I have existing dates in our database where some dates are formatted mm/dd/yyyy and others are dd/mm/yyyy. To be able to use MONTH() and YEAR() I need to convert the dates to yyyy/mm/dd but it doesn't seems like there is any easy way to do this. I've tried CONVERT() and DATEPART() with no success to convert my dates to the usable format in SQL Server 2008
My last resort is changing the 384 different dates this way.
UPDATE Hardware_RefreshData
SET InstallDate = '2014/9/9'
WHERE InstallDate = '9/9/2014
My goal is to be able to report on a specific month like this.
SELECT
InstallDate,
MONTH(InstallDate) AS Month,
YEAR(InstallDate) AS Year,
COUNT(*) AS Total
FROM
Hardware_RefreshData
GROUP BY
InstallDate
ORDER BY
YEAR(InstallDate) DESC, MONTH(InstallDate) DESC
Does anyone know of a better way to do this?
Now that we fixed the date Issue i was able to build my Query for my report
Here is what i was able to do to report on the fiscal year.
SELECT Technician, Count(*) as '2016/17 Total',
SUM(CASE WHEN DATEPART (Month, InstallDate) = 04 THEN 1 ELSE 0 END) AS Apr,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 05 THEN 1 ELSE 0 END) AS May,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 06 THEN 1 ELSE 0 END) AS Jun,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 07 THEN 1 ELSE 0 END) AS Jul,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 08 THEN 1 ELSE 0 END) AS Aug,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 09 THEN 1 ELSE 0 END) AS Sep,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 10 THEN 1 ELSE 0 END) AS Oct,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 11 THEN 1 ELSE 0 END) AS Nov,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 12 THEN 1 ELSE 0 END) AS Dec,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 01 THEN 1 ELSE 0 END) AS Jan,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 02 THEN 1 ELSE 0 END) AS Feb,
SUM(CASE WHEN DATEPART (Month, InstallDate) = 03 THEN 1 ELSE 0 END) AS Mar
FROM Hardware_RefreshData
Where InstallDate between '2016-04-01' and '2017-03-31'
GROUP BY Technician
ORDER BY Technician desc;
Thanks for the input :)
Related
i am trying to count new users recorded by each month of this year.
like
Need data month wise, which is registerd by month new users
JAn Feb Mar April May ..... Dec
1 2 4 2 5 ..... 1
through created_at date and user Id.
here is user_table
id created_at
1 2020-01-09 22:38:55
2 2020-02-09 22:38:55
3 2020-02-09 22:38:55
4 2020-03-09 22:38:55
5 2020-03-09 22:38:55
6 2020-03-09 22:38:55
7 2020-04-09 22:38:55
8 2020-04-09 22:38:55
9 2020-05-09 22:38:55
i am trying with this query
SELECT ut.id, Month(FROM_UNIXTIME(ut.created_at)), Count(*)
from $userTable ut
where FROM_UNIXTIME(ut.created_at) >= CURDATE() - INTERVAL 1 YEAR
GROUP BY Month(FROM_UNIXTIME(ut.created_at));
You can group by year and sum by month like this:
select YEAR(created_at) as year,
sum(case when Month(created_at) = 1 then 1 else 0 end) AS Jan,
sum(case when Month(created_at) = 2 then 1 else 0 end) AS Feb,
sum(case when Month(created_at) = 3 then 1 else 0 end) AS Mar,
sum(case when Month(created_at) = 4 then 1 else 0 end) AS Apr,
sum(case when Month(created_at) = 5 then 1 else 0 end) AS May,
sum(case when Month(created_at) = 6 then 1 else 0 end) AS Jun,
sum(case when Month(created_at) = 7 then 1 else 0 end) AS Jul,
sum(case when Month(created_at) = 8 then 1 else 0 end) AS Aug,
sum(case when Month(created_at) = 9 then 1 else 0 end) AS Sep,
sum(case when Month(created_at) = 10 then 1 else 0 end) AS Oct,
sum(case when Month(created_at) = 11 then 1 else 0 end) AS Nov,
sum(case when Month(created_at) = 12 then 1 else 0 end) AS Dec from ut group by YEAR(created_at)
all columns that being used in the select that are not an aggregated function need to be grouped, ut.id is not group and in your case should be removed from the select
Try
SELECT Month(FROM_UNIXTIME(ut.created_at)), Count(*) from $userTable ut
where FROM_UNIXTIME(ut.created_at) >= CURDATE() - INTERVAL 1 YEAR
GROUP BY Month(FROM_UNIXTIME(ut.created_at));
If you want to mix data from this year and last year for the past 12 months, you can use:
SELECT SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 1) AS Jan,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 2) AS Feb,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 3) AS Mar,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 4) AS Apr,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 5) AS May,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 6) AS Jun,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 7) AS Jul,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 8) AS Aug,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 9) AS Sep,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 10) AS Oct,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 11) AS Nov,
SUM(MONTH(FROM_UNIXTIME(ut.created_at)) = 12) AS Dec
FROM ut
WHERE FROM_UNIXTIME(ut.created_at) >= CURDATE() - INTERVAL 1 YEAR
Note: This assumes that FROM_UNIXTIME() is a actually necessary. It also uses a convenient MySQL shortcut for conditional aggreation.
