So here's the question: why this:
Monetary.of(new BigDecimal("100.00"), "EUR")
prints "EUR 1E+2", but any other decimal != .00 will print correct:
Monetary.of(new BigDecimal("100.01"), "EUR")
"EUR 100.01"???
OK,
it looks like the MonetaryAmount calls toString() which will call the engineeringString of the BigDecimal. The correct way to print a MonetaryAmount is to format it:
MonetaryFormats.getAmountFormat(Locale.getDefault()).format(Money.of(source.getValue(), source.getCurrency().getUid()))
Related
i try to construct JSON with string that contains "\n" in it like this :
ver_str= 'Package ID: version_1234\nBuild\nnumber: 154\nBuilt\n'
proj_ver_str = 'Version_123'
comb = '{"r_content": {0}, "s_version": {1}}'.format(ver_str,proj_ver_str)
json_content = json.loads()
d =json.dumps(json_content )
getting this error:
exec(compile(contents+"\n", file, 'exec'), glob, loc)
File "C:/Dev/python/new_tester/simple_main.py", line 18, in <module>
comb = '{"r_content": {0}, "s_version": {1}}'.format(ver_str,proj_ver_str)
KeyError: '"r_content"'
The error arises not because of newlines in your values, but because of { and } characters in your format string other than the placeholders {0} and {1}. If you want to have an actual { or a } character in your string, double them.
Try replacing the line
comb = '{"r_content": {0}, "s_version": {1}}'.format(ver_str,proj_ver_str)
with
comb = '{{"r_content": {0}, "s_version": {1}}}'.format(ver_str,proj_ver_str)
However, this will give you a different error on the next line, loads() missing 1 required positional argument: 's'. This is because you presumably forgot to pass comb to json.loads().
Replacing json.loads() with json.loads(comb) gives you another error: json.decoder.JSONDecodeError: Expecting value: line 1 column 15 (char 14). This tells you that you've given json.loads malformed JSON to parse. If you print out the value of comb, you see the following:
{"r_content": Package ID: version_1234
Build
number: 154
Built
, "s_version": Version_123}
This isn't valid JSON, because the string values aren't surrounded by quotes. So a JSON parsing error is to be expected.
At this point, let's take a look at what your code is doing and what you seem to want it to do. It seems you want to construct a JSON string from your data, but your code puts together a JSON string from your data, parses it to a dict and then formats it back as a JSON string.
If you want to create a JSON string from your data, it's far simpler to create a dict with your values and use json.dumps on that:
d = json.dumps({"r_content": ver_str, "s_version": proj_ver_str})
What is the best way to parse the string into key value pair using regex?
Sample input:
application="fre" category="MessagingEvent" messagingEventType="MessageReceived"
Expected output:
application "fre"
Category "MessagingEvent"
messagingEventType "MessageReceived"
We already tried the following regex and its working.
application=(?<application>(...)*) *category=(?<Category>\S*) *messagingEventType=(?<messagingEventType>\S*)
But we want a generic regex which will parse the sample input to the expected output as key value pair?
Any idea or solution will be helpful.
input = 'application="fre" category="MessagingEvent" messagingEventType="MessageReceived"'
puts input.
scan(/(\w+)="([^"]+)"/). # scan for KV-pairs
map{ |k, v| %Q|#{k.ljust(30,' ')}"#{v}"| }. # adjust as you requested
join($/) # join with platform-dependent line delimiters
#⇒ application "fre"
# category "MessagingEvent"
# messagingEventType "MessageReceived"
Instead of using regex, it can be done by spliting and storing the string in hash like below:
input = 'application="fre" category="MessagingEvent" messagingEventType="MessageReceived"'
res = {}
input.split.each { |str| a,b = str.split('='); res[a] = b}
puts res
==> {"application"=>"\"fre\"", "category"=>"\"MessagingEvent\"", "messagingEventType"=>"\"MessageReceived\""}
I'm having trouble serializing my ruby object to json, more specifically the format of the numbers.
I have written an rspec test to illustrate my issue more precisely.
expected = '{ "foo": 1.00, "bar": 4.50, "abc": 0.00, "xyz": 1.23 }'
it 'serializes as expected' do
my_hash = { "foo": 1, "bar": 4.5, "abc": 0, "xyz": 1.23}
expect(my_to_json_method(my_hash)).to eq expected
end
This is the case that I am having trouble with. I can use the sprintf but how do I get the string output as shown in the above example?
