CREATE TABLE `bank`.`Customer_registrationTable`
( `Account_no` INT NOT NULL ,
`Name` VARCHAR(100) NOT NULL ,
`Address` INT(100) NOT NULL ,
`Account_type` VARCHAR(100) NOT NULL ,
`Gender` VARCHAR(50) NOT NULL ,
`DOB` VARCHAR(100) NOT NULL ,
`Password` VARCHAR(100) NOT NULL ,
`Date` VARCHAR(100) NOT NULL ,
`Age` INT(10) NOT NULL ,
`Previous_Balance` DOUBLE(20) NOT NULL,
PRIMARY KEY (`Account_no`(30))) ENGINE = InnoDB;
after writing this I got problem that said,
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ') NOT NULL, PRIMARY KEY (`Account_no`(30))) WHERE ENGINE = InnoDB' at line 1
CREATE TABLE `bank`.`Customer_registrationTable`
( `Account_no` INT NOT NULL ,
`Name` VARCHAR(100) NOT NULL ,
`Address` INT(100) NOT NULL ,
`Account_type` VARCHAR(100) NOT NULL ,
`Gender` VARCHAR(50) NOT NULL ,
`DOB` VARCHAR(100) NOT NULL ,
`Password` VARCHAR(100) NOT NULL ,
`Date` VARCHAR(100) NOT NULL ,
`Age` INT(10) NOT NULL ,
`Previous_Balance` DOUBLE NOT NULL,
PRIMARY KEY (`Account_no`)) ENGINE = InnoDB;
PRIMARY KEY (Account_no) should not have (20)
Previous_Balance DOUBLE NOT NULL should not have (20), it should like DOUBLE(20, 2)
CREATE TABLE IF NOT EXISTS `customer_registrationtable` (
`Account_no` int(11) NOT NULL,
`Name` varchar(100) NOT NULL,
`Address` int(100) NOT NULL,
`Account_type` varchar(100) NOT NULL,
`Gender` varchar(50) NOT NULL,
`DOB` datetime NOT NULL,
`Password` varchar(100) NOT NULL,
`Date` datetime NOT NULL,
`Age` int(10) NOT NULL,
`Previous_Balance` double(20,2) NOT NULL,
PRIMARY KEY (`Account_no`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Related
CREATE TABLE `mealorder`.`order_item`
( `order_id` INT(20) NOT NULL AUTO_INCREMENT ,
`user_id` INT(20) NOT NULL ,
`item_type` VARCHAR(50) NOT NULL ,
`item_price` DOUBLE(20) NOT NULL ,
`item_quantity` INT(20) NULL ,
`date_time` DATETIME(5) NULL ,
`total_price` DOUBLE(20) NULL ,
PRIMARY KEY (`order_id`(20))) ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS `order_item` (
`order_id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) NOT NULL,
`item_type` varchar(50) NOT NULL,
`item_price` double NOT NULL,
`item_quantity` int(11) NOT NULL,
`date_time` datetime NOT NULL,
`total_price` double NOT NULL,
PRIMARY KEY (`order_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
AUTO_INCREMENT=1 ;
SQL sorgusu:
CREATE TABLE online(
idonline İNT( 10 ) UNSİGNED NOT NULL AUTO_INCREMENT ,
ip VARCHAR( 16 ) ,
domain VARCHAR( 100 ) ,
FKiduyeler İNT( 10 ) UNSİGNED,
lasttime TİMESTAMP DEFAULT 'CURRENT_TIMESTAMP',
PRIMARY KEY ( idonline ) ,
KEY online_index3587( ip ) ,
KEY online_index3588( domain ) ,
KEY online_index3592( FKiduyeler ) ,
KEY online_index3604( lasttime )
);
MySQL çıktısı: Belgeler
#1067 - Invalid default value for 'lasttime'
Before everthing sorry about my english; when l upload my db ,l got this proglem.Please help me.Thanks
CURRENT_TIMESTAMP instead of 'CURRENT_TIMESTAMP'
I instead of İ at multiple places.
