Mysql Group By Date - mysql

I have Table with 3 Columns, Column1 with Date and Column2 stores Points which is nothing but Some random Number between 1 to 9 and column 3 which have some unique email address in every cell.
Now I want to add the points grouped by date for last 5 days.
That is if I have 3 rows for day one, 1 rows for day two, 3 rows for day 3 and 2 rows for day 4 & 5 I should get the sum of points of these 11 rows grouped by date as 5 rows for five days.
Input
Date Points
Email
2012-07-01 5 a#sample.com
2012-07-01 6 b#sample.com
2012-07-01 2 c#sample.com
2012-07-02 5 d#sample.com
2012-07-03 8 e#sample.com
2012-07-03 7
f#sample.com
2012-07-03 1
y#sample.com
2012-07-04 3 x#sample.com
2012-07-04 2 f#sample.com
2012-07-05 3 g#sample.com
2012-07-05 9 b#sample.com
Output
Date Points
2012-07-01 13
2012-07-02 5
2012-07-03 16
2012-07-04 5
2012-07-05 12
Please suggest me a MySQL query for the above.

select `Date`,sum(`Points`) from my_table group by `Date`;

select `Date`,sum(`Points`) from my_table group by `Date` Limit 5;

select Date,sum(Points) from my_table group by Date;

select [Date],SUM(Points)
from myTable1
group by [Date]

You can do:
SELECT date, SUM(points) AS points
FROM tbl
WHERE date > CURDATE() - INTERVAL 5 DAY
GROUP BY date

Related

Select from db and limit result to where datetime is the same

I have a datetime field in my db. Now i want to select upcoming dates from NOW() based on the dates. If two datetimes is the same I want to select them. And if it's only one I want to select that date. Limit is that I never want to select more than two rows.
So if NOW() is 2021-06-18 12:00:00 row number 1 should be selected.
If NOW() is 2021-06-20 18:15:00 row number 3 and 4 should be selected.
1 2021-06-19 18:00:00
2 2021-06-20 18:00:00
3 2021-06-21 15:00:00
4 2021-06-21 15:00:00
5 2021-06-21 18:00:00
6 2021-06-21 18:00:00
I've tried
SELECT gamedate
FROM games
WHERE gamedate > NOW()
ORDER BY gamedate LIMIT 0 , 1
but that doesn't make any sense or what I want to do.
Use a subquery to get the next gamedate. Then use that in the main query to select at most two rows with that date.
SELECT id, gamedate
FROM games AS g
WHERE gamemedate = (SELECT MIN(gamedate) FROM games WHERE gamedate > NOW())
ORDER BY id
LIMIT 2

SQL joining on two columns with a variation on the first column

I have two tables:
Table 1: planA
ID Date Count
3 2017-01-01 10
2 2017-02-03 15
10 2017-01-30 8
Table 2: planB
ID Date Value
3 2017-01-02 11
2 2017-02-04 12
21 2017-01-30 3
3 2017-02-03 33
What I want to do is to join the two tables on (ID and Date) columns.
However, on Date, I want to use the next day to the date on the table 1.
Therefore, the joined table should look like the following:
PlanA.ID PlanA.Date PlanB.Date PlanA.Count PlanB.Value
3 2017-01-01 2017-01-02 10 11
2 2017-02-03 2017-02-04 15 12
Is this even possible?
Any suggestion would be appreciated!
Yes it is possible:
select
PlanA.ID,
PlanA.Date,
PlanB.Date,
PlanA.Count,
PlanB.Value
from
PlanA inner join PlanB
on (
PlanA.ID = PlanB.ID
and
PlanA.Date + INTERVAL 1 DAY = PlanB.Date
)
if Date is a column of type date, + INTERVAL 1 DAY will return the next day of the one given, and then you can perform the join.

