adding X amount of addChild per maxvalue in loop - actionscript-3

Question

The assignment is the spawn several light and dark feathers according to score points from a quiz. The light feathers symbolize the correct points (light_feather), and the dark feather are the incorrect points (dark_feather) (Each are being tracked). All the feathers are supposed to line up on one line, meaning first light feathers, followed by the dark feathers. I got the quiz dynamics figured out, and the function I have posted here is only for when they press end quiz.
var light_feather:LightFeather = new LightFeather();
var dark_feather:DarkFeather = new DarkFeather();
var good_answers:uint = 0;
var bad_answers:uint = 0;
function avsluttFunc (evt:MouseEvent)
{
var sum_LightFeatherX:Number = 0;
for (var i = 0; i < good_answers; i++) {
addChild(light_feather);
light_feather.x += 12 + (i*16);
light_feather.y = 0;
trace("Lys X-verdi: " + light_feather.x);
sum_LightFeatherX += Number(light_feather.x);
return sum_LightFeatherX;
}
trace(sum_LightFeatherX);
dark_feather.x += sum_LightFeatherX;
for (var j = 1; j <= bad_answers; j++) {
addChild(dark_feather);
dark_feather.x += 12 + (j*16);
dark_feather.y = 0;
trace("Mørk X-verdi: " + dark_feather.x);
}
/*
//Resetter poengsummen
good_answers = 0;
bad_answers = 0;
*/
}

Answer 1

You can do what you are looking for using only one for loop, take a look :
var good_answers:uint = 2;
var bad_answers:uint = 4;
function avsluttFunc(evt:MouseEvent)
{
for (var i:int = 0; i < good_answers + bad_answers; i++) {
var feather:DisplayObject = i < good_answers ? new LightFeather() : new DarkFeather();
feather.x += 12 + i * (feather.width + 1);
feather.y = 0;
addChild(feather);
}
}
This code example will create 4 DarkFeather instances next to 2 LightFeather ones.
Edit :
How to add your objects to an array ?
// feathers array should be accessible for both codes (adding and removing objects)
var feathers:Array = [];
for (var i:int = 0; i < good_answers + bad_answers; i++) {
var feather:DisplayObject = i < good_answers ? new LightFeather() : new DarkFeather();
addChild(feather);
feathers.push(feather);
}
then to remove them from the stage, you can do for example :
for (var i:int = 0; i < feathers.length; i++) {
var feather:DisplayObject = DisplayObject(feathers[i]);
feather.parent.removeChild(feather);
}
Hope that can help.