CREATE TABLE `online`(
idonline INT( 10 ) UNSIGNED NOT NULL AUTO_INCREMENT ,
ip VARCHAR( 16 ) ,
domain VARCHAR( 100 ) ,
FKiduyeler INT( 10 ) UNSIGNED,
lasttime TIMESTAMP DEFAULT CURRENT_TIMESTAMP, -- lose the single quotes here
PRIMARY KEY ( idonline ) ,
KEY online_index3587( ip ) ,
KEY online_index3588( domain ) ,
KEY online_index3592( FKiduyeler ) ,
KEY online_index3604( lasttime )
);
Thank for helping, but when l do that I'm getting this problem:
CREATE TABLE visitor_chats ( visitor_id varchar(32) NOT NULL,
browser_id varchar(32) NOT NULL, visit_id varchar(32) NOT NULL,
chat_id int(11) unsigned NOT NULL, fullname varchar(255) NOT NULL,
email varchar(255) NOT NULL, company varchar(255) NOT NULL, status
tinyint(1) unsigned NOT NULL, typing tinyint(1) unsigned NOT NULL,
waiting tinyint(1) unsigned NOT NULL, area_code varchar(255) NOT NULL,
first_active int(10) unsigned NOT NULL, last_active int(10) unsigned
NOT NULL, qpenalty int(10) unsigned NOT NULL, request_operator
varchar(32) NOT NULL, request_group varchar(32) NOT NULL, question
varchar(255) NOT NULL, customs text NOT NULL, allocated int(11)
unsigned NOT NULL, internal_active tinyint(1) unsigned NOT NULL,
internal_closed tinyint(1) unsigned NOT NULL, internal_declined
tinyint(1) unsigned NOT NULL, external_active tinyint(1) unsigned NOT
NULL, external_close tinyint(1) unsigned NOT NULL, exit int(11) [...]
MySQL error
"#1064 - You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'exit int(11) unsigned NOT NULL,PRIMARY KEY
(visitor_id,browser_id,visit_id,c' at line 26"
Good day,
I have an issue using the phpmyadmin for my database, I'm in new in this and this is the mysql structure from previewmysql:
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM(0) NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15) NULL,
`marital_status` ENUM(0) NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM(0) NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM(0) NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
The error is:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '0) NOT NULL , `email` VARCHAR(20) NOT NULL , `phone` INT(15) NULL , `marital_sta' at line 1
And also attached is my phpmyadmin table structure.
Will appreciate any help.
Try it.Hope errors goes boom.I just fixed your errors. But your table structure is not good enough. give time, then day by day you will also be expert on it.
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM('0','1') NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15),
`marital_status` ENUM('0','1') NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM('0','1') NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM('0','1') NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
Modify ENUM declaration as ENUM ('male', 'female') for gender column and others also as shown in your table. It will not accept ENUM(0).
ENUM(0) is wrong format , if you want that for gender roles then you can use :-
ENUM('Male', 'Female') i.e you can run this query :-
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM('Male', 'Female') NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15) NULL,
`marital_status` ENUM('Single','Married','divorced') NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM('no','yes') NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM('Cape Town','Woodstock') NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
You have used ENUM data type in your table. And provided 0 as argument but
An enumeration value must be a quoted string literal
You can refer the mySql documentation for more information
http://dev.mysql.com/doc/refman/5.7/en/enum.html
I wanted to make a database exactly as below:
So I wanted to define the primary and foreign keys for each table.
