In my build process I want to put the artifacts of the build steps into .tmp/serve directory.
I managed to set up gulp-watch to fire specific tasks when I modify files in my working directory. E.q. when I modify htmls, they are built and the artifacts are pasted into desired .tmp/serve directory
I'm having problems with reloading the files from .tmp/serve with browser-sync. When I save changes in my working directory multiple times, browser-sync refreshes only the previous changes (1 change delay). I guess the reload function fires before gulp-dest finishes. Note that if I refresh browser manually the current changes appear.
Am I doing something wrong?
Build htmls task
gulp.task('html', ['styles'], () => {
return gulp.src('app/*.html')
.pipe($.if('*.html', $.minifyHtml({conditionals: true, loose: true})))
.pipe(gulp.dest('.tmp/serve'))
;
});
Sever task
const reload = browserSync.reload;
gulp.task('serve', ['styles', 'fonts', 'build:scripts', 'html', 'images'], () => {
browserSync({
notify: false,
port: 9000,
server: {
baseDir: ['.tmp/serve'],
routes: {
'/bower_components': 'bower_components'
}
}
});
/*********** SEE THE LINES BELOW **************/
gulp.watch([
'.tmp/serve/**/*',
]).on('change', reload);
gulp.watch('app/styles/**/*.scss', ['styles']);
gulp.watch('app/fonts/**/*', ['fonts']);
gulp.watch('app/*.html', ['html']);
gulp.watch('app/scripts/**/*', ['build:scripts']);
gulp.watch('bower.json', ['wiredep', 'fonts']);
});
You can use run-sequence to reload after a build.
Your gulpfile would become like this..
var gulp = require('gulp'),
runSeq = require('run-sequence')
...
;
gulp.task('build', ['styles', 'fonts', 'build:scripts', 'html', 'images']);
gulp.task('serve', ['build', 'watch'], () => {
browserSync({
notify: false,
port: 9000,
server: {
baseDir: ['.tmp/serve'],
routes: {
'/bower_components': 'bower_components'
}
}
});
gulp.task('reload', function (callback) {
browserSync.reload();
callback();
});
gulp.task('watch', ['watch-styles', ...]);
gulp.task('watch-styles', function () {
gulp.watch('app/styles/**/*.scss', function () {
runSeq('styles', 'reload');
});
});
/* And so on for every watch task */
Note that run-sequence needs your tasks to either return a stream or to call a callback, otherwise it will cause gulp to pause indefinitely. Read the Doc to learn more.
Related
I have a Gulp + Browsersync setup which is compiling everything but when I try to view the site in the browser the localhost (Access URLs) is not working.
my code looks like below:
const browsersync = done => {
browserSync.init({
proxy: config.projectURL, // Proxing website.local:8000
open: config.browserAutoOpen, //false
injectChanges: config.injectChanges, //true
watchEvents: [ 'change', 'add', 'unlink', 'addDir', 'unlinkDir' ]
});
done();
};
// Helper function to allow browser reload with Gulp 4.
const reload = done => {
browserSync.reload();
done();
};
Running as follows:
gulp.task(
'default',
gulp.parallel( 'styles', 'customJS', 'images', browsersync, () => {
gulp.watch( config.watchPhp, reload ); // Reload on PHP file changes.
gulp.watch( config.watchStyles, gulp.parallel( 'styles' ) ); // Reload on SCSS file changes.
gulp.watch( config.watchJsCustom, gulp.series( 'customJS', reload ) ); // Reload on customJS file changes.
gulp.watch( config.imgSRC, gulp.series( 'images', reload ) ); // Reload on customJS file changes.
})
);
Any ideas would be greatly appreciated.
Thanks
creating the server with gulp-connect plugin.
the Code is fine, but when I run gulp, it start monitor the 'watch'
how can I run the server and run the watch function after creating the server.
