How to select distinct max value from multiple join table MySQL - mysql

This is my current query for selecting data:
select a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara, c.ID_Rad, d.ID_Lab
FROM tb_registrasi a
JOIN tb_negara_tujuan b
ON a.ID_Negara = b.ID_Negara
JOIN tb_radiologi c
ON a.No_Registrasi = c.No_Registrasi
JOIN tb_laboratorium d
ON a.No_Registrasi = d.No_Registrasi
And here's the result:
How do i distinct those ID_Rad and ID_Lab and I need the max value from each ID_Rad and ID_Lab so it will be like this:

Use GROUP BY and MAX, try this;)
select a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara, CONCAT('RA-', MAX(substring(c.ID_Rad, 4) + 0)) AS ID_Rad, CONCAT('Lab-',MAX(substring(d.ID_Lab, 5) + 0)) AS Id_Lab
FROM tb_registrasi a
JOIN tb_negara_tujuan b
ON a.ID_Negara = b.ID_Negara
JOIN tb_radiologi c
ON a.No_Registrasi = c.No_Registrasi
JOIN tb_laboratorium d
ON a.No_Registrasi = d.No_Registrasi
GROUP BY a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara

Related

how can i solve this question? using self inner join and some conditions?

the first picture is the table . second picture is the expected output.
conditions are 1. refids should be same. 2. for all the same ref ids (a.start,a.end &b.start,b.end) in the current and previous row. 3. should calculate the time difference which is greater than or equal to one day.
You want pairs of rows that match certain condition. You can perform a join to identify the pairs.
You don't say which version of MySQL you are using but in MySQL 8.x you can do:
with
x as (
select a.id
from my_table a
join my_table b on b.id = a.id + 1
and b.refid = a.refid
and (a.detail = 'a.end' and b.detail = 'a.start'
or a.detail = 'b.end' and b.detail = 'b.start')
)
select t.*
from my_table t
join x on t.id = x.id or t.id = x.id + 1
For MySQL 5.x you can do:
select t.*
from my_table t
join (
select a.id
from my_table a
join my_table b on b.id = a.id + 1
and b.refid = a.refid
and (a.detail = 'a.end' and b.detail = 'a.start'
or a.detail = 'b.end' and b.detail = 'b.start')
) x on t.id = x.id or t.id = x.id + 1

How to deduct in group by query in sum in access

I have query like this ::
SELECT account.AccountNumber, account.NAME, Sum(agro.price * agro.qty) AS Expr1
FROM ((account
INNER JOIN data ON account.AccountNumber = data.acno)
INNER JOIN agro ON agro.BillNo = data.BillNo)
WHERE data.db='true'
GROUP BY account.AccountNumber, account.NAME;
I want to deduct another groupby query output in to Sum(agro.price * agro.qty) this
the another group by query is SELECT Sum(rs),acno
FROM jma group by acno;
i want to deduct Sum(agro.price * agro.qty)-Sum(rs) how its work please help me solve this
If I am understanding you correctly the following query may work for you:
SELECT subQ.AccountNumber, subQ.NAME, (subQ.subSum - jmaSum.jSum) AS FinalSum
FROM
(
SELECT a.AccountNumber, a.NAME, Sum(ag.price * ag.qty) AS subSum
FROM (account AS a
INNER JOIN data AS d ON a.AccountNumber = d.acno)
INNER JOIN agro AS ag ON ag.BillNo = d.BillNo
WHERE d.db = 'true'
GROUP BY a.AccountNumber, a.NAME
) AS subQ
LEFT JOIN
(
SELECT Sum(j.rs) AS jSum, j.acno
FROM jma AS j
GROUP BY j.acno
) AS jmaSum ON subQ.AccountNumber = jmaSum.acno

