in MySQL data base, I have tow table like below :
gauges:
id data comments
-------------------------------------
1 x someThing
2 y someThing
4 z someThing
9 x someThing
documantaries:
id status gauge_id docName
--------------------------------
1 ok 1 x.png
2 nok 1
3 nok 1
4 ok 1 y.png
5 ok 1 z.png
6 nok 2 u.png
7 nok 2 x.png
8 ok 4 x.png
9 ok 2 u.png
10 ok 4 y.png
I need to select and join tables to find what is status in every row in first table according to second one.
like this :
result
id data status
-------------------------------------
1 x ok,nok,nok,ok,ok
2 y nok,nok,ok
4 z ok,ok
9 x
I think the link below is about my question but not exactly
Mysql Join results as single row
The code below is not working :
select gauges.*,documantaries.* join on gauges.id=documantaries.gauge_id ;
You can se left join and group_concat():
select g.id, g.data,
group_concat(d.status order by d.id) as statuses
from guages g left join
documantaries d
on d.gauge_id = g.id
group by g.id, g.data;
Here is a simplified version of my table:
It contains the columns
employee_id column2 column3 x y
and they are all NUMERIC
I am having trouble writing a complicated MySQL query. I want to get all the employeeid and column3 values for all employees that have the same value in column2 as another employee and have DIFFERENT values for x and y PAIR from every other employee. For example, if the following 4 rows were in table:
2 100 123.456 5 7
1 234 123.456 5 7
3 100 456.789 5 10
4 100 123.456 5 7
The rows 2 100 123.456 5 7 and 3 100 456.789 5 10 should be obtained because they have different employee ids (2 vs 3), the same value for column2 (100 and 100), and different x, y pair: (Employee 2 has x = 5 and y = 7, which is distinct from x = 5 and y = 10).
How can I compare the documents of table with other documents within itself?
SELECT e1.*
FROM employee e1
JOIN employee e2
ON e1.employee_id <> e2.employee_id
AND e1.column2 = e2.column2
AND e1.X <> e2.X
AND e1.Y <> e2.Y
But I guess your last condition should be
AND (e1.X <> e2.X OR e1.Y <> e2.Y)
Here is a simplified version of my table:
It contains the columns
employee_id column2 column3 x y
and they are all NUMERIC
I am having trouble writing a complicated MySQL query. I want to get all the employeeid and column3 values for all employees that have the same value in column2 as another employee and have DIFFERENT values for x and y PAIR from every other employee. For example, if the following 4 rows were in table:
2 100 123.456 5 7
1 234 123.456 5 7
3 100 456.789 5 10
4 100 123.456 5 7
The rows 2 100 123.456 5 7 and 3 100 456.789 5 10 should be obtained because they have different employee ids (2 vs 3), the same value for column2 (100 and 100), and different x, y pair: (Employee 2 has x = 5 and y = 7, which is distinct from x = 5 and y = 10).
How can I compare the documents of table with other documents within itself?
SELECT e1.*
FROM employee e1
JOIN employee e2
ON e1.employee_id <> e2.employee_id
AND e1.column2 = e2.column2
AND e1.X <> e2.X
AND e1.Y <> e2.Y
But I guess your last condition should be
AND (e1.X <> e2.X OR e1.Y <> e2.Y)
I'm coding a video game and using MySQL to display an icon showing the player where treasure is located. The database stores the locations by their X and Y on a square map. I would like to also count the number of items on each square.
So given a table such as this
Id x y
== == ==
1 2 3
2 3 2
3 3 2
4 4 4
5 4 4
6 4 4
I would like to return something to the effect of
x y count
= = =====
4 4 3
3 2 2
2 3 1
Use GROUP BY clause for results.
Select x, y, count(*) as 'count' from mytable group by x, y
What about concatenate your 2 columns and use DISTINCT ?
Select x, y, count(DISTINCT CONCAT(x, '_', y)) as 'count' from mytable group by x, y
SELECT x,y,SUM(1) FROM table GROUP BY x,y;
I have a table of data in MS Access 2007. There are 6 fields per record, thousands of records. I want to make a sort of pivot table like object. That is, if any two rows happens to be the same in the first 4 fields, then they will end up grouped together into one row. The column headers in this pivot table will be the values from the 5th field, and the value in the pivot table will be the 6th field, a dollar amount. Think of the 5th field as letters A, B, C, D, E, F, G. So, the table I start with might have a row with A in the 5th field and $3.48 in the 6th field. Another row may match in the first 4 fields, have B in the 5th field and $8.59 in the 6th field. Another may match in the first 4 fields, have E in the 5th field and $45.20 in the 6th field. I want all these rows to be turned into one row (in a new table) that starts with the first 4 fields where they match, then lists $3.48, $8.59, $0.00, $0.00, $45.20, $0.00, $0.00, corresponding to column headers A, B, C, D, E, F, G (since no records contained C, D, F, G, their corresponding values are $0.00), and then ends with one more field that totals up the money in that row.