var gulp = require("gulp"),
scss = require("gulp-scss"),
jsmin = require("gulp-jsmin"),
rename = require("gulp-rename"),
connect = require("gulp-connect");
var path = {
src: {
js: 'dist/js/**/*.js',
css: 'dist/css/**/*.scss',
img: 'dist/img/*.*',
html: '/**/*.html'
},
build: {
js: './js/',
css: './css/',
img: './img/'
}
};
/* connect server */
gulp.task("connect", function () {
connect.server({
root: './',
livereload: true
});
});
/* SASS into css */
gulp.task("styles", function () {
gulp.src(path.src.css)
.pipe(scss())
.pipe(gulp.dest(path.build.css))
.pipe(connect.reload());
});
/* minified JS */
gulp.task("scripts", function () {
gulp.src(path.src.js)
.pipe(jsmin())
.pipe(rename({ suffix: '.min' }))
.pipe(gulp.dest(path.build.js))
.pipe(connect.reload());
});
/* html */
gulp.task("html",function(){
gulp.src(path.src.html)
.pipe(connect.reload());
});
/* watch */
gulp.task('watch', function(){
gulp.watch([path.src.html],["html"]);
gulp.watch([path.src.css],["styles"]);
gulp.watch([path.src.js],["scripts"]);
});
gulp.task("default", ["connect", 'html', 'styles', 'scripts','watch']);
If I skip the watch function then gulp create the server.
Any Help!!!
Change this :
gulp.task("default", ["connect", 'html', 'styles', 'scripts', 'watch']);
to:
gulp.task("default", ['html', 'styles', 'scripts', 'watch']);
and
gulp.task('watch', ['connect'], function(){
gulp.watch([path.src.html],["html"]);
gulp.watch([path.src.css],["styles"]);
gulp.watch([path.src.js],["scripts"]);
});
Now the 'connect' task will run before the 'watch' task starts. I think that is what you want? Also, add return statements to all your tasks. As in
gulp.task("styles", function () {
return gulp.src(path.src.css) ...........
I am learning the front-end build system currently gulp, i want to use brower-sync and the problem is it is not throwing an error in the commad line but instead when it brings up the browser it will not display my html file and it will say "Cannot GET /" error in the browser window. This is my gulpfile.js code
var gulp = require('gulp'),
uglify = require('gulp-uglify'),
compass= require('gulp-compass'),
plumber = require('gulp-plumber'),
autoprefixer = require('gulp-autoprefixer'),
browserSync = require('browser-sync'),
reload = browserSync.reload,
rename = require('gulp-rename');
gulp.task('scripts', function() {
gulp.src(['public/src/js/**/*.js', '!public/src/js/**/*.min.js'])
.pipe(plumber())
.pipe(rename({suffix: '.min'}))
.pipe(uglify())
.pipe(gulp.dest('public/src/js/'));
});
gulp.task('styles', function() {
gulp.src('public/src/scss/main.scss')
.pipe(plumber())
.pipe(compass({
config_file: './config.rb',
css: './public/src/css/',
sass: './public/src/scss/'
}))
.pipe(autoprefixer('last 2 versions'))
.pipe(gulp.dest('public/src/css/'))
.pipe(reload({stream:true}));
});
gulp.task('html', function() {
gulp.src('public/**/*.html');
});
gulp.task('browser-sync', function() {
browserSync({
server: {
baseDir: "./public/"
}
});
});
gulp.task('watch', function() {
gulp.watch('public/src/js/**/*.js', ['scripts']);
gulp.watch('public/src/scss/**/*.scss', ['styles']);
gulp.watch('public/**/*.html', ['html']);
});
gulp.task('default', ['scripts', 'styles', 'html', 'browser-sync', 'watch']);
i am using windows and git bash and version is "browser-sync": "^2.12.5" so what is the problem and try to explain for me in order to get something out of it.
Is there an index.html file in your ./public/ folder? If not, you need to tell browserSync what is your start page. You can also get browserSync to show the listing of the base directory, see update below.
You could also try to use public without the leading dot.
Edit: The startPath config directive does not seem to work, use index instead
...
gulp.task('browser-sync', function() {
browserSync({
server: {
baseDir: "public/",
index: "my-start-page.html"
}
});
});
...
Update: Actually you can get directory listing with browserSync. That way it would show a list of files in public, not the Cannot Get error
...
gulp.task('browser-sync', function() {
browserSync({
server: {
baseDir: "public/",
directory: true
}
});
});
...