Based on this answer, I saw that:
"city" table has 1 PK (ID) and 1 FK (countrycode)
"countrylanguage" table has 2 PK (Language and countrycode) and 1 FK
(countrycode)
"country" table has 1 PK (Code)
So I tried to make some magic on a "pre-heated" code:
CREATE TABLE `City` (
`ID` int(11) NOT NULL,
`Name` varchar(35) NOT NULL ,
`CountryCode` varchar(3) NOT NULL DEFAULT '',
`District` varchar(20) NOT NULL ,
`Population` int(11) NOT NULL ,
PRIMARY KEY(`ID`) ,
FOREIGN KEY(`CountryCode`) REFERENCES `Country`(`Code`)
) ;
CREATE TABLE `CountryLanguage` (
`CountryCode` varchar(3) NOT NULL DEFAULT '',
`Language` varchar(30) NOT NULL ,
`IsOfficial` varchar(30) NOT NULL ,
`Percentage` float(4,1) NOT NULL ,
PRIMARY KEY(`Language`),
FOREIGN KEY(`CountryCode`) REFERENCES `Country`(`Code`)
) ;
CREATE TABLE `Country` (
`Code` varchar(3) NOT NULL DEFAULT '',
`Name` varchar(52) NOT NULL DEFAULT '',
`Continent` varchar(63),
`Region` varchar(26) NOT NULL DEFAULT '',
`SurfaceArea` float(10,2) NOT NULL DEFAULT '0.00',
`IndepYear` smallint(6) DEFAULT NULL,
`Population` int(11) NOT NULL DEFAULT '0',
`LifeExpectancy` float(3,1) DEFAULT NULL,
`GNP` float(10,2) DEFAULT NULL,
`GNPOld` float(10,2) DEFAULT NULL,
`LocalName` varchar(45) NOT NULL DEFAULT '',
`GovernmentForm` varchar(45) NOT NULL DEFAULT '',
`HeadOfState` varchar(60) DEFAULT NULL,
`Capital` int(11) DEFAULT NULL,
`Code2` varchar(2) NOT NULL DEFAULT '',
PRIMARY KEY(`Code`)
) ;
but my good ol' mysql command line client has the same ERROR 1005 thing twice, and says that it can't create tables 'test.city' and 'test.countrylanguage'
with the errno:150 thingy as an explanation.
So I searched a bit around here and I found some answers regarding to table elements not having the same type/parameter (f.e. INT(2) to INT(2) NOT NULL). As fas as I could see, Nothing like this happens here.
What is my coffee-drained brain missing here?
Thank you for your time in advance.
CREATE TABLE Country first, then CREATE TABLE City, and CREATE TABLE CountryLanguage, since TABLE Country is referenced by the other two tables.
wrong create sequnce you should create firts Country because City and CountryLanguage refer to country table
CREATE TABLE `Country` (
`Code` varchar(3) NOT NULL DEFAULT '',
`Name` varchar(52) NOT NULL DEFAULT '',
`Continent` varchar(63),
`Region` varchar(26) NOT NULL DEFAULT '',
`SurfaceArea` float(10,2) NOT NULL DEFAULT '0.00',
`IndepYear` smallint(6) DEFAULT NULL,
`Population` int(11) NOT NULL DEFAULT '0',
`LifeExpectancy` float(3,1) DEFAULT NULL,
`GNP` float(10,2) DEFAULT NULL,
`GNPOld` float(10,2) DEFAULT NULL,
`LocalName` varchar(45) NOT NULL DEFAULT '',
`GovernmentForm` varchar(45) NOT NULL DEFAULT '',
`HeadOfState` varchar(60) DEFAULT NULL,
`Capital` int(11) DEFAULT NULL,
`Code2` varchar(2) NOT NULL DEFAULT '',
PRIMARY KEY(`Code`)
) ;
CREATE TABLE `City` (
`ID` int(11) NOT NULL,
`Name` varchar(35) NOT NULL ,
`CountryCode` varchar(3) NOT NULL DEFAULT '',
`District` varchar(20) NOT NULL ,
`Population` int(11) NOT NULL ,
PRIMARY KEY(`ID`) ,
FOREIGN KEY(`CountryCode`) REFERENCES `Country`(`Code`)
) ;
CREATE TABLE `CountryLanguage` (
`CountryCode` varchar(3) NOT NULL DEFAULT '',
`Language` varchar(30) NOT NULL ,
`IsOfficial` varchar(30) NOT NULL ,
`Percentage` float(4,1) NOT NULL ,
PRIMARY KEY(`Language`),
FOREIGN KEY(`CountryCode`) REFERENCES `Country`(`Code`)
) ;
I have prblem with sql when i try to check if table extist.
