Add join to SQL query - mysql

I need to add a join 'level' to a pre-existing SQL query... unfortunately I keep getting errors with this query. I'm proabably falling somewhere but I cannot understand how to fix it.
The original query is the following:
SELECT
noleggio.*,
nome AS convenzionato
FROM
anag_convenzionati
RIGHT JOIN (SELECT
noleggio.*, targa, dc_standard AS dcstandard
FROM
veicoli_contratti
RIGHT JOIN (SELECT
noleggio.*,
nome AS assicurazione_pagante
FROM
anag_assicurazioni
RIGHT JOIN (SELECT
fatt_sconto_noleggio,
fatt_prezzo_noleggio,
id AS idnoleggio,
numero,
serie,
id_convenzionato,
stato_noleggio,
modalita_noleggio,
conducente,
locatario,
locazione_in_proprio,
id_assicurazione_pagante,
id_veicolo,
giorni,
fatt_giorni_noleggio,
fatt_prezzo_totale_noleggio,
data_pagamento_cliente_a_convenzionato,
ore_manodopera,
IF(locazione_in_proprio = 1, conducente, locatario) AS cedente
FROM
noleggio_veicoli
WHERE
((data_cancellazione IS NULL) OR (data_cancellazione = ''))
) AS noleggio ON noleggio.id_assicurazione_pagante = anag_assicurazioni.id
) AS noleggio ON noleggio.id_veicolo = veicoli_contratti.id
) AS noleggio ON noleggio.id_convenzionato = anag_convenzionati.id;
I need to join the resulting table with moduli_ocr table in this way:
SELECT
noleggio.*
FROM
(//query//) AS noleggio
LEFT JOIN
moduli_ocr ON moduli_ocr.id_noleggio = noleggio.id;
Where //query// is the code above.
The error I got (running the query in MySQL Workbench is:
Error Code: 1054. Unknown column 'noleggio.id' in 'on clause'
BTW I'm not sure if I have to use RIGHT or LEFT join but I will check this once the query is properly 'running'.
Best regards.

It seems that you assign idnoleggio alias to the field "id". Try joining on
moduli_ocr.id_noleggio = noleggio.idnoleggio;

Related

UPDATE Query Giving me an SQL Error (1064)

I am trying to update a table in my database from another table. Here is my Syntax, but I can't seem to find any issues with it. I keep getting SQL Error (1064).
UPDATE customers b
SET customers.takerid = customer_update_2016.ot
FROM customer_update_2016 a, customers b
WHERE a.phone = b.phone && a.lname = b.lname
SQL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM customer_update_2016 a, customers b WHERE a.phone = b.phone & a.lname =b' at line 3
Solution:
UPDATE customers
INNER JOIN customer_update_2016
ON customers.phone = customer_update_2016.phone
AND customers.lname = customer_update_2016.lname
SET customers.takerid = customer_update_2016.ot
you have both mysql and sql-server
which one?
UPDATE customers
SET customers.takerid = customer_update_2016.ot
FROM customers
JOIN customer_update_2016
on customers.phone = customer_update_2016.phone
and customers.lname = customer_update_2016.lname
and customers.takerid <> customer_update_2016.ot
Follow something like this always
UPDATE [table1_name] AS t1
INNER JOIN [table2_name] AS t2
ON t1.[column1_name] = t2.[column1_name]
SET t1.[column2_name] = t2.[column2_name];
To solve your problem you should use JOIN, in my case I had to pass data from one table to another like you and this was the way that solved my problem, hope it help with yours and others.(I'm using MariaDB v10.4)
UPDATE
table1
LEFT JOIN table2 AS tb2
ON tb2.fieldThatJoin = table1.fieldThatJoin//this part indicate the field that join them
SET
table1.field1 = tb2.field1;
//if you want to update more than one field then do this
table1.field1 = tb2.field1,
table1.field2 = tb2.field2,
table1.field3 = tb2.field3;//remember to put the ';' at the end

mysql statement prestashop error "checkedFrom"

In prestashop, i want to create a new SQL statement for export rows that i want. Here is my code:
SELECT nx7k_orders.reference
, nx7k_orders.date_add
, nx7k_order_detail.product_name
, nx7k_order_detail.product_quantity
, nx7k_customer.firstname
, nx7k_customer.lastname
FROM nx7k_orders
JOIN nx7k_order_detail
ON nx7k_order_detail.id_order = nx7k_orders.id_order
JOIN nx7k_customer
ON nx7k_customer.id_shop = nx7k_order_detail.id_shop
But, when I click Save button, on top it said, error "checkedFrom"
i think only works if you give alias to the tables:
SELECT no.reference,
no.date_add,
nod.product_name,
nod.product_quantity,
nc.firstname,
nc.lastname
FROM nx7k_orders no
JOIN nx7k_order_detail nod
ON nod.id_order = no.id_order
JOIN nx7k_customer nc
ON nc.id_shop = nod.id_shop

How to access subquery table in the main query with MySQL?

