Mysql query in django view - mysql

Question

I do not have much knowledge of mysql. My django model is as follows:
class Exercise_state(models.Model):
exercise = models.ForeignKey(Exercise, blank=True, null=True)
user = models.ForeignKey(User, blank=True, null=True)
intensity_level = models.IntegerField(default='1')
progress = models.IntegerField(default='0')
current_date = models.DateField(auto_now=True)
user_rating = models.IntegerField(default='0')
I want to retrieve count of user_id's which satisfy exercise_id=1 corresponding intensity_level=7 and so on for all exercise_id's till 7. In short, users who have reached intensity_level=7 in all the exercises.
I have written one query which is as follows:
select count(user_id) from demo_exercise_state where
exercise_id=1 and intensity_level=7 and
exercise_id=2 and intensity_level=7 and
exercise_id=3 and intensity_level=7 and
exercise_id=4 and intensity_level=7 and
exercise_id=5 and intensity_level=7 and
exercise_id=6 and intensity_level=7 and
exercise_id=7 and intensity_level=7;
As far as I can cross check results from my database directly no user has yet completed his training (i.e. who has reached intensity_level=7 in all exercise types), so it returns the count as '0'.
I am sure this can query be optimized as there is quite much repeatation, but I am not sure how.
Also I want to execute the same (i.e. get the same result) in my django view. There I have something like
all_exercise_finish_count = Exercise_state.objects.filter(exercise_id=1, intensity_level=7).count()
How can I reflect the same in this django view?

Answer 1

Update
Completely changing my answer because the subsequent discussion in the comment made it clear that the OPs intentions were quite different from what it first appeared to be.
You can find the users who have completed all the 7 excercises at intensity 7 in the following way
from django.db.models.import Count
Exercise_state.objects.annotate(
c = Count('exercise').filter(c=7, exercise_id= 7)
First form of the answer is below:
The original raw query can be greatly simplified with between
expr BETWEEN min AND max
If expr is greater than or equal to min and expr is less than or equal
to max, BETWEEN returns 1, otherwise it returns 0. This is equivalent
to the expression (min <= expr AND expr <= max) if all the arguments
are of the same type. Otherwise type conversion takes place according
to the rules described in Section 13.2, “Type Conversion in Expression
Evaluation”, but applied to all the three arguments.
select count(user_id) from demo_exercise_state where
exercise_id BETWEEN 1 and 7 AND intensity_level=7
And the django query can simply be
all_exercise_finish_count = Exercise_state.objects.filter(exercise_id__gte=1, intensity_level=7, excercise_id__lte=7).count()