how to find overlapping record with between date

I am using MySQL, I have following table structure
Id id2 classId sectionId validFrom validTill
------------------------------------------------------
1 1 5 13 2016-01-01 2016-03-30
2 1 5 22 2016-01-15 2016-03-30
3 1 5 23 2016-01-15 2016-04-29
4 1 5 13 2016-04-01 2016-04-30
9 10 6 24 2016-01-17 2016-02-05
10 10 6 25 2016-01-23 2016-02-05
11 10 6 24 2016-01-31 2016-02-05
My SQL statement is
SELECT count(*) as timeCount FROM TimeTableClassSection a
WHERE classId=5 AND sectionId=13 AND ((a.ValidFrom BETWEEN '2016-01-18' AND '2016-01-24') OR (a.ValidTill BETWEEN '2016-01-18' AND '2016-01-24'))
Its returning timeCount = 0. But it should return 1 as record with Id=1 falls between this date range ('2016-01-18' AND '2016-01-24')
I am trying to achieve, find out any overlapping record for particular classId & sectionId between provided date range.
If classId=5 and sectionId=13 has validFrom=2016-01-01 validTill=2016-03-30 exist, then any date range between this date range ('2016-01-18' AND '2016-01-24') should throw this record as count.
If I give date range 2015-12-25 to 2016-09-20 then record count should = 1
If I give date range 2016-2-1 to 2016-02-20 then record count should = 1
If I give date range 2016-2-1 to 2016-09-20 then record count should = 1
What wrong I am doing here ... all date format is in YYYY-MM-DD
You are only checking if the boundaries are within the date range, but you do not check whether the data range is within the boundaries. You should extend your where criteria:
...AND ((a.ValidFrom BETWEEN '2016-01-18' AND '2016-01-24')
OR (a.ValidTill BETWEEN '2016-01-18' AND '2016-01-24')
OR (a.ValidFrom<'2016-01-18' AND a.ValidTill>'2016-01-24'))

Daily count of Active Users for a given date range

I need to find the Daily total count of Active Users based on the Start Date and End Date.
REGISTRATION TABLE
id registration_no start_date end_date
1 1000 2014/12/01 2014/12/03
2 1001 2014/12/01 2014/12/03
3 1002 2014/12/02 2014/12/04
4 1003 2014/12/02 2014/12/04
5 1004 2014/12/02 2014/12/04
6 1005 2014/12/03 2014/12/05
7 1006 2014/12/05 2014/12/06
8 1007 2014/12/05 2014/12/09
9 1008 2014/12/06 2014/12/10
10 1009 2014/12/07 2014/12/11
The result should be in the following format.
Date Active Users
2014-12-01 2
2014-12-02 5
2014-12-03 6
2014-12-04 4
2014-12-05 3
2014-12-06 3
2014-12-07 3
2014-12-08 3
2014-12-09 3
2014-12-10 2
2014-12-11 1
2014-12-12 0
I know the following query is not working.
SELECT start_date, count(*) FROM registration
WHERE start_date >= '2014/12/01' AND end_date <='2014/12/12'
GROUP BY start_date
Which is not the desired output :
2014-12-01 2
2014-12-02 3
2014-12-03 1
2014-12-05 2
2014-12-06 1
2014-12-07 1
Any help would be much appreciated.
You need to create a "calendar" with all the days you need and then use a query like:
SELECT calDay as `Date`, count(id) as `Active Users`
FROM (SELECT cast('2014-12-01' + interval `day` day as date) calDay
FROM days31
WHERE cast('2014-12-01' + interval `day` day as date) < '2014-12-12') calendar
LEFT JOIN registration on (calDay between start_date and end_date)
GROUP BY calDay
ORDER BY calDay;
You can see it working in this fiddle, where days31 is just a view with integers 0-30. This allows the query to work in any calendar up to a period of 31 days. You can add more days to the view or generate them on the fly using cross joins. See http://www.artfulsoftware.com/infotree/qrytip.php?id=95
Try it.... please note on where condition FOR 2014-12-02, as per comment
SELECT DATE_FORMAT(start_date,'%Y-%m-%d')as Date, count(*) as ActiveUser FROM registration
WHERE (start_date >= '2014/12/02' AND end_date <='2014/12/02')
GROUP BY start_date

Mysql Sum and Group By Method

Input
Date Points
Email
2012-07-01 5 a#sample.com
2012-07-01 6 b#sample.com
2012-07-01 2 c#sample.com
2012-07-02 5 d#sample.com
2012-07-03 8 e#sample.com
2012-07-03 7
f#sample.com
2012-07-03 1
y#sample.com
2012-07-04 3 x#sample.com
2012-07-04 2 f#sample.com
2012-07-05 3 g#sample.com
2012-07-05 9 b#sample.com
Output
Date Points
2012-07-01 13
2012-07-02 5
2012-07-03 16
2012-07-04 5
2012-07-05 12
Suggest me an MySQL Query for output like the above
try
SELECT `date`, SUM(`Points`) AS sumPoint FROM table GROUP BY `date`
Note : dont forget to wrap date column with ` as DATE is reserve keyword of mySQL
SELECT date, SUM(Points) AS sumPoint
FROM table
GROUP BY DATE(date)
Since date column might be datetime or date type in table