Am making component for joomla and when make install.sql i have sql syntax error.
check this and tell me what i do wrong:
DROP TABLE IF EXIST `#__ik_property_item`;
DROP TABLE IF EXIST `#__ik_property_categories`;
DROP TABLE IF EXIST `#__ik_property_type`;
DROP TABLE IF EXIST `#__ik_property_price_type`;
DROP TABLE IF EXIST `#__ik_property_agnts`;
DROP TABLE IF EXIST `#__ik_property_companies`;
DROP TABLE IF EXIST `#__ik_property_agnts`;
CREATE TABLE `#__ik_property_item` (
`id` INT NOT NULL AUTO_INCREMENT ,
`category_id` INT NULL ,
`property_type_id` INT NULL ,
`price_type_id` INT NULL ,
`company_id` INT NOT NULL ,
`agent_id` INT NOT NULL ,
`title` VARCHAR(45) NULL ,
`street` VARCHAR(45) NULL ,
`status` INT NULL ,
`featured` INT NULL ,
`yt_video` TEXT NULL ,
`map_lattitude` INT NULL ,
`map_longitude` VARCHAR(45) NULL ,
`beds` INT NULL ,
`baths` VARCHAR(45) NULL ,
`garage` VARCHAR(45) NULL ,
`flat_size` VARCHAR(45) NULL ,
`kitchens` VARCHAR(45) NULL ,
`year_build` VARCHAR(45) NULL ,
`floor` VARCHAR(45) NULL ,
`price` INT NULL ,
`image_1` VARCHAR(45) NULL ,
`image_2` VARCHAR(45) NULL ,
`image_3` VARCHAR(45) NULL ,
`image_4` VARCHAR(45) NULL ,
`image_5` VARCHAR(45) NULL ,
`meta_title` VARCHAR(45) NULL ,
`meta_description` TEXT NULL ,
`intro_text` TEXT NULL ,
`full_text` TEXT NULL ,
PRIMARY KEY (`id`) );
CREATE TABLE `#__ik_property_categories` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NULL ,
PRIMARY KEY (`id`) );
CREATE TABLE `#__ik_property_type` (
`id` INT NOT NULL AUTO_INCREMENT ,
`title` VARCHAR(45) NULL ,
PRIMARY KEY (`id`) );
CREATE TABLE `#__ik_property_price_type` (
`id` INT NOT NULL AUTO_INCREMENT ,
`title` VARCHAR(45) NULL ,
PRIMARY KEY (`id`) );
CREATE TABLE `#__ik_property_agnts` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NULL ,
`last_name` VARCHAR(45) NULL ,
`first_name` VARCHAR(45) NULL ,
`email` VARCHAR(45) NULL ,
`website` VARCHAR(45) NULL ,
`phone` VARCHAR(45) NULL ,
`company` VARCHAR(45) NULL ,
PRIMARY KEY (`id`) );
CREATE TABLE `#__ik_property_companies` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NULL ,
`logo` VARCHAR(45) NULL ,
`email` VARCHAR(45) NULL ,
`phone` VARCHAR(45) NULL ,
`website` VARCHAR(45) NULL ,
`street` VARCHAR(45) NULL ,
`fax` VARCHAR(45) NULL ,
`intro_text` VARCHAR(45) NULL ,
`full_text` VARCHAR(45) NULL ,
`image_1` VARCHAR(45) NULL ,
`image_2` VARCHAR(45) NULL ,
`image_3` VARCHAR(45) NULL ,
PRIMARY KEY (`id`) );
When i remove
DROP TABLE IF EXIST `#__ik_property_item`;
DROP TABLE IF EXIST `#__ik_property_categories`;
DROP TABLE IF EXIST `#__ik_property_type`;
DROP TABLE IF EXIST `#__ik_property_price_type`;
DROP TABLE IF EXIST `#__ik_property_agnts`;
DROP TABLE IF EXIST `#__ik_property_companies`;
DROP TABLE IF EXIST `#__ik_property_agnts`;
All is success executed and when i call uninstall.sql code inside is like above all work good. But i need to check on installation if that tables exist if exist i must delete and save new.
Thanks