Difficult MySQL Statement

I've got this query but the result is wrong.
How can I use the min() statement and the Group by Statement so that I will get for each AthletenID the lowest DiszOrder?
Select
ar_Leistungen.`AthletenID`,
ar_Leistungen.`Leistung`,
ar_Leistungen.`Disziplin`,
ar_Leistungen.`Klasse`,
min(ar_Leistungen.`DiszOrder`),
ar_Athleten.`Vorname`,
ar_Athleten.`Jahrgang`,
ar_Wettkampf.`Wettkampfdatum`
from
ar_Leistungen,
ar_Athleten,
ar_Wettkampf
Where
ar_Athleten.ID = ar_Leistungen.AthletenID and
ar_Leistungen.WettkampfID = ar_Wettkampf.ID and
ar_Leistungen.`Disziplin` = '100' and
ar_Leistungen.`Leistung` > 0 and
(ar_Athleten.`Jahrgang` = '1995' or ar_Athleten.`Jahrgang` = '1994') and
ar_Wettkampf.`Wettkampfdatum` LIKE '%2013%'
Group By
AthletenID
Order by
DiszOrder Desc
Limit
0, 100
You can have a subquery which separately gets the lowest DiszOrder for each AthletenID and join it with the other table so you can freely get the other value of the columns.
SELECT a.AthletenID,
a.Leistung,
a.Disziplin,
ar_Leistungen.Klasse,
a.DiszOrder),
b.Vorname,
b.Jahrgang,
c.Wettkampfdatum
FROM ar_Leistungen a
INNER JOIN ar_Athleten b
ON b.ID = a.AthletenID
INNER JOIN ar_Wettkampf c
ON a.WettkampfID = c.ID
INNER JOIN
(
SELECT AthletenID, MIN(DiszOrder) DiszOrder
FROM ar_Leistungen
GROUP BY AthletenID
) d ON a.AthletenID = d.AthletenID AND
a.DiszOrder = d.DiszOrder
WHERE a.Disziplin = '100' AND
a.Leistung > 0 AND
(b.Jahrgang IN ('1995', '1994'))

Trying to add one last SUM() column to my query in SQL Server 2008

I have the first query which is producing correct results. What I need is I need to add the sum of values as a last column grouped by surveyid. I can't insert Sum(c.value) into the first query because it is an aggregate function. I have the correct query as my second query below. I know there's pivot functionality but not sure if it can be used here. I do realize that there will be repetition but that's okay.
'first query
SELECT
A.PATIENTID, B.STUDENTNUMBER, c.surveyid,
convert(varchar, A.CreatedDate, 107),
C.QuestionID, C.Value, D.Question
FROM
dbo.Survey A, dbo.Patient B, [dbo].[SurveyQuestionAnswer] C, [dbo].[LookupQuestions] D
WHERE
A.PATIENTID = B.ID
and c.SurveyID = A.ID
and c.QuestionID = d.ID
and c.questionid <> 10
ORDER BY
A.PATIENTID
'second query
select
c.surveyid,SUM(c.value) as scores
from
dbo.SurveyQuestionAnswer c
group by
c.SurveyID
order by
SurveyID '---not important
You can use SUM if you add the OVER clause. In this case:
SELECT
A.PATIENTID, B.STUDENTNUMBER, c.surveyid,
convert(varchar, A.CreatedDate, 107),
C.QuestionID, C.Value, D.Question,
SUM(c.Value) OVER(PARTITION BY c.surveyid) scores
FROM
dbo.Survey A
INNER JOIN dbo.Patient B
ON A.PATIENTID = B.ID
INNER JOIN [dbo].[SurveyQuestionAnswer] C
ON c.SurveyID = A.ID
INNER JOIN [dbo].[LookupQuestions] D
ON c.QuestionID = d.ID
WHERE
c.questionid <> 10
ORDER BY
A.PATIENTID
You could use something like this:
SELECT
s.PATIENTID, p.STUDENTNUMBER, sqa.surveyid,
CONVERT(varchar, s.CreatedDate, 107),
sqa.QuestionID, sqa.Value, lq.Question,
Scores = (SELECT SUM(Value) FROM dbo.SurveyQuestionAnswer s2 WHERE s2.SurveyID = s.ID)
FROM
dbo.Survey s
INNER JOIN
dbo.Patient p ON s.PatientID = p.ID
INNER JOIN
[dbo].[SurveyQuestionAnswer] sqa ON sqa.SurveyID = s.ID
INNER JOIN
[dbo].[LookupQuestions] lq ON sqa.QuestionID = lq.ID
WHERE
sqa.questionid <> 10
ORDER BY
s.PATIENTID
By having a subquery with the SUM(...) you should be able to get that sum as a single value and you don't need to use any grouping function

