I am using MySQL, I have following table structure
Id id2 classId sectionId validFrom validTill
------------------------------------------------------
1 1 5 13 2016-01-01 2016-03-30
2 1 5 22 2016-01-15 2016-03-30
3 1 5 23 2016-01-15 2016-04-29
4 1 5 13 2016-04-01 2016-04-30
9 10 6 24 2016-01-17 2016-02-05
10 10 6 25 2016-01-23 2016-02-05
11 10 6 24 2016-01-31 2016-02-05
My SQL statement is
SELECT count(*) as timeCount FROM TimeTableClassSection a
WHERE classId=5 AND sectionId=13 AND ((a.ValidFrom BETWEEN '2016-01-18' AND '2016-01-24') OR (a.ValidTill BETWEEN '2016-01-18' AND '2016-01-24'))
Its returning timeCount = 0. But it should return 1 as record with Id=1 falls between this date range ('2016-01-18' AND '2016-01-24')
I am trying to achieve, find out any overlapping record for particular classId & sectionId between provided date range.
If classId=5 and sectionId=13 has validFrom=2016-01-01 validTill=2016-03-30 exist, then any date range between this date range ('2016-01-18' AND '2016-01-24') should throw this record as count.
If I give date range 2015-12-25 to 2016-09-20 then record count should = 1
If I give date range 2016-2-1 to 2016-02-20 then record count should = 1
If I give date range 2016-2-1 to 2016-09-20 then record count should = 1
What wrong I am doing here ... all date format is in YYYY-MM-DD
You are only checking if the boundaries are within the date range, but you do not check whether the data range is within the boundaries. You should extend your where criteria:
...AND ((a.ValidFrom BETWEEN '2016-01-18' AND '2016-01-24')
OR (a.ValidTill BETWEEN '2016-01-18' AND '2016-01-24')
OR (a.ValidFrom<'2016-01-18' AND a.ValidTill>'2016-01-24'))
Related
I have two tables:
Table 1: planA
ID Date Count
3 2017-01-01 10
2 2017-02-03 15
10 2017-01-30 8
Table 2: planB
ID Date Value
3 2017-01-02 11
2 2017-02-04 12
21 2017-01-30 3
3 2017-02-03 33
What I want to do is to join the two tables on (ID and Date) columns.
However, on Date, I want to use the next day to the date on the table 1.
Therefore, the joined table should look like the following:
PlanA.ID PlanA.Date PlanB.Date PlanA.Count PlanB.Value
3 2017-01-01 2017-01-02 10 11
2 2017-02-03 2017-02-04 15 12
Is this even possible?
Any suggestion would be appreciated!
Yes it is possible:
select
PlanA.ID,
PlanA.Date,
PlanB.Date,
PlanA.Count,
PlanB.Value
from
PlanA inner join PlanB
on (
PlanA.ID = PlanB.ID
and
PlanA.Date + INTERVAL 1 DAY = PlanB.Date
)
if Date is a column of type date, + INTERVAL 1 DAY will return the next day of the one given, and then you can perform the join.
id ref_id dates
1 1 2017-01-01 00:00:00
2 1 2017-01-31 00:00:00
3 2 2017-01-01 00:00:00
4 2 2017-01-31 00:00:00
5 3 2016-01-01 00:00:00
6 3 2016-01-31 00:00:00
Query will be like
SELECT * FROM table WHERE dates GROUP By ref_id
I would like to compare ref_id wise Start Date in 1st row & End Date in 2nd row should be between Current Date.
So output will be only those ref_id which are in between current date.
Output
ref_id
1
2
or GROUP_CONCAT of that 1,2
Would like to using single query without UNION.
Try this:
SELECT ref_id
FROM table
GROUP BY ref_id
HAVING NOW() BETWEEN MIN(dates) AND MAX(dates)
The query uses NOW in order to get the current date/time value. If this value lies within the interval defined by the minimum and maximum date value of a ref_id group, then this ref_id is returned by the query.
