I want to achieve one thing though I'm not sure if it's possible.
So let's say I have a table with few columns, but only two of them are of interest to me right now. Example of table:
Column 1 | Column 2
blabla | blablahhhhh
wor154 | blablahhhhh
word123 | word12435564
something | some4565
What I want to achieve, is to select all fields where first 5 or more symbols of value of Column 2 don't match with first 5 or more symbols of value of Column 1. So I don't want to select rows where 5 or more symbols of value of Column 1 match 5 or more symbols of value of Column 2. In example, query should return only 2nd and 4th rows
So, is it possible and if it's, how it can be achieved. Thank you.
I'd go with a SUBSTRING():
SELECT col1 FROM table WHERE SUBSTRING(col1, 1, 5) <> SUBSTRING(col2, 1, 5);
You can use something similar to this:
select *
from table1
where substring(column1, 1, 5) != substring(column2, 1, 5)
See SQL Fiddle with Demo
Related
Example:
If my data set is
A B C
1 2 3
5 6 7
4 5 6
I could have "1", "5" and "4" show up by typing =query(A:C, select A).
I could have "1" and "4" show up by typing =query(A:C, select A where B < 6).
Lets say I wanted to query only entries that appeared after a certain row. In this case, row 3 is 4, 5, 6. So if I want only results that are row 3 or below, I could add a fourth column D somewhere, fill column D with =row(), and then have only **** show up by typing
=query(A:C, select A where D >= 3).
But I don't want to have to add a fourth column somewhere and fill it with the =row() formula. The query should be able to do this on its own.
Query parametres
try:
=QUERY(A:C,"select * offset 2",0)
offset parameter is zero base:
0 -- start from row 1
1 -- start from row 2
2 -- start from row 3
so on
You may find more usuful query tips here. Use special words: offset, limit, skipping. For example, to select only odd rows use:
=QUERY(A:C,"select * skipping 2",0)
Filter function
To have full control of rows you select, use this construction:
=filter(A:C,isodd(row(A:C))) -- only odd rows
=filter(A:C,row(A:C)=3) -- only 3-d row
=filter(A:C,row(A:C)>=3) -- all rows >= 3-d row
=query(filter(A:C,row(A:C)>=3),"select *") use filter + query
So, I had an issue like this, and here is what I did. I made a virtual column.
=query(A:C, select A where D >= 3) would then be something like
=query({A:C, ROW(A:C)}, "Select Col1 where Col4 >=3")
You have to make an array to query a column you do not want in your sheet. In doing so you can no longer use Column letters, so then A, B, C then becomes Col1, Col2, Col3 and so on.
I'm probably having a bad day, but this is somehow escaping me:
I want to return the second row in this table only.
userId val1 val2
1 11 12
2 13 14
3 13 15
4 16 17
Using SELECT * FROM table WHERE val1=13 AND val2=14 obviously returns 2 rows, the second and third. Whats the correct way to select ONLY the second row? Where val1 is 13 and val2 is 14?
EDIT: I'm an idiot.
Just use SELECT * FROM table WHERE val1=13 AND val2=14like you already mentioned in your question, because in fact, it actually returns only row number 2.
If it has been a very bad day & there is a typo in your question & val2 in third row also equals 14 - the only way your query would return two rows, then this would do what you want
SELECT *
FROM table
WHERE val1=13 AND val2=14
ORDER BY userId
LIMIT 1;
If you get 2 rows, then there must be 2 rows match the condition.
Maybe you could try:
select count(*)
from table
where val1=13 AND val2=14;
to show the size of result set.
Sorry if the title is a bit ambiguous and reminiscent of other semi-related questions), the issue is in fact quite simple.
I have a VARCHAR column which can have 1-character values such as M,G,D and S. If I sort the results alphabetically, in this example it will show them in the order: D-G-M-S. However, I need to display the rows in the following order:
G-D-M-S
Is there a way to accomplish this within the query? I know I can custom-sort the results in PHP, but I'd rather do it within the query if possible. For this example, I just need to switch the order of "G" and "D" in the results, and the solution to that simplistic problem will suffice for any answers.
