SQL Database with undefined columns - mysql

I'm working on a project where I'm dumping data into a mysql database about different people, however, each person can have many entries so I'm not sure how to have a lot of columns.
e.g
Name id
jack 234 01241990 13241990 03451993 10945
james 222 01131998 14242001 03414235 10945435 3456363 3465758
jill 1234 01131998 14242001 03414235 10945435 3456363 3465758 4253156316 6427247 583583
As you can see there can be many entries for each person, not in 100's, but I think the max can be around 20-30ish? So how do I build a database that I can insert values into without knowing how many entries will be per person, beforehand.
I am using perl script to insert values. Any ideas will be helpful
EDIT: People are suggesting to create two tables, however, when I joint he tables, I want one row for each person.
e.g After joining my view should look like
james 222 01131998 14242001 03414235 10945435 3456363 3465758

My suggestion would be to split the data into two tables (People and Data):
People:
NAME ID
Jack 234
James 222
Jill 1234
Data:
ID PeopleID Data
1 234 01241990
2 234 13241990
.
.
99 1234 6427247
100 1234 583583
You can then use joins to get the data for each person
SELECT p.Name,
p.ID,
d.Data
FROM People p
JOIN Data d
ON d.PeopleID = p.ID
ORDER BY p.Name --(assuming you want names in alphabetical order)
You should get something like the following
Name ID Data
Jack 234 01241990
Jack 234 13241990
.
.
Jill 1234 6427247
Jill 1234 583583

Related

Get unique data across certain column in multiple tables - sql

I know this is probably so odd to ask. But lets say I have 3 tables:
Table 1
ID
Name
1
Adam
2
David
3
Conor
Table 2
ID
Name
1
Adam
2
Derek
3
Niall
Table 3
ID
Name
1
Adam
2
David
3
John
Is there any way I can write a query to get the unique names across all 3 tables. So it would return "Adam, David, Conor, Derek, Niall, John"
Order doesn't matter
If it helps, all name values are related to a names table
yes , one way is to union them
select name from table1
union
select name from table2
union
select name from table3
union automatically removes duplicate cases

Select and compare two columns from different tables to find matched records

I'm just learning PHP and MySQL and I have two tables in the same database : FirstYear , SecondYear that have a structure like this :
StudentId |Math | Physics StudentId1 | Math1 | physics1
Joe 10 14 Alan 12 17
Alan 13 17 Smith 11 13
Smith 9 9 Joe 10 15
Is it possible to write a query that select and compare the two columns StudentId , StudentId1 to find matched records and if for example Joe=Joe after that compare records of math with math1 and physics with physics1 that are in the same row as matched records of StudentId with StudentId1 ;the idea of this query is to study the improvement of same student from first year to the second one ,Thanks .
Yes, it is possible but you have to complete SQL fundamental course.
In this situation you have to know about JOIN. Such as, Inner Join, Left Join, Right Join, Full Join etc. Also, compare with unique id, not name. Because, name always duplicate. It is not good practice. So, Know about primary key and foreign key.
However,
Query-
SELECT * FROM FirstYear INNER JOIN SecondYear ON FirstYear.StudentId = SecondYear.StudentId1 WHERE FirstYear.id = 1
Something like that, alternatively, you can try to another logic.

How to select data from multiple tables with limit 1 for one table

I have multiple checkboxes where user can add education data to database. My structure looks following in database: I have three tables, user_education where I keep the record users selected education levels (it can have multiple rows for the same user_id), education, where I store user education description (only one row per user_id), and education levels where I store all the degrees.
user_education
id | user_id | education_id
1 83 1
2 83 2
education_description
user_id | description
83 test
education_levels
education_id | education
1 alusharidus
2 keskharidus
3 Bachelor’s degree
4 Master’s degree
and so on. My question is how can I select all the data for the specific user, but only show the description once?
I tried running this:
select
user_education.education_id,
education_levels.education,
education_description.description
from
user_education
join education_description
left join education_levels
on user_education.education_id=education_levels.education_id and education_description.user_id = user_education.user_id WHERE user_education.user_id=83;
which gave me this:
and here is the description inserted multiple times, but I would like to only have it once. Is my structure wrong for this type of logic? If not, how can I select it only once, so I can append the data for the user after he submits the form?
EDIT
adding desired result
education_description
user_id | education | description
83 test testing
83 test2
83 test3
Can you please try this answer :-
select
user_education.education_id,
GROUP_CONCAT(education_levels.education separator ' ,'),
education_description.description
from
user_education
join education_description
left join education_levels
on user_education.education_id=education_levels.education_id and education_description.user_id = user_education.user_id
WHERE user_education.user_id=83
GROUP BY user_education.user_id;