select m1.id, m1.status, at.view_data, at.view_graph, ta.tag_string
from
access_tbl at, image_campaign_tbl m1
RIGHT JOIN
(select
GROUP_CONCAT(t.name) as tag_string , c.image_campaign_id
from campaign_tags_tbl c,tag_tbl t
where c.tag_id=t.id
$tag_q
group by c.image_campaign_id
) as ta
ON ta.image_campaign_id=m1.id
where
m1.client_id =$client_id
and m1.client_id = at.client_id
$prev_filter
limit $start,$end;
Error message:
in LOGS: DBD::mysql::db selectall_arrayref failed: Unknown column 't.name' in 'where clause' at /home/sakthi/rtads/Project/pm/Image/UI.pm line 2536.**
In Perl Module, I'm passing the same value of $tag_q to the $prev_filter to get the Pagination of filter based on TAGS values in the next page
if ( $prev_filter eq '' ) {
$prev_filter =
$search_clist_q . ' '
. $tag_q . ' '
}
From the error msg, I got the error which I'm doing. Since I'm trying to access the table of subquery in the main query, this error is happening.
So I want to know how to access the tag_string(or)t.name outside the subquery.
First of all, i suggest you to avoid use of old school syntax for jointures (FROM table1, table2,... WHERE table1.column1 = table2.column2 AND ...).
Here is the query that seems to return what you're looking for:
SELECT IC.id
,IC.status
,A.view_data
,A.view_graph
,TA.tag_string
FROM access_tbl A
INNER JOIN image_campaign_tbl IC ON IC.client_id = A.client_id
AND IC.client_id = $client_id
RIGHT JOIN (SELECT CT.image_campaign_id
,GROUP_CONCAT(T.name) AS [tag_string]
FROM campaign_tags_tbl CT
INNER JOIN tag_tbl T ON T.id = CT.tag_id
GROUP BY CT.image_campaign_id) TA ON TA.image_campaign_id = IC.id
WHERE <Your filters here>
LIMIT $start, $end
Hope this will help you.

Error fulfilling a column when comparing with a lookup table in another schema

I have a problem trying to fulfill a column id 'like' when comparing the values with another ones in a different schema.
This is the code I'm using:
update oldb.incidencias set impact_id =
(select impact_id
from
newdb.impacts
where
olddb.incidencias.impacto = newdb.impacts.impact_type);
And this is the error I get:
Error Code: 1054. Unknown column 'olddb.incidencias.impacto' in 'where clause'
You can try this:
update o
set o.impact_id = n.impact_id
from oldb.incidencias o
inner join newdb.impacts n
on o.impacto = n.impact_type
Or
update oldb.incidencias o
inner join newdb.impacts n
on o.impacto = n.impact_type
set o.impact_id = n.impact_id

MYSQL IF Function

I am using two joins on the same table for two different select statements. I am wanting to implement an IF function, due to the fact that the table may contain a zero, I am wanting to substitue the zero for the word 'None'
Here is my SQL that works:
SELECT
CONCAT(`payments`.`AssignedTo`," - ",`people2`.`FName`," ",`people2`.`LName`) AS `AssignedTo`,
CONCAT(`payments`.`PersonID`," - ",`people`.`FName`," ",`people`.`LName`) AS `PersonName`
FROM `mb_payments` as `payments`
LEFT JOIN `mb_people` AS `people` ON `people`.`PersonID` = `payments`.`PersonID`
LEFT JOIN `mb_people` AS `people2` ON `people2`.`PersonID` = `payments`.`AssignedTo`
Here is my SQL with the IF function that does not work:
SELECT
IF(AssignedTo IS 0,'None', CONCAT(`payments`.`AssignedTo`," - ",`people2`.`FName`," ",`people2`.`LName`)),
CONCAT(`payments`.`PersonID`," - ",`people`.`FName`," ",`people`.`LName`) AS `PersonName`
FROM `mb_payments` as `payments`
LEFT JOIN `mb_people` AS `people` ON `people`.`PersonID` = `payments`.`PersonID`
LEFT JOIN `mb_people` AS `people2` ON `people2`.`PersonID` = `payments`.`AssignedTo`
You can use CASE statement in this case or if you want to use IF statement then your statement is wrong.
It should be:
SELECT
IF(AssignedTo = 0,'None', CONCAT(`payments`.`AssignedTo`," - ",`people2`.`FName`," ",`people2`.`LName`)) AS Result,
CONCAT(`payments`.`PersonID`," - ",`people`.`FName`," ",`people`.`LName`) AS `PersonName`
FROM `mb_payments` as `payments`
LEFT JOIN `mb_people` AS `people` ON `people`.`PersonID` = `payments`.`PersonID`
LEFT JOIN `mb_people` AS `people2` ON `people2`.`PersonID` = `payments`.`AssignedTo`
Check out this blog: http://timmurphy.org/2009/08/13/inline-if-and-case-statements-in-mysql/
I think you want ".. = 0", not "... IS 0". You use IS when comparing with NULL.