Remove border around circular image - html

I have a round image (a .png file) which is transparent in the middle. I need to make the background inside the image a solid color. To do this, I made the background solid, and then put border-radius:50%, but this creates an ugly small white line. Is there anyway to get rid of this, or would I have to manually color the image in an image editor?
div {
width: 500px;
height: 500px;
background: black;
}
div img {
margin: 100px;
max-width: 50%;
background: white;
border-radius: 50%;
}
<div>
<img src="http://i.imgur.com/sDU7Lhz.png">
</div>
Fiddle here: https://jsfiddle.net/h3nwkoe1/

The problem is not with the image. The image is a transparent one and has no background to it at all. The problem is caused by the background: white and the border-radius: 50% added to the image element. It is due to the anti-aliasing pixel in browsers and is the same issue described in this thread.
The solution would be to use some method to fill the background partially to the element and not fully (that is, just enough to cover till the black circle that is already present on the image). Since the img tag cannot have pseudo-elements (atleast it won't work cross-browser), the best option is to use a radial-gradient for the background like in the below snippet.
Note: The thick green border is only for demo and can be removed without any side effect.
div {
width: 500px;
height: 500px;
background: black;
}
div img {
margin: 100px;
max-width: 50%;
background: radial-gradient(circle at center, white 60%, transparent 61%);
border-radius: 50%;
overflow: hidden;
border: 4px solid green;
}
<div>
<img src="http://i.imgur.com/sDU7Lhz.png">
</div>

I totally agree with Harry's explanation.
Another workaround could be to enclose the image in a div slightly smaller than the image (like 1px on each side), so that the circle formed using border-radius is smaller than the external black circle on the image.
It is a bit messier than the solution proposed by Harry. But it could be an alternative to gradient.
div#black {
width:500px;
height:500px;
background:black;
border: solid black 1px;
box-sizing: border-box;
}
div#circle {
margin: 100px;
width: 250px;
height: 250px;
background: white;
border-radius: 50%;
text-align: center;
}
div#circle img {
width: 252px;
height: 252px;
margin-left: -1px;
margin-top: -1px;
}
<div id="black">
<div id="circle">
<img src="http://i.imgur.com/sDU7Lhz.png">
</div>
</div>

Related

Why is there a light circle in my css circle?