Getting the latest date from a id

I run the above sql statement and i got this.[IMG]http://i1093.photobucket.com/albums/i422/walkgirl_1993/asd-1_zps5506632e.jpg[/IMG] i'm trying display the latest date which you can see the 3 and 4. For caseid 3, it should display the latest row which is the 2012-12-20 16:12:36.000. I tried using group by, order by. Google some website said to use rank but i'm not sure about the rank as i dont really get rank. Some suggestions?
select [Case].CaseID, Agent.AgentName, Assignment.Description, A.AgentName as EditedBy, A.DateEdited from Agent inner join [Case-Agent] on [Case-Agent].AgentID = Agent.AgentID inner join [Assignment] on Assignment.AssignmentID = [Case-Agent].AssignmentID inner join [Case] on [Case].CaseID = [Case-Agent].CaseID inner join (select EditedCase.CaseID, [EditedCase].DateEdited, [Agent].AgentName from EditedCase inner join [Agent] on [Agent].AgentID = [EditedCase].AgentID) A on A.CaseID = [Case].CaseID where [Assignment].AssignmentID = 0
To do it using RANK you just need to add the RANK to the subquery and get to rank the DateEdited for each CaseID and Agent and then in the main query put a WHERE clause to only select rows where the rank is 1. I think I have got the partition clause right - its a bit hard without seeing your data.
Like this:
SELECT
[Case].CaseID
,Agent.AgentName
,Assignment.Description
,A.AgentName AS EditedBy
,A.DateEdited
FROM Agent
INNER JOIN [Case-Agent] ON [Case-Agent].AgentID = Agent.AgentID
INNER JOIN [Assignment] ON Assignment.AssignmentID = [Case-Agent].AssignmentID
INNER JOIN [Case] ON [Case].CaseID = [Case-Agent].CaseID
INNER JOIN (SELECT
EditedCase.CaseID
,[EditedCase].DateEdited
,[Agent].AgentName
,RANK ( ) OVER (PARTITION BY EditedCase.CaseID, [Agent].AgentName
ORDER BY [EditedCase].DateEdited DESC ) AS pos
FROM EditedCase
INNER JOIN [Agent] on [Agent].AgentID = [EditedCase].AgentID) A on A.CaseID = [Case].CaseID
WHERE [Assignment].AssignmentID = 0
AND pos = 1
You could also change the sub query into an aggregate query that brings back the MAX date like this:
SELECT
[Case].CaseID
,Agent.AgentName
,Assignment.Description
,A.AgentName AS EditedBy
,A.DateEdited
FROM Agent
INNER JOIN [Case-Agent] ON [Case-Agent].AgentID = Agent.AgentID
INNER JOIN [Assignment] ON Assignment.AssignmentID = [Case-Agent].AssignmentID
INNER JOIN [Case] ON [Case].CaseID = [Case-Agent].CaseID
INNER JOIN (SELECT
EditedCase.CaseID
,MAX([EditedCase].DateEdited) AS DateEdited
,[Agent].AgentName
FROM EditedCase
INNER JOIN [Agent] on [Agent].AgentID = [EditedCase].AgentID
GROUP BY
EditedCase.CaseID
,[Agent].AgentName) A on A.CaseID = [Case].CaseID
WHERE [Assignment].AssignmentID = 0
AND pos = 1
You were on the right track; you need to use a ranking function here, for example row_number():
with LatestCase as
(
select [Case].CaseID
, Agent.AgentName
, Assignment.Description
, A.AgentName as EditedBy
, A.DateEdited
, caseRank = row_number() over (partition by [Case].CaseID order by A.DateEdited desc)
from Agent
inner join [Case-Agent] on [Case-Agent].AgentID = Agent.AgentID
inner join [Assignment] on Assignment.AssignmentID = [Case-Agent].AssignmentID
inner join [Case] on [Case].CaseID = [Case-Agent].CaseID
inner join
(
select EditedCase.CaseID
, [EditedCase].DateEdited
, [Agent].AgentName
from EditedCase
inner join [Agent] on [Agent].AgentID = [EditedCase].AgentID
) A on A.CaseID = [Case].CaseID where [Assignment].AssignmentID = 0
)
select *
from LatestCase
where caseRank = 1