I have table:
User nvarchar(30)
Date datetime
Total decimal(8,2)
And i need to get data per month like this:
I can get it this way (without month columns):
SELECT User, MONTHNAME(FROM_UNIXTIME(Date)) as month, SUM(Total) as total FROM `wp_banking_expenses` group by month,User
But i need it to make as on image above...
You can try to use condition aggregate function.
SELECT User,
SUM(CASE WHEN MONTHNAME(Date) = 'January' THEN Total END) as Jan,
SUM(CASE WHEN MONTHNAME(Date) = 'February' THEN Total END) as Feb,
SUM(CASE WHEN MONTHNAME(Date) = 'March' THEN Total END) as Mar,
SUM(CASE WHEN MONTHNAME(Date) = 'April' THEN Total END) as Apr,
SUM(CASE WHEN MONTHNAME(Date) = 'May' THEN Total END) as May,
SUM(CASE WHEN MONTHNAME(Date) = 'June' THEN Total END) as JUN,
SUM(CASE WHEN MONTHNAME(Date) = 'July' THEN Total END) as JUL,
SUM(CASE WHEN MONTHNAME(Date) = 'August' THEN Total END) as AUG,
SUM(CASE WHEN MONTHNAME(Date) = 'September' THEN Total END) as SEP,
SUM(CASE WHEN MONTHNAME(Date) = 'October' THEN Total END) as OCT,
SUM(CASE WHEN MONTHNAME(Date) = 'November' THEN Total END) as NOV,
SUM(CASE WHEN MONTHNAME(Date) = 'December' THEN Total END) as DEC
FROM `wp_banking_expenses`
group by User
use conditional aggregation using case when expression
select user,max(case when month='January' then total end) as Jan,
max(case when month='February' then total end) as Feb,
max(case when month='March' then total end) as Mar,
max(case when month='April' then total end) as Apr,
max(case when month='May' then total end) as May,
max(case when month='June' then total end) as June,
----
from
(
SELECT User, MONTHNAME(Date) as month, SUM(Total) as total
FROM `wp_banking_expenses`
group by month,User
)A group by user
below is my query
SELECT DISTINCT e2.status as status, e2.year as year, e2.month as month,e2.Jan,e2.Feb,e2.Mar,e2.Apr,e2.May,e2.Jun,e2.Jul,e2.Aug,e2.Sep,e2.Oct,e2.Nov, e2.Dece, e2.countTotal FROM tranx_history e1 INNER JOIN (
SELECT YEAR(e.create_dt) AS year, MONTH(e.create_dt) AS month,
SUM(CASE WHEN MONTH(e.create_dt) = 01 THEN 1 ELSE 0 END) AS Jan,
SUM(CASE WHEN MONTH(e.create_dt) = 02 THEN 1 ELSE 0 END) AS Feb,
SUM(CASE WHEN MONTH(e.create_dt) = 03 THEN 1 ELSE 0 END) AS Mar,
SUM(CASE WHEN MONTH(e.create_dt) = 04 THEN 1 ELSE 0 END) AS Apr,
SUM(CASE WHEN MONTH(e.create_dt) = 05 THEN 1 ELSE 0 END) AS May,
SUM(CASE WHEN MONTH(e.create_dt) = 06 THEN 1 ELSE 0 END) AS Jun,
SUM(CASE WHEN MONTH(e.create_dt) = 07 THEN 1 ELSE 0 END) AS Jul,
SUM(CASE WHEN MONTH(e.create_dt) = 08 THEN 1 ELSE 0 END) AS Aug,
SUM(CASE WHEN MONTH(e.create_dt) = 09 THEN 1 ELSE 0 END) AS Sep,
SUM(CASE WHEN MONTH(e.create_dt) = 10 THEN 1 ELSE 0 END) AS Oct,
SUM(CASE WHEN MONTH(e.create_dt) = 11 THEN 1 ELSE 0 END) AS Nov,
SUM(CASE WHEN MONTH(e.create_dt) = 12 THEN 1 ELSE 0 END) AS Dece,
SUM(CASE WHEN MONTH(e.create_dt) >= 01 AND MONTH(e.create_dt) <= 12 THEN 1 ELSE 0 END) as countTotal,
e.trnx_status as status
from tranx_history e
GROUP BY e.trnx_status, MONTH(e.create_dt),YEAR(e.create_dt) ) e2 ON YEAR(e1.create_dt) = e2.year AND MONTH(e1.create_dt) = e2.month ORDER BY e2.year asc, e2.month asc
For the Above query, The Output we are getting is first it is grouping by Jan then in the next row it is grouping by Feb even though status and year are same
i want the output Jan and Feb with same status and year in a single row not in different rows
My new query is giving me few errors:
Error: ORA-0093: SQL command not properly ended.
