Example:
If my data set is
A B C
1 2 3
5 6 7
4 5 6
I could have "1", "5" and "4" show up by typing =query(A:C, select A).
I could have "1" and "4" show up by typing =query(A:C, select A where B < 6).
Lets say I wanted to query only entries that appeared after a certain row. In this case, row 3 is 4, 5, 6. So if I want only results that are row 3 or below, I could add a fourth column D somewhere, fill column D with =row(), and then have only **** show up by typing
=query(A:C, select A where D >= 3).
But I don't want to have to add a fourth column somewhere and fill it with the =row() formula. The query should be able to do this on its own.
Query parametres
try:
=QUERY(A:C,"select * offset 2",0)
offset parameter is zero base:
0 -- start from row 1
1 -- start from row 2
2 -- start from row 3
so on
You may find more usuful query tips here. Use special words: offset, limit, skipping. For example, to select only odd rows use:
=QUERY(A:C,"select * skipping 2",0)
Filter function
To have full control of rows you select, use this construction:
=filter(A:C,isodd(row(A:C))) -- only odd rows
=filter(A:C,row(A:C)=3) -- only 3-d row
=filter(A:C,row(A:C)>=3) -- all rows >= 3-d row
=query(filter(A:C,row(A:C)>=3),"select *") use filter + query
So, I had an issue like this, and here is what I did. I made a virtual column.
=query(A:C, select A where D >= 3) would then be something like
=query({A:C, ROW(A:C)}, "Select Col1 where Col4 >=3")
You have to make an array to query a column you do not want in your sheet. In doing so you can no longer use Column letters, so then A, B, C then becomes Col1, Col2, Col3 and so on.
Related
I'm probably having a bad day, but this is somehow escaping me:
I want to return the second row in this table only.
userId val1 val2
1 11 12
2 13 14
3 13 15
4 16 17
Using SELECT * FROM table WHERE val1=13 AND val2=14 obviously returns 2 rows, the second and third. Whats the correct way to select ONLY the second row? Where val1 is 13 and val2 is 14?
EDIT: I'm an idiot.
Just use SELECT * FROM table WHERE val1=13 AND val2=14like you already mentioned in your question, because in fact, it actually returns only row number 2.
If it has been a very bad day & there is a typo in your question & val2 in third row also equals 14 - the only way your query would return two rows, then this would do what you want
SELECT *
FROM table
WHERE val1=13 AND val2=14
ORDER BY userId
LIMIT 1;
If you get 2 rows, then there must be 2 rows match the condition.
Maybe you could try:
select count(*)
from table
where val1=13 AND val2=14;
to show the size of result set.
I am fairly new to SQL, Big Query
I have a dataset and I want to retrieve values in column 2 corresponding to the values in column 1 if they satisfy certain conditions. I want to know how to do that. I am using Big Query Platform
Example Dataset D :
Col 1 ; Col 2
A ; 1
B ; 2
C ; 3
D ; 4
E ; 5
Query to retrieve values of col1, col2 such that col2 >2
Expected Output :
C ; 3
D ; 4
E ; 5
I am using big query platform.
According to me,
SELECT col1,col2
FROM [D]
WHERE col2>2
will give col1 and col2 as outputs where col2>2 but the values in col2 may or may not be the ones corresponding to col1.
Am I wrong ? If so, please suggest a query to get necessary output.
If you don't have a row A;5, it won't ever exist in your return. The only time you need to worry about the mismatch is if you're doing a join between one data set of {A, B, C, D, E} and another of {1, 2, 3, 4, 5}. Then every possible combination from A;1, A;2... to ...E;4, E;5 would be output, and filtering on col2 > 2 would produce A;3, B;3, C;3, ..., etc. But that isn't how your data is set up in your question, so don't worry. If you wonder how a select query will work, it's usually okay to just run it, unless it will take hours and consume tons of resources and you have a budget... but it seems more like you're doing homework.
Also don't ask for homework help on stack overflow.
I want to achieve one thing though I'm not sure if it's possible.
So let's say I have a table with few columns, but only two of them are of interest to me right now. Example of table:
Column 1 | Column 2
blabla | blablahhhhh
wor154 | blablahhhhh
word123 | word12435564
something | some4565
What I want to achieve, is to select all fields where first 5 or more symbols of value of Column 2 don't match with first 5 or more symbols of value of Column 1. So I don't want to select rows where 5 or more symbols of value of Column 1 match 5 or more symbols of value of Column 2. In example, query should return only 2nd and 4th rows
So, is it possible and if it's, how it can be achieved. Thank you.
I'd go with a SUBSTRING():
SELECT col1 FROM table WHERE SUBSTRING(col1, 1, 5) <> SUBSTRING(col2, 1, 5);
You can use something similar to this:
select *
from table1
where substring(column1, 1, 5) != substring(column2, 1, 5)
See SQL Fiddle with Demo
I have a table ABR with three columns: two lookup values, A and B and a result Result. I want the result to be returned given A and B
But, for some values of A, column B can be a wildcard. In that case I want the most specific row.
I can't seem to figure out the MySQL statement though - I found one, but it was 7 lines long and had 5 = and two IF's, there must be a better way.
A B Result
1 * First
2 * Second
2 1 Third
2 2 Fourth
3 * Fifth
Example wanted results:
A=1, B=5 -> First
A=1, B=0 -> First
A=2, B=2 -> Fourth
A=2, B=4 -> Second
A=3, B=7 -> Fifth
Do notice that the column values can change later: we can add extra rows for A and B, or remove values. Hardcoding stuff in the SQL is not acceptable.
SELECT Result
FROM ABR
WHERE A = #LookupA
AND (B = #LookupB OR B = '*')
ORDER BY B DESC LIMIT 1;
Is there a way to do something like this?
SELECT * FROM tablename WHERE x CONTAINS "1"
Basically, I want to select data from the database where x contains a specific number. The thing is, the x column in any row could contain "1, 2, 3" and I want to select all those that contain 1, specifically 1, not 11 or anything that contains 1, but specifically a 1.
Here's an example:
id title x
-------------------
1 row1 1,22,3
2 row2 1,5
3 row3 5,91
4 row4 70
And I want my query to return rows 1 and 2. I don't want row 3, as the 1 is inside the number 91. I don't want row 4 because there's no 1 there either.
You can use the FIND_IN_SET function like so:
SELECT * FROM tablename WHERE FIND_IN_SET('1', x)
This will also get optimised to use bit arithmetic if you are calling it on a SET type.
You can try this:
SELECT * FROM tablename WHERE x REGEXP "(^|,)1(,|$)"
Ideally you'd normalize your 'x' column out to a separate table.
But... you could also hack it like this:
SELECT * FROM tablename WHERE x LIKE '%,1' OR x LIKE '1,%' OR x LIKE '%,1,%'
This basically just handles the three different cases where the "1" is the first, last or a middle element in your list. (note if you've got a space after your commas you'd change the last part to '%, 1,%'
EDIT: Actually Dmitriy's REGEXP is nicer, and a'r's FIND_IN_SET looks ideal.