Convert json structure to row - json

Question

I have a table like:
CREATE TABLE myrecord AS
id INT
other TEXT
attributes JSONB
The attributes are structured like this:
[
{"name": "a", "value": "1"},
{"name": "b", "value": "2"}
]
I'd like to convert that to a result like:
id INT, other TEXT, a TEXT, b TEXT
So that for a given row like
1 | "foo" | {..as above..}
I get a result like
1 | "foo" | "1" | "2"
Right now I'm able to unpack the attribute structure like this:
CREATE TYPE myrecord_attributes AS (name TEXT, value TEXT);
SELECT
id,
other,
(json_populate_recordset(NULL :: myrecord_attributes,
attributes :: JSON)).*
FROM myrecord
But with that I get results like:
1 | "foo" | "a" | "1"
1 | "foo" | "b" | "2"
How can I flatten the result from json_populate_recordset into the appropriate structure? I'm also open to alternate solutions which don't use it like that at all.
I'm using postgres 9.4 if that matters

Answer 1

You can do as this:
select m.id,
m.other,
x.value::jsonb->>'name' as name,
x.value::jsonb->>'value' as value
from myrecord m,
json_array_elements(m.attributes) x;
And if you like it to return the values with double quotes just change ->> to ->
See it working here: http://sqlfiddle.com/#!15/450cc/9
This is making use of the implicit LATERAL JOIN in Postgres 9.3 or later.
EDIT
My first solution did not meet the OP's requirements, so, I've created another solution:
select m.id,
m.other,
max(case when x.value::json->>'name' = 'a'
then x.value::json->>'value' else '' end) as a,
max(case when x.value::json->>'name' = 'b'
then x.value::json->>'value' else '' end) as b
from myrecord m,
json_array_elements(m.attributes) x
group by m.id,
m.other;
See it working here: http://sqlfiddle.com/#!15/450cc/14

Answer 2

Assuming that your jsonb array always has two elements as given in your question, you can explicitly select all required elements:
SELECT id, other, (attributes->0)->>'value' AS a, (attributes->1)->>'value' AS b
FROM myrecord;