I have a table like this:
date amt sr
----------------------
2013-07-01 -10 1
2013-07-02 40 2
2013-07-03 10 3
2013-07-04 -10 4
2013-07-06 10 5
2013-07-07 -10 6
2013-07-08 10 7
2013-07-09 10 8
2013-07-10 10 9
I want this result:
date amt sr
--------------------------
2013-07-08 60 7
Get next date of last minimum negative amount date
Assuming a table called date_value with a date and int columns called dat and value
Then you can get the desired result by:
SELECT (
SELECT MIN(dat) FROM dbo.date_value
WHERE dat > ( SELECT MAX(dat) FROM dbo.date_value WHERE val < 0 )
) AS 'date',
SUM(val) AS 'amt'
FROM dbo.date_value
I have the following table:
id | start_date | end_date | client_id
1 2013-08-01 2013-08-09 1
2 2013-08-10 2013-08-10 1
3 2013-08-10 2013-08-17 1
4 2013-08-18 2013-08-18 1
5 2013-08-18 2013-08-18 1
6 2013-08-18 2013-08-31 1
7 2013-08-01 2013-08-09 2
8 2013-08-11 2013-08-11 2
9 2013-08-11 2013-08-17 2
10 2013-08-19 2013-08-20 2
what I'm trying to do is count the number of days that each client was present without repeating the days for each client, so from the previous data I'm looking to get:
client_id | total_days
1 31
2 18
So for client 1 I get 31 because he was "present" for 31 days, from 8/1/2013 - 8/31/2013 with no gaps, and for client 2 I get 18 because he was present for 18 days:
8/1 - 8/9 = 9 days
8/11 - 8/17 = 7 days
8/19 - 8/20 = 2 days
is there anyway to achieve this in MySQL, I've been trying for a while but have no idea on how to do it.
This is the fiddle
If overlapping ranges exist, then I suggest building a driver table that is a list of dates, then JOIN to that table using BETWEEN:
SELECT a.Client_ID, COUNT(DISTINCT b.Date)
FROM YourTable a
JOIN Dates b
ON b.Date BETWEEN a.start_date AND a.end_date
GROUP BY a.Client_ID
Demo: SQL Fiddle
There are plenty of places to find calendar table logic, here's one.
If ranges never overlap then you can use SUM(DATEDIFF()).
If there are no overlapping ranges. You can use the following query:
SELECT Client_id,
Sum(DATEDIFF(End_date, Start_date)) AS `Present`
FROM TABLE
GROUP BY Client_id;
This will give you an overview of the number of days a client was present.
I have Table with 3 Columns, Column1 with Date and Column2 stores Points which is nothing but Some random Number between 1 to 9 and column 3 which have some unique email address in every cell.
Now I want to add the points grouped by date for last 5 days.
That is if I have 3 rows for day one, 1 rows for day two, 3 rows for day 3 and 2 rows for day 4 & 5 I should get the sum of points of these 11 rows grouped by date as 5 rows for five days.
Input
Date Points
Email
2012-07-01 5 a#sample.com
2012-07-01 6 b#sample.com
2012-07-01 2 c#sample.com
2012-07-02 5 d#sample.com
2012-07-03 8 e#sample.com
2012-07-03 7
f#sample.com
2012-07-03 1
y#sample.com
2012-07-04 3 x#sample.com
2012-07-04 2 f#sample.com
2012-07-05 3 g#sample.com
2012-07-05 9 b#sample.com
Output
Date Points
2012-07-01 13
2012-07-02 5
2012-07-03 16
2012-07-04 5
2012-07-05 12
Please suggest me a MySQL query for the above.
select `Date`,sum(`Points`) from my_table group by `Date`;
select `Date`,sum(`Points`) from my_table group by `Date` Limit 5;
select Date,sum(Points) from my_table group by Date;
select [Date],SUM(Points)
from myTable1
group by [Date]
You can do:
SELECT date, SUM(points) AS points
FROM tbl
WHERE date > CURDATE() - INTERVAL 5 DAY
GROUP BY date