I have that little css which draws a circle and fills it till half using backgrounds. Both containing div's have the same size but the lower one's background is still visible.
Shouldn't the div.bg cover the div.fill? So the upper half of the cirlce should be completely black? (there is a thin white line)
body {
background: black;
}
#asd {
height: 35px;
width: 35px;
border-radius: 35px;
overflow: hidden;
position: relative;
}
span {
color: red;
text-align: center;
font-size: 10px;
line-height: 35px;
position: absolute;
height: 100%;
width: 100%;
z-index: 3;
}
#asd div {
height: 100%;
width: 100%;
position: absolute;
}
div.bg {
background: white;
z-index: 1;
}
div.fill {
background: black;
height: 50% !important;
z-index: 2;
}
<div id="asd">
<span>lorem</span>
<div class="bg"></div>
<div class="fill"></div>
</div>
This is due to anti aliasing, and colour addition.
First, the browser paints a perfectly white circle:
The white circle is behind the black circle, and to make the edges look smooth, the edge pixels are blended slightly. This is called anti-aliasing or supersampling.
Now the background circle has been anti-aliased, we're left with a perfect white circle surrounded by a grey outline. The exact shade of grey is decided by the browser, but usually this decision is made by interpolating between the background and foreground colours. Let's assume this creates 50% black/white.
The next step is to create a black circle over the top of the white circle, and this will be anti-aliased in exactly the same way. This is where the problem occurs, as an incorrect assumption is made by the browser.
The black circle, exactly the same size as the white circle, is blended into the background to look smooth. Because there are already 50% black/white pixels surrounding the white circle, the black is added to these using the same algorithm, creating 25% black/white.
This is simply a limitation/design choice of the individual browsers, and some would argue that it is indeed correct behaviour. As you've found, or will find, in web design there are many ways to skin a cat, so my advice would be to look for an alternative solution rather than hack this exact problem.
General rule of thumb: try not to include extra markup to achieve visual style. One can usually achieve everything with just CSS. Keep in mind background gradients, pseudo-elements and borders and most visuals are in reach.
As a head start, I would not suggest using two div elements for this styling. Instead, I would use the background property of the white circle to describe the visual effect you are looking for.
Specifically: background: linear-gradient(to bottom, black 50%, white 50%);
body {
background: black;
}
#asd {
height: 35px;
width: 35px;
border-radius: 35px;
overflow: hidden;
position: relative;
}
span {
color: red;
text-align: center;
font-size: 10px;
line-height: 35px;
position: absolute;
height: 100%;
width: 100%;
z-index: 3;
}
#asd div {
height: 100%;
width: 100%;
position: absolute;
}
div.bg {
background: linear-gradient(to bottom, black 50%, white 50%);
z-index: 1;
}
<div id="asd">
<span>lorem</span>
<div class="bg"></div>
</div>
I think you're referring to the jagged edges around your circle, which I think is a rendering artifact caused anti-aliassing.
The border-radius on the elements get sharpened so-to-speak by anti-aliassing, which renders differently coloured pixels around the element to smoothen out hard edges (please correct me if this is wrong, I'm no expert on this). Normally this is behaviour is fine, but in your case it cases artifacts.
Have a look at my snippet below. The result is the same, but uses a background gradient to achieve it.
body {
background: black;
}
.circle {
width: 35px;
height: 35px;
line-height: 35px;
font-size: 11px;
border-radius: 50%;
color: red;
text-align: center;
background: linear-gradient(0deg, white 50%, black 50%);
}
<div class="circle">
lorem
</div>

Joining diagonal divs with flex

I have 2 divs. Right div is an image cutted diagonally. Left divs must have some text inside. I want this to be fully responsive like this:
The problem occurs when I change window size, it's collapsing like in the image:
.
Also there is a text on left div that need to be displayed, but with flex this seems not to work so i disabled it. Please provide solution for this.
Here is my css and html:
#diagonal {
display: flex;
width: 100%;
}
#diagonal #ct-about-col-left {
width: 60%;
border-right: 190px solid transparent;
border-bottom: 500px solid grey;
z-index: 2;
}
#diagonal span {
display: none;
}
#ct-about-col-right {
height: 500px;
width: 50%;
border: 2px solid;
background-image: url(images/content/about/right-col-image.jpg);
z-index: 0;
margin-left: -12%;
margin-right: 0;
}
}
<div id="diagonal">
<div id="ct-about-col-left">
<span>We are the best</span>
<span>text1 text1 text1</span>
<span>Text2 text2 text2 text2</span>
<div>
<span>Read more</span>
</div>
</div>
<div id="ct-about-col-right"></div>
</div>
Maybe consider a slightly different mark-up and method of adding the picture (as a background-image) and making the angle (with transform: skew).
Live Demo: http://codepen.io/anon/pen/rjyKRo
<div class="container">
<div class="caption">
<p>CONTENT</p>
</div>
</div>
* { box-sizing: border-box; }
.container {
width: 100%;
height: 50vh;
overflow: hidden;
background-image: url("http://unsplash.it/600");
background-size: cover;
background-repeat: no-repeat;
background-position: 100% 50%;
}
.caption {
height: 100%;
width: 50%;
min-width: 500px;
padding-top: 20%;
padding-left: 130px;
background-color: #ddd;
transform: skew(10deg, 0deg);
transform-origin: 100% 100%;
}
.caption p {
transform: skew(-10deg, 0deg);
}
May I suggest another approach which will save You some markup space and CSS rules as well.
Simply create a full-width div with the ID of lets say ct-about, give it a background color grey and then simply chain the image background on top of the color like so:
background: url('images/content/about/right-col-image.jpg') no-repeat right top, grey;
This simply tells the browser, make my box grey and put that image over the grey color. The no-repeat right top properties are preventing the browser from repeating the image so you don't get a tile, tell ti to place the image on the far right and top positions.
This way everything will be responsive as well.
Here is a Fiddle for You to better understand.
You can find more information about multiple CSS backgrounds in the Mozilla Developer Network