First of all, you should not use floats to represent monetary values. So instead, let's use a more appropriate type: (there's also the Ruby Money gem)
require 'bigdecimal'
my_hash = {
foo: BigDecimal.new('1.00'),
bar: BigDecimal.new('4.50'),
abc: BigDecimal.new('0.00'),
xyz: BigDecimal.new('1.23')
}
There are several options to represent monetary values. All of the following JSON strings are valid according to the JSON specification and all require special treatment upon parsing. It's up to you to choose the most appropriate.
Note: I'm implementing a custom to_json method to convert the BigDecimal instances to JSON using Ruby's default JSON library. This is just for demonstration purposes, you should generally not patch core (or stdlib) classes.
1. Numbers with fixed precision
This is what you asked for. Note that many JSON libraries will parse these numbers as floating point values by default.
class BigDecimal
def to_json(*)
'%.2f' % self
end
end
puts my_hash.to_json
Output:
{"foo":1.00,"bar":4.50,"abc":0.00,"xyz":1.23}
2. Numbers as strings
This will work across all JSON libraries, but storing numbers as strings doesn't look quite right to me.
class BigDecimal
def to_json(*)
'"%.2f"' % self
end
end
puts my_hash.to_json
Output:
{"foo":"1.00","bar":"4.50","abc":"0.00","xyz":"1.23"}
3. Numbers as integers
Instead of representing monetary values as fractional numbers, you simply output the cents as whole numbers. This is what I usually do.
class BigDecimal
def to_json(*)
(self * 100).to_i.to_s
end
end
puts my_hash.to_json
Output:
{"foo":100,"bar":450,"abc":0,"xyz":123}
User Sprintf
sprintf('%.2f', 5.5)
And simply interpolate into your JSON as an ERB template.
You can use, sprintf and can take as many decimal points as you needed by mentioning %.(number)f.
Eg: For two decimals, %.2f
Here is a real implementation,
2.2.2 :019 > test = { "foo": (sprintf "%.2f","1.11"), "bar": (sprintf "%.2f","4.55"), "abc": (sprintf "%.2f","0.2") }
=> {:foo=>"1.11", :bar=>"4.55", :abc=>"0.20"}
Here is the reference
puts '{' << my_hash.map { |k, v| %Q|"#{k}": #{"%.2f" % v}| }.join(', ') << '}'
#⇒ {"foo": 1.00, "bar": 4.50, "abc": 0.00, "xyz": 1.23}
I have this JSON text:
data = {"one":"number","two":"string","three":"number","four":[{"five":"number","six","string"},{"five":"number","six":"string"}]}
How I can get "five"'s number and "six"'s string using Python 3.3 and using json module ?
P.S.: If I do print data['five'] it doesn't works with this error:
print(data['five'])
KeyError: 'five'
Thanks,
Marco
Try this:
data = {"one":"number","two":"string","three":"number","four":[{"five":"number","six":"string"},{"five":"number","six":"string"}]}
print(data['four'][0]['five']) # number
print(data['four'][0]['six']) # string
Is there a way in XQuery to do something like a tail() function?
What I'm trying to accomplish is to get the contents of a file (using "xdmp:filesystem-file($path)") and then display only the last 100 lines. I can't seem to find a good way to do this. Any ideas?
Thank you.
In plain XQuery, this can be accomplished by splitting into lines and getting the desired number of lines from the end of the sequence, then rejoining them, if necessary, i.e.
declare function local:tail($content as xs:string, $number as xs:integer)
{
let $linefeed := "
"
let $lines := tokenize($content, $linefeed)
let $tail := $lines[position() > last() - $number]
return string-join($tail, $linefeed)
};
A pure and short XPath 2.0 solution -- can be used not only in XQuery but in XSLT or in any other PL hosting XPath 2.0:
for $numLines in count(tokenize(., '
'))
return
tokenize(., '
')[position() gt $numLines -100]
Or:
for $numLines in count(tokenize(., '
'))
return
subsequence(tokenize(., '
'), $numLines -100 +1)
if your xdmp:file-xx is a nature of text file then you could use something like
let $f := 'any file system path'
return fn:tokenize(xdmp:filesystem-file($f), '[\n\r]+')[ fn:last() - 2 to fn:last()]
here
i have used newline & carriage return as my token splitter. if you need something else to tokenize u could. but simple log file tailing then this solution works fine.
given example tails last 2 lines of a given file. if you want more than alter fn:last()-2 to fn:last() - x