I have a really basic Date system on a site which displays the dates from the Database using a While loop, next to each date that is listed is a check box.
I would like the user to be able to select as many dates as they would like and click submit to remove these dates or edit these dates.
I am having trouble figuring out how I would get the data from multiple check-boxes using only one within the while loop which could be used multiple times?
Here is my current code:
<form action="" method="post">
<b>Current Dates:</b> <button type="submit" id="remove_dates" name="remove_dates" class="btn btn-danger btn-sm">Remove Selected</button>
<hr>
<div style="overflow-y: scroll;height:100px">
<?
$sqldate = "SELECT * FROM `foiu51r_calendar` ORDER BY date DESC";
$resultdate = $conn->query($sqldate);
if ($resultdate->num_rows > 0) {
// output data of each row
while($rowdate = $resultdate->fetch_assoc()) {
$date_id = $rowdate['date_id'];
$dates = $rowdate['date'];
?>
<input type="checkbox" id="date_id" name="date_id" value="<? echo $date_id; ?>"> <b><? echo date("d/m/Y", strtotime($dates)); ?></b><br>
<?
}
}
?>
</div>
</form>
if(isset($_POST['remove_dates'])){
$date_id = $_POST['date_id'];
}
I believe if you add this: [], to the name attribute, like this: <input type="checkbox" id="date_id" name="date_id[]" value="<? echo $date_id; ?>">. Then it will be handled as an array, which you can loop through with a foreach loop. and insert it into a database (or whatever you like).
Declare the name as an array, like as follows:
<input type="checkbox" id="date_id" name="date_id[]" value="<? echo $date_id; ?>">.
On submitting it will be handled as an array,
Then, you can loop the values of an array and for each element of an array use the id to remove the dates.
Related
I'm trying to access data from local wamp server from a Wordpress site using a Search box. I created the search box using the function get_search_form(), and I am unable to write a query in php to access using the same.
I have used Wamp server (localhost) and a Wordpress site.
I have tried writing an html code for the search box and tried to access the data using it. But it didn't work. I felt it's easy to run a single php script rather than a separate html and php scripts.
Code to fetch data from db:
$connect = mysqli_connect("localhost", "root", "", "mydb");
$output = '';
if(isset($_POST["query"]))
{
$search = mysqli_real_escape_string($connect, $_POST["query"]);
$query = "
SELECT * FROM clients;
WHERE Name LIKE '%".$search."%'
OR Aadhar LIKE '%".$search."%'
OR Mobile LIKE '%".$search."%'
OR Company LIKE '%".$search."%'
OR Description LIKE '%".$search."%'
";
}
else
{
$query = "SELECT * FROM clients ORDER BY Name";
}
$result = mysqli_query($connect, $query);
if(mysqli_num_rows($result) > 0)
{
$output .= '
<div class="table-responsive">
<table class="table table bordered">
<tr>
<th>Name</th>
<th>Aadhar</th>
<th>Mobile</th>
<th>Company</th>
<th>Description</th>
</tr>
';
while($row = mysqli_fetch_array($result)
{
$output .= '
<tr>
<td>'.$row["Name"].'</td>
<td>'.$row["Aadhar"].'</td>
<td>'.$row["Mobile"].'</td>
<td>'.$row["Company"].'</td>
<td>'.$row["Description"].'</td>
</tr>
';
}
echo $output;
}
else
{
echo 'Data Not Found';
}
I am successfully able to access all the data using this code.
First of all the function get_search_form(); will create a Search Box and a Submit button with a wrapper form. Form method is GET so $_POST in your code is completely wrong. Next is the search box created using this function have the name "s". The below code will be generated through the function :
<form role="search" method="get" class="search-form" action="">
<label>
<span class="screen-reader-text">Search for:</span>
<input type="search" class="search-field" placeholder="Search …" value="" name="s">
</label>
<input type="submit" class="search-submit" value="Search">
</form>
So change your code $_POST['query'] with $_GET['s']. Hope it will work for you.
I tried searching but no success i want to upload max 5 images to database along with user form data.I have table where all user data of form posted is saved along with images uploaded[image upload is attached with user form] picture fields in database are named as pic1,pic2,pic3.. pic5 + email,password etc I am successfull in uploading image data to database but not images.