Getting a page-curl transparent image to work with a solid background color

I have a small png with a transparent area I want to act as the bottom-right hand corner of a solid color div, but I can't seem to come up with an elegant way of doing this with css.
my current css:
div.example {
border-radius: 9px;
background-color: #fff;
background-image: url(bottom-right-corner-peel.png);
background-repeat: no-repeat;
background-position: right bottom;
}
The problem with the above code is that the background color of the div (#fff) shows through the transparent part of the png, ruining the effect. I can think of a couple extremely hacky approaches to fix this (for example - creating another div (or using ::after) to put an element below div in question, and use some tricks to make that work, but there must be a better way, right?
View the [revised] Demo:
http://jsbin.com/abacey/8/
Here is a solution to your problem: http://jsfiddle.net/promatik/uZFpZ/
I've added a #content-bottom next to #content:
<div id="content">
<h1>Corner Peel Demo</h1>
</div>
<div id="content-bottom">
<div id="content-space"></div>
<div id="content-corner"></div>
</div>
And added this in CSS:
div#content{
...
border-bottom-right-radius: 0px;
border-bottom-left-radius: 0px;
}
div#content-bottom {
height: 30px;
position: relative;
}
div#content-space {
height: 27px;
border-bottom-left-radius: 9px;
background-color: #fff;
margin-right: 42px;
}
div#content-corner {
position: absolute;
top: 0px;
right: 0px;
height: 27px;
width: 42px;
background-color: transparent;
background-image: url(data:image/png;base64,...');
}
My Ideas is to use the png to cover up the entire corner of the div.
Lets assume your png is 40x40px and the upper left part is white while the lower part is transparent.
You can use
border-bottom-right-radius: 40px;
to "cut off" the corner of the div. Therefore you have the background image visible. Now you lay your png over it to cover up the ugly round corner.
http://jsfiddle.net/Xd8CD/
(needs a better png...)

How do I create a circle or square with just CSS - with a hollow center?