select coalesce(a.group_name, 'Total') as group_name,
sum(case when month (a.sent_date)=1 then a.total_sent else 0 end) as January,
sum(case when month(a.sent_date)=2 then a.total_sent else 0 end) as February,
sum(case when month(a.sent_date)=3 then a.total_sent else 0 end) as March,
sum(case when month(a.sent_date)=4 then a.total_sent else 0 end) as April,
sum(case when month(a.sent_date)=5 then a.total_sent else 0 end) as May,
sum(case when month(a.sent_date)=6 then a.total_sent else 0 end) as June,
sum(case when month(a.sent_date)=7 then a.total_sent else 0 end) as July,
sum(case when month(a.sent_date)=8 then a.total_sent else 0 end) as August,
sum(case when month(a.sent_date)=9 then a.total_sent else 0 end) as September,
sum(case when month(a.sent_date)=10 then a.total_sent else 0 end) as October,
sum(case when month(a.sent_date)=11 then a.total_sent else 0 end) as November,
sum(case when month(a.sent_date)=12 then a.total_sent else 0 end) as December
from c_group a
where a.partner_id=123 AND
a.sent_date >= '01-JAN-2012'
and a.sent_date <= '31-DEC-2012'
group by a.group_name with rollup;
=========
This is my first time posting here and also a beginner at queries.
I am running a query which returns various folder names for all days. I want to group by the folder name and do a sum of the totals for each folder name by months and then a total of each column at the bottom. This is the query I am running:
select a.group_name, a.sent_date, a.total_sent
from
c_group a
where
a.partner_id=123
and a.sent_date >= '01-JAN-2012'
and a.sent_date <= '31-DEC-2012'
Displays as follows:
GROUP_NAME SENT_DATE TOTAL_SENT
Group A 1-Jan-12 37
Group B 3-Jan-12 25
Group C 1-May-12 10
Group D 1-May-12 8
Group D 1-Jan-12 11
Group A 1-Dec-12 9
I need the results to display as:
January February March April May June July August September October November December
Group A
Group B
Group C
Group D
...
....
...
....
Total Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above Sum of above
You want to combine conditional aggregation with rollup:
select coalesce(a.group_name, 'Total') as group_name,
sum(case when month(a.sent_date) = 1 then a.total_sent else 0 end) as January,
sum(case when month(a.sent_date) = 2 then a.total_sent else 0 end) as February,
. . .
sum(case when month(a.sent_date) = 12 then a.total_sent else 0 end) as December
from c_group a
where a.partner_id = 123 AND
a.sent_date >= '01-JAN-2012' AND
a.sent_date <= '31-DEC-2012'
group by a.group_name with rollup;
I have a table with column date; it contains records for some months, but not continuously.
To see which months are present (present meaning 1 or more records in a specific month), I tried to make an overview. It should be something like this:
2013 Jan Feb Mar - May Jun // etc
2012 Jan - - Apr May - // etc
I can get all first days of the present months, but am stuck in how to transpose. If I do this:
SELECT
IF (d = 1, month ,'-') AS Jan,
IF (d = 2, month ,'-') AS Feb,
IF (d = 3, month ,'-') AS Mar
FROM
(SELECT
MONTH(date) AS d,
DATE_FORMAT(date, '%Y-%m-01') AS month
FROM
table
GROUP BY
month
ORDER BY
month) m
GROUP BY YEAR(month)
If gives this as result:
Jan Feb Mar
- - Mar
- Feb -
While it should give:
Jan Feb Mar
- - Mar
Jan Feb Mar
This will let you do it without a subquery:
SELECT
MAX(CASE WHEN MONTH(date) = 1 THEN 'Jan' ELSE '-' END) AS Jan,
MAX(CASE WHEN MONTH(date) = 2 THEN 'Feb' ELSE '-' END) AS Feb,
MAX(CASE WHEN MONTH(date) = 3 THEN 'Mar' ELSE '-' END) AS Mar,
MAX(CASE WHEN MONTH(date) = 4 THEN 'Apr' ELSE '-' END) AS Apr,
MAX(CASE WHEN MONTH(date) = 5 THEN 'May' ELSE '-' END) AS May,
MAX(CASE WHEN MONTH(date) = 6 THEN 'Jun' ELSE '-' END) AS Jun,
... and so on through December
FROM table
GROUP BY YEAR(date)