//controller
if ($this->form_validation->run()!=true) {
$data['countryDrop'] = $this->Country_states_cities->getCountries();
$this->load->view('header');
$this->load->view('register',$data); //Display page
$this->load->view('footer');
}else{
$form=array();
$form['first_name']=$this->input->post("first_name",true);
$form['last_name']=$this->input->post("last_name",true);
$form['dob']=date('Y-m-d',strtotime($this->input->post("dob",true)));
$form['email']=$this->input->post("email",true);
$form['password']=sha1($this->input->post("password",true));
$form['phone']=$this->input->post("phone",true);
$form['addline2']=$this->input->post("addressline2",true);
$form['zip']=$this->input->post("zip",true);
$result = $this->Couch_reg->insert_new_user($form); //call to model
//model
function insert_new_user($form)
{
$this->db->insert('tbl_usrs',$form);
if ($this->db->affected_rows() > 0) {
return true;
} else {
return false;
}
}
//view
<input type="file" name="uploadfile[]" accept = "image/*" multiple = "multiple" size="20" /> <br />
as we can see model part is very short i want to collect images name in array form and send it to database.
You need to save the images in the upload folder and save the image name in the database.
<html>
<body>
<form method="POST" action="<?php echo site_url('my-controller/file_upload');?>" 'enctype'=>'multipart/form-data'>
<label for="file">Filename:</label>
<input type="file" name="userfile[]" id="file" multiple>
<input type="submit" value="upload"></form>
</body>
</html>
Then create controller
make funtion inside it:
$files = $_FILES;
$cpt = count($_FILES['userfile']['name']);
for($i=0; $i<$cpt; $i++)
{
$_FILES['userfile']['name']= $files['userfile']['name'][$i];
$_FILES['userfile']['type']= $files['userfile']['type'][$i];
$_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
$_FILES['userfile']['error']= $files['userfile']['error'][$i];
$_FILES['userfile']['size']= $files['userfile']['size'][$i];
$this->upload->initialize($this->set_upload_options());
$this->upload->do_upload();
$fileName = $_FILES['userfile']['name'];
$images[] = $fileName;
Hope this will help you.
For more you can try this: http://w3code.in/2015/09/upload-file-using-codeigniter/
I've been searching google to find the code, but I can't find it. What I want to do is pretty simple, but I'm not php expert.
I want to insert multiple cities' name in a single press of submit button (if that is possible)
I have created a database with 2 tables: 'cities' and 'states'
and I have populated the states table
so I need two fields or boxes, one is for states, which is drop down 'select' box which already filled with states name, pulled from the database,
the other one is a cities field which a text type field (type="text").
I want to be able to type in multiple cities name, probably separated with ',' a comma,
and with a single press of submit button, all the value will be inserted into mysql cities table and go on to the next state.
I know I need to create some sort of loop, but I have no idea how to do it.
*index.php (html):
<html>
<body>
<form action="save.php" method="POST">
<input type="text" name ="cities" value="">
<input type="text" name ="state" value="">
<input type="submit">
</form>
</body>
*save.php:
<?php
/* -------include you db connection here ----*/
if(isset($_POST['çities']) && $_POST['çities'] !='' && isset($_POST['state']) && $_POST['state'] !=''){
$cities = explode (',', $_POST['çities']);
$n = count($cities);
for($i=0;$i<$n;$i++){
//Insert data
mysql_query("insert into `cities` (city,state) values ('".$cities[$i]."','".$_POST['state']."') or die(mysql_error());
}
}
?>
First you create the input in the form like this:
<input type="text" name="cities"/>
And you then type: New York, New Jersey, San Francisco, Denver, etc.
Then on the .php file that receives the data (i'd guess it's a $_POST variable), so $_POST['cities'] then, you split it and loop:
// split the values by comma
$_POST['cities'] = explode(',',$_POST['cities']);
// loop the values
foreach($_POST['cities'] as $city) {
// trim (delete white space at the end and start for safety)
$city = trim($city);
mysql_query("insert into `cities` ('city','state') values ('".$city.','".$_POST['state']."');
}
And done.
