unquoted array-keys: if a constant of
the same name exists your script will
be unpredictable.
unescaped variables: malformed values
or even just containing a quote which
needs to be there will fail your
query or worse.
naïve exploding: not each $_POST-key
variable will contain the string
item and your list will fail, including subsequent use of $num