id_no doc_id item_no product customer
123 2 1 A Daisy
123 2 9 A Ben
123 4 3 A Daisy
123 4 4 A Ben
123 6 11 B Daisy
123 6 13 B Ben
when I put it in my report it results to
Daisy Daisy
Ben
And it is also the result in mysql
select distinct customer from receipt where id_no like '123'
result:
Daisy
Daisy
Ben
Another query that I tried:
select distinct id_no, customer, product from receipt where id_no like '123'
result:
123 Daisy A
123 Daisy B
123 Daisy A
123 Ben A
123 Ben B
desired result:
Daisy
Ben
Please help me please.
Thank you guys for the help I found out why the other one keeps on showing. It is because the other Daisy is spelled as Daissy that's why.
Most likely your Customer name contains additional characters between the two records. Depending on how the datatype is implemented, spaces could matter and have contributed to the difference.
Try concatenating a character before and after customer.
I am unfamiliar with the concepts in Crystal Reports, but from what I understand, you would have to create a formula like so:
"XXX" & {Receipt.Customer} & "XXX"
If you run it again, you might recognize there is additional space like so:
XXXDaisyXXX
XXXDaisy XXX
^____ Additional Space
There is no chance of error while you using distinct ..it should return distinct value ...any way you can try another way
SELECT customer FROM receipt WHERE id_no like '123' GROUP BY customer
I don't see why you are fetching three records. I tried implementing your database and ran your query. It returned the result as expected.
See the above pic. There may be some issue with the data type you used. You may try grouping via customer, but I don't think it should affect your result anyway.
Also Check if the data types match.
The selection you made from customer id and id_no is unique and with distinct it should return only two rows
plase try this code
i get solution
select distinct `customer` from receipt where `id_no`='123'
this is right
i tryied this is my past project
best of luck
Related
I have two tables in MS Access, one with foods and associated companies:
FoodID
Food
Company
1
Apple
Vino Farms
2
Orange
Citrus Co.
3
Banana
Vino Farms
and one with information about whether someone ate the food
ClientID
ClientName
Apple
Orange
Banana
1
Bob
Yes
No
Yes
2
Tyler
Yes
Yes
Yes
3
Joe
No
No
No
I'd like to write a query that creates a column populated by the company that makes the foods someone reported eating, separated by commas. If someone reports eating a more than one food made by the same company, I only want the company's name listed once:
ClientID
ClientName
AssociatedCompanies
1
Bob
Vino Farms
2
Tyler
Vino Farms, Citrus Co.
3
Joe
Any help would be greatly appreciated!
As indicated by Gustav, start by normalizing your "ate food" Table. It should look like:
1 Bob Apple
1 Bob Banana
2 Tyler Apple
2 Tyler Orange
2 Tyler Banana
You then get what you want with the following Query:
-- Group companies into one field, sepparated with commas
SELECT ClientID, ClientName, RemoveCommas(Company1 & ", " & Company2 & ", " ... & CompanyN)
FROM
( -- Convert rows (records) into columns (fields)
SELECT ClientID, ClientName
, Max(Iif(Company="Vino Farms", "Vino Farms", Null)) AS Company1
, Max(Iif(Company="Citrus Co.", "Citrus Co.", Null)) AS Company2
, ...
, Max(Iif(Company="Last_company", "Last_company", Null)) AS CompanyN
FROM
(-- Replace food by its manufacturing company
SELECT DISTINCT ClientID, ClientName, Company
FROM
Table_ate_food_normalized AS Ate
INNER JOIN
Table_food AS Comp
ON Ate.Food = Comp.Food
)
GROUP BY ClientID, ClientName
)
Notice the following relevant points:
This will only work, as you notice, for a fixed number of companies with names hardcoded in the Query. This is a very severe limitation. If these restrictions are not satisfied, I suggest that you use a TRANSFORM Query, but, you would not get the companies as a single text field with values sepparated by commas, and you would rather get them as a variable number of fields, each field having a Yes/No value (similar to your current "ate food" table).
I am assuming that the values of "food" and "Company" are each a candidate key in its Table. Otherwise, use the corresponding ID fields, and get the actual values using an inner join.
If you want to understand better the part of converting rows into columns, you may check the Query "K_rows_into_columns_1" from the database of examples dowloadable from LightningGuide.net.