It should just basically be an outline of the square or circle - that I can style accordingly (i.e. change the color to whatever I want, change the thickness of the border, etc.)
I would like to apply that circle or square over something else (like an image or something) and the middle part should be hollowed out, so you can see the image beneath the square or circle.
I would prefer for it to be mainly CSS + HTML.
Try This
div.circle {
-moz-border-radius: 50px/50px;
-webkit-border-radius: 50px 50px;
border-radius: 50px/50px;
border: solid 21px #f00;
width: 50px;
height: 50px;
}
div.square {
border: solid 21px #f0f;
width: 50px;
height: 50px;
}
<div class="circle">
<img/>
</div>
<hr/>
<div class="square">
<img/>
</div>
More here
You can use special characters to make lots of shapes. Examples:
http://jsfiddle.net/martlark/jWh2N/2/
<table>
<tr>
<td>hollow square</td>
<td>□</td>
</tr>
<tr>
<td>solid circle</td>
<td>•</td>
</tr>
<tr>
<td>open circle</td>
<td>๐</td>
</tr>
</table>
Many more can be found here: HTML Special Characters
i don't know of a simple css(2.1 standard)-only solution for circles, but for squares you can do easily:
.squared {
border: 2px solid black;
}
then, use the following html code:
<img src="…" alt="an image " class="squared" />
If you want your div to keep it's circular shape even if you change its width/height (using js for instance) set the radius to 50%. Example:
css:
.circle {
border-radius: 50%/50%;
width: 50px;
height: 50px;
background: black;
}
html:
<div class="circle"></div>
Circle Time! :) Easy way of making a circle with a hollow center : use border-radius, give the element a border and no background so you can see through it :
div {
display: inline-block;
margin-left: 5px;
height: 100px;
border-radius: 100%;
width:100px;
border:solid black 2px;
}
body{
background:url('http://lorempixel.com/output/people-q-c-640-480-1.jpg');
background-size:cover;
}
<div></div>
To my knowledge there is no cross-browser compatible way to make a circle with CSS & HTML only.
For the square I guess you could make a div with a border and a z-index higher than what you are putting it over. I don't understand why you would need to do this, when you could just put a border on the image or "something" itself.
If anyone else knows how to make a circle that is cross browser compatible with CSS & HTML only, I would love to hear about it!
#Caspar Kleijne border-radius does not work in IE8 or below, not sure about 9.
Shortly after finding this questions I found these examples on CSS Tricks: http://css-tricks.com/examples/ShapesOfCSS/
Copied so you don't have to click
.square {
width: 100px;
height: 100px;
background: red;
}
.circle {
width: 100px;
height: 100px;
background: red;
-moz-border-radius: 50px;
-webkit-border-radius: 50px;
border-radius: 50px;
}
/* Cleaner, but slightly less support: use "50%" as value */
<div class="square"></div>
<div class="circle"></div>
There are many other shape examples in the above link, but you will have to test for browser compatibility.
In case of circle all you need is one div, but in case of hollow square you need to have 2 divs.
The divs are having a display of inline-block which you can change accordingly. Live Codepen link: Click Me
In case of circle all you need to change is the border properties and the dimensions(width and height) of circle. If you want to change color just change the border color of hollow-circle.
In case of the square background-color property needs to be changed depending upon the background of page or the element upon which you want to place the hollow-square. Always keep the inner-circle dimension small as compared to the hollow-square. If you want to change color just change the background-color of hollow-square. The inner-circle is centered upon the hollow-square using the position, top, left, transform properties just don't mess with them.
Code is as follows:
/* CSS Code */
.hollow-circle {
width: 4rem;
height: 4rem;
background-color: transparent;
border-radius: 50%;
display: inline-block;
/* Use this */
border-color: black;
border-width: 5px;
border-style: solid;
/* or */
/* Shorthand Property */
/* border: 5px solid #000; */
}
.hollow-square {
position: relative;
width: 4rem;
height: 4rem;
display: inline-block;
background-color: black;
}
.inner-circle {
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
width: 3rem;
height: 3rem;
border-radius: 50%;
background-color: white;
}
<!-- HTML Code -->
<div class="hollow-circle">
</div>
<br/><br/><br/>
<div class="hollow-square">
<div class="inner-circle"></div>
</div>

is it possible to achieve an image clipping/masking effect with html + css3?

I'm trying to place a nice border around an image that's 250x250, using only html and css. The markup is this:
<div id="img-container"><img src="pic.jpg" border="0"/></div>
And the css is:
#img-container {
height: 225px;
width: 225px;
padding: 3px;
border: 1px solid black;
z-index: 10;
position: relative;
overflow: hidden;
border-radius: 10px;
}
#img-container img {
z-index: 5;
}
Basically, I want the div container to clip the picture's edges that exceed its boundaries. This will achieve the rounded edges effect using the border-radius property (-moz-border-radius, -webkit-border-radius, etc) - if it actually works or could even be done. Looking for tips and tricks on this. Thanks.
And, yes, I'm obviously not a web designer :)
Yes it's possible, but you should set the image as the div background using CSS:
#img-container {
height: 225px;
width: 225px;
padding: 3px;
border: 1px solid black;
background-image: url('pic.jpg');
border-radius: 10px;
}
This is necessary, otherwise you will get horrible white borders around the image (tested in Google Chrome).
as far as I understood your question, deleting the
#img-container img {
z-index: 5;
}
part should do the trick.
Or you could use the image as a background image:
#img-container {
...
background: url(pic.jpg) no-repeat top left;
}