So I have a table called "lu_regex" with a column called "regex"
Select * from lu_regex;
athedsl-\d+
i5[93][0-9a-fA-F]+\.versa
5ac[a-f0-9]+.+sky
The table contains 1000's of rows, with various Regular Expressions syntax, i'm just showing three in this example.
Now I'm trying to take user input and match that input against the rows in the table. So I'm doing this.
SELECT * FROM lu_regex where '5aca3a11.bb.sky.comr' regexp regex;
regex
5ac[a-f0-9]+.+sky
1 row returned.
I'm getting back what I expected, with that query, then I try this one.
SELECT * FROM lu_regex where 'athedsl-07371.home.otenet.gr' regexp regex;
0 rows returned.
It should match on "athedsl-\d+", but i'm assuming it has something to do with the "\d". I even tried adding this to the database "athedsl-\\d+" and that didn't cause a match either.
I'm trying to stick to a MySQL solution, what am I doing wrong, this should be possible.
I just found this link, it looks like a bug that hasn't been fixed. It was verified in 2013.
https://bugs.mysql.com/bug.php?id=70413
Bug #70413 \d is not working in REGEXP for a MySQL query
I think the solution is going to be is to replace all \d with [0-9]
Related
I have a table where the field "company_name" has weird characters, like "à","ö","¬","©","¬","†", etc. I want to return all "company_name"s that contain these characters anywhere within the string. My current query looks like this:
SELECT * FROM table WHERE
MATCH (company_name) AGAINST ('"Ä","à","ö","¬","©","¬","†"' in natural language mode);
But I keep getting no data from the query. I know this can't be the case, as there are definitely examples of them I can find manually. To be clear, the query itself isn't throwing any errors, just not returning any data.
The minimun word length is 3 pr 4 .
you can change it see manial
https://dev.mysql.com/doc/refman/8.0/en/fulltext-fine-tuning.html
or use regular expressiions
SELECT * FROM table WHERE
ompany_name REGEXP '[Äàö¬©¬†]+';
SELECT *
FROM table
WHERE company_name LIKE '%[^0-9a-zA-Z !"#$%&''()*+,\-./:;<=>?#\[\^_`{|}~\]\\]%' ESCAPE '\'
This will find any wacky stuff, including wide characters or 'euro-ASCII' or emoji.
I want to get entries from a mysql table, which contain a given id within a comma separated list. I want to use regular expressions and the LIKE selector.
My current approach looks like this
SELECT * FROM table WHERE list LIKE '%,0,%';
with the problem being that this ignores the first and last element in a list like '0,1,2,3'.
I've tried using the | or operator to test for all possible cases.
SELECT * FROM table WHERE list LIKE '(%,0,%)|(^0,%)';
I've tried this with and without the ^ character and with and without the parenthesis, but in all cases this approach didn't even match the characters in the middle. In fact, the or operator doesn't seem to be working in even the simplest expressions like
SELECT * FROM table WHERE list LIKE '%(1|2)%';
You should fix your data model! DO not store lists of things -- especially numbers -- in a string. SQL has a great data model for storing lists: it is called a table.
If you are stuck with someone else's really, really, really bad choice of dta model, you can work around in. MySQL has a handy function, find_in_set(), that does what you want:
WHERE find_in_set('0', list) > 0
Concatenate commas to the start and the end of the list:
SELECT * FROM table WHERE concat(',', list, ',') LIKE '%,0,%';
I need to create a query that looks for a exact match for a list of words like '+lg +customer +service' (this is one word and needs to be the exact match) unfortunately I cannot use a WHERE IN ('+lg +customer +service','+Phone +repairs'). Cannot use this because the app cannot build the list of values because it's over 36K, but I can use a REGEXP if I could get it right...
I tried to to use it like that:
WHERE Text REGEXP '/[\+Phone\ \+repairs]/|/[\+lg\ \+customer\ \+service]/'
This doesn't work though, returns no result as soon as I add this.
Anyone knows how REGEXP works for exact phrase match?
Referring the documentation, for an EXACT Match you could go for this
SELECT * FROM your_table where
content REGEXP '\\+lg \\+customer \\+service';
or multiple exact matches like
SELECT * FROM test.new_table where
content REGEXP '\\+lg \\+customer \\+service$,' or content REGEXP '\\+Phone \\+repairs$';
Checked using Mysql Workbench 6.3, Mysql 5.6 version
I need to find entries that contain more than 7 numbers in one of my mysql tables BUT the numbers are separated by letters or anything else.
What I have is this little piece of code I use to find entries like dsc123456789:
select * from crawl where title regexp '[0-9]{7}'
How can I find entries like dsc-123-456_78B9? I tried different things but without success so far.
Thanks
You can use the following solution:
SELECT *
FROM crawl
WHERE title REGEXP '(([^[:digit:]])?[[:digit:]]){8,}';
Why the original query of the answer doesn't work?
-- this query doesn't work!
SELECT *
FROM crawl
WHERE title REGEXP '\d([^\d]?\d){7,}'
MySQL can't use character groups like \d (digits). So the query fails every time. On PHP and other languages the regular expression would look like this:
\d([^\d]?\d){7,}
but on MySQL this isn't valid. So you have to use the character classes of MySQL to solve this:
(([^[:digit:]])?[[:digit:]]){8,}
Hint: Make sure you use {8} or {8,} instead of {7} since you want to find all entries with more than 7 numbers / digits.
I'm trying to update a field which contains HTML and I want to find all the rows that have forms in them and remove the form tags and anything in between them, however I'm running into problems with my select and the regex.
SELECT * FROM db.table WHERE body REGEXP "<form[^>].+?>.+?</form>";
and the error I get says:
'repetition-operator operand invalid' from regexp.
I was hoping to make that SELECT into a subselect for an update query but I'm stuck at this point.
I think your problem is in your form expression. Try the following:
"<form[^>]*>.+?</form>"
Remember that MySQL supports a limited set of regular expression matching and testing.
See this document.