I got this to work when the index.html file was inside the same folder:
browserSync.init({
server: {
baseDir: "./"
}
});
gulp.task('browser-sync', function() {
browserSync({
server: {
baseDir: "./"
},
port: 8080,
open: true,
notify: false
});
});
gulp.task('serve',['sass'], function() {
bs.init({
server: "./app",
startPath: "/index.html", // After it browser running
browser: 'chrome',
host: 'localhost',
port: 4000,
open: true,
tunnel: true
});
I solved my "Cannot GET" errors in browser-sync by always pointing to a .html file in code, or by having a folder structure ending with and index.html
About <!-- Cannot GET error-->
About <!-- same code as above, but works if your site structure is: ./about/index.html-->
About <!-- OK -->
My Gulp file for reference (using browser-sync with jekyll, so everything is in the ./_site folder, and the gulpfile is in ./)
var gulp = require('gulp');
var shell = require('gulp-shell');
var browserSync = require('browser-sync').create();
gulp.task('build', shell.task(['jekyll build --watch']));
// serving blog with Browsersync
gulp.task('serve', function () {
browserSync.init(
{
server: {baseDir: '_site/'}
}
);
// Reloads page when some of the already built files changed:
gulp.watch('_site/**/*.*').on('change', browserSync.reload);
});
gulp.task('default', ['build', 'serve']);
Hope it helps.
Michelangelo
May be you have not index.html in baseDir: '_site/'? In order to see your static web-page in the web-browser instead of that annoying message you have to rename a file your_file.html to index.html. This will solve Cannot GET/ problem.
In my case, this helped me:
server: {
baseDir: '.',
index: "index.html"
}
gulp.task('server', function()
{
browserSync.init(["public/src/css/","public/src/js"],{
server: "./",
startPath: "./index.html", // After it browser running
// browser: 'chrome',
host: 'localhost',
// port: 4000,
open: true,
tunnel: true });
});
gulp.task('default', ['scripts', 'styles', 'html', 'server', 'watch']);
Here are my tasks to delete, bundle and watch for changes. Everytime I bundle, it works fine (even if the file doesn't exist yet). However, with the watch task, it'll break when it deletes the file and won't rebuild. Thoughts?
gulp.task('delete', function() {
var path = 'app/public/bundle.js';
return del(path);
});
gulp.task('bundle', ['delete'], function() {
var projectFiles = glob.sync('./app/**/*.js')
return browserify({
entries: projectFiles,
extensions: ['.js']
})
.bundle()
.on('error', function(err){
gutil.log(err);
})
.pipe(source('bundle.js'))
.pipe(gulp.dest('./app/public/'))
.pipe(notify({message: 'Browserify bundlified!'}))
});
gulp.task('watch', function(){
gulp.watch('app/assets/sass/**/*', ['css']);
gulp.watch('./app/**/*.js', ['bundle']);
})
I'm trying to get browsersync (with stream) working, but it doesn't seem to work in pipe context. The sass compiles correctly, then nothing happens. My code is as follows:
gulp.task('sass', function () {
gulp.src('../css/source/*.scss')
.on('error', function (err) {
notify.onError({
title: "Gulp",
subtitle: "Failure!",
message: "<%= error.message %>",
sound: "Beep"
})(err);
this.emit('end');
})
.pipe(sourcemaps.init())
.pipe(sass())
.pipe(sourcemaps.write())
.pipe(concat('build.css'))
.pipe(gulp.dest('../css/build/dev'))
.pipe(browserSync.reload({stream:true}))
.pipe(csso())
.pipe(gulp.dest('../css/build/min'));
});
gulp.task('default', ['browser-sync'], function(){
gulp.watch('../css/source/*.scss', ['sass']);
});
In my terminal it does seem to register it though:
[BS] 1 file changed (build.css)
[BS] File changed: ../css/build/dev/build.css
The only way I can get a reload to happen is to add it to the watch task:
gulp.watch("../css/build/dev/*.css", browserSync.reload);
... but with this method I can't seem to enable the stream, as it doesn't accept a function. I have also tried browserSync.stream() as per the current docs to no avail.
Here is the browsersync task if it helps:
gulp.task('browser-sync', ['sass'], function() {
browserSync.init({
proxy: 'local.test.com',
host: '10.0.1.40'
});
});
Please help!
Remove the pipe to browserSync in task sass, and add a files key to browserSync.init():
browserSync.init({
...
files: ['../css/**/*.css'],
...
});
With the above setup you need neither gulp.watch() (that's for starting tasks based on file changes) nor a gulp task that depends on browserSync. Simply run gulp browser-sync.
Note that this watches the CSS directly to avoid a race condition between the scss changes and browserSync.