You can write your custom case statement:
Select *
from your_table
order by
case your_column
when 'G' then 1
when 'D' then 2
when 'M' then 3
when 'S' then 4
end
Also, another solution, is to change collation at physical level:
Change default Sorting by Adding a Simple Collation to an 8-Bit Character Set
What I would do is define a temp or permanent table with 2 columns :
letter | ordernum
-------------------
G | 1
D | 2
M | 3
S | 4
Then you join your exiting table to that new one on the field "letter", and use the new table "ordernum" field to do the sort...
SELECT
if(columnname='G',1,
if(columnname='D',2,
if(columnname='M',3,
if(columnname='S',4,0
)))) SortOrder
FROM tablename
ORDER BY
SortOrder ASC
Select col from table
order by case when col = 'G' then 1
when col = 'D' then 2
when col = 'M' then 3
case when col = 'S' then 4 else 5 end ;
Is there a way to do something like this?
SELECT * FROM tablename WHERE x CONTAINS "1"
Basically, I want to select data from the database where x contains a specific number. The thing is, the x column in any row could contain "1, 2, 3" and I want to select all those that contain 1, specifically 1, not 11 or anything that contains 1, but specifically a 1.
Here's an example:
id title x
-------------------
1 row1 1,22,3
2 row2 1,5
3 row3 5,91
4 row4 70
And I want my query to return rows 1 and 2. I don't want row 3, as the 1 is inside the number 91. I don't want row 4 because there's no 1 there either.
You can use the FIND_IN_SET function like so:
SELECT * FROM tablename WHERE FIND_IN_SET('1', x)
This will also get optimised to use bit arithmetic if you are calling it on a SET type.
You can try this:
SELECT * FROM tablename WHERE x REGEXP "(^|,)1(,|$)"
Ideally you'd normalize your 'x' column out to a separate table.
But... you could also hack it like this:
SELECT * FROM tablename WHERE x LIKE '%,1' OR x LIKE '1,%' OR x LIKE '%,1,%'
This basically just handles the three different cases where the "1" is the first, last or a middle element in your list. (note if you've got a space after your commas you'd change the last part to '%, 1,%'
EDIT: Actually Dmitriy's REGEXP is nicer, and a'r's FIND_IN_SET looks ideal.
Can someone give me a query that will return as a result rows ID 1 & 3?
ID Name Hidden
1 Mika 1,4,2
2 Loca 0
3 Nosta 4
4 Like 2
Something like this
SELECT * FROM table WHERE Hidden HAVING(4)
SELECT * FROM table WHERE FIND_IN_SET('4',Hidden);
docs for FIND_IN_SET
SELECT * FROM table WHERE CONCAT(',',Hidden,',') LIKE '%,4,%'
or you can avoid using LIKE like this
SELECT * FROM table WHERE INSTR(CONCAT(',',Hidden,','), ',4,') > 0
this will not get things like 40, 14, etc, but you need to make sure there are no spaces in the Hidden field (eg, 1, 4, 5 or update the concat and LIKE function accordingly.
SELECT * FROM table WHERE Hidden LIKE '%4%'
the % are wildcards.
Full Text Search might be a reasonable solution for this as long as you use the correct word breaks.
Either go with Full Text Search, as suggested, or
Spin the Hidden values off into a separate table, with the ID of current row.
Eg, Mika would have three entries in this table
ID = 1, Hidden =1
ID = 1, Hidden =4
ID = 1, Hidden =2
Then you could return results against this spin off table.
You may also want to consider normalizing the table and storing these "hidden" values in a separate table with an index on the apropriate column. Depending on the number of rows you have that would be much faster:
ID Hidden
1 1
1 4
1 2
3 4
4 2
and:
SELECT DISTINCT table.* FROM table, hidden_table WHERE table.ID = hidden_table.ID AND hidden_table.hidden = 4