Distinct is not working in crystal reports and in mysql

id_no doc_id item_no product customer
123 2 1 A Daisy
123 2 9 A Ben
123 4 3 A Daisy
123 4 4 A Ben
123 6 11 B Daisy
123 6 13 B Ben
when I put it in my report it results to
Daisy Daisy
Ben
And it is also the result in mysql
select distinct customer from receipt where id_no like '123'
result:
Daisy
Daisy
Ben
Another query that I tried:
select distinct id_no, customer, product from receipt where id_no like '123'
result:
123 Daisy A
123 Daisy B
123 Daisy A
123 Ben A
123 Ben B
desired result:
Daisy
Ben
Please help me please.
Thank you guys for the help I found out why the other one keeps on showing. It is because the other Daisy is spelled as Daissy that's why.
Most likely your Customer name contains additional characters between the two records. Depending on how the datatype is implemented, spaces could matter and have contributed to the difference.
Try concatenating a character before and after customer.
I am unfamiliar with the concepts in Crystal Reports, but from what I understand, you would have to create a formula like so:
"XXX" & {Receipt.Customer} & "XXX"
If you run it again, you might recognize there is additional space like so:
XXXDaisyXXX
XXXDaisy XXX
^____ Additional Space
There is no chance of error while you using distinct ..it should return distinct value ...any way you can try another way
SELECT customer FROM receipt WHERE id_no like '123' GROUP BY customer
I don't see why you are fetching three records. I tried implementing your database and ran your query. It returned the result as expected.
See the above pic. There may be some issue with the data type you used. You may try grouping via customer, but I don't think it should affect your result anyway.
Also Check if the data types match.
The selection you made from customer id and id_no is unique and with distinct it should return only two rows
plase try this code
i get solution
select distinct `customer` from receipt where `id_no`='123'
this is right
i tryied this is my past project
best of luck

Many to Many Relationship using Joins

I have a database two tables and a linking table that I need a JOIN query for:
Here are my Tables:
family (userid (int), loginName, etc)
member (memberid (int), loginName(this links member to a family),name, etc)
Linking Table:
user2member (userid,memberid)...would both be foreign keys?
I want to do two things:
1) Be able to have a family.loginName(12,Johnson) subscribe to another family.loginName (43,Smith) and record that into the linking table.
That would look like this:
12,43
2) When I do a query for all the member.name that are in the Johnson Family, I'll get all the Johnsons & all the Smiths.
If Johnson = Ted, Sue & Patty
IF Smith =Joe, Sue & Bob
my query results would be Johnson now = Ted,Sue,Patty,Joe,Sue,Bob
I asked this question a few days ago without good table names and I ended up confusing myself and the nice guy Ollie Jones who posted an answer similar to this for the query:
SELECT member.name
FROM family
JOIN user2member on family.userid = member.memberid
JOIN member on user2member.name = member.name
 WHERE family.userid = '30'
ORDER BY member.name
I had to change Ollie's answer to match my tables but I'm getting a limit error 0,30 on line 5.
This is my first time doing JOINS and I have no idea if this is correct.
Thanks,
Here's the link to my first question: mySQL table linking , group linked to other members lists, the displaying all members
I am not sure, if the tables you suggested would solve your problem. If I understand your question correct, there are two relationships:
a relationship for all family members (Johnson with Ted, Sue, Patty, Smith with Joe, Sue, Bob)
a relationship for subscriptions (a family can subscribe to another family)
I would suggest following tables:
family (f_id, f_loginName, etc.)
member (m_id, m_f_id, m_name) (foreign key to family, many-to-one relationship)
subscription (s_f_id,s_to_f_id) (linking is based on both family keys)
This would result in following contents:
family:
f_id f_loginName
12 Johnson
43 Smith
member:
m_id m_f_id m_name
1 12 Ted
2 12 Sue
3 12 Patty
4 43 Joe
5 43 Sue
6 43 Bob
subscription
s_f_id s_to_f_id
12 43
Now, to get all possible members for a specific family and it's subscriptions, I would use following SQL query. It has a simple join for family and it's family members. In the WHERE clause, the family Johnson is fetched (f_id = 12) and to get all family members from the subscriptions, it's easier to use a subquery.
SELECT f_loginName, m_name
FROM family
INNER JOIN member ON m_f_id = f_id
WHERE f_id = 12
OR f_id IN (SELECT s_to_f_id FROM subscription WHERE s_f_id = 12)
ORDER BY f_loginName, m_name;