Am just learning html. I need to write code that solves the quadratic equation formula. I tried php code embeding in html but am getting blank output. How do I get user values a, b, c and display conditional answers?
Here's a simple example of what you need to do. First make a HTML form:
<form method="post" action="index.php">
<input type="text" name="a" value="Enter 'a'" />
<input type="text" name="b" value="Enter 'b'" />
<input type="text" name="c" value="Enter 'c'" />
<input type="submit" name='calc' value="Calculate" />
</form>
There is your form. Now the calculations:
<?php
// Check if the form is submitted
if (isset($_POST['calc'])) {
//assign variables
$a = $_POST['a'];
$b = $_POST['b'];
$c = $_POST['c'];
//after assigning variables you can calculate your equation
$d = $b * $b - (4 * $a * $c);
$x1 = (-$b + sqrt($d)) / (2 * $a);
$x2 = (-$b - sqrt($d)) / (2 * $a);
echo "x<sub>1</sub> = {$x1} and x<sub>2</sub> = {$x2}";
} else {
// here you can put your HTML form
}
?>
You need to do more checks on it, but as I said before this is a simple example.
Edit: learn from the source , the official php site: http://php.net/manual/en/tutorial.forms.php
1.Create a form with the fields you want. <form method='post' ....>...</form>
2.The user submit the form and then write a PHP code which get the posted data ($_POST)
and manipulate it according to the quadratic equation formula.
3.Echo the result.
I have smaller example.
This file sends data from form to itself. When it sends something - result of condition
$_SERVER['REQUEST_METHOD']=='POST'
is true. If its true - server process code in "if" block. It assigns data sent from form to 2 variables, then adds them and store in "$sum" variable. Result is displayed.
<html>
<body>
<form method="POST">
<p>
A: <br />
<input name="number_a" type="text"></input>
</p>
<p>B: <br />
<input name="number_b" type="text"></input>
</p>
<p>
<input type="submit"/>
</p>
</form>
<?php
if ($_SERVER['REQUEST_METHOD']=='POST') // process "if block", if form was sumbmitted
{
$a = $_POST['number_a'] ; // get first number form data sent by form to that file itself
$b = $_POST['number_b'] ; // get second number form data sent by form to that file itself
$sum = $a + $b; // calculate something
echo "A+B=" . $sum; // print this to html source, use "." (dot) for append text to another text/variable
}
?>
</body>
</html>
You need PHP server to test/use this! PHP file must be processed by web server, which creates page. Opening php file from disk will not work. If you need more explanations - ask for it in comments.
I'm writting a web app, I'm doing a html form with javascript to validate the data, I'm using a servlet to insert the data in a DB, but I need, when the form load, fill a select in the html form with the rows of a table in a MySql DB, I think I have to make a query in a ResultSet and then fill the select in the html form with this info, and then use the HttpServletResponse, but I have no idea how to make this
Use PHP to access the database and then put it into the form. Something like this:
$id = $_GET['id'];
$result = mysql_query("SELECT * FROM table_name WHERE id='$id'");
$info = mysql_fetch_array($result))
$name = $info['name'];
$email = $info['email'];
$anotherField = $info['another_field'];
In this, the info array has all of the database data in it of the id. But of course you would change the values and stuff. Change table_name to the table name, and if you are going to do something in the URL like ?id=373384 or something, then this will work. (I would assume you are doing it this way.) But, if it isn't 'id', just change WHERE id='$id' to what is in the database to identify a line.
$info['name']; would be the "name" column in your table. But, you can change 'name' and stuff to what you have in your database.
Here is the form code to pre-fill it with data:
<form>
<input type="text" name="name" value="<?php echo $name ?>" />
<input type="text" name="name" value="<?php echo $email ?>" />
<!--etc...-->
<input type="submit" value="Submit" />
</form>
You would need to change a lot of this, but I'm sure you get the point of it. :)
Note: This is not a simple copy+paste script. You will have to do a lot of charing because I don't know what your table values are and stuff.
If you have any questions, please do ask.