Currently, I have some VBA code that does this, written by someone else a few years ago. It is extremely slow and I am hoping for a better way. I asked a previous question (but not very clearly so I was advised to create a new question), where I was asking if there was a better way to do this in VBA. My question asked about reading and writing large amounts of data all at once in Access through VBA, which I know is a good practice in Excel. That is, I was hoping to take my original table and just assign the entire thing to an array all at once (as in Excel, instead of cell by cell), then work with that array in VBA and create some new array and then write that entire array all at once to a new table (instead of record by record, field by field). From the answers in that question, it seems like that is not really a possibility in Access, but my best bet might be to use some sort of query. I tried the Query Wizard and found the Cross Tab query which is close to what I describe above. But, there appears to be a max of 3 fields used in the Row Heading, whereas here I have 4. And, instead of putting $0.00 when a value is not specified (like C, D, F, G in my example above), it just leaves a blank.
Update (in response to Remou's comment to give sample data): Here is some sample data.
ID a b c d e f
7 1 2 3 5 A 5
8 1 2 3 5 B 10
9 1 2 3 5 C 15
10 1 2 3 5 D 20
11 1 2 3 5 E 25
12 1 2 4 4 A 16
13 1 2 4 4 B 26
14 1 3 3 7 D 11
15 1 3 3 7 B 11
The result should be:
a b c d an bn cn dn en Total
1 2 3 5 5 10 15 20 25 75
1 2 4 4 16 26 0 0 0 42
1 3 3 7 0 11 0 11 0 22
But, when I copy and paste the SQL given by Remou, the only output I get is
a b c d an bn cn dn en
1 2 3 5 5 10 15 20 25
This is, I think, what you want, but it would be better to consider database design, because this is a spreadsheet-like solution.
SELECT t0.a,
t0.b,
t0.c,
t0.d,
Iif(Isnull([a1]), 0, [a1]) AS an,
Iif(Isnull([b1]), 0, [b1]) AS bn,
Iif(Isnull([c1]), 0, [c1]) AS cn,
Iif(Isnull([d1]), 0, [d1]) AS dn,
Iif(Isnull([e1]), 0, [e1]) AS en
FROM (((((SELECT DISTINCT t.a,
t.b,
t.c,
t.d
FROM table3 t) AS t0
LEFT JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS a1
FROM table3 t
WHERE t.e = "A") AS a0
ON ( t0.d = a0.d )
AND ( t0.c = a0.c )
AND ( t0.b = a0.b )
AND ( t0.a = a0.a ))
LEFT JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS b1
FROM table3 t
WHERE t.e = "B") AS b0
ON ( t0.d = b0.d )
AND ( t0.c = b0.c )
AND ( t0.b = b0.b )
AND ( t0.a = b0.a ))
LEFT JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS c1
FROM table3 t
WHERE t.e = "C") AS c0
ON ( t0.d = c0.d )
AND ( t0.c = c0.c )
AND ( t0.b = c0.b )
AND ( t0.a = c0.a ))
LEFT JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS d1
FROM table3 t
WHERE t.e = "D") AS d0
ON ( t0.d = d0.d )
AND ( t0.c = d0.c )
AND ( t0.b = d0.b )
AND ( t0.a = d0.a ))
LEFT JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS e1
FROM table3 t
WHERE t.e = "E") AS e0
ON ( t0.d = e0.d )
AND ( t0.c = e0.c )
AND ( t0.b = e0.b )
AND ( t0.a = e0.a );
Table3
ID a b c d e f
1 1 2 3 4 a €10.00
2 1 2 3 4 b €10.00
3 1 2 3 4 c €10.00
4 1 2 3 4 d €10.00
5 1 2 3 4 e €10.00
6 1 2 3 5 a €10.00
7 1 2 3 5 b
8 1 2 3 5 c €10.00
9 1 2 3 5 d €10.00
10 1 2 3 5 e €10.00
Result
There are two rows, because there are only two different sets in the first four columns.
a b c d an bn cn dn en
1 2 3 4 €10.00 €10.00 €10.00 €10.00 €10.00
1 2 3 5 €10.00 €0.00 €10.00 €10.00 €10.00
The way the sql above is supposed to work, is that it selects each of the four definition columns and the currency column from the table where the sort column has a particular sort letter and labels the currency column with the sort letter, each of these sub queries are then assembled, however, you can take a sub query and look at the results. The last one is the part between the parentheses:
INNER JOIN (SELECT t.a,
t.b,
t.c,
t.d,
t.f AS e1
FROM table3 t
WHERE t.e = "E") AS e0