You have to code the user defined VBA function "RemoveCommas()" to remove unncessary commas from the string containing the listing of companies. If unncessesary commas do not bother you, then you can do the Query without coding this functions.
If you want to code the TRANSFORM alternative that I suggested above, you may check the Query "K_rows_into_columns_2" from the database of examples dowloadable from LightningGuide.net.
I have 2 tables as follows
Human
id name
1 John
2 mark
Computer
id human_id
1 2
2 null
I want my answer to be as following
name no_of_computer
John 0
mark 1
I tried the following but am wrong
select h.name,c.human_id) as 'no_of_computer' from human h
join
computer c on c.human_id = h.id
group by h.id
my code is not counting the null as 0 so its just avoiding that and only showing that mark has 1 computer, but I want to see John has 0 computer too. please help me out, thanks in advance
You can use a subquery that's something like:
SELECT
h.Name,
(SELECT COUNT(c.id_of_computers)
FROM computers c
WHERE c.id_human = h.id) as no_of_computer
FROM humans h
Do not cut and paste this to test, as I paid no attention to actual ID names in your tables. You'll have to look at that. 👍
I am a newbie in programming and just started with a project. My question is how should the query look like to get the right data?
My table:
id rfid beer email
1 12345 3 markus.test#gmail.com
2 54321 4 hans.test#gmail.com
3 63737 1 mark.test#gmail.com
4 12345 -2 markus.test#gmail.com
5 54321 -3 hans.test#gmail.com
The query result should look like
[{email: markus.test#gmail.com, beer:1},{email:hans.test#gmail.com, beer:1}....]
I know that you can use SUM(beer) in the query, but I don't know who to match them with the right email.
If you group your data then aggregate functions like sum() will sum for each group and not the complete result
select email, sum(beer) as beer
from your_table
group by email
I have a simple question that I wasn't really sure how to search for (or title!). I apologize if this has been asked a million times. For the following table, how do I generate a report that will detail the number of companies that a person has worked for and how many people have also worked for that same number? So, for example, this table should return:
people, companiesperperson
1, 1
2, 2
1, 3
for the following table called personalinfo:
id_number first last company
1 John Doe Intel
2 John Doe Microsoft
3 Phil Jenkins Amgen
4 Phil Jenkins Bayer
5 Phil Jenkins Sanofi
6 Josh Edwards Walgreens
7 Amy Dill URS
8 Amy Dill ARCADIS
Let me know if this is still confusing and if I can further clarify what I am looking to do.
Thanks!
This is a rough estimate of the query but
SELECT count as companiesperperson, COUNT(first, last) as people FROM
(SELECT COUNT(company) as count, first, last FROM personalinfo GROUP BY (first, last)) as a
GROUP BY count
To explain the query first in the subquery we are asking for the names and count of companies after splitting up all the rows by names
Then in the outer query we split up all the rows by their count and ask how many unique names can be found in each group.
There may be a few syntax errors I've left straggling but the group by feature is really what's essential to understanding how to solve this question.
I'm working on a project where I'm dumping data into a mysql database about different people, however, each person can have many entries so I'm not sure how to have a lot of columns.
e.g
Name id
jack 234 01241990 13241990 03451993 10945
james 222 01131998 14242001 03414235 10945435 3456363 3465758
jill 1234 01131998 14242001 03414235 10945435 3456363 3465758 4253156316 6427247 583583
As you can see there can be many entries for each person, not in 100's, but I think the max can be around 20-30ish? So how do I build a database that I can insert values into without knowing how many entries will be per person, beforehand.
I am using perl script to insert values. Any ideas will be helpful
EDIT: People are suggesting to create two tables, however, when I joint he tables, I want one row for each person.
e.g After joining my view should look like
james 222 01131998 14242001 03414235 10945435 3456363 3465758
My suggestion would be to split the data into two tables (People and Data):
People:
NAME ID
Jack 234
James 222
Jill 1234
Data:
ID PeopleID Data
1 234 01241990
2 234 13241990
.
.
99 1234 6427247
100 1234 583583
You can then use joins to get the data for each person
SELECT p.Name,
p.ID,
d.Data
FROM People p
JOIN Data d
ON d.PeopleID = p.ID
ORDER BY p.Name --(assuming you want names in alphabetical order)
You should get something like the following
Name ID Data
Jack 234 01241990
Jack 234 13241990
.
.
Jill 1234 6427247
Jill 1234 583583