i have the sql below:
$result = DB::table('tblA')
->join('tblB','tblB.id', '=', 'tblA.photoid')
->join('tblB','tblB.id', '=', 'tblA.linkedphotoid')
...
I have tblA with photoid and linkedphotoid and both link to one same table(tblB) and same column.
How to write it in laravel sql?
You can add OR condition in your join
$result = DB::table('tblA')
->join('tblB', function($join) {
$join->on('tblB.id', '=', 'tblA.photoid')->orOn('tblB.id', '=', 'tblA.linkedphotoid');
})
->get();
Related
Good day all, I am trying to count all records in a table but only if the table does not contain data in a specific column (deleted_at). It is a join table the table names are companies and employees. I am currently counting the records with a DB::raw but it should only count it if the deleted_at column is null. Please understand that i am a beginner.
public function index()
{
$user = Auth::user()->id;
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('COUNT(e.id) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->where('c.deleted_at', '=', null)
->groupBy('c.id')
->get();
return view('account.companies.index')
->with('companies', $companies);
}
If you are using Mysql then you could use conditional aggregation
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('SUM(c.deleted_at IS NULL) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->groupBy('c.id')
->get();
In mysql when an expression is used inside sum(a= b) it will result as a boolean 0/1 so you can get your conditional count using above
Or you could use whereNull() method in your query
->whereNull('c.deleted_at')
Use this code:
$employeeCount = DB::table('employees')
->select('companies.name', DB::raw('count(employees.id) as employee_count'))
->join('companies', 'employees.company','=','companies.id')
->groupBy('companies.id')
->get();
I have a 3 table questions,registrations,ssi_tracks i need to get details from the registraions table by corresponding to other two tables
i need to get details from registrations based on
questions.question_schedul=0 ,ssi_tracks.track_first_status
i have wrote query but it says the column is not found here is my query
$register = DB::table('registrations')
->join('questions', 'registrations.registration_id', '=', 'questions.question_id')
->join('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('address', 'model', 'chassis', 'delivery_date','ssi_tracks.track_first_status')
->where([["questions.question_schedul", "=", $dropselected] and ['ssi_tracks.track_first_status',0]])
->get();
Try this:
$register = DB::table('registrations as R')
->select('R.address', 'R.model', 'R.chassis', 'R.delivery_date','S.track_first_status')
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
->join('ssi_tracks as S','R.registration_id','=','S.registration_id')
->where('Q.question_schedul', '=', $dropselected)
->where('S.track_first_status', '=', 0)
->get();
Make sure you have used the right column here from question table for matching registration id:
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
try this query :
$register = DB::table('registrations')
->leftJoin('questions', 'registrations.registration_id', '=', 'questions.question_id')
->leftJoin('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('registrations.address', 'registrations.model', 'registrations.chassis', 'registrations.delivery_date','ssi_tracks.track_first_status')
->where(['questions.question_schedul'=>$dropselected,'ssi_tracks.track_first_status'=>0])
->get();
I try these code in MySQl:
SELECT
A.*,
B.name,
C.name
FROM
eventlog_tbl as A
LEFT JOIN users B ON A.byuser=B.email
LEFT JOIN users C ON A.affectiveuser=C.email;
I try these in Laravel
return DB::table('eventlog_tbl')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','users.name','users.name')
->get();
How can i convert it to Laravel?
Try below code:
$res = DB::table('eventlog_tbl')
->leftjoin('users AS A', 'A.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users AS B', 'B.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','A.name as byuser_name','B.name as affectiveuser_name')
->get();
print_r($res);
This is your query written using the Laravel query builder.
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name', 'users_2.name')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
Edit:
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name AS user_1', 'users_2.name AS user_2')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
The problem is that both name columns are called the same thing. As per the accepted answer, these will need to be aliased differently too.
Why don't you convert this to use relationships? I have probably got the relationships wrong, something like this:
class EventLog extends Model
{
public function byUser()
{
return $this->hasOne(User::class, 'byuser', 'id');
}
public function affectiveUser()
{
return $this->hasOne(User::class, 'affectiveuser', 'id');
}
}
And then
$event_log = EventLog::with(['byUser', 'affectiveUser')->all();
foreach ($event_log as $item) {
echo $item->byUser->email();
}
I have 2 tables 'users' and 'instantUsers'. I want to join them on users.id = instantUsers.user_id and want to add 2 where clauses on the resulting. I'm not getting how to do both. The query I'm using is -
DB::table('users')
->join('instantUsers', function($join) use ($userId) {
$join->on('users.id', '=', 'instantUsers.user_id');
})
->where('instantUsers.instantMode', '=', '1')
->where (function($query) use ($userId) {
$query->where('instantUsers.user_id', '!=', $userId);
})
->get();
You can try this one maybe this will help you:
DB::table('users as table1')->join('instantUsers as table2','table1.id','=','table2.fkId') ->where('table2.instantMode','=','1')->where('table2.user_id','!=',$userId)->get();
Your 'instantUsers.instantMode','=','1' expression can be done in a join, resulting in a better performance.
I would write it like this
DB::table('users')
->join('instantUsers', function($join) use ($userId) {
$join
->on('users.id', '=', 'instantUsers.user_id')
->on('instantUsers.instantMode', '=', 1);
})
->where('users.id', '!=', $userId)
->get();
How to create this query using Laravel's Query Builder:
SELECT `content`.`tagable_id`,`taged`.`tag_id`
FROM `taged`
RIGHT JOIN
(SELECT `taged`.`tagable_id`,`taged`.`tag_id`
FROM `taged`
WHERE `taged`.`mask_flag`='0'
AND `taged`.`tagable_type`='App\\\Post'
AND `taged`.`user_id`='1') AS `content`
ON `taged`.`mask_flag`='1'
AND `content`.`tagable_id`=`taged`.`tagable_id`
AND `taged`.`tagable_type`='App\\\Post'
AND `taged`.`user_id`='1'
The parenthesis around the inner SELECT taged.tagable_id... is where my main problem lies.
Here is your Laravel query:
$result = DB::table('taged')
->select('content.tagable_id', 'taged.tag_id')
->rightJoin(DB::raw('SELECT tagable_id, tag_id FROM taged AS content'), function($join)
{
$join->on('taged.mask_flag', '=', 1);
$join->on('content.tagable_id', '=', 'taged.tagable_id');
$join->on('taged.tagable_type', '=', 'App\\\Post');
$join->on('taged.user_id', '=', 1);
})
->where('content.mask_flag', '=', 0);
->where('content.tagable_type', '=', 'App\\\Post');
->where('content.user_id', '=', 1);
->get();